PSLE Mathematics
           Yeap Ban Har
    Marshall Cavendish Institute


      yeapbanhar@gmail.com
www.moe.edu.sg/education/syllabuses
3 Things About
Problem Solving
in PSLE



2 Sections in
PSLE with
Challenging
Problems
These tend to be the places where
  the challenging problem solving
                    are assessed.
5 Steps to help
Your Child with
Challenging
Problems
2 Examples to
Show the Five
Steps
The speaker is demonstrating what an adult helping
       children does. What does an adult do to help
   children   manage their reading?
Solution:

2 fifths of 20-cent coins + 3 sevenths of 50-cent coins  39 coins

4 fifths of 20-cent coins + 6 sevenths of 50-cent coins  2 x 39 coins = 78 coins

1 fifth of 20-cent coins + 1 sevenths of 50-cent coins  94 – 78 = 16

5 fifths of 20-cent coins + 5 sevenths of 50-cent coins  5 x 16 = 80

2 sevenths of 50-cent coins  94 – 80 = 14

                                         There are 14   2 x 7 = 49 fifty-cent coins.

                                        There are 94 – 49 = 45 twenty-cent coins.

                                Sally had 49 x 50 cents + 45 x 20 cents or $33.50.




                                                                     Answer:$33.50
94 – 2 x 39 = 94 – 78 = 14 + 2 = 16
94 – 2 x 39 = 94 – 78 = 14 + 2 = 16
94 – 2 x 39 = 94 – 78 = 14 + 2 = 16
?



94 – 2 x 39 = 94 – 78 = 14 + 2 = 16
?



94 – 2 x 39 = 94 – 78 = 14 + 2 = 16

39 – 2 x 16 = 39 – 32 = 7

How many 50-cent coins?
How many 20-cent coins?
Solution:

(a) (3m + 6) cm

(b) length = 3 x 4 cm + 6 cm = 18 cm and width = 3 cm

        area = 18 cm x 3 cm = 54 cm2
2 Common and
1 Unusual
Challenging
Problems
9 parts   6 parts   5 parts   $120  16 parts

                               $30  4 parts

                              $150  20 parts

                              He had $150 at first.
compare
men




women


             837 – 648 = 837 – 637 – 11 = 200 – 11 = 189
        1 third of the men + 1 third of the children  189

             men + children  189 x 3 = 570 – 3 = 567

             women  837 – 567 = 837 – 537 – 30 = 270

             men  270     3 x 4 = 90 x 4 = 360
             children  837 – 360 – 270 = 837 – 630 = 207


             There were 207 children at first.
men




women




children


837 – 648 = 189

837 – 3 x 189 = 270

…..
8   13
2      3   4        5           6



13 x ?   13 x 21          What is the
                       dimensions of the
21 x ?   21 x 34       rectangle with the
                        least number of
                       squares being 10?
See
patterns, trends
MARSHALL CAVENDISH INSTITUTE’S
                WORKSHOP FOR PARENTS:
      COACHING CHILDREN IN PRIMARY
        MATHEMATICS PROGRAMME
                        (BATCH 2)
                (END OF JUNE – SEPT 2012)


         4-Session Programme for Parents / Tutors
   Understand the Mathematics curriculum for different
                      primary levels
 Topics like Fractions, Geometry, Word Problem Solving and
                     Algebra will be covered
  Please contact geraldynsng@sg.marshallcavendish.com
                  Class size of about 30.

Seminar for Parents on PSLE Mathematics

  • 1.
    PSLE Mathematics Yeap Ban Har Marshall Cavendish Institute yeapbanhar@gmail.com
  • 2.
  • 3.
    3 Things About ProblemSolving in PSLE
  • 4.
  • 5.
  • 6.
  • 7.
    2 Sections in PSLEwith Challenging Problems
  • 8.
    These tend tobe the places where the challenging problem solving are assessed.
  • 9.
    5 Steps tohelp Your Child with Challenging Problems
  • 11.
    2 Examples to Showthe Five Steps
  • 12.
    The speaker isdemonstrating what an adult helping children does. What does an adult do to help children manage their reading?
  • 13.
    Solution: 2 fifths of20-cent coins + 3 sevenths of 50-cent coins  39 coins 4 fifths of 20-cent coins + 6 sevenths of 50-cent coins  2 x 39 coins = 78 coins 1 fifth of 20-cent coins + 1 sevenths of 50-cent coins  94 – 78 = 16 5 fifths of 20-cent coins + 5 sevenths of 50-cent coins  5 x 16 = 80 2 sevenths of 50-cent coins  94 – 80 = 14 There are 14 2 x 7 = 49 fifty-cent coins. There are 94 – 49 = 45 twenty-cent coins. Sally had 49 x 50 cents + 45 x 20 cents or $33.50. Answer:$33.50
  • 17.
    94 – 2x 39 = 94 – 78 = 14 + 2 = 16
  • 18.
    94 – 2x 39 = 94 – 78 = 14 + 2 = 16
  • 19.
    94 – 2x 39 = 94 – 78 = 14 + 2 = 16
  • 20.
    ? 94 – 2x 39 = 94 – 78 = 14 + 2 = 16
  • 21.
    ? 94 – 2x 39 = 94 – 78 = 14 + 2 = 16 39 – 2 x 16 = 39 – 32 = 7 How many 50-cent coins? How many 20-cent coins?
  • 29.
    Solution: (a) (3m +6) cm (b) length = 3 x 4 cm + 6 cm = 18 cm and width = 3 cm area = 18 cm x 3 cm = 54 cm2
  • 30.
    2 Common and 1Unusual Challenging Problems
  • 32.
    9 parts 6 parts 5 parts $120  16 parts $30  4 parts $150  20 parts He had $150 at first.
  • 33.
  • 34.
    men women 837 – 648 = 837 – 637 – 11 = 200 – 11 = 189 1 third of the men + 1 third of the children  189 men + children  189 x 3 = 570 – 3 = 567 women  837 – 567 = 837 – 537 – 30 = 270 men  270 3 x 4 = 90 x 4 = 360 children  837 – 360 – 270 = 837 – 630 = 207 There were 207 children at first.
  • 35.
    men women children 837 – 648= 189 837 – 3 x 189 = 270 …..
  • 39.
    8 13
  • 40.
    2 3 4 5 6 13 x ? 13 x 21 What is the dimensions of the 21 x ? 21 x 34 rectangle with the least number of squares being 10?
  • 41.
  • 42.
    MARSHALL CAVENDISH INSTITUTE’S WORKSHOP FOR PARENTS: COACHING CHILDREN IN PRIMARY MATHEMATICS PROGRAMME (BATCH 2) (END OF JUNE – SEPT 2012)  4-Session Programme for Parents / Tutors  Understand the Mathematics curriculum for different primary levels  Topics like Fractions, Geometry, Word Problem Solving and Algebra will be covered  Please contact geraldynsng@sg.marshallcavendish.com  Class size of about 30.