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International Journal of Modern Trends in Engineering
and Research
www.ijmter.com
@IJMTER-2014, All rights Reserved 215
e-ISSN: 2349-9745
p-ISSN: 2393-8161
MATHEMATICAL MODELING OF COMPLEX REDUNDANT
SYSTEM UNDER HEAD-OF-LINE REPAIR
Sonendra Kumar Gupta1
, Dr. Rekha Choudhari2
1
Research Scholar, Shri Ventakateshwara University, Gajraula (U.P)
2
Department of Mathematics, Govt. Engg. College, Bharatpur (Raj.)
Abstract— Suppose a composite system consisting of two subsystems designated as ‘P’ and
‘Q’ connected in series. Subsystem ‘P’ consists of N non-identical units in series, while the
subsystem ‘Q’ consists of three identical components in parallel redundancy.
Keywords- Reliability Analysis, Abel Lemma, Laplace transform, cost profit function.
1. INTRODUCTION
In reliability analysis, it has been mostly assumed that the system has an immediate repair
facility and after detection of failure, the unit goes under repair. But in many cases it is not
advisable to always have a repair facility. In this paper the authors have considered a
composite system consisting of two subsystems designated as ‘P’ and ‘Q’ connected in
series. Subsystem ‘P’ consists of N non-identical units in series, while the subsystem ‘Q’
consists of three identical components in parallel redundancy. In this model it is considered
that the system goes to complete breakdown state if any unit of subsystem ‘P’ fails or more
than 1 unit of subsystem ‘Q’ is in the failed condition. Also, the system works with reduced
efficiency if one unit of subsystem ‘Q’ failed. The system as a whole can also fail from
normal efficiency state if there is any failure due to environmental reasons. Supplementary
variable technique and Laplace transforms have been utilized to obtain various state
probabilities and the cost incurred for the system is obtained. Failure and repair times of the
units follow exponential and general time distributions respectively.
So in earlier research [1, 2, 3, 4], different techniques have been applied to evaluate
the reliability of distribution system, including distributed generation such as an analytical
technique using the load duration curve, distributed processing technique, Characteristic
function based approach for computing the probability distributers of reliability indices,
probabilistic method for assessing the reliability and quantity of power supply to a customer,
composite load point model, practical reliability assessment algorithm, validation method and
impact of substation on distribution reliability respectively.
2. ASSUMPTIONS
(i). Initially, all units are good.
(ii). A failed unit is repaired at a single service channel.
(iii). The parallel subsystem is composed of three identical units, while series subsystem is
composed of N non-identical units.
(iv). Failures are statistically independent.
(v). Environmental failure rates are constant.
(vi). After repair, units work like new.
(vii). Repairs follow general time distribution.
(viii). First come first served (Head-of-line) repair policy is being adopted.
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 216
3. NOTATIONS
/ /i Ef f f′ : Constant failure rates of any unit of subsystem / th
B i unit of
subsystem A/environmental failure.
1 2 3 4( ) / (y) / ( ) / ( )r x r r z r α : Repair rates with general time distribution from states 4 0toS S
1 0toS S or 3 4toS S , 2 0toS S , 5 0toS S
3
( )NP t : Probability that at time ‘t’ the system is operating in the state of
Normal efficiency.
2
(y, )NP t ∆ : The probability that at time ‘t’, the system is in degraded state
due to the failure of one unit of subsystem B. The elapsed
repair time lies in the interval (y, y )+ ∆
( , )F
NP z t ∆ : The probability that at time ‘t’, the system is in failed state due
to the failure of more than one unit of subsystem B, the elapsed
repair time lies in the interval ( , )z z + ∆
3
( , )iP x t ∆ : The probability that at time ‘t’, the system is in failed state due
to the failure of ith
unit of subsystem A. The elapsed repair
time lies in the interval ( , )x x + ∆
2
(y, )iP t ∆ : The probability that at time ‘t’ the repair time lies in the
interval (y, y )+ ∆
( , )EP tα ∆ : The probability that at time ‘t’, the system is in failed state, due
to the environmental failure, the elapsed repair time lies in the
interval ( , )α α + ∆
Figure 1 represents the state transition diagram of the system.
