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2
Solutions
Henry’s Law
Let’s start the
session….
Mole fraction
● Ratio of number of moles of one component to the total number of
moles of all the components (solvent and solute) present in the
solution. It is denoted by the letter x followed by the subscript
representing the component.
Solutions Lecture- 2
Mole fraction
● Ratio of number of moles of one component to the total number of
moles of all the components (solvent and solute) present in the
solution. It is denoted by the letter x followed by the subscript
representing the component.
Solutions Lecture- 2
Mole fraction
Mole fraction of A, (xA)=
Mole fraction of B, (xB)=
nA / nA + nB
nB / nA + nB
Now , the sum of the mole fractions of solute and
solvent in binary solution is unity
xA + xB = nA / nA + nB nb/ nA + nB = 1
Molality (m)
The molality of a solution is defined as the number of moles of solute dissolved
per 1000 g or 1kg of the solvent. It is represented by ‘m’
Solutions Lecture- 2
Molality (m)
The molality of a solution is defined as the number of moles of solute dissolved
per 1000 g or 1kg of the solvent. It is represented by ‘m’
Solutions Lecture- 2
Solutions Lecture- 2
Solutions Lecture- 2
Parts per million (ppm)
It is the number of parts of the component present per million parts of the
solution.
Solutions Lecture- 2
Parts per million (ppm)
It is the number of parts of the component present per million parts of the
solution.
Solutions Lecture- 2
Solutions Lecture- 2
Ǫ. 1
A sample of drinking water was found to be severely contaminated with
chloroform, CHCl3, supposed to be carcinogen. The level of contamination
was 15 ppm (by mass)
(i) Express this in percent by mass.
(ii)_ Determine the molality of chloroform in the water sample.
Solutions Lecture- 2
Ǫ. 1
A sample of drinking water was found to be severely contaminated with
chloroform, CHCl3, supposed to be carcinogen. The level of contamination
was 15 ppm (by mass)
(i) Express this in percent by mass.
(ii)_ Determine the molality of chloroform in the water sample.
Solutions Lecture- 2
Ǫ. 1
A sample of drinking water was found to be severely contaminated with
chloroform, CHCl3, supposed to be carcinogen. The level of contamination
was 15 ppm (by mass)
(i) Express this in percent by mass.
(ii)_ Determine the molality of chloroform in the water sample.
Solutions Lecture- 2
Ǫ. 2
Concentrated nitric acid used in the laboratory work in 68% nitric acid by
mass in aqueous solution. What should be the molarity of such a sample
of the acid if the density of solution is 1.5 g mL–1 ?
Solutions Lecture- 2
Calculate the molarity of a solution containing 40 g of NaOH dissolved in two litre of the
solution.
Ǫ. 3
Solutions Lecture- 2
The mole fraction of the solute in one molal aqueous solution is
(a) 0.027
(c) 0.018
(b) 0.036
(d) 0.009
Ǫ. 4
Solutions Lecture- 2
The mole fraction of the solute in one molal aqueous solution is
(a) 0.027
(c) 0.018
(b) 0.036
(d) 0.009
Ǫ. 4
Solutions Lecture- 2
Solubility
● Solubility of a substance is its maximum amount that can dissolve
in specific amount of solvent under given set of conditions.
Solutions Lecture- 2
Solubility
● Solubility of a substance is its maximum amount that can dissolve
in specific amount of solvent under given set of conditions.
Solutions Lecture- 2
Effect of temperature
 For endothermic dissolution process, solubility increase with increase in
temperature.
 For exothermic dissolution process, solubility decrease with increase in
temperatre
Effect of Pressure
No significant effect since solids and liquids are highly incompressible and
practically remain unaffected by change in pressure.
Solubility of gases in liquids
Effect of pressure- Henry’s Law - on solubility of gases in liquids
⇒the solubility of a gas at a given temperature is directly proportional
to the pressure at which it is dissolved.
Solutions Lecture- 2
Solubility of gases in liquids
Effect of pressure- Henry’s Law - on solubility of gases in liquids
⇒the solubility of a gas at a given temperature is directly proportional
to the pressure at which it is dissolved.
Solutions Lecture- 2
Solutions Lecture- 2
Solubility of gases in liquids
Effect of pressure- Henry’s Law - on solubility of gases in liquids
Solutions Lecture- 2
I. Soft drinks, soda water and other carbonated beverages contains
dissolved carbon dioxide.
APPLICATIONS OF HENRY'S LAW
I. Anoxia - the low content of blood oxygen causes climbers to
become weak and reduces their thinking ability which are
symptoms of anoxia.
