SlideShare a Scribd company logo
1 of 3
Download to read offline
Student Name: _______________________________________________ Pd. ____ Date: __________
Stoichiometry Word Problems 2 SOLUTIONS
1. Cellular respiration occurs in animal cells, a reaction that is essentially the combustion of a sugar
called glucose, C6H12O6. If the average human uses 550 liters of oxygen when breathing, how many
grams of glucose are used by this process?
Balanced Equation: C6H12O6 + 6 O2 6 CO2 + 6 H2O
6126
26126
6126
2
6126
2
22
61.736
1
180
6
1
4.22
1
1
550
OHCg
OHCmol
OHCg
Omol
OHCmol
OL
OmolOL
=

























2. Nitroglycerin, C3H5(ONO2)3, was invented in 1846 by an Italian chemist named Ascanio Sobrero.
Nitroglycerine contains both an oxidant and a fuel. When it detonates, it decomposes to form carbon
dioxide, water, nitrogen, and oxygen, all in a gaseous state. Every mole of the explosive that
decomposes in this way generates a tremendous amount of energy – approximately 1.5 MJ (1 MJ = 1
megajoule = 1 x 106
J = 1 MJ).
a. If 1.135 kilograms of nitroglycerin detonates, how many total liters of gas (assuming
STP) are produced?
Balanced Equations: 4 C3H5(ONO2)3 10 H2O + 12 CO2 + 6 N2 + O2
3253 )(ONOHC812
1
4.22
4
29
227
1
1
1000
1
135.1
L
gasmol
gasL
nitromol
gasmol
nitrog
nitromol
nitrokg
nitrognitrokg
=





























b. How much energy is produced by the explosion?
MJ
nitromol
energyMJ
nitrog
nitromol
nitrokg
nitrognitrokg
5.7
1
1
227
1
1
1000
1
135.1
=























3. Sodium hydroxide is a strong, inexpensive base used commonly in many industrial chemical
processes. It is manufactured by creating a strong aqueous brine (NaCl) solution and applying an
intense electrical current. The sodium ions react with the water to generate sodium hydroxide,
hydrogen gas, and chlorine gas. If 2345 g of salt is mixed with 4562 g of water:
a. Which reactant is limiting?
Balanced Equation: 2 NaCl + 2 H2O 2 NaOH + H2 + Cl2
OHg
OHmol
OHg
NaClmol
OHmol
NaClg
NaClmolNaClg
2
2
22
54.721
1
18
2
2
5.58
1
1
2345
=























Since the amount of H2O required is less than the amount provided (4562 g), it is in
excess, so NaCl is the limiting reagent.
b. How much base is produced?
Use the limiting reactant (NaCl):
NaOHg
NaOHmol
NaOHg
NaClmol
NaOHmol
NaClg
NaClmolNaClg
42.1603
1
40
2
2
5.58
1
1
2345
=























c. How much of the excess reactant is left over?
From part (a), 721.54 g of water were consumed. Subtract this from the given (4562 –
721.54 = 3840 g H2O are left over.
4. Prior to World War II, ammonia was produced by a process called dry distillation, by which
ammonium chloride and quicklime (calcium oxide) react to form calcium chloride, calcium
hydroxide, and ammonia. The reaction looks like this:
2 NH4Cl + 2 CaO CaCl2 + Ca(OH)2 + 2 NH3
If 75.6 g of ammonium chloride is allowed to react with 52.8 g of quicklime:
a. How many grams of the excess reactant are left over?
CaOg
CaOmol
CaOg
ClNHmol
CaOmol
ClNHg
ClNHmolClNHg
50.97
1
1.56
2
2
5.43
1
1
6.75
44
44
=























Since more quicklime is needed than is provided, quicklime is the limiting reactant.
Therefore:
ClNHg
ClNHmol
ClNHg
CaOmol
ClNHmol
CaOg
CaOmolCaOg
4
4
44
94.40
1
5.43
2
2
1.56
1
1
8.52
=























75.6 – 40.4 = 35.2 grams of NH4Cl are left over.
b. How many grams of ammonia are formed?
Use the limiting reactant:
3
3
43
0.16
1
0.17
2
2
1.56
1
1
8.52
NHg
NHmol
ClNHg
CaOmol
NHmol
CaOg
CaOmolCaOg
=























