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WARM UP
 What's the mass of 1 mole of water?
 What's the mass of 2 moles of Carbon Dioxide?
 What’s the mass of 3.5 moles of Sodium Chloride?
CHAPTER 12
STOICHIOMETRY
WHAT IS IT??
 Chemists use balanced chemical equations as a
basis to calculate
A. How much reactant is needed
B. How much product is formed in a reaction.
 The calculation of quantities in chemical reactions
is called Stoichiometry
 stoicheion "element“
 metron "measure"
LIKE A RECIPE
 A balanced chemical equation provides the same kind of quantitative
information that a recipe does.
LET’S LOOK AT AN EVERYDAY EXAMPLE!
 In a five day work
week, tiny tike is
scheduled to make 640
tricycles. How many
wheels should be in the
plant on Monday
morning to make those
tricycles?
INTERPRETING CHEMICAL EQUATIONS
 A balanced chemical equation can be interpreted in terms of different
quantities, including numbers of
 Representative Particles
 Atoms
 Molecules
 Functional Units
 Moles
 Mass - Grams
 Volume - Liters
INTERPRETING CHEMICAL EQUATIONS
This reaction requires the use of
a catalyst, high pressure (100–
1,000 atmospheres), and
elevated temperature (400–550
°C [750–1020 °F]).
USES OF AMMONIA
 The major use of ammonia is as a fertilizer
 Explosives (e.g., Trinitrotoluene (TNT),
nitroglycerin, and nitrocellulose)
 Synthetic fibers, such as nylon and rayon
 Dyeing and scouring of cotton, wool, and silk
 A coolant in refrigeration and air-conditioning
equipment
 Minor uses is inclusion in certain household
cleansing agents
INTERPRETING (CONT.)
INTERPRETING (CONT.)
 Always remember : Mass and atoms are always
conserved in a chemical reaction.
EXAMPLE OF INTERPRETING A CHEMICAL
REACTION
SECTION 2
CHEMICAL CALCULATIONS
WRITING AND USING MOLE RATIOS
 Mole Ratios are used to convert between:
 moles of reactant and moles of product
 moles of reactants
 moles of products
 A mole ratio is a conversion factor derived from the
coefficients of a balanced chemical equation interpreted
in terms of moles.
EXAMPLE #1
EXAMPLE #2
PRACTICE ON YOUR OWN
 Page 360 #11
11. This equation shows the formation of aluminum oxide, which
is found on the surface of aluminum objects exposed to the air.
4Al(s) + 3O2(g)  2Al2O3(s)
a. Write the six mole ratios that can be derived from this
equation.
b. How many moles of aluminum are needed to form 3.7 mol
Al2O3?
MASS TO MASS CALCULATIONS
EXAMPLE #4
PRACTICE ON YOUR OWN
 Page 361 # 13
13. Acetylene gas (C2H2) is produced by adding water to calcium
carbide (CaC2).
CaC2(s) + 2H2O(l)  C2H2(g) + Ca(OH)2(aq)
How many grams of acetylene are produced by adding water to 5.00 g
CaC2?
PRACTICE ON YOUR OWN
 Page 361 # 13
13. Acetylene gas (C2H2) is produced by adding water to calcium
carbide (CaC2).
CaC2(s) + 2H2O(l)  C2H2(g) + Ca(OH)2(aq)
How many grams of acetylene are produced by adding water to 5.00 g
CaC2?
INTERPRETING CHEMICAL EQUATIONS
 A balanced chemical equation can be interpreted in terms of different
quantities, including numbers of
 Moles
 Mass - Grams
 Representative Particles
 Atoms
 Molecules
 Functional Units
 Volume - Liters
INTERPRETING (CONT.)
unit
given
unit
requested
OTHER STOICHIOMETRIC CALCULATIONS
 In a typical stoichiometric problem,
 given quantity is first converted to moles
 mole ratio from the balanced equation is
used to calculate the number of moles of
the wanted substance
 moles are converted to any other unit of
measurement related to the unit mole, as
the problem requires
PROBLEM SOLVING APPROACH
PROBLEM SOLVING APPROACH
unit
given
unit
requested
Analyze List the knowns and the unknown.
