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Chapter 6
Solutions
Denniston
Topping
Caret
7th
Edition
Copyright© The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
6.1 Properties of Solutions
• Solution - homogeneous mixture
• Solute - the substance in the mixture present
in lesser quantity
• Solvent - the substance present in the largest
quantity
• Aqueous solution - solution where the
solvent is water
• Solutions can be liquids as well as solids and
gases
Examples of Solutions
• Air - oxygen and several trace gases are
dissolved in the gaseous solvent, nitrogen
• Alloys - brass and other homogeneous
metal mixtures in the solid state
• Focus on liquid solutions as many important
chemical reactions take place in liquid
solutions
6.1PropertiesofSolutions
• Clear, transparent, no visible particles
• May have color
• Electrolytes are formed from solutes that are
soluble ionic compounds
• Nonelectrolytes do not dissociate
• Volumes of solute and solvent are not additive
– 1 L ethanol + 1 L water does not give 2 L of solution
6.1PropertiesofSolutions
)(-Cl)(Na)NaCl( OH2
aqaqs +→ +
General Properties of Liquid
Solutions
6.1PropertiesofSolutions
Solutions and Colloids
• Colloidal suspension - contains solute
particles which are not uniformly
distributed
– Due to larger size of particles (1nm - 200 nm)
– Appears identical to solution from the
naked eye
– Smaller than 1 nm, have solution
– Larger than 1 nm, have a precipitate
6.1PropertiesofSolutions Degree of Solubility
• Solubility - how much of a particular solute can
dissolve in a certain solvent at a specified
temperature
• Factors which affect solubility:
1 Polarity of solute and solvent
• The more different they are, the lower the solubility
2 Temperature
• Increase in temperature usually increases solubility
3 Pressure
• Usually has no effect
• If solubility is of gas in liquid, directly proportional
to applied pressure
6.1PropertiesofSolutions Saturation
• Saturated solution - a solution that contains all the
solute that can be dissolved at a particular
temperature
• Supersaturated solution - contains more solute
than can be dissolved at the current temperature
• How is this done?
• Heat solvent, saturate it with solute then cool slowly
• Sometimes the excess will precipitate out
• If it doesn’t precipitate, the solution will be
supersaturated
6.1PropertiesofSolutions Solubility and Equilibrium
• If excess solute is added to a solvent, some
dissolves
• At first, rate of dissolution is large
• Later, reverse reaction – precipitation – occurs
more quickly
• When equilibrium is reached the rates of
dissolution and precipitation are equal, there is
some dissolved and some undissolved solute
• A saturated solution is an example of a dynamic
equilibrium
6.1PropertiesofSolutions Solubility of Gases: Henry’s Law
• Henry’s law – the number of moles of a gas
dissolved in a liquid at a given temperature is
proportional to the partial pressure of the gas
above the liquid
• Gas solubility in a liquid is directly proportional to
the pressure of the gas in the atmosphere in
contact with the liquid
• Gases are most soluble at low temperatures
• Solubility decreases significantly at higher
temperatures
– Carbonated beverages – CO2 solubility less when warm
– Respiration – facilitates O2 and CO2 exchange in lungs
6.2 Concentration Based on Mass
• Concentration - amount of solute dissolved
in a given amount of solution
• Concentration of a solution has an effect on
– Physical properties
• Melting and boiling points
– Chemical properties
• Solution reactivity
6
• Amount of solute = mass of solute in grams
• Amount of solution = volume in milliliters
• Express concentration as a percentage by
multiplying ratio by 100% = weight/volume
percent or % (W/V)
%100
solutionofsmilliliter
soluteofgrams