5. Hydrochloric acid reacts with zinc metal to form zinc chloride and hydrogen gas. If 345.2 g of zinc
metal reacts with 231.6 grams of acid. How many liters of hydrogen gas are produced? How many
moles of zinc chloride are produced?
Balanced Equation: 2 HCl + Zn ZnCl2 + H2
Zng
Znmol
Zng
HClmol
Znmol
HClg
HClmolHClg
49.207
1
4.65
2
1
5.36
1
1
6.231
=























HCl is limiting,
2
2
22
35.6
1
0.2
2
1
5.36
1
1
6.231
Hg
Hmol
Hg
HClmol
Hmol
HClg
HClmolHClg
=























ZnClg
ZnClmol
ZnClg
HClmol
ZnClmol
HClg
HClmolHClg
12.320
1
9.100
2
1
5.36
1
1
6.231
=























6. Dappolonium gas (Dp2 mw=5 g/mol) and Rockthehousium (Rk, mw=7 g/mol) combine to form
Dapphousium (RkDp2), an amazingly hard material with transdimensional properties. If 17 grams of
Dp2 and 32 grams of Rk combine, which is the limiting reactant? How many grams of
Dapphousium is formed?
Balanced Equation: 2 Rk + Dp2 RkDp2
Rkg
Rkmol
Rkg
Dpmol
Rkmol
Dpg
DpmolDpg
6.47
1
7
1
2
5
1
1
17
22
22
=























Rockthehousium is limiting.
2
2
22
43.27
1
12
2
1
7
1
1
32
RkDpg
RkDpmol
RkDpg
Rkmol
RkDpmol
Rkg
RkmolRkg
=
























More Related Content

What's hot

Empirical formulas
Empirical formulasEmpirical formulas
Empirical formulas
ZB Chemistry
 
Chapter 11.4 : Effusion and Diffusion
Chapter 11.4 : Effusion and DiffusionChapter 11.4 : Effusion and Diffusion
Chapter 11.4 : Effusion and Diffusion
Chris Foltz
 
Chapter 1 kinetic particle theory (1)
Chapter 1   kinetic particle theory (1)Chapter 1   kinetic particle theory (1)
Chapter 1 kinetic particle theory (1)
AR Sharmila Jose
 
Law of multiple proportions and law of definite proportions
Law of multiple proportions and law of definite proportionsLaw of multiple proportions and law of definite proportions
Law of multiple proportions and law of definite proportions
Nikki Wilkinson
 
Unit 7 4 stoichiometry – limiting reactants
Unit 7 4 stoichiometry – limiting reactantsUnit 7 4 stoichiometry – limiting reactants
Unit 7 4 stoichiometry – limiting reactants
jwallach
 

What's hot (20)

Empirical formulas
Empirical formulasEmpirical formulas
Empirical formulas
 
Chapter 11.4 : Effusion and Diffusion
Chapter 11.4 : Effusion and DiffusionChapter 11.4 : Effusion and Diffusion
Chapter 11.4 : Effusion and Diffusion
 
The mole concept
The mole conceptThe mole concept
The mole concept
 
Mole Concept
Mole ConceptMole Concept
Mole Concept
 
Chem.pptx
Chem.pptxChem.pptx
Chem.pptx
 
Balancing Chemical Equations
Balancing Chemical EquationsBalancing Chemical Equations
Balancing Chemical Equations
 
Collision Theory
Collision TheoryCollision Theory
Collision Theory
 
Configuration practice
Configuration practiceConfiguration practice
Configuration practice
 
Gas Laws
Gas LawsGas Laws
Gas Laws
 
Molecular formula
Molecular formulaMolecular formula
Molecular formula
 
Moles molar mass_avonumb pt1
Moles molar mass_avonumb pt1Moles molar mass_avonumb pt1
Moles molar mass_avonumb pt1
 
Le chatelier principles in dynamic equilibrium reactions
Le chatelier principles in dynamic equilibrium reactionsLe chatelier principles in dynamic equilibrium reactions
Le chatelier principles in dynamic equilibrium reactions
 
Stoichiometry
StoichiometryStoichiometry
Stoichiometry
 
CARBON COMPOUNDS SCIENCE 9
CARBON COMPOUNDS SCIENCE 9CARBON COMPOUNDS SCIENCE 9
CARBON COMPOUNDS SCIENCE 9
 
Chapter 1 kinetic particle theory (1)
Chapter 1   kinetic particle theory (1)Chapter 1   kinetic particle theory (1)
Chapter 1 kinetic particle theory (1)
 
Law of multiple proportions and law of definite proportions
Law of multiple proportions and law of definite proportionsLaw of multiple proportions and law of definite proportions
Law of multiple proportions and law of definite proportions
 