Knowns
• mass of water 29.2 g H2O
• 2 mol H2O = 1 mol O2 (from balanced equation)
• 1 mol H2O = 18.0 g H2O (molar mass)
• 1 mol O2 = 6.02 x 1023 molecules O2
Unknown
• molecules of oxygen = ? molecules O2
The following calculations need to be done:
g H2O  mol H2O  mol O2  molecules O2
The appropriate mole ratio relating mol O2 to mol H2O from the
balanced equation is 1 mole O2 /2 mol H2O.
PRACTICE ON YOUR OWN
 Page 364 # 15
15. How many molecules of oxygen are produced by the
decomposition of 6.54 g of potassium chlorate (KClO3)?
2KClO3(s)  2KCl(s) + 3O2(g)
HOMEWORK
 Textbook page 364 - 366 ques. 16, 18, 20
VOLUME- VOLUME
12.3
LIMITING REAGENT AND PERCENT
YIELD
LIMITING REAGENT AND EXCESS REAGENT
 Limiting Reagent is the reagent that determines
the amount of product that can be formed by a
reaction
H2 + O2  H2O
O2 – Red
H2 - Blue
 Excess Reagent- is the reagent not used up (what
is left over in a chemical reaction)
LIMITING REAGENT AND EXCESS REAGENT
EXAMPLE
CHEMICAL EQUATION FOR THE PREPARATION OF
AMMONIA
EXAMPLE #1
PRACTICE ON YOUR OWN
 Page 370 # 25
PERCENT YIELD
 The percent yield is a measure of the efficiency of a
reaction carried out in the laboratory.
 Theoretical yield -maximum amount of product that could
be formed from given amounts of reactants
 Actual yield the amount of product that actually forms when
the reaction is carried out in the laboratory
EXAMPLE #1 (PERCENT YIELD )
EXAMPLE #2 PERCENT YIELD
PRACTICE ON YOUR OWN
 Page 374-375 # 29 and 31

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Chapter 12.ppt

  • 1. WARM UP  What's the mass of 1 mole of water?  What's the mass of 2 moles of Carbon Dioxide?  What’s the mass of 3.5 moles of Sodium Chloride?
  • 3. WHAT IS IT??  Chemists use balanced chemical equations as a basis to calculate A. How much reactant is needed B. How much product is formed in a reaction.  The calculation of quantities in chemical reactions is called Stoichiometry  stoicheion "element“  metron "measure"
  • 4. LIKE A RECIPE  A balanced chemical equation provides the same kind of quantitative information that a recipe does.
  • 5. LET’S LOOK AT AN EVERYDAY EXAMPLE!  In a five day work week, tiny tike is scheduled to make 640 tricycles. How many wheels should be in the plant on Monday morning to make those tricycles?
  • 6. INTERPRETING CHEMICAL EQUATIONS  A balanced chemical equation can be interpreted in terms of different quantities, including numbers of  Representative Particles  Atoms  Molecules  Functional Units  Moles  Mass - Grams  Volume - Liters
  • 7. INTERPRETING CHEMICAL EQUATIONS This reaction requires the use of a catalyst, high pressure (100– 1,000 atmospheres), and elevated temperature (400–550 °C [750–1020 °F]).
  • 8. USES OF AMMONIA  The major use of ammonia is as a fertilizer  Explosives (e.g., Trinitrotoluene (TNT), nitroglycerin, and nitrocellulose)  Synthetic fibers, such as nylon and rayon  Dyeing and scouring of cotton, wool, and silk  A coolant in refrigeration and air-conditioning equipment  Minor uses is inclusion in certain household cleansing agents
  • 10. INTERPRETING (CONT.)  Always remember : Mass and atoms are always conserved in a chemical reaction.