V
W
% ×=
solutionofamount
soluteofamount
ionconcentrat =
Weight/Volume Percent
6.2ConcentrationBasedon
Mass
6.2ConcentrationBasedon
Mass
Calculating Weight/Volume
Percent
Calculate the percent composition or % (W/V) of
2.00 x 102
mL containing 20.0 g sodium chloride
20.0 g NaCl, mass of solute
2.00 x 102
mL, total volume of solution
% (W/V) = 20.0g NaCl / 2.00 x 102
mL x 100%
= 10.0% (W/V) sodium chloride
6.2ConcentrationBasedon
Mass
Calculate Weight of Solute from
Weight/Volume Percent
Calculate the number of grams of glucose in
7.50 x 102
mL of a 15.0% solution
15.0% (W/V) = Xg glucose/7.50 x 102
mL x 100%
Xg glucose x 100% = (15.0% W/V)(7.50 x 102
mL)
Xg glucose = 113 g glucose
%100
solutionofsmilliliter
soluteofgrams
V
W
% ×=
%100
solutionsgrams
solutegrams
W
W
% ×=
6.2ConcentrationBasedon
Mass
Weight/Weight Percent
• Weight/weight percent is most useful for
solutions of 2 solids whose masses are
easily obtained
• Calculate % (W/W) of platinum in gold
ring with 14.00 g Au and 4.500 g Pt
[4.500 g Pt / (4.500 g Pt + 14.00 g Au)] x 100%
= 4.500 g / 18.50 g x 100% = 24.32% Pt
6.3 Concentration of Solutions:
Moles and Equivalents
• Chemical equations represent the relative
number of moles of reactants producing
products
• Many chemical reactions occur in solution
where it is most useful to represent
concentrations on a molar basis
• The most common mole-based
concentration unit is molarity
• Molarity
– Symbolized M
– Defined as the number of moles of solute per
liter of solution
Molarity6.3MolesandEquivalents
solutionL
solutemoles
=M
• Calculate the molarity of 2.0 L of
solution containing 5.0 mol NaOH
• Use the equation
• Substitute into the equation:
MNaOH = 5.0 mol solute
2.0 L solution
= 2.5 M
Calculating Molarity from Moles6.3MolesandEquivalents
solutionL
solutemoles
=M
• If 5.00 g glucose are dissolved in 1.00 x 102
mL of
solution, calculate molarity, M, of the glucose solution
• Convert from g glucose to moles glucose
– Molar mass of glucose = 1.80 x 102
g/mol
5.00 g x 1 mol / 1.80 x 102
g = 2.78 x 10-2
mol glucose
– Convert volume from mL to L
1.00 x 102
mL x 1 L / 103
mL = 1.00 x 10-1
L
• Substitute into the equation:
Mglucose = 2.78 x 10-2
mol glucose
1.00 x 10-1
L solution
= 2.78 x 10-1
M
Calculating Molarity From Mass6.3MolesandEquivalents
solutionL
solutemoles
=M
solutionL
solutemoles
=M
6.3MolesandEquivalents Dilution
Dilution is required to prepare a less
concentrated solution from a more
concentrated one
– M1 = molarity of solution before dilution
– M2 = molarity of solution after dilution
– V1 = volume of solution before dilution
– V2 = volume of solution after dilution
moles solute = (M)(L solution)
• In a dilution will the
number of moles of solute
change?
– No, only fewer per unit
volume
• So,
• Knowing any three terms
permits calculation of the
fourth
M1V1 = M2V2
6.3MolesandEquivalents Dilution
• Calculate the molarity of a solution made by
diluting 0.050 L of 0.10 M HCl solution to a
volume of 1.0 L
– M1 = 0.10 M molarity of solution before dilution
– M2 = X M molarity of solution after dilution
– V1 = 0.050 L volume of solution before dilution
– V2 = 1.0 L volume of solution after dilution
• Use dilution expression
• X M = (0.10 M) (0.050 L) / (1.0 L)
0.0050 M HCl OR 5.0 x 10-3
M HCl
M1V1 = M2V2
6.3MolesandEquivalents Calculating Molarity
After Dilution
6.3MolesandEquivalents Representation of Concentration
of Ions in Solution
Two common ways of expressing
concentration of ions in solution:
1. Moles per liter (molarity)
• Molarity emphasizes the number of
individual ions
2. Equivalents per liter (eq/L)
• Emphasis on charge
iononchargesofnumber
(g)ionofmassmolar
ionanofequivalentOne =
6.3MolesandEquivalents Comparison of Molarity and
Equivalents
1 M Na3PO4
• What would the concentration of PO4
3-
ions be?