Entropy
EntropyEntropy
Entropy
 
Unit 7 4 stoichiometry – limiting reactants
Unit 7 4 stoichiometry – limiting reactantsUnit 7 4 stoichiometry – limiting reactants
Unit 7 4 stoichiometry – limiting reactants
 
Concentration of Solution
Concentration of SolutionConcentration of Solution
Concentration of Solution
 
Ionic, covalent, and metallic bonds
Ionic, covalent, and metallic bondsIonic, covalent, and metallic bonds
Ionic, covalent, and metallic bonds
 

Similar to Activity --stoichiometry-word-problems-2-solutions

Recitation before exam-student
Recitation before exam-studentRecitation before exam-student
Recitation before exam-student
Elise Myers
 
Analytical instruments week 1
Analytical instruments week 1Analytical instruments week 1
Analytical instruments week 1
andreapearce
 
Biochapter9respiration 151125144235-lva1-app6891
Biochapter9respiration 151125144235-lva1-app6891Biochapter9respiration 151125144235-lva1-app6891
Biochapter9respiration 151125144235-lva1-app6891
Cleophas Rwemera
 

Similar to Activity --stoichiometry-word-problems-2-solutions (20)

CLASS X CHEMISTRY
CLASS X CHEMISTRY CLASS X CHEMISTRY
CLASS X CHEMISTRY
 
Quantitative aspect of Stoichiometry
Quantitative aspect of StoichiometryQuantitative aspect of Stoichiometry
Quantitative aspect of Stoichiometry
 
Exp 8
Exp 8Exp 8
Exp 8
 
Llecture 10.ppt
Llecture  10.pptLlecture  10.ppt
Llecture 10.ppt
 
SI #7 Key
SI #7 KeySI #7 Key
SI #7 Key
 
Respiration
RespirationRespiration
Respiration
 
STOICHIMETRY.ppt
STOICHIMETRY.pptSTOICHIMETRY.ppt
STOICHIMETRY.ppt
 
Respiration ppt
Respiration pptRespiration ppt
Respiration ppt
 
C16 alcohols and carboxylic acids
C16 alcohols and carboxylic acidsC16 alcohols and carboxylic acids
C16 alcohols and carboxylic acids
 
C16 alcohols and carboxylic acids
C16 alcohols and carboxylic acidsC16 alcohols and carboxylic acids
C16 alcohols and carboxylic acids
 
Recitation before exam-student
Recitation before exam-studentRecitation before exam-student
Recitation before exam-student
 
Chlorine.pptx
Chlorine.pptxChlorine.pptx
Chlorine.pptx
 
K-12 Carbon Capture: Chalk from CO2
K-12 Carbon Capture:  Chalk from CO2K-12 Carbon Capture:  Chalk from CO2
K-12 Carbon Capture: Chalk from CO2
 
Chemical reactions
Chemical reactionsChemical reactions
Chemical reactions
 
Cellular respiration
Cellular respirationCellular respiration
Cellular respiration
 
Alcohol, phenol & ether
Alcohol, phenol & etherAlcohol, phenol & ether
Alcohol, phenol & ether
 
Analytical instruments week 1
Analytical instruments week 1Analytical instruments week 1
Analytical instruments week 1
 
Chapter 12.ppt
Chapter 12.pptChapter 12.ppt
Chapter 12.ppt
 
Chapter 9: Respiration
Chapter 9: RespirationChapter 9: Respiration
Chapter 9: Respiration
 
Biochapter9respiration 151125144235-lva1-app6891
Biochapter9respiration 151125144235-lva1-app6891Biochapter9respiration 151125144235-lva1-app6891
Biochapter9respiration 151125144235-lva1-app6891
 

Recently uploaded

SURVEY I created for uni project research
SURVEY I created for uni project researchSURVEY I created for uni project research
SURVEY I created for uni project research
CaitlinCummins3
 
SPLICE Working Group: Reusable Code Examples
SPLICE Working Group:Reusable Code ExamplesSPLICE Working Group:Reusable Code Examples
SPLICE Working Group: Reusable Code Examples
Peter Brusilovsky
 
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPSSpellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
AnaAcapella
 

Recently uploaded (20)

UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024
 
Observing-Correct-Grammar-in-Making-Definitions.pptx
Observing-Correct-Grammar-in-Making-Definitions.pptxObserving-Correct-Grammar-in-Making-Definitions.pptx
Observing-Correct-Grammar-in-Making-Definitions.pptx
 
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUMDEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
 
SURVEY I created for uni project research
SURVEY I created for uni project researchSURVEY I created for uni project research
SURVEY I created for uni project research
 