  • 11. EXAMPLE OF INTERPRETING A CHEMICAL REACTION
  • 13. WRITING AND USING MOLE RATIOS  Mole Ratios are used to convert between:  moles of reactant and moles of product  moles of reactants  moles of products  A mole ratio is a conversion factor derived from the coefficients of a balanced chemical equation interpreted in terms of moles.
  • 16. PRACTICE ON YOUR OWN  Page 360 #11 11. This equation shows the formation of aluminum oxide, which is found on the surface of aluminum objects exposed to the air. 4Al(s) + 3O2(g)  2Al2O3(s) a. Write the six mole ratios that can be derived from this equation. b. How many moles of aluminum are needed to form 3.7 mol Al2O3?
  • 17. MASS TO MASS CALCULATIONS
  • 19. PRACTICE ON YOUR OWN  Page 361 # 13 13. Acetylene gas (C2H2) is produced by adding water to calcium carbide (CaC2). CaC2(s) + 2H2O(l)  C2H2(g) + Ca(OH)2(aq) How many grams of acetylene are produced by adding water to 5.00 g CaC2?
  • 20. PRACTICE ON YOUR OWN  Page 361 # 13 13. Acetylene gas (C2H2) is produced by adding water to calcium carbide (CaC2). CaC2(s) + 2H2O(l)  C2H2(g) + Ca(OH)2(aq) How many grams of acetylene are produced by adding water to 5.00 g CaC2?
  • 21. INTERPRETING CHEMICAL EQUATIONS  A balanced chemical equation can be interpreted in terms of different quantities, including numbers of  Moles  Mass - Grams  Representative Particles  Atoms  Molecules  Functional Units  Volume - Liters
  • 23. unit given unit requested OTHER STOICHIOMETRIC CALCULATIONS  In a typical stoichiometric problem,  given quantity is first converted to moles  mole ratio from the balanced equation is used to calculate the number of moles of the wanted substance  moles are converted to any other unit of measurement related to the unit mole, as the problem requires
  • 26. Analyze List the knowns and the unknown. Knowns • mass of water 29.2 g H2O • 2 mol H2O = 1 mol O2 (from balanced equation) • 1 mol H2O = 18.0 g H2O (molar mass) • 1 mol O2 = 6.02 x 1023 molecules O2 Unknown • molecules of oxygen = ? molecules O2 The following calculations need to be done: g H2O  mol H2O  mol O2  molecules O2 The appropriate mole ratio relating mol O2 to mol H2O from the balanced equation is 1 mole O2 /2 mol H2O.
  • 27. PRACTICE ON YOUR OWN  Page 364 # 15 15. How many molecules of oxygen are produced by the decomposition of 6.54 g of potassium chlorate (KClO3)? 2KClO3(s)  2KCl(s) + 3O2(g)
  • 28. HOMEWORK  Textbook page 364 - 366 ques. 16, 18, 20
  • 30.
  • 31. 12.3 LIMITING REAGENT AND PERCENT YIELD
  • 32. LIMITING REAGENT AND EXCESS REAGENT  Limiting Reagent is the reagent that determines the amount of product that can be formed by a reaction H2 + O2  H2O O2 – Red H2 - Blue
  • 33.  Excess Reagent- is the reagent not used up (what is left over in a chemical reaction) LIMITING REAGENT AND EXCESS REAGENT
  • 34. EXAMPLE CHEMICAL EQUATION FOR THE PREPARATION OF AMMONIA
  • 36. PRACTICE ON YOUR OWN  Page 370 # 25
  • 37. PERCENT YIELD  The percent yield is a measure of the efficiency of a reaction carried out in the laboratory.  Theoretical yield -maximum amount of product that could be formed from given amounts of reactants  Actual yield the amount of product that actually forms when the reaction is carried out in the laboratory
  • 40. PRACTICE ON YOUR OWN  Page 374-375 # 29 and 31