Mpi lab manual eee

SHRI RAWATPURA SARKAR INSTITUTE OF TECHNOLOGY-II,
NEW RAIPUR
MICROPROCESSOR & PERIPHEARLS LAB MANUAL, DEPT.OF EEE, SRIT-II NEW RAIPUR Page 1
List of Experiment
S.No List Of Program
Introduction to Microprocessor 8085
1 To transfer data into specified Register.
2 To add content of two register and store result in another register.
3
To add contents of two memory locations & store result in another memory
locations.
4 To find 2’s complement of 8 bit numbers.
5 To mask upper nibble of the 8 bit number.
6 To transfer block of 10 data bytes from one memory location to another.
7 To multiply two 8 bit numbers.
8 To add contents of a block of 10 data bytes.
9 To find largest among the 10 given data bytes.
10 To arrange given data bytes in ascending order.
11. To convert the binary number into its equivalent BCD.
12 To pack the unpacked BCD numbers.
13 To unpack the BCD numbers.

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INTRODUCTION TO MICROPROCESSOR 8085
Architecture of 8085 Microprocessor
a) General purpose register
It is an 8 bit register i.e. B,C,D,E,H,L. The combination of 8 bit register is known as
register pair, which can hold 16 bit data. The HL pair is used to act as memory pointer is
accessible to program.
b) Accumulator
It is an 8 bit register which hold one of the data to be processed by ALU and stored
the result of the operation.
c) Program counter (PC)
It is a 16 bit pointer which maintain the address of a byte entered to line stack.
d) Stack pointer (Sp)
It is a 16 bit special purpose register which is used to hold line memory address for
line next instruction to be executed.
e) Arithmetic and logical unit
It carries out arithmetic and logical operation by 8 bit address it uses the accumulator
content as input the ALU result is stored back into accumulator.
f) Temporary register
It is an 8 bit register associated with ALU hold data, entering an operation, used by
the microprocessor and not accessible to programs.
g) Flags
Flag register is a group of fire, individual flip flops line content of line flag register
will change after execution of arithmetic and logic operation. The line states flags are
i) Carry flag (C)
ii) Parity flag (P)
iii) Zero flag (Z)
iv) Auxiliary carry flag (AC)
v) Sign flag (S)
h) Timing and control unit
Synchronous all microprocessor, operation with the clock and generator and control
signal from it necessary to communicate between controller and peripherals.
i) Instruction register and decoder
Instruction is fetched from line memory and stored in line instruction register decoder
the stored information.
j) Register Array
These are used to store 8 bit data during execution of some instruction.

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PIN Description
Address Bus
1. The pins Ao – A15 denote the address bus.
2. They are used for most significant bit
Address / Data Bus
1. AD0 – AD7 constitutes the address / Data bus
2. These pins are used for least significant bit
ALE : (Address Latch Enable)
1. The signal goes high during the first clock cycle and enables the lower order
address bits.
IO / M
1. This distinguishes whether the address is for memory or input.
2. When this pins go high, the address is for an I/O device.
S0 – S1
S0 and S1 are status signal which provides different status and functions.
RD
1. This is an active low signal
2. This signal is used to control READ operation of the microprocessor.
WR
1. WR is also an active low signal
2. Controls the write operation of the microprocessor.
HOLD
1. This indicates if any other device is requesting the use of address and data bus.
HLDA
1. HLDA is the acknowledgement signal for HOLD
2. It indicates whether the hold signal is received or not.
INTR
1. INTE is an interrupt request signal
2. IT can be enabled or disabled by using software
INTA
1. Whenever the microprocessor receives interrupt signal
2. It has to be acknowledged.
RST 5.5, 6.5, 7.5
1. These are nothing but the restart interrupts
2. They insert an internal restart junction automatically.

