Quadrilateral
What is a Quadrilateral ?
 It is a four-sided polygon with four angles
 The sum of interior angles is 360
Types of Quadrilateral
Square Rectangle Parallelogram Rhombus
Kite TrapeziumCyclic Quadrilateral
Rectangles and Squares
Rectangle
What is a rectangle?
A quadrilateral where opposite sides are parallel.
Properties of a Rectangle
 Opposite sides are congruent
 Opposite sides are parallel
 Internal angles are congruent
 All internal angles are right angled (90 degrees)
Perimeter of a Rectangle
Step 1: Add up the
sides
DONE
Example:
Perimeter:
x + y + x + y
OR
2x + 2y
Area of a Rectangle
How?
Multiply the length with the width
Example:
Area = x . y
The Diagonal of a Rectangle
To find the length of diagonal on a rectangle:
Let diagonal = D
D squared = x squared + y squared
D
Properties of the Diagonals on
Rectangles
Diagonals do not intersect at right angles
 Angles at the intersection can differ
 Opposite angles at intersection are
congruent
Square
What is a square?
A quadrilateral with sides of equal length.
Properties of a Square
The sides are congruent
 Angles are congruent
 Total internal angle is 360 degrees
 All internal angles are right-angled
(90 degrees)
 Opposite angles are congruent
 Opposite sides are congruent
 Opposite sides are parallel
Perimeter of a Square
Step 1:
Add up all the sides
DONE
Example:
Perimeter:
a + a + a + a
OR
4a
Area of a Square
How?
Multiply two of the sides together or just “SQUARE” the
length of one side
Example:
Area = a x a
OR
a squared
Diagonal of a Square
To find the length of the
diagonal of the square,
multiply the length of one
side with the square root
of 2.
Example:
d = a
Properties of the Diagonals in Squares
The diagonals intersect at
90 degree angles
(right-angled)
 Diagonals are
perpendicular
 Diagonals are congruent
Parallelogram
Opposite sides:
 Parallel
 Equal in length
Parallelogram
Opposite Interior Angles:
 Equal
 A = C
B = D
D + C = 180
Known as supplementary
angles.
Parallelogram
The diagonals:
 Bisect each other
 Intersect each other at the half way point
Each diagonal separates it into 2 congruent
triangles.
Perimeter of Parallelogram
Perimeter = 2(a+b)
a
b
Area of Parallelogram
Area = Base x Height
Area of Parallelogram (Example)
Solution:
180o – 135o = 45o
sin 45o = h / 15
h = 10.6
18
Area = Base x Height
= 18 x 10.6
= 190.8
Rhombus
A flat shape with 4 equal straight sides that looks
like a diamond.
Properties of Rhombus
1 - All sides are congruent (equal lengths).
length AB = length BC = length CD = length DA =
a.
2 - Opposite sides are parallel.
AD is parallel to BC and AB is parallel to DC.
3 - The two diagonals are perpendicular.
AC is perpendicular to BD.
4 - Opposite internal angles are congruent (equal
sizes).
internal angle A = internal angle C
and
internal angle B = internal angle D.
5 - Any two consecutive internal angles are
supplementary : they add up to 180 degrees.
angle A + angle B = 180 degrees
angle B + angle C = 180 degrees
angle C + angle D = 180 degrees
angle D + angle A = 180 degrees
Area of Rhombus
Perimeter of Rhombus
Example :
Question : The lengths of the diagonals of a rhombus are 20 and 48 meters.
Find the perimeter of the rhombus.
Solution :
• Below is shown a rhombus with the given diagonals.
Consider the right triangle BOC and apply Pythagora's theorem as follows
• BC 2 = 10 2 + 24 2
• and evaluate BC
• BC = 26 meters.
• We now evaluate the perimeter P
as follows:
• P = 4 * 26 = 104 meters.
CYCLIC QUADRILATERAL
A cyclic quadrilateral is a quadrilateral when there is a
circle passing through all its four vertices.
Theorem 1: Sum of the opposite angles of a cyclic quadrilateral is 180°.
