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Ways to factor…
There a few different ways to approaching factoring an
expression. However, the first thing you should always
look for is the Greatest Common Factor (GCF).

              How to find the GCF video

              Factoring using GCF video
Why GCF first?
You look for the GCF first because it will help you factor

quadratics using the second method by making the
numbers smaller.

The second method of factor involves undoing the
distributive property….I call it unFOILing 

There are several videos posted on this method, but
here’s an example…..
Factor: x2 + 6x + 8


Look at the last number.
                                                                         x2 + 6x + 8
If the sign in a positive, the signs in the parenthesis
                                                                    Here the 8 is positive.
will be the same.
Look at the sign on the middle number.
We know the signs will be the same because 8 is
positive. We look a the middle number and it's also                       (x + )(x + )
positive. So both signs in the parenthesis will be
positive.

Find factors of the last number that when you
mulitply them you get that last number, but when
you combine them you get the middle number.
                                                                         (x + 4)(x + 2)
So we're looking for factors of 8 that we multiply
them we get an 8, but when we add them we get a
6.....4 and 2.

Check it with FOIL.                                           (x + 4)(x + 2) = x2 + 4x +2x +8
You never get a factoring problem wrong! You can
always check it by multiplying.                                            It works!
Factor: x2 - 3x - 54
Special Case: The Difference of two Perfect Squares

The difference of two perfect squares is very easy to
factor, but everyone always forgets about them.!They're
in the form (ax)2 - c where a and c are perfect squares.

There's no visible b-value...so b = 0. You factor
them by taking the square root of a and the square root
of c and placing them in parenthesis that have opposite
signs.

Whenever you have a binomial that is subtraction, always check
  to
see it’s this special case. It usually does NOT have a GCF.

Here's an example….
Example
                                 Factor : 4x2 – 9

Set up parenthesis with opposite signs   ( + )( - )


Find the square root of a and place then
answer in the front sections of the
                                         ( 2x + )( 2x - )
parenthesis
sqrt(4x2) = 2x

Find the square root of c and place
them at the end of the parenthesis.      ( 2x + 3 )( 2x - 3 )
sqrt(9) = 3

                  Difference of Two Perfect Squares Video
Practice Factoring
1. x2 + 4x – 5
2. x2 - 3x + 2
3. x2 - 6x – 7
4. x2 + 4x + 4
Solutions
1. x2 + 4x – 5 = (x+5)(x-1)
2. x2 - 3x + 2 = (x-1)(x-2)
3. x2 - 6x – 7 = (x-7)(x+1)
4. x2 + 4x + 4 = (x +2)(x+2)
Practice:
             Common
              Factors




 Practice:               Practice:
Difference
  of Two
                          Factor
 Squares                   a=1




             Factoring
               with
              Algebra
               Tiles
What if the leading coefficient isn’t a 1?
                                Factor: 3x2 + 11x - 4
Set up two pairs of parenthesis                         (       )(     )
Look over the equation
                                                        (   +   )(   - )
Look at the a-value
Unfortunately, the a-value is not a one, so we need Factors of A Factors of C
to list factors in a chart.                                  1, 3     2,2 and 1,4
We're looking for the pair of factors that when I         1*2 - 3*2 = -4 NO
find the difference of the products                        1*3 - 1*4= -1 NO
will yield the b-value.                                  1*1 - 3*4= -12 YES!

Enter in values                                                (x - 4)(3x + 1)
Check with FOIL
                                                     (x - 4)(3x + 1)= 3x^2 -12x + x - 4
It's possible that you have the right numbers but in
                                                                    = 3x^2 -11x -4
the wrong spots, so you have to check.
Factoring when a≠ 1
Terms in a quadratic expression may have some common factors
         before you break them down into linear factors.

      Remember, the greatest common factor, GCF, is the
 greatest number that is a factor of all terms in the expression.

                        When a ≠ 1, we
  should always check to see if the quadratic expression has a
                    greatest common factor.
Factor 2x -22x +36      2
                               Step 1:
 a ≠ 1, so we should check to see if the quadratic expression
                 has a greatest common factor.
                        It has a GCF of 2.
                  2x2 -22x +36 = 2(x2 -11x +18)
                                Step 2:
Once we factor out the GCF, the quadratic expression now has a value of
 a =1 and we can use the process we just went through in the previous
                               examples.


