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              Chapter 6
              Solutions




Denniston
Topping
Caret
7th Edition
6.1 Properties of Solutions
• Solution - homogeneous mixture
• Solute - the substance in the mixture present
  in lesser quantity
• Solvent - the substance present in the largest
  quantity
• Aqueous solution - solution where the
  solvent is water
• Solutions can be liquids as well as solids and
  gases
6.1 Properties of Solutions          Examples of Solutions

                              • Air - oxygen and several trace gases are
                                dissolved in the gaseous solvent, nitrogen
                              • Alloys - brass and other homogeneous
                                metal mixtures in the solid state
                              • Focus on liquid solutions as many important
                                chemical reactions take place in liquid
                                solutions
6.1 Properties of Solutions      General Properties of Liquid
                                          Solutions
                              • Clear, transparent, no visible particles
                              • May have color
                              • Electrolytes are formed from solutes that are
                                soluble ionic compounds
                              • Nonelectrolytes do not dissociate
                                  NaCl(s ) H→ Na + (aq ) + Cl- (aq )
                                            2O



                              • Volumes of solute and solvent are not additive
                                 – 1 L ethanol + 1 L water does not give 2 L of solution
6.1 Properties of Solutions
                                  Solutions and Colloids
                              • Colloidal suspension - contains solute
                                particles which are not uniformly
                                distributed
                                – Due to larger size of particles (1nm - 200 nm)
                                – Appears identical to solution from the
                                  naked eye
                                – Smaller than 1 nm, have solution
                                – Larger than 1 nm, have a precipitate
6.1 Properties of Solutions              Degree of Solubility
                              • Solubility - how much of a particular solute can
                                dissolve in a certain solvent at a specified
                                temperature
                              • Factors which affect solubility:
                                 1 Polarity of solute and solvent
                                    • The more different they are, the lower the solubility
                                 2 Temperature
                                    • Increase in temperature usually increases solubility
                                 3 Pressure
                                    • Usually has no effect
                                    • If solubility is of gas in liquid, directly proportional
                                      to applied pressure
6.1 Properties of Solutions                        Saturation
                              • Saturated solution - a solution that contains all the
                                solute that can be dissolved at a particular
                                temperature
                              • Supersaturated solution - contains more solute
                                than can be dissolved at the current temperature
                              • How is this done?
                                 • Heat solvent, saturate it with solute then cool slowly
                                 • Sometimes the excess will precipitate out
                                 • If it doesn’t precipitate, the solution will be
                                   supersaturated
6.1 Properties of Solutions        Solubility and Equilibrium
                              • If excess solute is added to a solvent, some
                                dissolves
                              • At first, rate of dissolution is large
                              • Later, reverse reaction – precipitation – occurs
                                more quickly
                              • When equilibrium is reached the rates of
                                dissolution and precipitation are equal, there is
                                some dissolved and some undissolved solute
                              • A saturated solution is an example of a dynamic
                                equilibrium
6.1 Properties of Solutions   Solubility of Gases: Henry’s Law
                              • Henry’s law – the number of moles of a gas
                                dissolved in a liquid at a given temperature is
                                proportional to the partial pressure of the gas
                                above the liquid
                              • Gas solubility in a liquid is directly proportional to
                                the pressure of the gas in the atmosphere in
                                contact with the liquid
                              • Gases are most soluble at low temperatures
                              • Solubility decreases significantly at higher
                                temperatures
                                 – Carbonated beverages – CO2 solubility less when warm
                                 – Respiration – facilitates O2 and CO2 exchange in lungs
6.2 Concentration Based on Mass
                                                 6
• Concentration - amount of solute dissolved
  in a given amount of solution
• Concentration of a solution has an effect on
  – Physical properties
     • Melting and boiling points
  – Chemical properties
     • Solution reactivity
6.2 Concentration Based on
                                  Weight/Volume Percent
                             • Amount of solute = mass of solute in grams
                             • Amount of solution = volume in milliliters
                                                   amount of solute
                                  concentration =
          Mass