( ),EP tα ( ),F
NP z t
( )2
y,iP t
( )3
,iP x t
( )3r z
5S
ef 0S ( )2 yr 1S
2 'f
2S
( )3
NP t ( )2
y,NP t
3 'f( )4r α
f ( )1r x f
4S 3S
( )2 yr
Good State
Degraded State
Failed State
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 217
4. FORMULATION OF MATHEMATICAL MODEL
The analysis crucially depends on the method of supplementary variables technique and the
supplementary variable x denotes the time that a unit has been elapsed undergoing repair.
Viewing the nature of the problem, we obtain the following set of difference-differential
equations:
3 2
2 3
0 0
3 ( ) (y, ) (y) y ( , ) ( )F
e N i Nf f f P t P t r d P z t r z dz
t
∞ ∞
 ∂
′+ + + = + 
∂ 
∫ ∫
3
1 4
0 0
( , ) ( ) ( , ) ( )i EP x t r x dx P t r dα α α
∞ ∞
+ +∫ ∫ (1.1)
2
22 (y) (y, ) 0
y
Nf f r P t
t
 ∂ ∂
′+ + + + = 
∂ ∂ 
(1.2)
3 ( ) ( , ) 0F
Nr z P z t
t z
 ∂ ∂
+ + = 
∂ ∂ 
(1.3)
3
1( ) ( , ) 0ir z P x t
t x
 ∂ ∂
+ + = 
∂ ∂ 
(1.4)
2 2
2 (y) (y, ) (y, )
y
i Nr P t f P t
t
 ∂ ∂
+ + = 
∂ ∂ 
(1.5)
4 ( ) ( , ) 0Er P t
t
α α
α
 ∂ ∂
+ + = 
∂ ∂ 
(1.6)
Boundary Conditions:
2 3
(0, ) 3 ( )N NP t f P t′= (1.7)
2
(0, ) 2 ( )F
N NP t f P t′= (1.8)
3 3 2
20
(0, ) ( ) (y, ) (y) yi N iP t f P t P t r d
∞
= + ∫ (1.9)
2
(0, ) 0iP t = (2.0)
3
(0, ) ( )i e NP t f P t= (2.1)
Initial Condition
3
(0) 1NP = , otherwise zero (2.2)
5. SOLUTION OF MATHEMATICAL MODEL
Taking Laplace transforms of equations (1.1) through (2.1) and using initial conditions one
may obtain:
[ ]
3 2
2 30 0
3 ( ) 1 (y, ) (y) y ( , ) ( )
F
N N Nes f f f P s P s r d P z s r z dz
∞ ∞
′+ + + = + +∫ ∫
3
1 40 0
( , ) ( ) ( , ) ( )N EP x s r x dx P s r dα α α
∞ ∞
+ +∫ ∫ (2.3)
2
22 (y) (y, ) 0
y
Ns f r P s
 ∂
′+ + + = ∂ 
(2.4)
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 218
3 ( ) ( , ) 0
F
Ns r z P z s
z
∂ 
+ + = ∂ 
(2.5)
3
1 ( ) ( , ) 0is r z P x s
x
∂ 
+ + = ∂ 
(2.6)
2 2
2 (y) (y, ) (y, )
y
i Ns r P s f P s
 ∂
+ + = ∂ 
(2.7)
4 ( ) ( , ) 0Es r P sα α
α
∂ 
+ + = ∂ 
(2.8)
2 3
(0, ) 3 ( )N NP s f P s′= (2.9)
2
(0, ) 2 ( )
F
N NP s f P s′= (3.0)
3 3 2
20
(0, ) ( ) (y, ) (y) yi N iP s f P s P s r d
∞
= + ∫ (3.1)
2
(0, ) 0iP s = (3.2)
3
(0, ) ( )E NeP s f P s= (3.3)
After solving the above equations, we get finally
3 1
( )
( )
NP s
A s
= (3.4)
2
2 3
( ) ( 2 )
( )