                        x2 -11x +18 = (x -2)(x-9)

                Therefore, 2x2 -22x +36 is = 2 (x -2)(x-9).
A≠ 1 and NO GCF
                2x + 13x – 7
                  2


 Step 1: a ≠ 1, so we should check to see if the quadratic
  expression has a greatest common factor.
                  It does not have a GCF!
 This type of trinomial is much more difficult to factor
  than the previous. Instead of factoring the c value
  alone, one has to also factor the a value.
 Our factors of a become coefficients of our x-terms
  and the factors of c will go right where they did in the
  previous examples.
2x + 13x – 7
                            2

Step 1: Find the product ac.
                          ac= -14
Step 2: Find two factors of ac that add to give b.
            S 1 and -14 = -13
            1 -1 and 14 = 13 This is our winner!
            - 2 and -7 = -5
            2 -2 and 7 = 5
Step 3: Split the middle term into two terms, using the
  numbers found in step above.
                     2x2 -1x + 14x – 7
Step 4: Factor out the common binomial using the box
                        method.
                       2x2 -1x + 14x – 7

Quadratic   Factor 1
 Term                             2x   2
                                           -1x
 Factor 2   Constant
             Term                  14x     -7

       Find the GCF for each column
                 and row!
Numbers in RED represent the GCF
   of each row and column
             2x        -1
      x     2x2        -1x
      7      14x       -7

  The factors are (x + 7)(2x - 1).
Practice Factoring
1. 2x2 11x + 5
2. 3x2 - 5x - 2
3. 7x2 - 16x + 4
4. 3x2 + 12x + 12
Solutions
1.   2x +11x + 5 = (2x + 1)(x + 5)
       2


2.   3x2 - 5x - 2 = (3x + 1)(x - 2)
3.   7x2 - 16x + 4 = (7x - 2)(x - 2)
4.   3x2 + 12x + 12 = 3(x + 2)(x + 2)
Special Products
Factoring Strategies
Prime Factors
Remember:
   This won’t work for all quadratic trinomials,
     because not all quadratic trinomials can be
  factored into products of binomials with integer
                      coefficients.
                We call these prime!
       (Prime Numbers are 3, 5, 7, 11, 13, etc.)
Expressions such as x2 + 2x - 7, cannot be factored at
       all, and is therefore known as a prime
                     polynomial.
Practicing Factoring when
             a ≠1.
Please watch the demonstration below on factoring
    when a ≠ 1. There will be interactive examples
            provided to help when a ≠ 1.

               MORE FACTORING

          Upon completion of the video and
demonstration, please complete Mastery Assignment
                       Part 2.
Practice:
                      All Other
Gizmo: Factoring        Cases

   ax2 + bx + c



                      More
     Practice:
    Application
                   Instruction
     Problems

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Solving by factoring remediation notes