                                                  amount of solution
                             • Express concentration as a percentage by
                               multiplying ratio by 100% = weight/volume
                               percent or % (W/V)
                                   W   grams of solute
                                 %   =                       ×100%
                                   V milliliters of solution
6.2 Concentration Based on    Calculating Weight/Volume
                                        Percent
                             Calculate the percent composition or % (W/V) of
                             2.00 x 102 mL containing 20.0 g sodium chloride
                                20.0 g NaCl, mass of solute
          Mass



                                2.00 x 102 mL, total volume of solution

                             % (W/V) = 20.0g NaCl / 2.00 x 102 mL x 100%

                                       = 10.0% (W/V) sodium chloride
Calculate Weight of Solute from
6.2 Concentration Based on
                           Weight/Volume Percent
                             Calculate the number of grams of glucose in
                             7.50 x 102 mL of a 15.0% solution
          Mass


                                          W   grams of solute
                                      %     =                       × 100%
                                          V milliliters of solution

                             15.0% (W/V) = Xg glucose/7.50 x 102 mL x 100%
                             Xg glucose x 100% = (15.0% W/V)(7.50 x 102 mL)
                             Xg glucose = 113 g glucose
6.2 Concentration Based on       Weight/Weight Percent
                                    W   grams solute
                                  %   =               ×100%
                                    W grams solutions
                             • Weight/weight percent is most useful for
          Mass


                               solutions of 2 solids whose masses are
                               easily obtained
                             • Calculate % (W/W) of platinum in gold
                               ring with 14.00 g Au and 4.500 g Pt
                               [4.500 g Pt / (4.500 g Pt + 14.00 g Au)] x 100%
                               = 4.500 g / 18.50 g x 100% = 24.32% Pt
6.3 Concentration of Solutions:
      Moles and Equivalents
• Chemical equations represent the relative
  number of moles of reactants producing
  products
• Many chemical reactions occur in solution
  where it is most useful to represent
  concentrations on a molar basis
6.3 Moles and Equivalents                  Molarity
                            • The most common mole-based
                              concentration unit is molarity
                            • Molarity
                              – Symbolized M
                              – Defined as the number of moles of solute per
                                liter of solution

                                       moles solute
                                    M=
                                        L solution
6.3 Moles and Equivalents   Calculating Molarity from Moles
                             • Calculate the molarity of 2.0 L of
                               solution containing 5.0 mol NaOH
                             • Use the equation              moles solute
                                                        M=
                                                              L solution
                             • Substitute into the equation:
                                  MNaOH = 5.0 mol solute
                                            2.0 L solution
                                          = 2.5 M
6.3 Moles and Equivalents   Calculating Molarity From Mass
                            • If 5.00 g glucose are dissolved in 1.00 x 102 mL of
                              solution, calculate molarity, M, of the glucose solution
                            • Convert from g glucose to moles glucose
                               – Molar mass of glucose = 1.80 x 102 g/mol
                               5.00 g x 1 mol / 1.80 x 102 g     = 2.78 x 10-2 mol glucose
                               – Convert volume from mL to L
                               1.00 x 102 mL x 1 L / 103 mL = 1.00 x 10-1 L
                            • Substitute into the equation:
                                                                         moles solute
                                                                      M=
                                                                          L solution
                                   Mglucose = 2.78 x 10-2 mol glucose
                                                   1.00 x 10-1 L solution
                                              = 2.78 x 10-1 M
6.3 Moles and Equivalents                     Dilution
                              Dilution is required to prepare a less
                              concentrated solution from a more
                              concentrated one
                                – M1 = molarity of solution before dilution
                                – M2 = molarity of solution after dilution
                                – V1 = volume of solution before dilution
                                – V2 = volume of solution after dilution

                               moles solute
                            M=                    moles solute = (M)(L solution)
                                L solution
6.3 Moles and Equivalents                     Dilution
                            • In a dilution will the
                              number of moles of solute
                              change?
                              – No, only fewer per unit
                                volume
                            • So, M1V1 = M2V2
                            • Knowing any three terms
                              permits calculation of the
                              fourth
6.3 Moles and Equivalents            Calculating Molarity
                                        After Dilution
                            • Calculate the molarity of a solution made by
                              diluting 0.050 L of 0.10 M HCl solution to a
                              volume of 1.0 L
                               –   M1 = 0.10 M molarity of solution before dilution
                               –   M2 = X M molarity of solution after dilution
                               –   V1 = 0.050 L volume of solution before dilution
                               –   V2 = 1.0 L volume of solution after dilution

