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More – Coordinate Plane, Midpoint, and Relations and Functions Module 4 Topic 1
Example 1 Remember that the quadrants are I, II, III, or IV. Quadrant I = (positive x-value, positive y-value) Quadrant II = (negative x-value, positive y-value) Quadrant III = (negative x-value, negative y-value) Quadrant IV = (positive x-value, negative y-value)
Example 2 Similar Problem: Find the coordinates of the midpoint of M(-3, 0) and N(-7, -5). Midpoint is the average of the x-values and the average of the y-values. Midpoint = (x2 + x1) ÷ 2 , (y2 + y1) ÷ 2 Midpoint = (-7 + -3) ÷ 2 , (-5 + 0) ÷ 2 Midpoint = -10 ÷ 2 , -5 ÷ 2 Midpoint = -5, -2.5 so we write it as an ordered pair (-5, -2.5)
Example 3 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} Is the relation a function? Yes - because the x-values do not repeat!
Example 4 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} State the domain of the relation. Domain = all x-values of the relation 2, 7, -5, -2, 0 but let's put these in order so we have -5, -2, 0, 2, 7
Example 5 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} State the range of the relation. Range = all y-values of the relation 4, 7, 4, -8, 0  but let's put these in order so we have -8, 0, 4, 4, 7 and let's not repeat any so we have -8, 0 , 4, 7
Example 6 Similar Problem: If f(x) = 3x + 6, find f(-4). Plug in -4 for x in the function 3x + 6 3(-4) + 6 -12 + 6 -6

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Module 4 topic 1 2nd

  • 1. More – Coordinate Plane, Midpoint, and Relations and Functions Module 4 Topic 1
  • 2. Example 1 Remember that the quadrants are I, II, III, or IV. Quadrant I = (positive x-value, positive y-value) Quadrant II = (negative x-value, positive y-value) Quadrant III = (negative x-value, negative y-value) Quadrant IV = (positive x-value, negative y-value)
  • 3. Example 2 Similar Problem: Find the coordinates of the midpoint of M(-3, 0) and N(-7, -5). Midpoint is the average of the x-values and the average of the y-values. Midpoint = (x2 + x1) ÷ 2 , (y2 + y1) ÷ 2 Midpoint = (-7 + -3) ÷ 2 , (-5 + 0) ÷ 2 Midpoint = -10 ÷ 2 , -5 ÷ 2 Midpoint = -5, -2.5 so we write it as an ordered pair (-5, -2.5)
  • 4. Example 3 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} Is the relation a function? Yes - because the x-values do not repeat!
  • 5. Example 4 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} State the domain of the relation. Domain = all x-values of the relation 2, 7, -5, -2, 0 but let's put these in order so we have -5, -2, 0, 2, 7
  • 6. Example 5 Similar Problem: Use the following relation to answer questions 7 - 9. {(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)} State the range of the relation. Range = all y-values of the relation 4, 7, 4, -8, 0 but let's put these in order so we have -8, 0, 4, 4, 7 and let's not repeat any so we have -8, 0 , 4, 7
  • 7. Example 6 Similar Problem: If f(x) = 3x + 6, find f(-4). Plug in -4 for x in the function 3x + 6 3(-4) + 6 -12 + 6 -6