This document discusses simple machines and their mechanical advantages. It describes six simple machines: lever, wheel and axle, pulley, inclined plane, wedge, and screw. It defines mechanical advantage as the ratio of resistance and effort forces or the ratio of distances traveled. Ideal mechanical advantage ignores friction while actual mechanical advantage accounts for it. Mechanical advantage can be greater than, less than, or equal to one depending on the machine. The document provides examples of calculating mechanical advantage for levers, wheels and axles, and pulley systems. It notes that efficiency is the ratio of actual to ideal mechanical advantage.
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4. Mechanical Advantage
Ratio of the magnitude of the
resistance and effort forces
Ratio of distance traveled by the effort
and the resistance force
Calculated ratios allow designers to
manipulate speed, distance, force, and
function
5. Mechanical Advantage Example
A mechanical advantage of 4:1 tells us
what about a mechanism?
Magnitude of Force:
Effort force magnitude is 4 times less than the magnitude
of the resistance force.
Distance Traveled by Forces:
Effort force travels 4 times greater distance than
the resistance force.
6. Work
The force applied on an object times the
distance traveled by the object parallel
to the force
Initial position Final position
Force (F)
Parallel Distance (d║)
Work = Force · Distance = F · d║
7. Work
The product of the effort times the distance
traveled will be the same regardless of the
system mechanical advantage
8. Mechanical Advantage Ratios
One is the magic number
If MA is greater than 1:
Proportionally less effort force is required to
overcome the resistance force
Proportionally greater effort distance is
required to overcome the resistance force
If MA is less than 1:
Proportionally greater effort force is required
to overcome the resistance force
Proportionally less effort distance is
required to overcome the resistance force
MA can never be less than or equal to zero.
9. Ideal Mechanical Advantage (IMA)
Theory-based calculation
Friction loss is not taken into consideration
Ratio of distance traveled by effort and
resistance force
Used in efficiency and safety factor design
calculations
DE
IMA =
DR
DE = Distance traveled by effort force
DR = Distance traveled by resistance force
10. Actual Mechanical Advantage (AMA)
Inquiry-based calculation
Frictional losses are taken into consideration
Used in efficiency calculations
FR
Ratio of force magnitudes
AMA =
FE
FR = Magnitude of resistance force
FE = Magnitude of effort force
11. Real World Mechanical Advantage
Can you think of a
machine that has a
mechanical advantage
greater than 1?
12. Real World Mechanical Advantage
Can you think of
a machine that
has a mechanical
advantage less
than 1?
13. Lever
A rigid bar used to exert a pressure or
sustain a weight at one point of its length
by the application of a force at a second
and turning at a third on a fulcrum.
14. 1st Class Lever
Fulcrum is located between the effort and
the resistance force
Effort and resistance forces are applied to
the lever arm in the same direction
Only class of lever that can have a MA
greater than or less than 1
Effort Resistance
MA =1
Effort Resistance
Resistance Effort
MA <1 MA >1
15. 2nd Class Lever
Fulcrum is located at one end of the lever
Resistance force is located between the fulcrum
and the effort force
Resistance force and effort force are in opposing
directions
Always has a mechanical advantage >1
Resistance
Effort
16. 3rd Class Lever
Fulcrum is located at one end of the lever
Effort force is located between the fulcrum and
the resistance
Resistance force and effort force are in
opposing directions
Always has a mechanical advantage < 1
Resistance
Effort
17. Moment
The turning effect of a force about a point equal to
the magnitude of the force times the
perpendicular distance from the point to the line
of action from the force.
M = dxF
Torque: A force that produces or tends to
produce rotation or torsion.
18. Lever Moment Calculation
5.5 in. Resistance
15 lb
15 lbs
Effort
Calculate the effort moment acting on the lever above.
M= dxF
Effort Moment = 5.5 in. x 15 lb
Effort Moment = 82.5 in. lb
19. Lever Moment Calculation
When the effort and resistance moments
are equal, the lever is in static equilibrium.
Static equilibrium:
A condition where there are no net external
forces acting upon a particle or rigid body
and the body remains at rest or continues
at a constant velocity.
20. Lever Moment Calculation
Effort Resistance
5.5 in. ?
36 2/3 lb
15 15 lbs
lb
Using what you know regarding static equilibrium, calculate the
unknown distance from the fulcrum to the resistance force.
Static equilibrium:
Effort Moment = Resistance Moment
82.5 in.-lb = 36 2/3 lb x DR
82.5 in.-lb /36.66 lb = DR
DR = 2.25 in.
21. Lever IMA
DE Resistance
IMA = Effort
DR
Both effort and resistance
forces will travel in a circle if
unopposed.
Circumference is the distance around the perimeter of a circle.
Circumference = 2 p r
DE = 2 π (effort arm length)
DR = 2 π (resistance arm length)
2 π (effort arm length)
______________________
IMA =
2 π (resistance arm length)
22. Lever AMA
The ratio of applied resistance force to
applied effort force
2.25
FR 5.5 in. in.
AMA = 32 lb
FE 16 lb
Effort Resistance
What is the AMA of the lever above? AMA = 2:1
32lb
AMA = Why is the IMA larger than the AMA?