  • 1.
  • 2. Ways to factor… There a few different ways to approaching factoring an expression. However, the first thing you should always look for is the Greatest Common Factor (GCF). How to find the GCF video Factoring using GCF video
  • 3. Why GCF first? You look for the GCF first because it will help you factor quadratics using the second method by making the numbers smaller. The second method of factor involves undoing the distributive property….I call it unFOILing  There are several videos posted on this method, but here’s an example…..
  • 4. Factor: x2 + 6x + 8 Look at the last number. x2 + 6x + 8 If the sign in a positive, the signs in the parenthesis Here the 8 is positive. will be the same. Look at the sign on the middle number. We know the signs will be the same because 8 is positive. We look a the middle number and it's also (x + )(x + ) positive. So both signs in the parenthesis will be positive. Find factors of the last number that when you mulitply them you get that last number, but when you combine them you get the middle number. (x + 4)(x + 2) So we're looking for factors of 8 that we multiply them we get an 8, but when we add them we get a 6.....4 and 2. Check it with FOIL. (x + 4)(x + 2) = x2 + 4x +2x +8 You never get a factoring problem wrong! You can always check it by multiplying. It works!
  • 5.
  • 6. Factor: x2 - 3x - 54
  • 7. Special Case: The Difference of two Perfect Squares The difference of two perfect squares is very easy to factor, but everyone always forgets about them.!They're in the form (ax)2 - c where a and c are perfect squares. There's no visible b-value...so b = 0. You factor them by taking the square root of a and the square root of c and placing them in parenthesis that have opposite signs. Whenever you have a binomial that is subtraction, always check to see it’s this special case. It usually does NOT have a GCF. Here's an example….
  • 8. Example Factor : 4x2 – 9 Set up parenthesis with opposite signs ( + )( - ) Find the square root of a and place then answer in the front sections of the ( 2x + )( 2x - ) parenthesis sqrt(4x2) = 2x Find the square root of c and place them at the end of the parenthesis. ( 2x + 3 )( 2x - 3 ) sqrt(9) = 3 Difference of Two Perfect Squares Video
  • 9. Practice Factoring 1. x2 + 4x – 5 2. x2 - 3x + 2 3. x2 - 6x – 7 4. x2 + 4x + 4
  • 10. Solutions 1. x2 + 4x – 5 = (x+5)(x-1) 2. x2 - 3x + 2 = (x-1)(x-2) 3. x2 - 6x – 7 = (x-7)(x+1) 4. x2 + 4x + 4 = (x +2)(x+2)
  • 11. Practice: Common Factors Practice: Practice: Difference of Two Factor Squares a=1 Factoring with Algebra Tiles
  • 12.
  • 13. What if the leading coefficient isn’t a 1? Factor: 3x2 + 11x - 4 Set up two pairs of parenthesis ( )( ) Look over the equation ( + )( - ) Look at the a-value Unfortunately, the a-value is not a one, so we need Factors of A Factors of C to list factors in a chart. 1, 3 2,2 and 1,4 We're looking for the pair of factors that when I 1*2 - 3*2 = -4 NO find the difference of the products 1*3 - 1*4= -1 NO will yield the b-value. 1*1 - 3*4= -12 YES! Enter in values (x - 4)(3x + 1) Check with FOIL (x - 4)(3x + 1)= 3x^2 -12x + x - 4 It's possible that you have the right numbers but in = 3x^2 -11x -4 the wrong spots, so you have to check.
  • 14. Factoring when a≠ 1 Terms in a quadratic expression may have some common factors before you break them down into linear factors. Remember, the greatest common factor, GCF, is the greatest number that is a factor of all terms in the expression. When a ≠ 1, we should always check to see if the quadratic expression has a greatest common factor.
  • 15. Factor 2x -22x +36 2 Step 1: a ≠ 1, so we should check to see if the quadratic expression has a greatest common factor. It has a GCF of 2. 2x2 -22x +36 = 2(x2 -11x +18) Step 2: Once we factor out the GCF, the quadratic expression now has a value of a =1 and we can use the process we just went through in the previous examples. x2 -11x +18 = (x -2)(x-9) Therefore, 2x2 -22x +36 is = 2 (x -2)(x-9).
  • 16. A≠ 1 and NO GCF 2x + 13x – 7 2  Step 1: a ≠ 1, so we should check to see if the quadratic expression has a greatest common factor. It does not have a GCF!  This type of trinomial is much more difficult to factor than the previous. Instead of factoring the c value alone, one has to also factor the a value.  Our factors of a become coefficients of our x-terms and the factors of c will go right where they did in the previous examples.
  • 17. 2x + 13x – 7 2 Step 1: Find the product ac. ac= -14 Step 2: Find two factors of ac that add to give b.  S 1 and -14 = -13  1 -1 and 14 = 13 This is our winner!  - 2 and -7 = -5  2 -2 and 7 = 5 Step 3: Split the middle term into two terms, using the numbers found in step above. 2x2 -1x + 14x – 7
  • 18. Step 4: Factor out the common binomial using the box method. 2x2 -1x + 14x – 7 Quadratic Factor 1 Term 2x 2 -1x Factor 2 Constant Term 14x -7 Find the GCF for each column and row!
  • 19. Numbers in RED represent the GCF of each row and column 2x -1 x 2x2 -1x 7 14x -7 The factors are (x + 7)(2x - 1).
  • 20. Practice Factoring 1. 2x2 11x + 5 2. 3x2 - 5x - 2 3. 7x2 - 16x + 4 4. 3x2 + 12x + 12
  • 21. Solutions 1. 2x +11x + 5 = (2x + 1)(x + 5) 2 2. 3x2 - 5x - 2 = (3x + 1)(x - 2) 3. 7x2 - 16x + 4 = (7x - 2)(x - 2) 4. 3x2 + 12x + 12 = 3(x + 2)(x + 2)
  • 24. Prime Factors Remember: This won’t work for all quadratic trinomials, because not all quadratic trinomials can be factored into products of binomials with integer coefficients. We call these prime! (Prime Numbers are 3, 5, 7, 11, 13, etc.) Expressions such as x2 + 2x - 7, cannot be factored at all, and is therefore known as a prime polynomial.
  • 25. Practicing Factoring when a ≠1. Please watch the demonstration below on factoring when a ≠ 1. There will be interactive examples provided to help when a ≠ 1. MORE FACTORING Upon completion of the video and demonstration, please complete Mastery Assignment Part 2.
  • 26. Practice: All Other Gizmo: Factoring Cases ax2 + bx + c More Practice: Application Instruction Problems