                            • Use dilution expression                  M1V1 = M2V2
                            • X M = (0.10 M) (0.050 L) / (1.0 L)
                               0.0050 M HCl         OR   5.0 x 10-3 M HCl
6.3 Moles and Equivalents   Representation of Concentration
                                  of Ions in Solution
                            Two common ways of expressing
                              concentration of ions in solution:
                              1. Moles per liter (molarity)
                                 • Molarity emphasizes the number of
                                   individual ions

                              2. Equivalents per liter (eq/L)
                                 • Emphasis on charge
6.3 Moles and Equivalents      Comparison of Molarity and
                                     Equivalents
                                                  1 M Na3PO4

                            • What would the concentration of PO43- ions be?
                            • 1M
                            • Equivalent is defined by the charge
                            • One Equivalent of an ion is the number of grams
                              of the ion corresponding to Avogadro’s number of
                              electrical charges
                                                             molar mass of ion (g)
                                One equivalent of an ion =
                                                           number of charges on ion
6.3 Moles and Equivalents   Molarity vs. Equivalents – 1 M Na3PO4
                             • 1 mol Na+ = 1 equivalent Na+
                             • 1 mol PO43- = 3 equivalents PO43-
                             • Equivalents of Na+?
                               – 3 mol Na+ = 3 equivalents of Na+

                             • Equivalents of PO43-?
                               – 1 mol PO43- = 3 equivalents of PO43-
6.3 Moles and Equivalents     Calculating Ion Concentration
                            • Calculate eq/L of phosphate ion, PO43- in a
                              solution with 5.0 x 10-3 M phosphate
                            • Need to use two conversion factors:
                               – mol PO43-      mol charge
                               – mol charge         eq PO43
                            5.0 x 10-3 mol PO43- x 3 mol charge x 1 eq
                                   1L                 1 mol PO43- 1mol charge

                            • 1.5 x 10-2 eq PO43- /L
6.4 Concentration-Dependent
              Solution Properties
•    Colligative properties - properties of
     solutions that depend on the concentration
     of the solute particles, rather than the
     identity of the solute
•    Four colligative properties of solutions
    1.   vapor pressure lowering
    2.   boiling point elevation
    3.   freezing point depression
    4.   osmotic pressure
6.4 Concentration-Dependent       Vapor Pressure of a Liquid
                              Consider Raoult’s law in molecular
     Solution Properties
                                terms
                              • Vapor pressure of a solution
                                results from escape of solvent
                                molecules from liquid to gas
                                phase
                              • Partial pressure of gas phase
                                solvent molecules increases
                                until equilibrium vapor
                                pressure is reached
                              • Presence of solute molecules
                                hinders escape of solvent
                                molecules, lowering
                                equilibrium vapor pressure
6.4 Concentration-Dependent       Vapor Pressure Lowering
                              • Raoult’s law - when a nonvolatile solute is
     Solution Properties
                                added to a solvent, vapor pressure of the solvent
                                decreases in proportion to the concentration of
                                the solute
                              • Solute molecules (red below) serve as a barrier to
                                the escape of solvent molecules resulting in a
                                decrease in the vapor pressure
6.4 Concentration-Dependent   Freezing Point Depression and
     Solution Properties         Boiling Point Elevation
                              • Freezing point depression may be explained
                                considering the equilibrium between solid and
                                liquid states
                                 – Solute molecules interfere with the rate at which
                                   liquid water molecules associate to form the solid
                                   state
                              • Boiling point elevation can be explained
                                considering the definition as the temperature at
                                which vapor pressure of the liquid equals the
                                atmospheric pressure
                                 – If a solute is present, then the increase in boiling
                                   temperature is necessary to raise the vapor pressure
                                   to atmospheric temperature
6.4 Concentration-Dependent     Freezing Point Depression
                              • Freezing point depression (∆Tf) - is proportional
     Solution Properties
                                to the number of solute particles
                                 – Solute particles, not just solute
                              • How does an electrolyte behave?
                                 – Dissociate into ions
                              • An equal concentration of NaCl will affect the
                                freezing point twice as much as glucose (a
                                nonelectrolyte)
                              • Each solvent has a unique freezing point
                                depression constant or proportionality factor


