MATH321
APPLIED DIFFERENTIAL
EQUATIONS
RLC Circuits and Differential
Equations
Designed and built RLC circuit to test response
time of current
Derive the constant coefficient differential
equation
 Resistance (R) = 643.108 Ω
 Inductor (L) = 9.74 × 10^-3 H
 Capacitor (C) = 9.42 × 10^-8 F
Kirchhoff’s Voltage Law (KVL)
The sum of voltage
drops across the
elements of a
series circuit is
equal to applied
voltage.
Voltage Drop per Circuit Elements
Inductor Resistor Capacitor
Substitute and Differentiation
Differentiate both sides for equation for
current
Substitute dQ/dt for I in original equation and
arrive at second order differential equation
Current is the rate of change of charge (in
Coulombs) with respect to time
Substitute voltage drops into equation
KVL )(tVVVV CLR
)(
1
tVQ
C
RI
dt
dI
L
)(tI
dt
dQ
)(
1
'" tVQ
C
RQLQ
)('
1
'" tVI
C
RILI
General forms of equation
Which is the same as:
Divide by L:
0)(
1)()(
2
2
ti
LCdt
tdi
L
R
dt
tid
0)(
)(
2
)( 2
02
2
ti
dt
tdi
dt
tid
Calculate Parameters for Substitution
0
1
''' I
LC
I
L
R
I
5.660272
L
R
92
0 100899.1
1
LC
0100899.1'5.66027'' 9
III
0100899.15.66027 92
RR
0)(
1)()(
2
2
ti
LCdt
tdi
L
R
dt
tid
Solve Characteristic Equation for R
62.32
76.33013
62.3276.33013
)1(2
)100899.1)(1(45.66027
5.66027
2
4
0)100899.1(5.66027
92
2
92
iR
iR
R
a
acb
bR
RR
Select Natural Response of Circuit
Three forms:
 Over-damped: Two negative real roots
 Under-damped: Two distinct complex roots
 Critically-damped: Two real, distinct roots
Underdamped Circuit
 Response is a decaying exponential that oscillates
t
d etCtCti d
))cos()sin(()( 21
Substitute Parameters into Underdamped
Equation
t
t
d
etCtCti
L
CR
etCtCti
d
d
62.32
21
2
0
22
0
0
0
21
))57.23cos()57.23sin(()(
57.231
30339999997452.0
2
62.32
76.33013
))cos()sin(()(
LTSpice vs Oscilloscope
t
etCtCti 62.32
21 ))57.23cos()57.23sin(()(

Rlc circuits and differential equations1

  • 1.
  • 2.
    Designed and builtRLC circuit to test response time of current
  • 3.
    Derive the constantcoefficient differential equation  Resistance (R) = 643.108 Ω  Inductor (L) = 9.74 × 10^-3 H  Capacitor (C) = 9.42 × 10^-8 F
  • 4.
    Kirchhoff’s Voltage Law(KVL) The sum of voltage drops across the elements of a series circuit is equal to applied voltage.
  • 5.
    Voltage Drop perCircuit Elements Inductor Resistor Capacitor
  • 6.
    Substitute and Differentiation Differentiateboth sides for equation for current Substitute dQ/dt for I in original equation and arrive at second order differential equation Current is the rate of change of charge (in Coulombs) with respect to time Substitute voltage drops into equation KVL )(tVVVV CLR )( 1 tVQ C RI dt dI L )(tI dt dQ )( 1 '" tVQ C RQLQ )(' 1 '" tVI C RILI
  • 7.
    General forms ofequation Which is the same as: Divide by L: 0)( 1)()( 2 2 ti LCdt tdi L R dt tid 0)( )( 2 )( 2 02 2 ti dt tdi dt tid
  • 8.
    Calculate Parameters forSubstitution 0 1 ''' I LC I L R I 5.660272 L R 92 0 100899.1 1 LC 0100899.1'5.66027'' 9 III 0100899.15.66027 92 RR 0)( 1)()( 2 2 ti LCdt tdi L R dt tid
  • 9.
    Solve Characteristic Equationfor R 62.32 76.33013 62.3276.33013 )1(2 )100899.1)(1(45.66027 5.66027 2 4 0)100899.1(5.66027 92 2 92 iR iR R a acb bR RR
  • 10.
    Select Natural Responseof Circuit Three forms:  Over-damped: Two negative real roots  Under-damped: Two distinct complex roots  Critically-damped: Two real, distinct roots
  • 11.
    Underdamped Circuit  Responseis a decaying exponential that oscillates t d etCtCti d ))cos()sin(()( 21
  • 12.
    Substitute Parameters intoUnderdamped Equation t t d etCtCti L CR etCtCti d d 62.32 21 2 0 22 0 0 0 21 ))57.23cos()57.23sin(()( 57.231 30339999997452.0 2 62.32 76.33013 ))cos()sin(()(
  • 13.
    LTSpice vs Oscilloscope t etCtCti62.32 21 ))57.23cos()57.23sin(()(