Type your answers in the black boxes and check them with the correct
answers on the last slide
Rules
Current is the same through all the components
Voltage is shared out across the components
The resistance of components adds together
Potential difference = current x resistance
volts = amps x ohms
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3A
3A
3A
3A
3A
THE CURRENT IN A SERIES
CIRCUIT IS THE SAME AT
EVERY POINT.
What happens if one lamp is unscrewed?
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No current flows if there is a gap in the
circuit
What happens if one cell is turned around?
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Reversing the cell reverses the pushing effect
(cells provide a pd to push the charge)
What happens if another cell is added
the same way as the others?
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Increasing the pd in the same direction
increases the pushing effect on the charges
What happens if another cell is added
the other way to the others?
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Adding pd in the opposite direction makes
the pushing effect on the charges less
What happens if another bulb is added?
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Adding a bulb adds resistance to the flow
of charge
What happens if both cells are turned around?
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The pd pushes the current the other way but
the brightness of the bulbs remains the same.
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Equations
V = I x R I = V/R R = V/I
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3A
6V battery
2 Ohm 4 Ohm
Adding resistors in series is
dead easy- the total resistance
is now 6 Ohm
Divide the voltage by the total resistance
and type your answer with units in the box
Question 1 Using the equation for current (I) we
can work out that 3Amps of
current will be flowing
Equations
V = I x R I = V/R R = V/I
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1A
12V battery
R R
Total Resistance =
Value for R =
Work out the total resistance of the circuit
and a value for R
Question 2
Equations
V = I x R I = V/R R = V/I
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A
12V
1 Ohm 3 Ohm
V V
Notice that the circuit is NOT affected by the
meters and the resistors are still in series
I = 12/4 = 3A
3A
V V
pd across
the 1 Ohm
resistor
Question 3
pd across
the 3 Ohm
resistor
Rules you should remember and be able
to use:-
Current is the same through all the components
Voltage is shared out across the components
The resistance of components adds together
Potential difference = current x resistance
volts = amps x ohms
answers
Question 1 1Amp
Question 2 Total Resistance = 12/1 = 12 Ohms
If the resistors are both the same
then R = 6 Ohms
Question 3 PD across 1 Ohm resistor = 3 Volts
PD across 3 Ohm = 9 Volts
series circuits.ppt

series circuits.ppt

  • 1.
    Type your answersin the black boxes and check them with the correct answers on the last slide
  • 2.
    Rules Current is thesame through all the components Voltage is shared out across the components The resistance of components adds together Potential difference = current x resistance volts = amps x ohms
  • 3.
  • 4.
    - - - - - - - - - - - - - -- - 3A 3A 3A 3A 3A THE CURRENT IN A SERIES CIRCUIT IS THE SAME AT EVERY POINT.
  • 5.
    What happens ifone lamp is unscrewed? - - - - - - - - No current flows if there is a gap in the circuit
  • 6.
    What happens ifone cell is turned around? - - - - - - - - Reversing the cell reverses the pushing effect (cells provide a pd to push the charge)
  • 7.
    What happens ifanother cell is added the same way as the others? - - - - - - - - Increasing the pd in the same direction increases the pushing effect on the charges
  • 8.
    What happens ifanother cell is added the other way to the others? - - - - - - - - Adding pd in the opposite direction makes the pushing effect on the charges less
  • 9.
    What happens ifanother bulb is added? - - - - - - - - Adding a bulb adds resistance to the flow of charge
  • 10.
    What happens ifboth cells are turned around? - - - - - - - - The pd pushes the current the other way but the brightness of the bulbs remains the same. - - - - - - - -
  • 11.
    Equations V = Ix R I = V/R R = V/I - - - - - - - - 3A 6V battery 2 Ohm 4 Ohm Adding resistors in series is dead easy- the total resistance is now 6 Ohm Divide the voltage by the total resistance and type your answer with units in the box Question 1 Using the equation for current (I) we can work out that 3Amps of current will be flowing
  • 12.
    Equations V = Ix R I = V/R R = V/I - - - - - - - - 1A 12V battery R R Total Resistance = Value for R = Work out the total resistance of the circuit and a value for R Question 2
  • 13.
    Equations V = Ix R I = V/R R = V/I - - - - - - - - A 12V 1 Ohm 3 Ohm V V Notice that the circuit is NOT affected by the meters and the resistors are still in series I = 12/4 = 3A 3A V V pd across the 1 Ohm resistor Question 3 pd across the 3 Ohm resistor
  • 14.
    Rules you shouldremember and be able to use:- Current is the same through all the components Voltage is shared out across the components The resistance of components adds together Potential difference = current x resistance volts = amps x ohms
  • 15.
    answers Question 1 1Amp Question2 Total Resistance = 12/1 = 12 Ohms If the resistors are both the same then R = 6 Ohms Question 3 PD across 1 Ohm resistor = 3 Volts PD across 3 Ohm = 9 Volts