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MIDLINE
THEOREM
GRADE 9 MATHEMATICS
®ᵯ
Midline Theorem
The segment that joins the
midpoints of two sides of a triangle
is parallel to the third side and half
as long.
Midline Theorem
Midline is equal to one half of
the base of a triangle.
A
D E
B
C
DE=
𝟏
𝟐
(𝑨𝑩)
1. If DE = 10.5 cm , What is AB?
A
D E
B
C
EXAMPLES!!!
1. If DE = 10.5 cm , What is AB?
Answer: AB = 21 cm
A
D E
B
C
10.5=
𝟏
𝟐
(𝑨𝑩)
EXAMPLES!!!
2. If BC= 32 cm , What is CE?
A
D E
B
C
EXAMPLES!!!
2. If BC= 32 cm , What is CE?
Answer: CE = 16 cm
A
D E
B
C
EXAMPLES!!!
3. If AB = 30 cm, What is DE?
A
D E
B
C
EXAMPLES!!!
3. If AB = 30 cm, What is DE?
A
D E
B
C
DE=
𝟏
𝟐
(𝑨𝑩)
DE=
𝟏
𝟐
(𝟑𝟎)
DE= 15 cm
EXAMPLES!!!
4. DE= (3x – 2) cm and AB = (9x – 13) cm,
solve for x.
A
D E
B
C
EXAMPLES!!!
4. DE= (3x – 2) cm and AB
= (9x – 13) cm, solve for x.
A
D E
B
C
DE=
𝟏
𝟐
(𝑨𝑩)
3x – 2 =
𝟏
𝟐
(𝟗𝒙 − 𝟏𝟑)
6x – 4 = 𝟗𝒙 − 𝟏𝟑
6x – 9x = −𝟏𝟑 + 𝟒
– 3x = −𝟗
x = 𝟑
EXAMPLES!!!
4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x.
x = 𝟑
AB = (9x – 13) cm
DE= (3x – 2) cm
4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x.
DE = 3x – 2
x = 𝟑
DE = 3(3) – 2
DE = 7 cm
AB = (9x – 13) cm
AB = 9x – 13
AB = 9(3) – 13
AB = 14 cm
DE= (3x – 2) cm
“Alldreamsarewithin reach.All youhave to dois
keep movingtowardsthem”.
-Viola Davis-

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MIDLINE THEOREM.pptx

  • 2. Midline Theorem The segment that joins the midpoints of two sides of a triangle is parallel to the third side and half as long.
  • 3. Midline Theorem Midline is equal to one half of the base of a triangle. A D E B C DE= 𝟏 𝟐 (𝑨𝑩)
  • 4. 1. If DE = 10.5 cm , What is AB? A D E B C EXAMPLES!!!
  • 5. 1. If DE = 10.5 cm , What is AB? Answer: AB = 21 cm A D E B C 10.5= 𝟏 𝟐 (𝑨𝑩) EXAMPLES!!!
  • 6. 2. If BC= 32 cm , What is CE? A D E B C EXAMPLES!!!
  • 7. 2. If BC= 32 cm , What is CE? Answer: CE = 16 cm A D E B C EXAMPLES!!!
  • 8. 3. If AB = 30 cm, What is DE? A D E B C EXAMPLES!!!
  • 9. 3. If AB = 30 cm, What is DE? A D E B C DE= 𝟏 𝟐 (𝑨𝑩) DE= 𝟏 𝟐 (𝟑𝟎) DE= 15 cm EXAMPLES!!!
  • 10. 4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x. A D E B C EXAMPLES!!!
  • 11. 4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x. A D E B C DE= 𝟏 𝟐 (𝑨𝑩) 3x – 2 = 𝟏 𝟐 (𝟗𝒙 − 𝟏𝟑) 6x – 4 = 𝟗𝒙 − 𝟏𝟑 6x – 9x = −𝟏𝟑 + 𝟒 – 3x = −𝟗 x = 𝟑 EXAMPLES!!!
  • 12. 4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x. x = 𝟑 AB = (9x – 13) cm DE= (3x – 2) cm
  • 13. 4. DE= (3x – 2) cm and AB = (9x – 13) cm, solve for x. DE = 3x – 2 x = 𝟑 DE = 3(3) – 2 DE = 7 cm AB = (9x – 13) cm AB = 9x – 13 AB = 9(3) – 13 AB = 14 cm DE= (3x – 2) cm
  • 14. “Alldreamsarewithin reach.All youhave to dois keep movingtowardsthem”. -Viola Davis-