• 1 M
• Equivalent is defined by the charge
• One Equivalent of an ion is the number of grams
of the ion corresponding to Avogadro’s number of
electrical charges
6.3MolesandEquivalents Molarity vs. Equivalents – 1 M Na3PO4
• 1 mol Na+
= 1 equivalent Na+
• 1 mol PO4
3-
= 3 equivalents PO4
3-
• Equivalents of Na+
?
– 3 mol Na+
= 3 equivalents of Na+
• Equivalents of PO4
3-
?
– 1 mol PO4
3-
= 3 equivalents of PO4
3-
6.3MolesandEquivalents Calculating Ion Concentration
• Calculate eq/L of phosphate ion, PO4
3-
in a
solution with 5.0 x 10-3
M phosphate
• Need to use two conversion factors:
– mol PO4
3-
mol charge
– mol charge eq PO4
3
5.0 x 10-3
mol PO4
3-
x 3 mol charge x 1 eq
1 L 1 mol PO4
3-
1mol charge
• 1.5 x 10-2
eq PO4
3-
/L
6.4 Concentration-Dependent
Solution Properties
• Colligative properties - properties of
solutions that depend on the concentration
of the solute particles, rather than the
identity of the solute
• Four colligative properties of solutions
1. vapor pressure lowering
2. boiling point elevation
3. freezing point depression
4. osmotic pressure
Vapor Pressure of a Liquid
Consider Raoult’s law in molecular
terms
• Vapor pressure of a solution
results from escape of solvent
molecules from liquid to gas
phase
• Partial pressure of gas phase
solvent molecules increases
until equilibrium vapor
pressure is reached
• Presence of solute molecules
hinders escape of solvent
molecules, lowering
equilibrium vapor pressure
6.4Concentration-Dependent
SolutionProperties
6.4Concentration-Dependent
SolutionProperties
Vapor Pressure Lowering
• Raoult’s law - when a nonvolatile solute is
added to a solvent, vapor pressure of the solvent
decreases in proportion to the concentration of
the solute
• Solute molecules (red below) serve as a barrier to
the escape of solvent molecules resulting in a
decrease in the vapor pressure
6.4Concentration-Dependent
SolutionProperties
Freezing Point Depression and
Boiling Point Elevation
• Freezing point depression may be explained
considering the equilibrium between solid and
liquid states
– Solute molecules interfere with the rate at which
liquid water molecules associate to form the solid
state
• Boiling point elevation can be explained
considering the definition as the temperature at
which vapor pressure of the liquid equals the
atmospheric pressure
– If a solute is present, then the increase in boiling
temperature is necessary to raise the vapor pressure
to atmospheric temperature
• Freezing point depression (∆Tf) - is proportional
to the number of solute particles
– Solute particles, not just solute
• How does an electrolyte behave?
