Right Triangle
Trigonometry
Digital Lesson
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 2
The six trigonometric functions of a right triangle, with an acute
angle , are defined by ratios of two sides of the triangle.
The sides of the right triangle are:
 the side opposite the acute angle ,
 the side adjacent to the acute angle ,
 and the hypotenuse of the right triangle.
The trigonometric functions are
sine, cosine, tangent, cotangent, secant, and cosecant.
opp
adj
hyp
θ
sin  = cos  = tan  =
csc  = sec  = cot  =
opp
hyp
adj
hyp
hyp
adj
adj
opp
opp
adj
hyp
opp
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 3
Calculate the trigonometric functions for  .
The six trig ratios are
4
3
5

sin  =
5
4
tan  =
3
4
sec  =
3
5
cos  =
5
3
cot  =
4
3
csc  =
4
5
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Geometry of the 45-45-90 triangle
Consider an isosceles right triangle with two sides of
length 1.
1
1
45
45
2
2
1
1 2
2


The Pythagorean Theorem implies that the hypotenuse
is of length .
2
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Calculate the trigonometric functions for a 45 angle.
2
1
1
45
csc 45 = = =
1
2 2
opp
hyp
sec 45 = = =
1
2 2
adj
hyp
cos 45 = = =
2
2
2
1
hyp
adj
sin 45 = = =
2
2
2
1
hyp
opp
cot 45 = = = 1
opp
adj
1
1
tan 45 = = = 1
adj
opp
1
1
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60○ 60○
Consider an equilateral triangle with
each side of length 2.
The perpendicular bisector
of the base bisects the
opposite angle.
The three sides are equal, so the
angles are equal; each is 60.
Geometry of the 30-60-90 triangle
2 2
2
1 1
30○ 30○
3
Use the Pythagorean Theorem to
find the length of the altitude, .
3
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Calculate the trigonometric functions for a 30 angle.
1
2
30
3
csc 30 = = = 2
1
2
opp
hyp
sec 30 = = =
3
2
3
3
2
adj
hyp
cos 30 = =
2
3
hyp
adj
tan 30 = = =
3
1
3
3
adj
opp
cot 30 = = =
1
3 3
opp
adj
sin 30 = =
2
1
hyp
opp
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Calculate the trigonometric functions for a 60 angle.
1
2
60○
3
csc 60 = = =
3
2
3
3
2
opp
hyp
sec 60 = = = 2
1
2
adj
hyp
cos 60 = =
2
1
hyp
adj
tan 60 = = =
1
3
3
adj
opp
cot 60 = = =
3
1
3
3
opp
adj
sin 60 = =
2
3
hyp
opp
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Trigonometric Identities are trigonometric
equations that hold for all values of the variables.
Example: sin  = cos(90 ), for 0 <  < 90
Note that  and 90  are complementary
angles.
Side a is opposite θ and also
adjacent to 90○– θ .
a
hyp
b
θ
90○– θ
sin  = and cos (90 ) = .
So, sin  = cos (90 ).
b
a
b
a
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Fundamental Trigonometric Identities for 0 <  < 90.
Cofunction Identities
sin  = cos(90  ) cos  = sin(90  )
tan  = cot(90  ) cot  = tan(90  )
sec  = csc(90  ) csc  = sec(90  )
Reciprocal Identities
sin  = 1/csc  cos  = 1/sec  tan  = 1/cot 
cot  = 1/tan  sec  = 1/cos  csc  = 1/sin 
Quotient Identities
tan  = sin  /cos  cot  = cos  /sin 
Pythagorean Identities
sin2  + cos2  = 1 tan2  + 1 = sec2  cot2  + 1 = csc2 
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 11
Example:
Given sin  = 0.25, find cos , tan , and sec .
cos  = = 0.9682
tan  = = 0.258
sec  = = 1.033
1
9682
.
0
9682
.
0
25
.
0
0.9682
1
Use the Pythagorean Theorem to solve for
the third side.
0.9682
Draw a right triangle with acute angle , hypotenuse of length
one, and opposite side of length 0.25.
θ
1
0.25
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Example: Given sec  = 4, find the values of the
other five trigonometric functions of  .
Use the Pythagorean Theorem to solve
for the third side of the triangle.
tan  = = cot  =
1
15
15
1
15
sin  = csc  = =
4
15
15
4

sin
1
cos  = sec  = = 4
4
1

cos
1
15
θ
4
1
Draw a right triangle with an angle  such
that 4 = sec  = = .
adj
hyp
1
4
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 13
Example:
Given sin  = 0.25, find cos , tan , and sec .
cos  = = 0.9682
tan  = = 0.258
sec  = = 1.033
1
9682
.
0
9682
.
0
25
.
0
0.9682
1
Use the Pythagorean Theorem to solve for
the third side.
0.9682
Draw a right triangle with acute angle , hypotenuse of length
one, and opposite side of length 0.25.
θ
1
0.25

