Question 5

Question 5 What’s the equation?

Question ,[object Object],[object Object],[object Object]

DO NOT MOVE ON UNTIL YOU HAVE ANSWERED THE QUESTION OR YOU NEED HELP!

Things You Should Know ,[object Object],[object Object],[object Object]

Finding “a” ,[object Object],[object Object],[object Object],[object Object],[object Object]

Finding “a” ,[object Object],So now we know that the common ratio is 2/3. Now we need to find the first term. * When dividing fractions, multiply the two by the reciprocal of the fraction in the denominator.

Finding “a” ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Finding “a” Divide each side by 8/27. Now we have the 1 st term. Now we can plug it in to the other equation and solve for the sum!

Finding “a” t 1 =1 r=2/3 * When dividing fractions, multiply the two by the reciprocal of the fraction in the denominator. Hooray! We found the sum of the sequence! We now also have the value of “a”. Now let’s go back to the question.

Putting in “a”. ,[object Object],[object Object],a=3 The 9 and 6 reduce. The 4 and 2 reduce. Now let’s rewrite the question.

Finding the Vertex ,[object Object],[object Object],[object Object],[object Object]

Finding the Vertex ,[object Object]

Finding the Vertex ,[object Object],*tan 2 α -1=sec 2 α therefore 1-tan 2 α =-sec 2 α (multiplied both sides by -1)

Finding the Vertex ,[object Object],*tan 2 α -1=sec 2 α therefore 1-tan 2 α =-sec 2 α (multiplied both sides by -1) *one of the cos α in the cos 2 α reduces with the cos α in the denominator.

Finding the Vertex ,[object Object],*tan 2 α -1=sec 2 α therefore 1-tan 2 α =-sec 2 α (multiplied both sides by -1) *one of the cos α in the cos 2 α reduces with the cos α in the denominator. So the x coordinate of the vertex is 0.

Finding the Distance ,[object Object],[object Object],[object Object]

Finding the Distance ,[object Object],[object Object],[object Object],[object Object]

Finding the Distance ,[object Object],[object Object],[object Object],[object Object],[object Object],Let’s look again at the unit circle.

Finding the Distance ,[object Object],[object Object],[object Object],[object Object],[object Object],Let’s look again at the unit circle. Go 2 π radians around the circle again. Now we are looking for the cosine value or the x coordinate. In this case, it’s 1.

Finding the Distance ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Cool! Now we know how far the vertex is from the focus point. Now let’s look at the question again.

Finding the Equation ,[object Object],[object Object],[object Object]

Finding the Equation ,[object Object],[object Object],[object Object],[object Object]

Finding the Equation ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Finding the Equation ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Hooray! Mary found the equation! Does she have the courage to go back now?

Click on the “xD” just above this presentation to move on to the season finale!

Question 5

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Question 5