                                                                  ∆Tf=kf m
6.4 Concentration-Dependent        Boiling point elevation
                              • Boiling point elevation (∆Tb) - is
     Solution Properties
                                proportional to the number of solute
                                particles
                              • An electrolyte will affect boiling point to
                                a greater degree than a nonelectrolyte of
                                the same concentration
                              • Each solvent has a unique boiling point
                                elevation constant

                                                            ∆Tb=kb m
6.4 Concentration-Dependent            Osmotic Pressure
                              • Some types of membranes appear impervious
     Solution Properties
                                to matter, but actually have a network of small
                                holes called pores
                              • These pores may be large enough to permit
                                small solvent molecules to move from one side
                                of the membrane to the other
                              • Solute molecules cannot cross the membrane as
                                they are too large
                              • Semipermeable membrane - allows
                                solvent but not solute to diffuse from one side
                                to another
6.4 Concentration-Dependent
                                  Osmotic Pressure
                              • Osmosis - the
     Solution Properties
                                movement of
                                solvent from a
                                dilute solution to a
                                more concentrated
                                solution through a
                                semipermeable
                                membrane
                              • Requires pressure
                                to stop this flow
6.4 Concentration-Dependent          Osmotic Pressure
     Solution Properties
                              • Osmotic pressure (π) - the amount of
                                pressure required to stop the flow across
                                a semipermeable membrane
                                            π=MRT
                              • Osmolarity - the molarity of particles in
                                solution
                                – Osmol, used for osmotic pressure
                                  calculation
6.4 Concentration-Dependent            Tonicity and the Cell
                              • Living cells contain aqueous solution and these cells
     Solution Properties
                                are also surrounded by aqueous solution
                              • Cell function requires maintenance of the same osmotic
                                pressure inside and outside the cell
                              • Solute concentration of fluid surrounding cells higher
                                than inside results in a hypertonic solution causing
                                water to flow into the surroundings, causing collapse =
                                crenation
                              • Solute concentration of fluid surrounding cells too low,
                                results in a hypotonic solution causing water to flow
                                into the cell, causing rupture = hemolysis
                              • Isotonic solutions have identical osmotic pressures and
                                no osmotic pressure difference across the cell
                                membrane
6.4 Concentration-Dependent      Tonicity and the Cell
     Solution Properties

                              Crenation   Hemolysis   Isotonic
6.4 Concentration-Dependent   Pickling Cucumber in Hypertonic
     Solution Properties            Brine Due to Osmosis
6.5 Water as a Solvent
• Water is often referred to as the “universal
  solvent”
• Excellent solvent for polar molecules
• Most abundant liquid on earth
• 60% of the human body is water
  – transports ions, nutrients, and waste into and out of
    cells
  – solvent for biochemical reactions in cells and
    digestive tract
  – reactant or product in some biochemical processes