Example: ∠P + ∠R=180° and
∠S + ∠Q=180°
Theorem 2: Sum of all the angles of a cyclic quadrilateral is 360°.
Example: ∠P+∠Q+∠R+∠S = 360°
Proving Cyclic Quadrilateral Theorem
Area of Cyclic Quadrilateral
The area of the cyclic quadrilateral with sides a,b,c and d,
and perimeter S= a+b+c+d is given by Brahmagupta’s
Formula.
Kite
 Two pairs of equal length - a & a, b & b, are
adjacent to each other.
 Diagonals are perpendicular to each other.
Perimeter = AB +BC + CD + DA
Area = ½ x d1 x d2
PERIMETER
AREA
Area = ½ x d1 x d2
= ½ x 4.8 x 10
= 24cm2
Area = ½ x d1 x d2
= ½ x (4+9) x
(3+3)
= 39m2
EXAMPLE
Find the length of the diagonal of a kite whose area is 168 cm2 and one
diagonal is 14 cm.
Solution:
Given: Area of the kite (A) = 168 cm2 and one diagonal (d1) = 14 cm.
Area of Kite = ½ x d1 x d2
168 = ½ x 14 x d2
d2 = 168/7
d2 = 24cm
EXAMPLE
Trapezium
Properties:
Only one pair of opposite side is parallel.
Area
Example
Class Activity
Question 1
• Only one pair of opposite side is parallel.
Question 2
• Opposite sides are parallel.
• All sides are congruent (equal lengths).
• Opposite internal angles are congruent (equal sizes).
• The two diagonals are perpendicular.
• Any two consecutive internal angles are supplementary : they add up to
180 degrees.
Question 3
Opposite sides:
• Parallel
• Equal in length
The diagonals:
• Bisect each other
• Intersect each other at the half way point
Each diagonal separates it into 2 congruent triangles
Question 4
• Two pairs of equal length - a & a, b & b, are adjacent
to each other.
• Diagonals are perpendicular to each other.

Maths Quadrilaterals

  • 1.
  • 2.
    What is aQuadrilateral ?  It is a four-sided polygon with four angles  The sum of interior angles is 360
  • 3.
    Types of Quadrilateral SquareRectangle Parallelogram Rhombus Kite TrapeziumCyclic Quadrilateral
  • 4.
  • 5.
    Rectangle What is arectangle? A quadrilateral where opposite sides are parallel.
  • 6.
    Properties of aRectangle  Opposite sides are congruent  Opposite sides are parallel  Internal angles are congruent  All internal angles are right angled (90 degrees)
  • 7.
    Perimeter of aRectangle Step 1: Add up the sides DONE Example: Perimeter: x + y + x + y OR 2x + 2y
  • 8.
    Area of aRectangle How? Multiply the length with the width Example: Area = x . y
  • 9.
    The Diagonal ofa Rectangle To find the length of diagonal on a rectangle: Let diagonal = D D squared = x squared + y squared D
  • 10.
    Properties of theDiagonals on Rectangles Diagonals do not intersect at right angles  Angles at the intersection can differ  Opposite angles at intersection are congruent
  • 11.
    Square What is asquare? A quadrilateral with sides of equal length.
  • 12.
    Properties of aSquare The sides are congruent  Angles are congruent  Total internal angle is 360 degrees  All internal angles are right-angled (90 degrees)  Opposite angles are congruent  Opposite sides are congruent  Opposite sides are parallel
  • 13.
    Perimeter of aSquare Step 1: Add up all the sides DONE Example: Perimeter: a + a + a + a OR 4a
  • 14.
    Area of aSquare How? Multiply two of the sides together or just “SQUARE” the length of one side Example: Area = a x a OR a squared
  • 15.
    Diagonal of aSquare To find the length of the diagonal of the square, multiply the length of one side with the square root of 2. Example: d = a
  • 16.
    Properties of theDiagonals in Squares The diagonals intersect at 90 degree angles (right-angled)  Diagonals are perpendicular  Diagonals are congruent
  • 17.