– Dissociate into ions
• An equal concentration of NaCl will affect the
freezing point twice as much as glucose (a
nonelectrolyte)
• Each solvent has a unique freezing point
depression constant or proportionality factor
∆Tf=kf m
6.4Concentration-Dependent
SolutionProperties
Freezing Point Depression
• Boiling point elevation (∆Tb) - is
proportional to the number of solute
particles
• An electrolyte will affect boiling point to
a greater degree than a nonelectrolyte of
the same concentration
• Each solvent has a unique boiling point
elevation constant
∆Tb=kb m
6.4Concentration-Dependent
SolutionProperties
Boiling point elevation
Osmotic Pressure
• Some types of membranes appear impervious
to matter, but actually have a network of small
holes called pores
• These pores may be large enough to permit
small solvent molecules to move from one side
of the membrane to the other
• Solute molecules cannot cross the membrane as
they are too large
• Semipermeable membrane - allows
solvent but not solute to diffuse from one side
to another
6.4Concentration-Dependent
SolutionProperties
6.4Concentration-Dependent
SolutionProperties
Osmotic Pressure
• Osmosis - the
movement of
solvent from a
dilute solution to a
more concentrated
solution through a
semipermeable
membrane
• Requires pressure
to stop this flow
• Osmotic pressure (π) - the amount of
pressure required to stop the flow across
a semipermeable membrane
• Osmolarity - the molarity of particles in
solution
– Osmol, used for osmotic pressure
calculation
π=MRT
6.4Concentration-Dependent
SolutionProperties
Osmotic Pressure
6.4Concentration-Dependent
SolutionProperties
Tonicity and the Cell
• Living cells contain aqueous solution and these cells
are also surrounded by aqueous solution
• Cell function requires maintenance of the same osmotic
pressure inside and outside the cell
• Solute concentration of fluid surrounding cells higher
than inside results in a hypertonic solution causing
water to flow into the surroundings, causing collapse =
crenation
• Solute concentration of fluid surrounding cells too low,
results in a hypotonic solution causing water to flow
into the cell, causing rupture = hemolysis
• Isotonic solutions have identical osmotic pressures and
no osmotic pressure difference across the cell
membrane
IsotonicHemolysisCrenation
6.4Concentration-Dependent
SolutionProperties
Tonicity and the Cell
Pickling Cucumber in Hypertonic
Brine Due to Osmosis
6.4Concentration-Dependent
SolutionProperties
6.5 Water as a Solvent
• Water is often referred to as the “universal
solvent”
• Excellent solvent for polar molecules
• Most abundant liquid on earth
• 60% of the human body is water
– transports ions, nutrients, and waste into and out of
cells
– solvent for biochemical reactions in cells and
digestive tract
– reactant or product in some biochemical processes

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Mecchapter6 120814200155-phpapp01

  • 1. Chapter 6 Solutions Denniston Topping Caret 7th Edition Copyright© The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
  • 2. 6.1 Properties of Solutions • Solution - homogeneous mixture • Solute - the substance in the mixture present in lesser quantity • Solvent - the substance present in the largest quantity • Aqueous solution - solution where the solvent is water • Solutions can be liquids as well as solids and gases
  • 3. Examples of Solutions • Air - oxygen and several trace gases are dissolved in the gaseous solvent, nitrogen • Alloys - brass and other homogeneous metal mixtures in the solid state • Focus on liquid solutions as many important chemical reactions take place in liquid solutions 6.1PropertiesofSolutions
  • 4. • Clear, transparent, no visible particles • May have color • Electrolytes are formed from solutes that are soluble ionic compounds • Nonelectrolytes do not dissociate • Volumes of solute and solvent are not additive – 1 L ethanol + 1 L water does not give 2 L of solution 6.1PropertiesofSolutions )(-Cl)(Na)NaCl( OH2 aqaqs +→ + General Properties of Liquid Solutions