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Mec chapter 6

  • 1. Copyright© The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chapter 6 Solutions Denniston Topping Caret 7th Edition
  • 2. 6.1 Properties of Solutions • Solution - homogeneous mixture • Solute - the substance in the mixture present in lesser quantity • Solvent - the substance present in the largest quantity • Aqueous solution - solution where the solvent is water • Solutions can be liquids as well as solids and gases
  • 3. 6.1 Properties of Solutions Examples of Solutions • Air - oxygen and several trace gases are dissolved in the gaseous solvent, nitrogen • Alloys - brass and other homogeneous metal mixtures in the solid state • Focus on liquid solutions as many important chemical reactions take place in liquid solutions
  • 4. 6.1 Properties of Solutions General Properties of Liquid Solutions • Clear, transparent, no visible particles • May have color • Electrolytes are formed from solutes that are soluble ionic compounds • Nonelectrolytes do not dissociate NaCl(s ) H→ Na + (aq ) + Cl- (aq ) 2O • Volumes of solute and solvent are not additive – 1 L ethanol + 1 L water does not give 2 L of solution
  • 5. 6.1 Properties of Solutions Solutions and Colloids • Colloidal suspension - contains solute particles which are not uniformly distributed – Due to larger size of particles (1nm - 200 nm) – Appears identical to solution from the naked eye – Smaller than 1 nm, have solution – Larger than 1 nm, have a precipitate
  • 6. 6.1 Properties of Solutions Degree of Solubility • Solubility - how much of a particular solute can dissolve in a certain solvent at a specified temperature • Factors which affect solubility: 1 Polarity of solute and solvent • The more different they are, the lower the solubility 2 Temperature • Increase in temperature usually increases solubility 3 Pressure • Usually has no effect • If solubility is of gas in liquid, directly proportional to applied pressure
  • 7. 6.1 Properties of Solutions Saturation • Saturated solution - a solution that contains all the solute that can be dissolved at a particular temperature • Supersaturated solution - contains more solute than can be dissolved at the current temperature • How is this done? • Heat solvent, saturate it with solute then cool slowly • Sometimes the excess will precipitate out • If it doesn’t precipitate, the solution will be supersaturated
  • 8. 6.1 Properties of Solutions Solubility and Equilibrium • If excess solute is added to a solvent, some dissolves • At first, rate of dissolution is large • Later, reverse reaction – precipitation – occurs more quickly • When equilibrium is reached the rates of dissolution and precipitation are equal, there is some dissolved and some undissolved solute • A saturated solution is an example of a dynamic equilibrium
  • 9. 6.1 Properties of Solutions Solubility of Gases: Henry’s Law • Henry’s law – the number of moles of a gas dissolved in a liquid at a given temperature is proportional to the partial pressure of the gas above the liquid • Gas solubility in a liquid is directly proportional to the pressure of the gas in the atmosphere in contact with the liquid • Gases are most soluble at low temperatures • Solubility decreases significantly at higher temperatures – Carbonated beverages – CO2 solubility less when warm – Respiration – facilitates O2 and CO2 exchange in lungs
  • 10. 6.2 Concentration Based on Mass 6 • Concentration - amount of solute dissolved in a given amount of solution • Concentration of a solution has an effect on – Physical properties • Melting and boiling points – Chemical properties • Solution reactivity
  • 11. 6.2 Concentration Based on Weight/Volume Percent • Amount of solute = mass of solute in grams • Amount of solution = volume in milliliters amount of solute concentration = Mass amount of solution • Express concentration as a percentage by multiplying ratio by 100% = weight/volume percent or % (W/V) W grams of solute % = ×100% V milliliters of solution
  • 12. 6.2 Concentration Based on Calculating Weight/Volume Percent Calculate the percent composition or % (W/V) of 2.00 x 102 mL containing 20.0 g sodium chloride 20.0 g NaCl, mass of solute Mass 2.00 x 102 mL, total volume of solution % (W/V) = 20.0g NaCl / 2.00 x 102 mL x 100% = 10.0% (W/V) sodium chloride
