The document provides 20 math word problems that require solving equations for a variable. It works through each problem step-by-step showing the work and reasoning to isolate the variable. Common steps include distributing terms, combining like terms, adding/subtracting the same quantity to both sides of the equation, and dividing/multiplying both sides by the same non-zero quantity. The final problems involve multiple steps to solve more complex equations.

1. Unit 2 Post Assessment
Missed Problems

2. Question 1
Solve for x: 3x = 30 Multiplication is the operation
being performed on the
3x = 30 variable (x) so we need to
undo multiplication by
3x/3 = 30/3 dividing each side of the
equation by 3.
x = 10
Check your equation!
3(10)
30

3. Question 2
Solve for a: -2a = 16 Multiplication is the operation
being performed on the
-2a = 16 variable (a) so we need to
undo multiplication by
-2a/-2 = 16/-2 dividing each side of the
equation by -2.
a = -8
Check your equation!
-2(-8)
16

4. Question 5
Solve for d: d – 12 = 10 Subtraction is the operation
being performed on the
d – 12 = 10 variable (d) so we need to
undo subtraction by adding
d – 12 + 12 = 10 + 12 each side of the equation by
12
d = 22
Check your equation!
22 – 12
10

5. Question 6
Solve for f: f – 1.5 = 3.5 Subtraction is the operation
being performed on the
f – 1.5 = 3.5 variable (f) so we need to
undo subtraction by adding
f – 1.5 + 1.5 = 3.5 + 1.5 each side of the equation by
1.5
f=5
Check your equation!
5 – 1.5
3.5

6. Question 7
Solve for t: 3 + t = 17 Addition is the operation
being performed on the
3 + t = 17 variable (t) so we need to
undo addition by subtracting
3 + t – 3 = 17 – 3 each side of the equation by
3.
t = 14
Check your equation!
3 + 14
17

7. Question 9
Solve for l: s = l + w Addition is the operation
being performed between l
s=l+w and w so we need to subtract
w to the other side to get l
s–w=l+w–w alone.
s–w=l

8. Question 11
Tenisha is twice as tall as her little brother. If Tenisha is 60
inches tall, how old is her little brother?
Brother’s height is ½ of Tenisha’s
60/2 is 30 so Tenisha’s little brother is 30 inches tall.

9. Question 12
You and Michael have a total of $19.75. If
Michael has $8.25, how much money do you
have.
You + Michael = $19.75
You + $8.25 = $19.75
Subtract $8.25 on each side.
You = $11.50

10. Question 13
Solve for x: 7x – 10 = 10 This is a two-step equation.
We are multiplying 7 to the
7x – 10 = 10 variable and subtraction 10
so we need to undo these
7x – 10 + 10 = 10 + 10 two operations.
7x = 20 Step 1: Undo subtraction by
adding
7x/7 = 20/7
Add 10 to each side
x = 20/7
Step 2: Undo multiplication by
dividing
Divide by 7 on each side.

11. Question 14
At the grocery store you This is a two-step equation.
purchase 2 gallons of milk We are multiplying 2 to the
and loaf of bread. You spent variable and adding 2 so we
a total of $8. If you know a need to undo these two
loaf of bread costs $2, how operations.
much does a gallon of milk
cost? Step 1: Undo addition by
subtracting 2 on each side
2x + 2 = 8
Step 2: Undo multiplication by
2x = 6 dividing by 2 on each side.
x=3

12. Question 16
Solve for a: 4a + a – 11 = 24 Multiple Step Equation
4a + a – 11 = 24 1) Combine like terms
5a – 11 = 24 4a + a = 5a
5a = 35 2) Add 11 to each side.
a=7 3) Divide by 5 on each side.

13. Question 17
Solve for y: 4x – 8y = 16 Multiple Step Equation
4x – 8y = 16 Subtract 4x on each side.
-8y = -4x + 16 Divide by -8 on each side.
y=½x–2

14. Question 18
Solve for p: 6p + 2(p – 1) = 22 Multiple Step Equation
6p + 2(p – 1) = 22 1) Distribute 2
6p + 2p – 2 = 22 2) Combine like terms 6p + 2p
8p – 2 = 22 3) Add 2 to each side
8p = 24 4) Divide by 8 on each side.
p=3

15. Question 19
Solve for r: 5 + 7r + 3r = 8(r – 4) Multiple Step Equation
5 + 7r + 3r = 8(r – 4) 1) Distribute 8
5 + 7r + 3r = 8r – 32 2) Combine like terms 7r + 3r
5 + 10r = 8r – 32 3) Subtract 8r to each side
5 + 2r = -32 4) Subtract 5 on each side.
2r = -37
r = -37/2

16. Question 20
Solve for n: 3(n -2) + 1 = n + 4 + 2n Multiple Step Equation
3(n – 2) + 1 = n + 4 + 2n 1) Distribute 3
3n – 6 + 1 = n + 4 + 2n 2) Combine like terms
3n – 5 = 3n + 4 3) Subtract 3n on each side
-5 = 4 -5 does not equal 4 so this
equation does not have a
No Solution solution!