  • 5. 6.1PropertiesofSolutions Solutions and Colloids • Colloidal suspension - contains solute particles which are not uniformly distributed – Due to larger size of particles (1nm - 200 nm) – Appears identical to solution from the naked eye – Smaller than 1 nm, have solution – Larger than 1 nm, have a precipitate
  • 6. 6.1PropertiesofSolutions Degree of Solubility • Solubility - how much of a particular solute can dissolve in a certain solvent at a specified temperature • Factors which affect solubility: 1 Polarity of solute and solvent • The more different they are, the lower the solubility 2 Temperature • Increase in temperature usually increases solubility 3 Pressure • Usually has no effect • If solubility is of gas in liquid, directly proportional to applied pressure
  • 7. 6.1PropertiesofSolutions Saturation • Saturated solution - a solution that contains all the solute that can be dissolved at a particular temperature • Supersaturated solution - contains more solute than can be dissolved at the current temperature • How is this done? • Heat solvent, saturate it with solute then cool slowly • Sometimes the excess will precipitate out • If it doesn’t precipitate, the solution will be supersaturated
  • 8. 6.1PropertiesofSolutions Solubility and Equilibrium • If excess solute is added to a solvent, some dissolves • At first, rate of dissolution is large • Later, reverse reaction – precipitation – occurs more quickly • When equilibrium is reached the rates of dissolution and precipitation are equal, there is some dissolved and some undissolved solute • A saturated solution is an example of a dynamic equilibrium
  • 9. 6.1PropertiesofSolutions Solubility of Gases: Henry’s Law • Henry’s law – the number of moles of a gas dissolved in a liquid at a given temperature is proportional to the partial pressure of the gas above the liquid • Gas solubility in a liquid is directly proportional to the pressure of the gas in the atmosphere in contact with the liquid • Gases are most soluble at low temperatures • Solubility decreases significantly at higher temperatures – Carbonated beverages – CO2 solubility less when warm – Respiration – facilitates O2 and CO2 exchange in lungs
  • 10. 6.2 Concentration Based on Mass • Concentration - amount of solute dissolved in a given amount of solution • Concentration of a solution has an effect on – Physical properties • Melting and boiling points – Chemical properties • Solution reactivity 6
  • 11. • Amount of solute = mass of solute in grams • Amount of solution = volume in milliliters • Express concentration as a percentage by multiplying ratio by 100% = weight/volume percent or % (W/V) %100 solutionofsmilliliter soluteofgrams V W % ×= solutionofamount soluteofamount ionconcentrat = Weight/Volume Percent 6.2ConcentrationBasedon Mass
  • 12. 6.2ConcentrationBasedon Mass Calculating Weight/Volume Percent Calculate the percent composition or % (W/V) of 2.00 x 102 mL containing 20.0 g sodium chloride 20.0 g NaCl, mass of solute 2.00 x 102 mL, total volume of solution % (W/V) = 20.0g NaCl / 2.00 x 102 mL x 100% = 10.0% (W/V) sodium chloride
  • 13. 6.2ConcentrationBasedon Mass Calculate Weight of Solute from Weight/Volume Percent Calculate the number of grams of glucose in 7.50 x 102 mL of a 15.0% solution 15.0% (W/V) = Xg glucose/7.50 x 102 mL x 100% Xg glucose x 100% = (15.0% W/V)(7.50 x 102 mL) Xg glucose = 113 g glucose %100 solutionofsmilliliter soluteofgrams V W % ×=
  • 14. %100 solutionsgrams solutegrams W W % ×= 6.2ConcentrationBasedon Mass Weight/Weight Percent • Weight/weight percent is most useful for solutions of 2 solids whose masses are easily obtained • Calculate % (W/W) of platinum in gold ring with 14.00 g Au and 4.500 g Pt [4.500 g Pt / (4.500 g Pt + 14.00 g Au)] x 100% = 4.500 g / 18.50 g x 100% = 24.32% Pt
  • 15. 6.3 Concentration of Solutions: Moles and Equivalents • Chemical equations represent the relative number of moles of reactants producing products • Many chemical reactions occur in solution where it is most useful to represent concentrations on a molar basis