  • 18.
    Parallelogram Opposite Interior Angles: Equal  A = C B = D D + C = 180 Known as supplementary angles.
  • 19.
    Parallelogram The diagonals:  Bisecteach other  Intersect each other at the half way point Each diagonal separates it into 2 congruent triangles.
  • 20.
  • 21.
  • 22.
    Area of Parallelogram(Example) Solution: 180o – 135o = 45o sin 45o = h / 15 h = 10.6 18 Area = Base x Height = 18 x 10.6 = 190.8
  • 23.
    Rhombus A flat shapewith 4 equal straight sides that looks like a diamond.
  • 24.
    Properties of Rhombus 1- All sides are congruent (equal lengths). length AB = length BC = length CD = length DA = a. 2 - Opposite sides are parallel. AD is parallel to BC and AB is parallel to DC. 3 - The two diagonals are perpendicular. AC is perpendicular to BD. 4 - Opposite internal angles are congruent (equal sizes). internal angle A = internal angle C and internal angle B = internal angle D. 5 - Any two consecutive internal angles are supplementary : they add up to 180 degrees. angle A + angle B = 180 degrees angle B + angle C = 180 degrees angle C + angle D = 180 degrees angle D + angle A = 180 degrees
  • 25.
  • 26.
  • 27.
    Example : Question :The lengths of the diagonals of a rhombus are 20 and 48 meters. Find the perimeter of the rhombus. Solution : • Below is shown a rhombus with the given diagonals. Consider the right triangle BOC and apply Pythagora's theorem as follows • BC 2 = 10 2 + 24 2 • and evaluate BC • BC = 26 meters. • We now evaluate the perimeter P as follows: • P = 4 * 26 = 104 meters.
  • 28.
    CYCLIC QUADRILATERAL A cyclicquadrilateral is a quadrilateral when there is a circle passing through all its four vertices.
  • 29.
    Theorem 1: Sumof the opposite angles of a cyclic quadrilateral is 180°. Example: ∠P + ∠R=180° and ∠S + ∠Q=180° Theorem 2: Sum of all the angles of a cyclic quadrilateral is 360°. Example: ∠P+∠Q+∠R+∠S = 360°
  • 30.
  • 31.
    Area of CyclicQuadrilateral The area of the cyclic quadrilateral with sides a,b,c and d, and perimeter S= a+b+c+d is given by Brahmagupta’s Formula.
  • 32.
    Kite  Two pairsof equal length - a & a, b & b, are adjacent to each other.  Diagonals are perpendicular to each other.
  • 33.
    Perimeter = AB+BC + CD + DA Area = ½ x d1 x d2 PERIMETER AREA
  • 34.
    Area = ½x d1 x d2 = ½ x 4.8 x 10 = 24cm2 Area = ½ x d1 x d2 = ½ x (4+9) x (3+3) = 39m2 EXAMPLE
  • 35.
    Find the lengthof the diagonal of a kite whose area is 168 cm2 and one diagonal is 14 cm. Solution: Given: Area of the kite (A) = 168 cm2 and one diagonal (d1) = 14 cm. Area of Kite = ½ x d1 x d2 168 = ½ x 14 x d2 d2 = 168/7 d2 = 24cm EXAMPLE
  • 36.
    Trapezium Properties: Only one pairof opposite side is parallel.
  • 37.
  • 39.
  • 41.
  • 42.
    Question 1 • Onlyone pair of opposite side is parallel.
  • 43.
    Question 2 • Oppositesides are parallel. • All sides are congruent (equal lengths). • Opposite internal angles are congruent (equal sizes). • The two diagonals are perpendicular. • Any two consecutive internal angles are supplementary : they add up to 180 degrees.
  • 44.
    Question 3 Opposite sides: •Parallel • Equal in length The diagonals: • Bisect each other • Intersect each other at the half way point Each diagonal separates it into 2 congruent triangles
  • 45.
    Question 4 • Twopairs of equal length - a & a, b & b, are adjacent to each other. • Diagonals are perpendicular to each other.