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TRAP
1. Trap is the only non-maskable interrupt
2. It cannot be enabled (or) disabled using program.
RESET IN
1. This pin resets the program counter to 0 to 1 and results interrupt enable and
HLDA flip flops.
X1, X2
These are the terminals which are connected to external oscillator to produce the
necessary and suitable clock operation.
SID
This pin provides serial input data
SOD
This pin provides serial output data
VCC and VSS
1. VCC is +5V supply pin
2. VSS is ground pin
Specifications
1. Processors
Intel 8085 at E144 MHz clock
2. Memory
Monitor RAM: 0000– IFFF
EPROM Expansion: 2000– 3FFF’s
0000– FFF
System RAM: 4000– 5FFF
Monitor data area 4100– 5FFF
RAM Expansion 6000– BFFF
3. Input / Output
Parallel: A8 TTL input timer with 2 number of 32-55 only input timer available in -85 EBI.
Serial: Only one number RS 232-C, Compatible, crucial interface using 8281A
Timer: 3 channel -16 bit programmable units, using 8253 channel ‘0’ used for no band late.
Clock generator. Channel ‘1’ is used for single stopping used program.
Display: 6 digit – 7 segment LED display with filter 4 digit for adder display and 2 digit for
data display.
Key board: 21 keys, soft keyboard including common keys and hexa decimal keys.
RES: Reset keys allow to terminate any present activity and retain to  - 85 its on initialize
state.

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INT: Maskable interrupt connect to CPU’s RST 7.5 interrupt
DEC: Decrement the adder by 1
EXEC: Execute line particular value after selecting address through go command.
NEXT: Increment the address by 1 and then display its content.
IC’s Used
8085 - 8 bit p
8253 - programmable internal timer
8255 - programmable peripheral interface
8279 - program mable key boards / display interface
8251 - programmable communication interface
2764 - 8 KV VV EPROM
6264 - 8K STATIC PROM
7414 - Hex inverter
7432 - Quad 21/p OR GATE
7409 - Quad 21/p AND GATE
7400 - NAND Gate
7404 - Dual D-FF
74373 - Octal ‘D’ Latch
74139 - Dual 2 to 4 line decoder
74138 - 3 to 8 line decoder
In Enter Program into Trainer Kit
1. Press ‘RESET’ key
2. Sub (key processor represent address field)
3. Enter the address (16 bit) and digit in hex
4. Press ‘NEXT’ key
5. Enter the data
6. Again press “NEXT”
7. Again after taking the program, are use HLT instruction
its Hex code
8. Press “NEXT”
How to executive program
1. Press “RESET”
2. Press “GO”
3. Enter the address location in which line program was executed
4. Press “Execute” key

NEW RAIPUR
PROGRAM 1
Aim:
To write an assembly language for transfer data into specified register.
Apparatus required:
8085 micro processor kit
(0-5V) DC battery
Algorithm:
Suppose
data s are
20 and 30
Step1 : MOV A, 20 H
Step2 : MOV B, 30 H
Step3 : MOV C,A
Step4 : MOV D, B.
Step5 : HLT
OUTPUT:
Before Execution: A= 20; B= 30
After Execution: C= 20; D=30

SHRI RAWATPURA SARKAR INSTITUTE OF TECHNOLOGY-II, NEW
RAIPUR
PROGRAM 2
Aim:
To write an assembly language for adding two 8 bit numbers by using micro processor kit.
Apparatus required:
(0-5V) DC battery
Algorithm:
Step1 : Start the microprocessor
Step2 : Intialize the carry as ‘Zero’
Step3 : Load the first 8 bit data into the accumulator
Step4 : Copy the contents of accum ulator into the register ‘B’
Step5 : Load the second 8 bit data into the accumulator.
Step6 : Add the 2 - 8 bit datas and check for carry.
Step7 : Jump on if no carry
Step8 : Increment carry if there is
Step9 : Store the added request in accumulator
Step10 : More the carry value to accumulator
Step11 : Store the carry value in accumulator
Step12 : Stop the program execution.
Address Label Mnemonics Hex Code Comments
4100 MVI C,00 OE, 00 Initialize the carry as zero
4102 LDA 4300 3A, (00, 43) Load the first 8 bit data
4105 MOV, B,A 47 Copy the value of 8 bit data
into register B
4106 LDA 4301 3A, (01, 43) Load the second 8 bit data
into the accumulator
4109 ADD B 80 Add the hoo values
410A JNC D2, 0E, 41 Jump on if no carry
410D INR C OC If carry is there increment it
by one
410E Loop STA 4302 32 (02, 43) Stone the added value in the
accumulator
4111 MOV A,C 79 More the value of carry to
the accumulator from
register C
4112 STA 4303 32 (03, 43) Store the value of carry in
the accumulator
4115 HLT 76 Stop the program execution