N r
f
P s D s f f
A s
′
′= + + (3.5)
2 3
2
6
( ) ( 2 ) ( )
( )
F
N r r
f
P s D s f f D s
A s
′
′= + + (3.6)
2 2
2 3
( ) ( ) ( 2 )
(2 ) ( )
i r r
f f
P s D s D s f f
f f A s
′
 ′= − + + ′ +
(3.7)
{ }2 2
3 3
( ) 1 ( ) ( 2 ) ( )
( ) 2
i r r
f f
P s S s S s f f D s
A s f f
η
′ 
′= + + + ′+ 
(3.8)
4
( ) ( )
( )
e
E r
f
P s D s
A s
= (3.9)
Where, 2 32
( ) 3 3 ( 2 ) 6 ( 2 ) ( )r re rA s s f f f f S s f f f D s f f S s′ ′ ′ ′ ′= + + + − + + − + +
{ }2 2 4
3
1 ( ) ( 2 ) ( ) ( )
2
r r re
f
f S s S s f f S s f S s
f f
η
′ 
′− + − + + − ′ + 
(4.0)
It is interesting to note that sum of relation (3.4) through (3.9) =
1
s
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 219
6. ERGODIC BEHAVIOUR OF THE SYSTEM
Using Abel’s Lemma
0
lim ( ) lim ( ) (say)
s t
s F s F t F
→ → ∞
= = , provided the limit on the R.H.S. exists, the
time independent probabilities are obtained as follows by making use above lemma in the
relations (3.4) through (3.9)
3 1
(0)
NP
A
=
′
(4.1)
2
2 3
(2 )
(0)
N r
f
P D f f
A
′
′= +
′
(4.2)
2 3
6
(2 )
(0)
F
N r r
f
P D f f M
A
′
′= +
′
(4.3)
3 2
2 3
(2 )
(2 ) (0)
i r r
ff
P M D f f
f f A
′
 ′= − + ′ ′+
(4.4)
3
(0)
i
f
P M
A
η=
′
(4.5)
4
(0)
e
E r
f
P M
A
=
′
(4.6)
Where,
0
(0) ( )
s
d
A A s
ds =
 ′ =  
 
and kM = Mean time to repair kth
unit
7. EVALUATION OF UP AND DOWN STATE PROBABILITIES
We have,
1 3
( ) 1
3 2
up
e
f
P s
s f f f s f f
′ 
= + ′ ′+ + + + + 
(4.7)
Taking inverse on both sides, we get
{ } { }
3 3
( ) 1 exp (3 ) exp (2 )up e
e e
f f
P t f f f t f f t
f f f f
′ ′ 
′ ′= − − + + + − + 
′ ′+ + 
(4.8)
and ( ) 1 ( )down upP t P t= − (4.9)
8. COST PROFIT ANALYSIS FUNCTION
The cost profit function is defined as,
1 20
( ) ( )
t
upG t C P t dt C t= −∫ (5.0)
Where,
G(t) = Expected cost for total time,
C1 = Revenue cost per unit up time and C2 = Service cost per unit time
Putting the value of Pup(t) in equation (5.0), we get
{ } { }
1 1 2
1 exp (3 ) 1 exp (2 )3 3
( ) 1
3 2
e
e e e
f f f t f f tf f
G t C C C t
f f f f f f f f f
′ ′ − − + + − − + ′ ′   
= − + −      
′ ′ ′ ′+ + + + +       
(5.1)
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 220
9. NUMERICAL COMPUTATION
Substituting 1 20.001, 0.002, 0.003, 2, 1ef f f C C′= = = = = and all repair rates are zero.