  • 13. Calculate Weight of Solute from 6.2 Concentration Based on Weight/Volume Percent Calculate the number of grams of glucose in 7.50 x 102 mL of a 15.0% solution Mass W grams of solute % = × 100% V milliliters of solution 15.0% (W/V) = Xg glucose/7.50 x 102 mL x 100% Xg glucose x 100% = (15.0% W/V)(7.50 x 102 mL) Xg glucose = 113 g glucose
  • 14. 6.2 Concentration Based on Weight/Weight Percent W grams solute % = ×100% W grams solutions • Weight/weight percent is most useful for Mass solutions of 2 solids whose masses are easily obtained • Calculate % (W/W) of platinum in gold ring with 14.00 g Au and 4.500 g Pt [4.500 g Pt / (4.500 g Pt + 14.00 g Au)] x 100% = 4.500 g / 18.50 g x 100% = 24.32% Pt
  • 15. 6.3 Concentration of Solutions: Moles and Equivalents • Chemical equations represent the relative number of moles of reactants producing products • Many chemical reactions occur in solution where it is most useful to represent concentrations on a molar basis
  • 16. 6.3 Moles and Equivalents Molarity • The most common mole-based concentration unit is molarity • Molarity – Symbolized M – Defined as the number of moles of solute per liter of solution moles solute M= L solution
  • 17. 6.3 Moles and Equivalents Calculating Molarity from Moles • Calculate the molarity of 2.0 L of solution containing 5.0 mol NaOH • Use the equation moles solute M= L solution • Substitute into the equation: MNaOH = 5.0 mol solute 2.0 L solution = 2.5 M
  • 18. 6.3 Moles and Equivalents Calculating Molarity From Mass • If 5.00 g glucose are dissolved in 1.00 x 102 mL of solution, calculate molarity, M, of the glucose solution • Convert from g glucose to moles glucose – Molar mass of glucose = 1.80 x 102 g/mol 5.00 g x 1 mol / 1.80 x 102 g = 2.78 x 10-2 mol glucose – Convert volume from mL to L 1.00 x 102 mL x 1 L / 103 mL = 1.00 x 10-1 L • Substitute into the equation: moles solute M= L solution Mglucose = 2.78 x 10-2 mol glucose 1.00 x 10-1 L solution = 2.78 x 10-1 M
  • 19. 6.3 Moles and Equivalents Dilution Dilution is required to prepare a less concentrated solution from a more concentrated one – M1 = molarity of solution before dilution – M2 = molarity of solution after dilution – V1 = volume of solution before dilution – V2 = volume of solution after dilution moles solute M= moles solute = (M)(L solution) L solution
  • 20. 6.3 Moles and Equivalents Dilution • In a dilution will the number of moles of solute change? – No, only fewer per unit volume • So, M1V1 = M2V2 • Knowing any three terms permits calculation of the fourth
  • 21. 6.3 Moles and Equivalents Calculating Molarity After Dilution • Calculate the molarity of a solution made by diluting 0.050 L of 0.10 M HCl solution to a volume of 1.0 L – M1 = 0.10 M molarity of solution before dilution – M2 = X M molarity of solution after dilution – V1 = 0.050 L volume of solution before dilution – V2 = 1.0 L volume of solution after dilution • Use dilution expression M1V1 = M2V2 • X M = (0.10 M) (0.050 L) / (1.0 L) 0.0050 M HCl OR 5.0 x 10-3 M HCl
  • 22. 6.3 Moles and Equivalents Representation of Concentration of Ions in Solution Two common ways of expressing concentration of ions in solution: 1. Moles per liter (molarity) • Molarity emphasizes the number of individual ions 2. Equivalents per liter (eq/L) • Emphasis on charge
  • 23. 6.3 Moles and Equivalents Comparison of Molarity and Equivalents 1 M Na3PO4 • What would the concentration of PO43- ions be? • 1M • Equivalent is defined by the charge • One Equivalent of an ion is the number of grams of the ion corresponding to Avogadro’s number of electrical charges molar mass of ion (g) One equivalent of an ion = number of charges on ion
  • 24. 6.3 Moles and Equivalents Molarity vs. Equivalents – 1 M Na3PO4 • 1 mol Na+ = 1 equivalent Na+ • 1 mol PO43- = 3 equivalents PO43- • Equivalents of Na+? – 3 mol Na+ = 3 equivalents of Na+ • Equivalents of PO43-? – 1 mol PO43- = 3 equivalents of PO43-
  • 25. 6.3 Moles and Equivalents Calculating Ion Concentration • Calculate eq/L of phosphate ion, PO43- in a solution with 5.0 x 10-3 M phosphate • Need to use two conversion factors: – mol PO43- mol charge – mol charge eq PO43 5.0 x 10-3 mol PO43- x 3 mol charge x 1 eq 1L 1 mol PO43- 1mol charge • 1.5 x 10-2 eq PO43- /L
  • 26. 6.4 Concentration-Dependent Solution Properties • Colligative properties - properties of solutions that depend on the concentration of the solute particles, rather than the identity of the solute • Four colligative properties of solutions 1. vapor pressure lowering 2. boiling point elevation 3. freezing point depression 4. osmotic pressure