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Input
Without carry
Input Address Value
4300 04
4301 02
Output
Output Address Value
4302 06
4303 00 (carry)
With carry
Input Address Value
4300 FF
4301 FF
Output Address Value
4302 FE
4303 01 (carry)
Calculation 1111 1111
1111 1111
---------------
(1) 1111 1110
=========
F E
Result:
The assembly language program for 8 bit addition of two numbers was executed successfully
by using 8085 micro processing kit.

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PROGRAM 3
Aim:
To write an assembly language to add contents of two memory locations and store result in
another memory locations.
Add the contents of memory locations 4000H and 4001H and place the result in memory
location 4002H.
Apparatus required:
(0-5V) DC battery
Program:
(4000H) = 14H
(4001H) = 89H
Result = 14H + 89H = 9DH Source
program
LXI H 4000H : HL points 4000H
MOV A, M : Get first operand
INX H : HL points 4001H
ADD M : Add second operand
INX H : HL points 4002H
MOV M, A : Store result at 4002H
HLT : Term inate program

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PROGRAM 4
Aim:
To write an assembly language for finding the 2’s complement of 8 bit number.
Apparatus required:
8085 micro processor kit (0-5V) DC battery
Program:
Address Mnemonics Operand Opcode Remarks
2000 LDA 3000H 3A Load H-L pair with data from 3000H.
2001 00 Lower-order of 3000H.
2002 30 Higher-order of 3000H.
2003 CMA 2F Complement accumulator.
2004 INR A 2C Increment accumulator.
2005 STA 3001H 32 Store the result at memory location 3001H.
2008 HLT 76 Halt.
Explanation:
o This program finds the 2’s complement of an 8-bit number stored in memory location
3000H. 

o Let us assume that the operand stored at memory location 3000H is 85H. 

o The operand is moved to accumulator from memory location 3000H. 

o Then, its complement is found by using CMA instruction. 

o One is added to accumulator by incrementing it to find its 2’s complement. 

o The result is stored at memory location 3001H. 
Output:
Before Execution:
3000H: 85H
After Execution: 3001H: 7BH

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PROGRAM 5
Aim:
To write an assembly language to mask upper nibble of the 8 bit number.
Apparatus required:
(0-5V) DC battery
Program:
(4000H) = 45H
Result = 4000H = 0fH
program
LDA 4000H : A= contents of 4000H
ANI 0FH : A ANDed with 0FH
STA 4000H : 4000H= Contents of A
HLT : Terminate Program
Output:
Before Execution:
4000H: 45H
After Execution: 4000H: 05H

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PROGRAM 6
Aim:
To write an assembly language to transfer block of 10 data bytes from one memory location to
another.
Transfer ten bytes of data from one memory to another memory block. Source memory block
starts from memory location 2200H where as destination memory block starts from memory
location 2300H
Apparatus required:
(0-5V) DC battery
Program:
LXI H, 4150 : Initialize memory pointer
MVI B, 08 : count for 8-bit
MVI A, 54
LOOP : RRC
JC LOOP1
MVI M, 00 : store zero it no carry
JMP COMMON
LOOP2: MVI M, 01 : store one if there is a carry
COMMON: INX H
DCR B : check for carry
JNZ LOOP
HLT : Terminate the program

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PROGRAM 7
Aim:
To write an assembly language to multiply two 8 bit number.
Apparatus required:
8085 micro processor kit (0-5V)
DC battery
Program:
Address Mnemonics Operand Opcode Remarks
2000 LXI H, 3000H 21 Load H-L pair with address 3000H.
2003 MOV B, M 46 Move the 1st operand from memory to reg. B.
2004 INX H 23 Increment H-L pair.
2005 MOV C, M 4E Move the 2nd operand from memory to reg. C.
2006 MVI A, 00H 3E Initialize accumulator with 00H.
2007 00 Immediate value 00H.
2008 ADD B 80 Add B with A.
2009 DCR C 0D Decrement reg. C (counter).
200A JNZ 2008H C2 Jump back to address 2008H if C ≠ 0.
200B 08 Lower-order of 2008H.
200C 20 Higher-order of 2008H.
200D INX H 23 Increment H-L pair.
200E MOV M, A 77 Move the result from accumulator to memory.
200F HLT 76 Halt.
Explanation:
o This program multiplies two operands stored in memory location 3000H and 3001H,
using successive addition method. 