16lb
What is the IMA of the lever above? IMA = 2.44:1
IMA=
DE 5.5in.
IMA =
DR 2.25in.
23. Efficiency
In a machine, the ratio of useful energy output to
the total energy input, or the percentage of the
work input that is converted to work output
The ratio of AMA to IMA
AMA
% Efficiency = 100
IMA
What is the efficiency of the lever on the previous
slide? Click to return to previous slide
2.00
100 = 82.0%
AMA = 2:1
% Efficiency =
IMA = 2.44:1 2.44
No machine is 100% efficient.
24. Wheel & Axle
A wheel is a lever arm that is fixed to a shaft, which is
called an axle.
The wheel and axle move together as a simple lever to lift
or to move an item by rolling.
It is important to know within the wheel and axle system
which is applying the effort and resistance force – the
wheel or the axle.
Can you think of an example
of a wheel driving an axle?
25. Wheel & Axle IMA Ǿ6 in. Ǿ20 in.
DE
IMA =
DR
Both effort and resistance
forces will travel in a circle if
unopposed.
Circumference = 2pr or πd
DE = π [Diameter of effort (wheel or axle)]
DR = π [Diameter resistance (wheel or axle)]
π (effort diameter)
______________________
IMA =
π (resistance diameter)
What is the IMA of the wheel above if the axle is driving the wheel?
6 in. / 20 in. = .3 = .3:1 = 3:10
What is the IMA of the wheel above if the wheel is driving the axle?
20 in. / 6 in. = 3.33 = 3.33:1
26. Ǿ6 in.
Wheel & Axle AMA Ǿ20 in.
FR 200lb
AMA =
FE
Use the wheel and axle assembly 70lb
illustration to the right to solve the
following.
What is the AMA if the wheel is driving the axle?
200lb/70lb = 2.86 = 2.86:1
What is the efficiency of the wheel and axle assembly?
AMA 2.86
% Efficiency = 100 = 100 = 85.9%
IMA 3.33
27. Pulley
A pulley is a lever consisting of a wheel with a
groove in its rim which is used to change the
direction and magnitude of a force exerted by a
rope or cable.
28. Pulley IMA
Fixed Pulley
- 1st class lever with an IMA of 1
- Changes the direction of force
10 lb
5 lb 5 lb
Movable Pulley
- 2nd class lever with an IMA of 2
- Force directions stay constant
10 lb
10 lb
29. Pulleys In Combination
Fixed and movable pulleys in combination
(called a block and tackle) provide
mechanical advantage and a change of
direction for effort force.
If a single rope or cable is threaded
multiple times through a system of pulleys,
Pulley IMA = # strands opposing the
force of the load and
movable pulleys
What is the IMA of the pulley
system on the right? 4
30. Compound Machines
If one simple machine is used after another, the
mechanical advantages multiply.
31. Pulleys In Combination
With separate ropes or cables, the output of one
pulley system can become the input of another
pulley system. This is a compound machine.
10 lbf 10 lbf
What is the IMA of the
pulley system on the left?
20 lbf 20 lbf
40 lbf 40 lbf
80 lbf
32. Pulley AMA
FR
AMA =
FE
What is the AMA of the pulley system
on the right?
800lb
AMA = AMA = 3.48 = 3.48:1
230lb
What is the efficiency of the pulley
system on the right? 230 lb
AMA 3.48
% Efficiency = 100 100
IMA 4 800 lb
= 87%
33. Common misconception: Angles don’t matter
Pulley IMA = # strands opposing load only if
strands are opposite/parallel to the resistance
force.
Calculating IMA
IMA=2
requires trigonometry
34. Common misconception:
“Count the effort strand if it pulls up”
sometimes
Pulley IMA = # strands opposing the
load. 80 lbf
Count a strand if it IMA=2
opposes the load or the
load’s movable pulley.
40 lbf 40 lbf
It might pull up or
down.
35. Image Resources
Microsoft, Inc. (2008). Clip art. Retrieved January 10, 2008, from
http://office.microsoft.com/en-us/clipart/default.aspx
Editor's Notes
The terms moment and torque are synonymous.
Note: The IMA of this system is only about 3.9 because the shortest segment of the rope, tied to the fixed pulley, is not vertical. Since the load is downward, only the upward component of that strand’s force will count, and at the angle shown, the vertical component is about 0.9 times the angled force in that strand. Because resolving a vector into components is not covered until unit 2, this fine point is glossed over at this time. Could you lift this motorcycle? Ideally, it will take 150 lb of force. A student weighing less than 150 lb could hang on the rope without lifting the motorcycle. This demonstrates an advantage of having the free end pointing upward; then a person can pull with a force greater than their own weight.
In the pulley on the right, the IMA is not 2. Although the vertical forces from the two strands still are each half the resistance force, the tension in the string depends on the angle. We will not be addressing these types of problems, though you will learn how to do so in unit 2 when you deal with trusses.In your measurements, keep the strands in the opposite direction from the resistance force to avoid this complication.
In the movable pulley here, the effort force is used to pull the movable pulley down along with the load. This is used, for example, in pulling the foot of a sail downward after it has been hoisted. The resistance will only be forced downward 1 ft for every 2 ft of rope pulled out of the system.