1. Availability
( ) 0.2 exp ( 0.010 ) 1.2exp ( 0.005 )upP t t t= − − + −
2. Cost Analysis function
1 exp ( 0.010 ) 1 exp ( 0.005 )
( ) 0.4 2.4
0.010 0.005
t t
G t t
− − − −   
= − + −   
   
10. INTERPRETATION
10.1 Table 1 outlines the variation of availability of the model with time and their
corresponding curve
S.No. t Pup(t)
1 0 1
2 1 0.996005
3 2 0.9920201
4 3 0.9880452
5 4 0.9840805
6 5 0.980126
7 6 0.9761817
8 7 0.9722477
9 8 0.9683241
10 9 0.9644107
11 10 0.9605078
12 11 0.9566154
13 12 0.9527334
14 13 0.9488619
15 14 0.9450009
16 15 0.9411506
Table 1: Availability as function of time
Figure 2: Availability as function of time
Availability V/S Time
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 221
10.2 Table 2 exhibits expected cost function with respect to time and their corresponding
curve
11. CONCLUSION
Table 1 and Figure 2 provide information how availability of the complex engineering
repairable system changes with respect to the time when failure rate increases availability of
the system decreases.
Table 2 and Figure 3 when revenue cost per unit time C1 and C2 are fixed, then one can
conclude by observing this graph that as cost increases, when time increases.
S.No. t G(t)
1 0 0
2 1 0.9960033
3 2 1.9840267
4 3 2.9640903
5 4 3.9362144
6 5 4.9004192
7 6 5.8567252
8 7 6.805153
9 8 7.7457231
10 9 8.6784561
11 10 9.603373
12 11 10.520494
13 12 11.429841
14 13 12.331435
15 14 13.225296
16 15 14.111446
Table 2: Cost Profit as function of time
Figure 3: Cost Profit as function of time
Cost Profit V/S timeCost function V/S Time
International Journal of Modern Trends in Engineering and Research (IJMTER)
Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161
@IJMTER-2014, All rights Reserved 222
Hence the present study clearly proves the importance of head-of line repair policy in
comparison of [17-18] which seem to be possible in many engineering systems when it is
analyzed with the help of the copula. The further research area is widely open, where one
may think of the application of other members of copula family, MTTF and sensitivity
analysis.
12. References
[1]. Agnihotri, R. K., Khare, A., and Jain, S. (2008). Reliability analysis of a system of boiler used in eady-
made garment industry, Journal of Reliability and Statistical Studies, 1(1), p. 33-41
[2]. Bae, I.-S. and Kim, J.-O. (2007). Reliability evaluation of distributed generation based on operation
ode. IEEE Transactions on Power Systems, 22(2), p. 785-790.
[3]. Carpaneto, E. and Chicco, G. (2004). Evaluation of the probability density functions of distributed
system reliability indices with a characteristic functions-based approach. IEEE Transactions on Power
Systems, 19(2), p.724-734.
[4]. Pandey. S. B., Singh, S. B. and Sharma, S. (2008). Reliability and cost analysis of a system with
multiple components using copula, Journal of Reliability and Statistical Studies, 1(1), p. 25-32.