Stl Algorithms in C++ jjjjjjjjjjjjjjjjjj
Stl Algorithms in C++ jjjjjjjjjjjjjjjjjjStl Algorithms in C++ jjjjjjjjjjjjjjjjjj
Stl Algorithms in C++ jjjjjjjjjjjjjjjjjj
 
PSYPACT- Practicing Over State Lines May 2024.pptx
PSYPACT- Practicing Over State Lines May 2024.pptxPSYPACT- Practicing Over State Lines May 2024.pptx
PSYPACT- Practicing Over State Lines May 2024.pptx
 
SPLICE Working Group: Reusable Code Examples
SPLICE Working Group:Reusable Code ExamplesSPLICE Working Group:Reusable Code Examples
SPLICE Working Group: Reusable Code Examples
 
Major project report on Tata Motors and its marketing strategies
Major project report on Tata Motors and its marketing strategiesMajor project report on Tata Motors and its marketing strategies
Major project report on Tata Motors and its marketing strategies
 
OS-operating systems- ch05 (CPU Scheduling) ...
OS-operating systems- ch05 (CPU Scheduling) ...OS-operating systems- ch05 (CPU Scheduling) ...
OS-operating systems- ch05 (CPU Scheduling) ...
 
male presentation...pdf.................
male presentation...pdf.................male presentation...pdf.................
male presentation...pdf.................
 
OSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & SystemsOSCM Unit 2_Operations Processes & Systems
OSCM Unit 2_Operations Processes & Systems
 
Đề tieng anh thpt 2024 danh cho cac ban hoc sinh
Đề tieng anh thpt 2024 danh cho cac ban hoc sinhĐề tieng anh thpt 2024 danh cho cac ban hoc sinh
Đề tieng anh thpt 2024 danh cho cac ban hoc sinh
 
Mattingly "AI & Prompt Design: Named Entity Recognition"
Mattingly "AI & Prompt Design: Named Entity Recognition"Mattingly "AI & Prompt Design: Named Entity Recognition"
Mattingly "AI & Prompt Design: Named Entity Recognition"
 
Supporting Newcomer Multilingual Learners
Supporting Newcomer  Multilingual LearnersSupporting Newcomer  Multilingual Learners
Supporting Newcomer Multilingual Learners
 
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPSSpellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
 
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community PartnershipsSpring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
 
VAMOS CUIDAR DO NOSSO PLANETA! .
VAMOS CUIDAR DO NOSSO PLANETA!                    .VAMOS CUIDAR DO NOSSO PLANETA!                    .
VAMOS CUIDAR DO NOSSO PLANETA! .
 
Trauma-Informed Leadership - Five Practical Principles
Trauma-Informed Leadership - Five Practical PrinciplesTrauma-Informed Leadership - Five Practical Principles
Trauma-Informed Leadership - Five Practical Principles
 
Including Mental Health Support in Project Delivery, 14 May.pdf
Including Mental Health Support in Project Delivery, 14 May.pdfIncluding Mental Health Support in Project Delivery, 14 May.pdf
Including Mental Health Support in Project Delivery, 14 May.pdf
 
ANTI PARKISON DRUGS.pptx
ANTI         PARKISON          DRUGS.pptxANTI         PARKISON          DRUGS.pptx
ANTI PARKISON DRUGS.pptx
 