APPLICATIONS OF HENRY'S LAW
I. Bends - scuba divers suffer from the painful effects when they
come towards the surface
APPLICATIONS OF HENRY'S LAW
Solutions Lecture- 2
Solutions Lecture- 2
Solutions Lecture- 2
Solutions Lecture -2 28 April (1).pptx

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Solutions Lecture -2 28 April (1).pptx

  • 3. Mole fraction ● Ratio of number of moles of one component to the total number of moles of all the components (solvent and solute) present in the solution. It is denoted by the letter x followed by the subscript representing the component. Solutions Lecture- 2
  • 4. Mole fraction ● Ratio of number of moles of one component to the total number of moles of all the components (solvent and solute) present in the solution. It is denoted by the letter x followed by the subscript representing the component. Solutions Lecture- 2
  • 5. Mole fraction Mole fraction of A, (xA)= Mole fraction of B, (xB)= nA / nA + nB nB / nA + nB Now , the sum of the mole fractions of solute and solvent in binary solution is unity xA + xB = nA / nA + nB nb/ nA + nB = 1
  • 6. Molality (m) The molality of a solution is defined as the number of moles of solute dissolved per 1000 g or 1kg of the solvent. It is represented by ‘m’ Solutions Lecture- 2
  • 7. Molality (m) The molality of a solution is defined as the number of moles of solute dissolved per 1000 g or 1kg of the solvent. It is represented by ‘m’ Solutions Lecture- 2
  • 10. Parts per million (ppm) It is the number of parts of the component present per million parts of the solution. Solutions Lecture- 2
  • 11. Parts per million (ppm) It is the number of parts of the component present per million parts of the solution. Solutions Lecture- 2
  • 13. Ǫ. 1 A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogen. The level of contamination was 15 ppm (by mass) (i) Express this in percent by mass. (ii)_ Determine the molality of chloroform in the water sample. Solutions Lecture- 2
  • 14. Ǫ. 1 A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogen. The level of contamination was 15 ppm (by mass) (i) Express this in percent by mass. (ii)_ Determine the molality of chloroform in the water sample. Solutions Lecture- 2
  • 15. Ǫ. 1 A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogen. The level of contamination was 15 ppm (by mass) (i) Express this in percent by mass. (ii)_ Determine the molality of chloroform in the water sample. Solutions Lecture- 2
  • 16. Ǫ. 2 Concentrated nitric acid used in the laboratory work in 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of the acid if the density of solution is 1.5 g mL–1 ? Solutions Lecture- 2
  • 17. Calculate the molarity of a solution containing 40 g of NaOH dissolved in two litre of the solution. Ǫ. 3 Solutions Lecture- 2
  • 18. The mole fraction of the solute in one molal aqueous solution is (a) 0.027 (c) 0.018 (b) 0.036 (d) 0.009 Ǫ. 4 Solutions Lecture- 2
  • 19. The mole fraction of the solute in one molal aqueous solution is (a) 0.027 (c) 0.018 (b) 0.036 (d) 0.009 Ǫ. 4 Solutions Lecture- 2
  • 20. Solubility ● Solubility of a substance is its maximum amount that can dissolve in specific amount of solvent under given set of conditions. Solutions Lecture- 2
  • 21. Solubility ● Solubility of a substance is its maximum amount that can dissolve in specific amount of solvent under given set of conditions. Solutions Lecture- 2
  • 22. Effect of temperature  For endothermic dissolution process, solubility increase with increase in temperature.  For exothermic dissolution process, solubility decrease with increase in temperatre Effect of Pressure No significant effect since solids and liquids are highly incompressible and practically remain unaffected by change in pressure.
  • 23. Solubility of gases in liquids Effect of pressure- Henry’s Law - on solubility of gases in liquids ⇒the solubility of a gas at a given temperature is directly proportional to the pressure at which it is dissolved. Solutions Lecture- 2
  • 24. Solubility of gases in liquids Effect of pressure- Henry’s Law - on solubility of gases in liquids ⇒the solubility of a gas at a given temperature is directly proportional to the pressure at which it is dissolved. Solutions Lecture- 2
  • 26. Solubility of gases in liquids Effect of pressure- Henry’s Law - on solubility of gases in liquids Solutions Lecture- 2
  • 27. I. Soft drinks, soda water and other carbonated beverages contains dissolved carbon dioxide. APPLICATIONS OF HENRY'S LAW
  • 28. I. Anoxia - the low content of blood oxygen causes climbers to become weak and reduces their thinking ability which are symptoms of anoxia. APPLICATIONS OF HENRY'S LAW
  • 29. I. Bends - scuba divers suffer from the painful effects when they come towards the surface APPLICATIONS OF HENRY'S LAW
  • 30.