3
2
1
Group:
         Aqmalia Shafira
         Sabila Anjani
         Anindhito
         Julio Caesar
         Febiola Efriani
   Is geometrical polygon-shaped base
    and the establishment of a triangular
    field that intersect at one point.
    Intersection of the straight sides of the
    pyramid called cusp pyramid.
1   2                 3          4




        1. Triangular Pyramid

        2. Rectangular Pyramid

        3. Pentagonal Pyramid

        4. Hexagonal Pyramid
 Triangular Pyramid has 6 lines
 Rectangular Pyramid has 8 lines
 Pentagonal Pyramid has 10 lines
 Hexagonal Pyramid has 12 lines




                            FORMULA
Lines = 2n
Where n is the type of the pyramid
base. If the type of base on the
pyramid is square, then n = 4. If the
type of base on the pyramid is a
triangle, then n = 3, and so on.
Sides of Triangular Pyramid
                              •Triangular Pyramid has 4 side
                              •The field of side: Triangle(4)




       Sides of Rectangular Pyramid
Rectangular Pyramid has 5 side
The field of side: Triangle (4) Rectangle (1)
In the Triangular Pyramid, there are 9
   corners and there are 4 vertex.
In the Rectangular Pyramid, there are 12
   corners and there are 5 vertex.



                                  FORMULA
points = n + 1

Where n is the type of the pyramid
base. If the type of base on the
pyramid is square, then n = 4. If the
type of base on the pyramid is a
triangle, then n = 3, and so on.
 Surface area pyramid =
= Area□ ABCD + Area ∆ TAB + Area ∆ TBC
  + Area ∆ TCD + Area ∆ TAD



     Luas Permukaan pada Limas =
Luas alas + jumlah seluruh luas sisi tegak
    Base pyramid form a right triangle with
    sides of length 12 cm, 16 cm, 20 cm. If
    the pyramid height 21 cm, then the
    volume of the pyramid is....
ANSWER
Lalas =   ½xaxt
          = ½ x 16 x 12
          = 96 cm²

Vlimas    =   1/  x Lalas x tLimas
                   3
          =   1/ x 96 x 21
                3
          =   672 cm³
   Picture below is a rectangular pyramid.
    ABCD with base side length of 6 cm and
    4 cm tall pyramid. Then the surface area
    of ​the pyramid is ...
1.   OF = ½ x AB = ½ x 6 = 3 cm
     TF² = TO² + OF²
         = 4² + 3² = 16 + 9 = 25
     TF = √25 = 5 cm

Lp    = Lalas + Lsisi tegak
      = AB x BC + 4 x ½ x BC x TF
      =6x6+4x½x6x5
      = 96 cm²
                                    ANSWER
Pyramid Mathematics

Pyramid Mathematics

  • 1.
  • 2.
  • 3.
  • 6.
    Group: Aqmalia Shafira Sabila Anjani Anindhito Julio Caesar Febiola Efriani
  • 7.
    Is geometrical polygon-shaped base and the establishment of a triangular field that intersect at one point. Intersection of the straight sides of the pyramid called cusp pyramid.
  • 8.
    1 2 3 4 1. Triangular Pyramid 2. Rectangular Pyramid 3. Pentagonal Pyramid 4. Hexagonal Pyramid
  • 9.
     Triangular Pyramidhas 6 lines  Rectangular Pyramid has 8 lines  Pentagonal Pyramid has 10 lines  Hexagonal Pyramid has 12 lines FORMULA
  • 10.
    Lines = 2n Wheren is the type of the pyramid base. If the type of base on the pyramid is square, then n = 4. If the type of base on the pyramid is a triangle, then n = 3, and so on.
  • 11.
    Sides of TriangularPyramid •Triangular Pyramid has 4 side •The field of side: Triangle(4) Sides of Rectangular Pyramid Rectangular Pyramid has 5 side The field of side: Triangle (4) Rectangle (1)
  • 12.
    In the TriangularPyramid, there are 9 corners and there are 4 vertex. In the Rectangular Pyramid, there are 12 corners and there are 5 vertex. FORMULA
  • 13.
    points = n+ 1 Where n is the type of the pyramid base. If the type of base on the pyramid is square, then n = 4. If the type of base on the pyramid is a triangle, then n = 3, and so on.
  • 15.
     Surface areapyramid = = Area□ ABCD + Area ∆ TAB + Area ∆ TBC + Area ∆ TCD + Area ∆ TAD Luas Permukaan pada Limas = Luas alas + jumlah seluruh luas sisi tegak
  • 16.
    Base pyramid form a right triangle with sides of length 12 cm, 16 cm, 20 cm. If the pyramid height 21 cm, then the volume of the pyramid is....
  • 17.
    ANSWER Lalas = ½xaxt = ½ x 16 x 12 = 96 cm² Vlimas = 1/ x Lalas x tLimas 3 = 1/ x 96 x 21 3 = 672 cm³
  • 18.
    Picture below is a rectangular pyramid. ABCD with base side length of 6 cm and 4 cm tall pyramid. Then the surface area of ​the pyramid is ...
  • 19.
    1. OF = ½ x AB = ½ x 6 = 3 cm TF² = TO² + OF² = 4² + 3² = 16 + 9 = 25 TF = √25 = 5 cm Lp = Lalas + Lsisi tegak = AB x BC + 4 x ½ x BC x TF =6x6+4x½x6x5 = 96 cm² ANSWER