Explains about the concept ,formula,and solving problems on area of a square and parallelogram.The development of a formula is also explained with the help of examples for both triangle and parallelogram.The power point is made for VIIth standard s.s.c board text book.

1. Area of a triangle
and parallelogram
STANDARD : 7TH

2. • The area of any shape is a measure of the 2 dimensional
space that it covers.
• Area is measured in squares – e.g. square cm, square meters
and square km.

4. What is the area
L=length H=height
of this parallelogram?
W=width

5. PARALLELOGRAM
What is the area
L=length H=height
of this parallelogram?
W=width
CUT HERE

6. What is the area
of this parallelogram?
Move and paste Here
B= base
H=height
 This Is ( like) a rectangle obtained from Parallelogram
Area of Rectangle = Area of parallelogram

7. Area of Rectangle= Base x Height
(perpendicular height H)
B= base
H=height
L=length
B = base
H=height

8. Find the area of parallelogram whose base is 30 cm and
height is 20cm
Suppose ABCD is a parallelogram
Given : l ( BC ) = 30 cm , l ( AE ) = 20 cm
To find out : A ( )ABCD
Area of Parallelogram= Base x
Height
A
B
D
20 cm
E C
A ( )ABCD = l ( BC ) × l ( AE ) 30 cm
= 30cm× 20cm
= 600 sq cm
Solution :
The area of parallelogram is 600 sq cm

9. If the area of parallelogram is 250 sq cm and its height is
25 cm , what is the length of its base.
Suppose DEFG is a parallelogram
Given : l ( DH ) = 25 cm , A ( DEFG ) = 250 sq cm
To find out : l ( EF ) =?
SOLUTION :
Area of Parallelogram= Base x Height
A ( DEFG ) = l ( EF ) × l ( DH)
250 cmxcm = l ( EF) x 25 cm
250 Xcm Xcm = l ( EF)
25 xcm
10 cm = l ( EF)
The length of its base is 10 cm
D
E F
G
H

10.  EVALUATIVE QUESTIONS

11. Evaluation:
 The area of parallelogram ABCD is 300 sqcm . The length of its base
is 15 cm what will be the height of parallelogram.
 If the length of base of parallelogram is 15 cm and its height is 30 cm.
find o the area of parallelogram.
 The area of parallelogram ABCD is 450 sqcm . The length of its
height is 9 cm what will be the base of parallelogram.

13. L=length H=height
What is the area
of this triangle?
W=width
COPY THIS

14. PASTE HERE
H=height
W=width
L=length
cho

15. L=length H=height
W=width
FLIP HORIZONTALLY!

16. The area of the
L=length H=height
triangle is ½ the
B = Base
Area of triangle= ½ (Base x Height)
INVERT HERE
area of this
parallelogram

17. 8cm
10cm
6cm
7cm
Area of triangle =½ base X height
= ½ x 10 cm x 8cm
= ½ x 80 sq cm
=40 sq cm
Area of triangle =½ base X height
= ½ x 6cm x 7cm
= ½x42sqcm
=21 sq cm
EXAMPLES

18. If the area of triangle is 90 sq m and its base
is 20 m , what is the length of its height.
J
k L M
Suppose JKM is a triangle
Given : A( JKM ) = 90 sq m , l ( KM ) = 20 m
To find out : l ( JL )
Solution :
Area of triangle =½ X base X height
90sqm = ½ X l ( KM )X l
The length of height of triangle is 9m
(JL)
90sqm = ½ X 20 m X l (JL)
90sqm = 10m X l (JL)
9m = l (JL)

19.  The area of triangle GEF is 100 sqcm . The length of its
base is 25 cm. what will be the height of triangle.
 If the length of base of triangle is 12 cm and its height is
27 cm. find out the area of triangle.
 The area of triangle RPS is 120 sqcm . The length of its
height is 5 cm what will be the base of triangle.