o In successive addition method, the second operand is considered as counter, and the

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first number is added with itself until counter decrements to zero. 

o Let us assume that the operands stored at memory location 3000H is 02H and 3001H is
05H. 

o Then, by using successive addition method, we get 02H + 02H + 02H + 02H + 02H =
0AH. 

o Initially, H-L pair is loaded with the address of first memory location. 


The first operand is moved to register B from memory location 3000H and H-L pair is
incremented to point to next memory location. 

o The second operand is moved to register C from memory location 3001H to act as
counter. 

o Accumulator is initialized to 00H. 

o Register B is added with accumulator and the result is stored in accumulator. 

o Register C (counter) is decremented by 1. 

o Then, counter is checked for zero. If it hasn’t become zero yet, then register B is again
added with accumulator, and counter is again checked for zero. 
 If counter becomes zero, then H-L pair is incremented and the result is moved
from accumulator to memory location 3002H. 
Output:
Before Execution:
3000H: 02H
3001H: 05H
After Execution:
3002H: 0A

NEW RAIPUR
MICROPROCESSOR& PERIPHEARLSLAB MANUAL,DEPT.OF EEE,SRIT-IINEWRAIPUR
Page 15
PROGRAM 8
Aim:
To write an assembly language to add contents of a block of 10 data bytes.
Calculate the sum of series of numbers. The length of the series is in memory location
4200H and the series begins from memory location 4201H.
Consider the sum to be 8 bit number. So, ignore carries. Store the sum at memory
location 4300H.
Consider the sum to be 16 bit number. Store the sum at memory locations 4300H
and 4301H.
Apparatus required:
8085 micro
processor kit
(0-5V) DC battery
Program:
4200H = 04H
4201H = 10H
4202H = 45H
4203H = 33H
4204H = 22H
Result = 10 +41 + 30 + 12 = H
4300H = H
LDA 4200H
MOV C, A : Initialize counter
SUB A : sum = 0
LXI H, 420lH : Initialize pointer
BACK: ADD M : SUM = SUM + data
INX H : increment pointer
DCR C : Decrement counter
JNZ BACK : if counter 0 repeat
STA 4300H : Store sum
HLT : Terminate program

NEW RAIPUR
MICROPROCESSOR& PERIPHEARLSLAB MANUAL,DEPT.OF EEE,SRIT-IINEWRAIPUR
Page 16
PROGRAM 9
Aim:
To write an assembly language to find largest am0ng the 10 given databytes.
Find the largest number in a block of data. The length of the block is in memory
location 2200H and the block itself starts from memory location 2201H.
Store the maximum number in memory location 2300H. Assume that the
numbers in the block are all 8 bit unsigned binary numbers.
Apparatus required:
8085 micro
processor kit
(0-5V) DC battery
Sample problem
(2200H) = 04
(2201H) = 34H
(2202H) = A9H
(2203H) = 78H
(2204H) =56H
Result = (2202H) = A9H
program
LDA 2200H
MOV C, A : Initialize counter
XRA A : Maximum = Minimum possible value = 0
LXI H, 2201H : Initialize pointer
BACK: CMP M : Is number> maximum
JNC SKIP : Yes, replace maximum

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MOV A, M
SKIP: INX H
DCR C
JNZ BACK
STA 2300H : Store maximum number
HLT : Terminate program execution