right_triangle_trig.ppt

  • 1.
  • 2.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 2 The six trigonometric functions of a right triangle, with an acute angle , are defined by ratios of two sides of the triangle. The sides of the right triangle are:  the side opposite the acute angle ,  the side adjacent to the acute angle ,  and the hypotenuse of the right triangle. The trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant. opp adj hyp θ sin  = cos  = tan  = csc  = sec  = cot  = opp hyp adj hyp hyp adj adj opp opp adj hyp opp
  • 3.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 3 Calculate the trigonometric functions for  . The six trig ratios are 4 3 5  sin  = 5 4 tan  = 3 4 sec  = 3 5 cos  = 5 3 cot  = 4 3 csc  = 4 5
  • 4.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 4 Geometry of the 45-45-90 triangle Consider an isosceles right triangle with two sides of length 1. 1 1 45 45 2 2 1 1 2 2   The Pythagorean Theorem implies that the hypotenuse is of length . 2
  • 5.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 5 Calculate the trigonometric functions for a 45 angle. 2 1 1 45 csc 45 = = = 1 2 2 opp hyp sec 45 = = = 1 2 2 adj hyp cos 45 = = = 2 2 2 1 hyp adj sin 45 = = = 2 2 2 1 hyp opp cot 45 = = = 1 opp adj 1 1 tan 45 = = = 1 adj opp 1 1
  • 6.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 6 60○ 60○ Consider an equilateral triangle with each side of length 2. The perpendicular bisector of the base bisects the opposite angle. The three sides are equal, so the angles are equal; each is 60. Geometry of the 30-60-90 triangle 2 2 2 1 1 30○ 30○ 3 Use the Pythagorean Theorem to find the length of the altitude, . 3
  • 7.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 7 Calculate the trigonometric functions for a 30 angle. 1 2 30 3 csc 30 = = = 2 1 2 opp hyp sec 30 = = = 3 2 3 3 2 adj hyp cos 30 = = 2 3 hyp adj tan 30 = = = 3 1 3 3 adj opp cot 30 = = = 1 3 3 opp adj sin 30 = = 2 1 hyp opp
  • 8.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 8 Calculate the trigonometric functions for a 60 angle. 1 2 60○ 3 csc 60 = = = 3 2 3 3 2 opp hyp sec 60 = = = 2 1 2 adj hyp cos 60 = = 2 1 hyp adj tan 60 = = = 1 3 3 adj opp cot 60 = = = 3 1 3 3 opp adj sin 60 = = 2 3 hyp opp
  • 9.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 9 Trigonometric Identities are trigonometric equations that hold for all values of the variables. Example: sin  = cos(90 ), for 0 <  < 90 Note that  and 90  are complementary angles. Side a is opposite θ and also adjacent to 90○– θ . a hyp b θ 90○– θ sin  = and cos (90 ) = . So, sin  = cos (90 ). b a b a
  • 10.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 10 Fundamental Trigonometric Identities for 0 <  < 90. Cofunction Identities sin  = cos(90  ) cos  = sin(90  ) tan  = cot(90  ) cot  = tan(90  ) sec  = csc(90  ) csc  = sec(90  ) Reciprocal Identities sin  = 1/csc  cos  = 1/sec  tan  = 1/cot  cot  = 1/tan  sec  = 1/cos  csc  = 1/sin  Quotient Identities tan  = sin  /cos  cot  = cos  /sin  Pythagorean Identities sin2  + cos2  = 1 tan2  + 1 = sec2  cot2  + 1 = csc2 
  • 11.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 11 Example: Given sin  = 0.25, find cos , tan , and sec . cos  = = 0.9682 tan  = = 0.258 sec  = = 1.033 1 9682 . 0 9682 . 0 25 . 0 0.9682 1 Use the Pythagorean Theorem to solve for the third side. 0.9682 Draw a right triangle with acute angle , hypotenuse of length one, and opposite side of length 0.25. θ 1 0.25
  • 12.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 12 Example: Given sec  = 4, find the values of the other five trigonometric functions of  . Use the Pythagorean Theorem to solve for the third side of the triangle. tan  = = cot  = 1 15 15 1 15 sin  = csc  = = 4 15 15 4  sin 1 cos  = sec  = = 4 4 1  cos 1 15 θ 4 1 Draw a right triangle with an angle  such that 4 = sec  = = . adj hyp 1 4
  • 13.
    Copyright © byHoughton Mifflin Company, Inc. All rights reserved. 13 Example: Given sin  = 0.25, find cos , tan , and sec . cos  = = 0.9682 tan  = = 0.258 sec  = = 1.033 1 9682 . 0 9682 . 0 25 . 0 0.9682 1 Use the Pythagorean Theorem to solve for the third side. 0.9682 Draw a right triangle with acute angle , hypotenuse of length one, and opposite side of length 0.25. θ 1 0.25