Activity --stoichiometry-word-problems-2-solutions

  • 1. Student Name: _______________________________________________ Pd. ____ Date: __________ Stoichiometry Word Problems 2 SOLUTIONS 1. Cellular respiration occurs in animal cells, a reaction that is essentially the combustion of a sugar called glucose, C6H12O6. If the average human uses 550 liters of oxygen when breathing, how many grams of glucose are used by this process? Balanced Equation: C6H12O6 + 6 O2 6 CO2 + 6 H2O 6126 26126 6126 2 6126 2 22 61.736 1 180 6 1 4.22 1 1 550 OHCg OHCmol OHCg Omol OHCmol OL OmolOL =                          2. Nitroglycerin, C3H5(ONO2)3, was invented in 1846 by an Italian chemist named Ascanio Sobrero. Nitroglycerine contains both an oxidant and a fuel. When it detonates, it decomposes to form carbon dioxide, water, nitrogen, and oxygen, all in a gaseous state. Every mole of the explosive that decomposes in this way generates a tremendous amount of energy – approximately 1.5 MJ (1 MJ = 1 megajoule = 1 x 106 J = 1 MJ). a. If 1.135 kilograms of nitroglycerin detonates, how many total liters of gas (assuming STP) are produced? Balanced Equations: 4 C3H5(ONO2)3 10 H2O + 12 CO2 + 6 N2 + O2 3253 )(ONOHC812 1 4.22 4 29 227 1 1 1000 1 135.1 L gasmol gasL nitromol gasmol nitrog nitromol nitrokg nitrognitrokg =                              b. How much energy is produced by the explosion? MJ nitromol energyMJ nitrog nitromol nitrokg nitrognitrokg 5.7 1 1 227 1 1 1000 1 135.1 =                        3. Sodium hydroxide is a strong, inexpensive base used commonly in many industrial chemical processes. It is manufactured by creating a strong aqueous brine (NaCl) solution and applying an intense electrical current. The sodium ions react with the water to generate sodium hydroxide, hydrogen gas, and chlorine gas. If 2345 g of salt is mixed with 4562 g of water: a. Which reactant is limiting? Balanced Equation: 2 NaCl + 2 H2O 2 NaOH + H2 + Cl2 OHg OHmol OHg NaClmol OHmol NaClg NaClmolNaClg 2 2 22 54.721 1 18 2 2 5.58 1 1 2345 =                        Since the amount of H2O required is less than the amount provided (4562 g), it is in excess, so NaCl is the limiting reagent.
  • 2. b. How much base is produced? Use the limiting reactant (NaCl): NaOHg NaOHmol NaOHg NaClmol NaOHmol NaClg NaClmolNaClg 42.1603 1 40 2 2 5.58 1 1 2345 =                        c. How much of the excess reactant is left over? From part (a), 721.54 g of water were consumed. Subtract this from the given (4562 – 721.54 = 3840 g H2O are left over. 4. Prior to World War II, ammonia was produced by a process called dry distillation, by which ammonium chloride and quicklime (calcium oxide) react to form calcium chloride, calcium hydroxide, and ammonia. The reaction looks like this: 2 NH4Cl + 2 CaO CaCl2 + Ca(OH)2 + 2 NH3 If 75.6 g of ammonium chloride is allowed to react with 52.8 g of quicklime: a. How many grams of the excess reactant are left over? CaOg CaOmol CaOg ClNHmol CaOmol ClNHg ClNHmolClNHg 50.97 1 1.56 2 2 5.43 1 1 6.75 44 44 =                        Since more quicklime is needed than is provided, quicklime is the limiting reactant. Therefore: ClNHg ClNHmol ClNHg CaOmol ClNHmol CaOg CaOmolCaOg 4 4 44 94.40 1 5.43 2 2 1.56 1 1 8.52 =                        75.6 – 40.4 = 35.2 grams of NH4Cl are left over. b. How many grams of ammonia are formed? Use the limiting reactant: 3 3 43 0.16 1 0.17 2 2 1.56 1 1 8.52 NHg NHmol ClNHg CaOmol NHmol CaOg CaOmolCaOg =                       
  • 3. 5. Hydrochloric acid reacts with zinc metal to form zinc chloride and hydrogen gas. If 345.2 g of zinc metal reacts with 231.6 grams of acid. How many liters of hydrogen gas are produced? How many moles of zinc chloride are produced? Balanced Equation: 2 HCl + Zn ZnCl2 + H2 Zng Znmol Zng HClmol Znmol HClg HClmolHClg 49.207 1 4.65 2 1 5.36 1 1 6.231 =                        HCl is limiting, 2 2 22 35.6 1 0.2 2 1 5.36 1 1 6.231 Hg Hmol Hg HClmol Hmol HClg HClmolHClg =                        ZnClg ZnClmol ZnClg HClmol ZnClmol HClg HClmolHClg 12.320 1 9.100 2 1 5.36 1 1 6.231 =                        6. Dappolonium gas (Dp2 mw=5 g/mol) and Rockthehousium (Rk, mw=7 g/mol) combine to form Dapphousium (RkDp2), an amazingly hard material with transdimensional properties. If 17 grams of Dp2 and 32 grams of Rk combine, which is the limiting reactant? How many grams of Dapphousium is formed? Balanced Equation: 2 Rk + Dp2 RkDp2 Rkg Rkmol Rkg Dpmol Rkmol Dpg DpmolDpg 6.47 1 7 1 2 5 1 1 17 22 22 =                        Rockthehousium is limiting. 2 2 22 43.27 1 12 2 1 7 1 1 32 RkDpg RkDpmol RkDpg Rkmol RkDpmol Rkg RkmolRkg =                       