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PROGRAM 10
Aim:
To write an assembly language to arrange given data bytes in ascending order.
Write a program to sort given 10 numbers from memory location 2200H in the ascending
order.
Apparatus required:
(0-5V) DC battery
Program:
MVI B, 09 : Initialize counter
START : LXI H, 2200H: Initialize memory pointer
MVI C, 09H : Initialize counter 2
BACK: MOV A, M : Get the number
INX H : Increment memory pointer
CMP M : Compare number with next number
JC SKIP : If less, don't interchange
JZ SKIP : If equal, don't interchange
MOV D, M
MOV M, A
DCX H
MOV M, D
INX H : Interchange two numbers
SKIP: DCR C : Decrement counter 2
JNZ BACK : If not zero, repeat
DCR B : Decrement counter 1
JNZ START
HLT :Terminate program execution

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PROGRAM 11
Aim:
To write an assembly language to convert the binary number into its equivalent BCD.
Write a main program and a conversion subroutine to convert the binary number
stored at 6000H into its equivalent BCD number. Store the result from memory
location 6100H
Apparatus required:
(0-5V) DC battery
Program:
(6000) H = 8AH
1.8AH ? 64H (Decimal 100) :. Divide by 64H (Decimal 100)
8AH/64H ? Quotient = 1, Remainder = 26H
26H < 64H (Decimal 100) :. Go to step 2 and Digit 2 = 1
2.26H ? OAH (Decimal 10) :. Divide by OAH (Decimal 10)
26H/OAH ? Quotient = 3, Remainder = O8H
OSH < OAH (Decimal 10) :. Go to step 3 and Digit 1 = 3
3. Digit 0 = O8H
LXI SP, 27FFH : Initialize stack pointer
LDA 6000H : Get the binary number in accumulator
CALL SUBROUTINE : Call subroutine
HLT : Terminate program execution
Subroutine to convert binary number into its equivalent BCD number:
PUSH B : Save BC register pair contents
PUSH D : Save DE register pair contents
MVI B, 64H : Load divisor decimal 100 in B register
MVI C, 0AH : Load divisor decimal 10 in C register
MVI D, 00H : Initialize Digit 1
MVI E, 00H : Initialize Digit 2
STEP1: CMP B : Check if number < Decimal 100
JC STEP 2 : if yes go to step 2
SUB B : Subtract decimal 100

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INR E : update quotient
JMP STEP 1 : go to step1
STEP2: CMP C : Check if number < Decimal 10
JC STEP 3 : if yes go to step 3
SUB C : Subtract decimal 10
INR D : Update quotient
JMP STEP 2 : Continue division by 10
STEP3: STA 6100H : Store Digit 0
MOV A, D : Get Digit 1
STA 6101H : Store Digit 1
MOV A, E : Get Digit 2
STA 6102H : Store Digit 2
POP D : Restore DE register pair
POP B : Restore BC register pair
RET : Return to main program

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PROGRAM 12
Aim:
To write an assembly language to Pack the two unpacked BCD numbers stored in memory
locations 4200H and 4201H and store result in memory location 4300H. Assume the least
significant digit is stored at 4200H.
Apparatus required:
(0-5V) DC battery
Program:
(4200H) = 04
(4201H) = 09
Result = (4300H) = 94
Source program:
LDA 4201H : "Get the Most significant BCD digit"
RLC
RLC
RLC
RLC : "Adjust the position ofthe second digit (09 is changed to 90)"
ANI FOH : "Make least significant BCD digit zero"
MOVC, A : "store the partial result"
LDA 4200H : "Get the lower BCD digit"
ADD C : "Add lower BCD digit"
STA 4300H : "Store the result"
HLT : "Terminate program execution"

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PROGRAM 13
Aim:
To write an assembly language to Two digit BCD number is stored in memory location 4200H.
Unpack the BCD number and store the two digits in memory locations 4300H and 4301H such
that memory location 4300H will have lower BCD digit.
Apparatus required:
(0-5V) DC battery
Program:
(4200H) = 58
Result = (4300H) = 08 and
(4301H) = 05
Source program:
LDA 4200H : "Get the packed BCD number"
ANI FOH : "Mask lower nibble"
RRC
RRC
RRC
RRC : "Adjust higher BCD digit as a lower digit"
STA 4301H : "Store the partial result"
LDA 4200H : "Get the original BCDnumber"
ANI OFH : "Mask higher nibble"
STA 4201H : "Store the result"
HLT : "Terminate program execution"

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