The document describes the steps to solve a circuit with three resistors (R1, R2, R3) connected to an 80V power supply. It involves combining parallel resistors, calculating total resistance, current, voltage drops across resistors, and branch currents. It then shows calculating power dissipated in each resistor. The key steps are: combining R2 and R3 since they are in parallel, calculating total circuit resistance and current, determining voltage drops using Ohm's Law, and then power calculations for each resistor element.

1. Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω

2. Redraw circuit , replace 2 parrellel resistors with one: Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

3. Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

4. Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

5. Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 1/Rt = 2/15 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

6. Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 1/Rt = 2/15 Rt = 7.5 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5 Ω

7. Replace 2 resistors in series, for one: 10 Ω + 7.5Ω = 17.5 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

8. R total = 17.5Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

9. R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

10. R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω I total = 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

11. R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω I total = 4.57A DRAW THIS ON YOUR CIRCUITS Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

12. Work out Voltdrops: VR1 = R1x I Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

13. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

14. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

15. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

16. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

17. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

18. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

19. Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

20. WORK OUT BRANCH CURRENTS Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

21. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

22. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

23. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

24. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

25. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

26. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

27. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A DRAW RESULTS ON CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

28. WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A DRAW RESULTS ON CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

29. Now that you have all the branch currents you can work out anything required: Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

30. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

31. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

32. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

33. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

34. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W PR3 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

35. Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W PR3 = I x V = 1.71A x 34.275V = 58.61W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A