  • 16. • The most common mole-based concentration unit is molarity • Molarity – Symbolized M – Defined as the number of moles of solute per liter of solution Molarity6.3MolesandEquivalents solutionL solutemoles =M
  • 17. • Calculate the molarity of 2.0 L of solution containing 5.0 mol NaOH • Use the equation • Substitute into the equation: MNaOH = 5.0 mol solute 2.0 L solution = 2.5 M Calculating Molarity from Moles6.3MolesandEquivalents solutionL solutemoles =M
  • 18. • If 5.00 g glucose are dissolved in 1.00 x 102 mL of solution, calculate molarity, M, of the glucose solution • Convert from g glucose to moles glucose – Molar mass of glucose = 1.80 x 102 g/mol 5.00 g x 1 mol / 1.80 x 102 g = 2.78 x 10-2 mol glucose – Convert volume from mL to L 1.00 x 102 mL x 1 L / 103 mL = 1.00 x 10-1 L • Substitute into the equation: Mglucose = 2.78 x 10-2 mol glucose 1.00 x 10-1 L solution = 2.78 x 10-1 M Calculating Molarity From Mass6.3MolesandEquivalents solutionL solutemoles =M
  • 19. solutionL solutemoles =M 6.3MolesandEquivalents Dilution Dilution is required to prepare a less concentrated solution from a more concentrated one – M1 = molarity of solution before dilution – M2 = molarity of solution after dilution – V1 = volume of solution before dilution – V2 = volume of solution after dilution moles solute = (M)(L solution)
  • 20. • In a dilution will the number of moles of solute change? – No, only fewer per unit volume • So, • Knowing any three terms permits calculation of the fourth M1V1 = M2V2 6.3MolesandEquivalents Dilution
  • 21. • Calculate the molarity of a solution made by diluting 0.050 L of 0.10 M HCl solution to a volume of 1.0 L – M1 = 0.10 M molarity of solution before dilution – M2 = X M molarity of solution after dilution – V1 = 0.050 L volume of solution before dilution – V2 = 1.0 L volume of solution after dilution • Use dilution expression • X M = (0.10 M) (0.050 L) / (1.0 L) 0.0050 M HCl OR 5.0 x 10-3 M HCl M1V1 = M2V2 6.3MolesandEquivalents Calculating Molarity After Dilution
  • 22. 6.3MolesandEquivalents Representation of Concentration of Ions in Solution Two common ways of expressing concentration of ions in solution: 1. Moles per liter (molarity) • Molarity emphasizes the number of individual ions 2. Equivalents per liter (eq/L) • Emphasis on charge
  • 23. iononchargesofnumber (g)ionofmassmolar ionanofequivalentOne = 6.3MolesandEquivalents Comparison of Molarity and Equivalents 1 M Na3PO4 • What would the concentration of PO4 3- ions be? • 1 M • Equivalent is defined by the charge • One Equivalent of an ion is the number of grams of the ion corresponding to Avogadro’s number of electrical charges
  • 24. 6.3MolesandEquivalents Molarity vs. Equivalents – 1 M Na3PO4 • 1 mol Na+ = 1 equivalent Na+ • 1 mol PO4 3- = 3 equivalents PO4 3- • Equivalents of Na+ ? – 3 mol Na+ = 3 equivalents of Na+ • Equivalents of PO4 3- ? – 1 mol PO4 3- = 3 equivalents of PO4 3-
  • 25. 6.3MolesandEquivalents Calculating Ion Concentration • Calculate eq/L of phosphate ion, PO4 3- in a solution with 5.0 x 10-3 M phosphate • Need to use two conversion factors: – mol PO4 3- mol charge – mol charge eq PO4 3 5.0 x 10-3 mol PO4 3- x 3 mol charge x 1 eq 1 L 1 mol PO4 3- 1mol charge • 1.5 x 10-2 eq PO4 3- /L
  • 26. 6.4 Concentration-Dependent Solution Properties • Colligative properties - properties of solutions that depend on the concentration of the solute particles, rather than the identity of the solute • Four colligative properties of solutions 1. vapor pressure lowering 2. boiling point elevation 3. freezing point depression 4. osmotic pressure
  • 27. Vapor Pressure of a Liquid Consider Raoult’s law in molecular terms • Vapor pressure of a solution results from escape of solvent molecules from liquid to gas phase • Partial pressure of gas phase solvent molecules increases until equilibrium vapor pressure is reached • Presence of solute molecules hinders escape of solvent molecules, lowering equilibrium vapor pressure 6.4Concentration-Dependent SolutionProperties