  • 27. 6.4 Concentration-Dependent Vapor Pressure of a Liquid Consider Raoult’s law in molecular Solution Properties terms • Vapor pressure of a solution results from escape of solvent molecules from liquid to gas phase • Partial pressure of gas phase solvent molecules increases until equilibrium vapor pressure is reached • Presence of solute molecules hinders escape of solvent molecules, lowering equilibrium vapor pressure
  • 28. 6.4 Concentration-Dependent Vapor Pressure Lowering • Raoult’s law - when a nonvolatile solute is Solution Properties added to a solvent, vapor pressure of the solvent decreases in proportion to the concentration of the solute • Solute molecules (red below) serve as a barrier to the escape of solvent molecules resulting in a decrease in the vapor pressure
  • 29. 6.4 Concentration-Dependent Freezing Point Depression and Solution Properties Boiling Point Elevation • Freezing point depression may be explained considering the equilibrium between solid and liquid states – Solute molecules interfere with the rate at which liquid water molecules associate to form the solid state • Boiling point elevation can be explained considering the definition as the temperature at which vapor pressure of the liquid equals the atmospheric pressure – If a solute is present, then the increase in boiling temperature is necessary to raise the vapor pressure to atmospheric temperature
  • 30. 6.4 Concentration-Dependent Freezing Point Depression • Freezing point depression (∆Tf) - is proportional Solution Properties to the number of solute particles – Solute particles, not just solute • How does an electrolyte behave? – Dissociate into ions • An equal concentration of NaCl will affect the freezing point twice as much as glucose (a nonelectrolyte) • Each solvent has a unique freezing point depression constant or proportionality factor ∆Tf=kf m
  • 31. 6.4 Concentration-Dependent Boiling point elevation • Boiling point elevation (∆Tb) - is Solution Properties proportional to the number of solute particles • An electrolyte will affect boiling point to a greater degree than a nonelectrolyte of the same concentration • Each solvent has a unique boiling point elevation constant ∆Tb=kb m
  • 32. 6.4 Concentration-Dependent Osmotic Pressure • Some types of membranes appear impervious Solution Properties to matter, but actually have a network of small holes called pores • These pores may be large enough to permit small solvent molecules to move from one side of the membrane to the other • Solute molecules cannot cross the membrane as they are too large • Semipermeable membrane - allows solvent but not solute to diffuse from one side to another
  • 33. 6.4 Concentration-Dependent Osmotic Pressure • Osmosis - the Solution Properties movement of solvent from a dilute solution to a more concentrated solution through a semipermeable membrane • Requires pressure to stop this flow
  • 34. 6.4 Concentration-Dependent Osmotic Pressure Solution Properties • Osmotic pressure (π) - the amount of pressure required to stop the flow across a semipermeable membrane π=MRT • Osmolarity - the molarity of particles in solution – Osmol, used for osmotic pressure calculation
  • 35. 6.4 Concentration-Dependent Tonicity and the Cell • Living cells contain aqueous solution and these cells Solution Properties are also surrounded by aqueous solution • Cell function requires maintenance of the same osmotic pressure inside and outside the cell • Solute concentration of fluid surrounding cells higher than inside results in a hypertonic solution causing water to flow into the surroundings, causing collapse = crenation • Solute concentration of fluid surrounding cells too low, results in a hypotonic solution causing water to flow into the cell, causing rupture = hemolysis • Isotonic solutions have identical osmotic pressures and no osmotic pressure difference across the cell membrane
  • 36. 6.4 Concentration-Dependent Tonicity and the Cell Solution Properties Crenation Hemolysis Isotonic
  • 37. 6.4 Concentration-Dependent Pickling Cucumber in Hypertonic Solution Properties Brine Due to Osmosis
  • 38. 6.5 Water as a Solvent • Water is often referred to as the “universal solvent” • Excellent solvent for polar molecules • Most abundant liquid on earth • 60% of the human body is water – transports ions, nutrients, and waste into and out of cells – solvent for biochemical reactions in cells and digestive tract – reactant or product in some biochemical processes