  • 28. 6.4Concentration-Dependent SolutionProperties Vapor Pressure Lowering • Raoult’s law - when a nonvolatile solute is added to a solvent, vapor pressure of the solvent decreases in proportion to the concentration of the solute • Solute molecules (red below) serve as a barrier to the escape of solvent molecules resulting in a decrease in the vapor pressure
  • 29. 6.4Concentration-Dependent SolutionProperties Freezing Point Depression and Boiling Point Elevation • Freezing point depression may be explained considering the equilibrium between solid and liquid states – Solute molecules interfere with the rate at which liquid water molecules associate to form the solid state • Boiling point elevation can be explained considering the definition as the temperature at which vapor pressure of the liquid equals the atmospheric pressure – If a solute is present, then the increase in boiling temperature is necessary to raise the vapor pressure to atmospheric temperature
  • 30. • Freezing point depression (∆Tf) - is proportional to the number of solute particles – Solute particles, not just solute • How does an electrolyte behave? – Dissociate into ions • An equal concentration of NaCl will affect the freezing point twice as much as glucose (a nonelectrolyte) • Each solvent has a unique freezing point depression constant or proportionality factor ∆Tf=kf m 6.4Concentration-Dependent SolutionProperties Freezing Point Depression
  • 31. • Boiling point elevation (∆Tb) - is proportional to the number of solute particles • An electrolyte will affect boiling point to a greater degree than a nonelectrolyte of the same concentration • Each solvent has a unique boiling point elevation constant ∆Tb=kb m 6.4Concentration-Dependent SolutionProperties Boiling point elevation
  • 32. Osmotic Pressure • Some types of membranes appear impervious to matter, but actually have a network of small holes called pores • These pores may be large enough to permit small solvent molecules to move from one side of the membrane to the other • Solute molecules cannot cross the membrane as they are too large • Semipermeable membrane - allows solvent but not solute to diffuse from one side to another 6.4Concentration-Dependent SolutionProperties
  • 33. 6.4Concentration-Dependent SolutionProperties Osmotic Pressure • Osmosis - the movement of solvent from a dilute solution to a more concentrated solution through a semipermeable membrane • Requires pressure to stop this flow
  • 34. • Osmotic pressure (π) - the amount of pressure required to stop the flow across a semipermeable membrane • Osmolarity - the molarity of particles in solution – Osmol, used for osmotic pressure calculation π=MRT 6.4Concentration-Dependent SolutionProperties Osmotic Pressure
  • 35. 6.4Concentration-Dependent SolutionProperties Tonicity and the Cell • Living cells contain aqueous solution and these cells are also surrounded by aqueous solution • Cell function requires maintenance of the same osmotic pressure inside and outside the cell • Solute concentration of fluid surrounding cells higher than inside results in a hypertonic solution causing water to flow into the surroundings, causing collapse = crenation • Solute concentration of fluid surrounding cells too low, results in a hypotonic solution causing water to flow into the cell, causing rupture = hemolysis • Isotonic solutions have identical osmotic pressures and no osmotic pressure difference across the cell membrane
  • 37. Pickling Cucumber in Hypertonic Brine Due to Osmosis 6.4Concentration-Dependent SolutionProperties
  • 38. 6.5 Water as a Solvent • Water is often referred to as the “universal solvent” • Excellent solvent for polar molecules • Most abundant liquid on earth • 60% of the human body is water – transports ions, nutrients, and waste into and out of cells – solvent for biochemical reactions in cells and digestive tract – reactant or product in some biochemical processes