MATHEMATICAL MODELING OF COMPLEX REDUNDANT SYSTEM UNDER HEAD-OF-LINE REPAIR
MATHEMATICAL MODELING OF COMPLEX REDUNDANT SYSTEM UNDER HEAD-OF-LINE REPAIR

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MATHEMATICAL MODELING OF COMPLEX REDUNDANT SYSTEM UNDER HEAD-OF-LINE REPAIR

  • 1. Scientific Journal Impact Factor (SJIF): 1.711 International Journal of Modern Trends in Engineering and Research www.ijmter.com @IJMTER-2014, All rights Reserved 215 e-ISSN: 2349-9745 p-ISSN: 2393-8161 MATHEMATICAL MODELING OF COMPLEX REDUNDANT SYSTEM UNDER HEAD-OF-LINE REPAIR Sonendra Kumar Gupta1 , Dr. Rekha Choudhari2 1 Research Scholar, Shri Ventakateshwara University, Gajraula (U.P) 2 Department of Mathematics, Govt. Engg. College, Bharatpur (Raj.) Abstract— Suppose a composite system consisting of two subsystems designated as ‘P’ and ‘Q’ connected in series. Subsystem ‘P’ consists of N non-identical units in series, while the subsystem ‘Q’ consists of three identical components in parallel redundancy. Keywords- Reliability Analysis, Abel Lemma, Laplace transform, cost profit function. 1. INTRODUCTION In reliability analysis, it has been mostly assumed that the system has an immediate repair facility and after detection of failure, the unit goes under repair. But in many cases it is not advisable to always have a repair facility. In this paper the authors have considered a composite system consisting of two subsystems designated as ‘P’ and ‘Q’ connected in series. Subsystem ‘P’ consists of N non-identical units in series, while the subsystem ‘Q’ consists of three identical components in parallel redundancy. In this model it is considered that the system goes to complete breakdown state if any unit of subsystem ‘P’ fails or more than 1 unit of subsystem ‘Q’ is in the failed condition. Also, the system works with reduced efficiency if one unit of subsystem ‘Q’ failed. The system as a whole can also fail from normal efficiency state if there is any failure due to environmental reasons. Supplementary variable technique and Laplace transforms have been utilized to obtain various state probabilities and the cost incurred for the system is obtained. Failure and repair times of the units follow exponential and general time distributions respectively. So in earlier research [1, 2, 3, 4], different techniques have been applied to evaluate the reliability of distribution system, including distributed generation such as an analytical technique using the load duration curve, distributed processing technique, Characteristic function based approach for computing the probability distributers of reliability indices, probabilistic method for assessing the reliability and quantity of power supply to a customer, composite load point model, practical reliability assessment algorithm, validation method and impact of substation on distribution reliability respectively. 2. ASSUMPTIONS (i). Initially, all units are good. (ii). A failed unit is repaired at a single service channel. (iii). The parallel subsystem is composed of three identical units, while series subsystem is composed of N non-identical units. (iv). Failures are statistically independent. (v). Environmental failure rates are constant. (vi). After repair, units work like new. (vii). Repairs follow general time distribution. (viii). First come first served (Head-of-line) repair policy is being adopted.
  • 2. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 216 3. NOTATIONS / /i Ef f f′ : Constant failure rates of any unit of subsystem / th B i unit of subsystem A/environmental failure. 1 2 3 4( ) / (y) / ( ) / ( )r x r r z r α : Repair rates with general time distribution from states 4 0toS S 1 0toS S or 3 4toS S , 2 0toS S , 5 0toS S 3 ( )NP t : Probability that at time ‘t’ the system is operating in the state of Normal efficiency. 2 (y, )NP t ∆ : The probability that at time ‘t’, the system is in degraded state due to the failure of one unit of subsystem B. The elapsed repair time lies in the interval (y, y )+ ∆ ( , )F NP z t ∆ : The probability that at time ‘t’, the system is in failed state due to the failure of more than one unit of subsystem B, the elapsed repair time lies in the interval ( , )z z + ∆ 3 ( , )iP x t ∆ : The probability that at time ‘t’, the system is in failed state due to the failure of ith unit of subsystem A. The elapsed repair time lies in the interval ( , )x x + ∆ 2 (y, )iP t ∆ : The probability that at time ‘t’ the repair time lies in the interval (y, y )+ ∆ ( , )EP tα ∆ : The probability that at time ‘t’, the system is in failed state, due to the environmental failure, the elapsed repair time lies in the interval ( , )α α + ∆ Figure 1 represents the state transition diagram of the system. ( ),EP tα ( ),F NP z t ( )2 y,iP t ( )3 ,iP x t ( )3r z 5S ef 0S ( )2 yr 1S 2 'f 2S ( )3 NP t ( )2 y,NP t 3 'f( )4r α f ( )1r x f 4S 3S ( )2 yr Good State Degraded State Failed State
  • 3. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 217 4. FORMULATION OF MATHEMATICAL MODEL The analysis crucially depends on the method of supplementary variables technique and the supplementary variable x denotes the time that a unit has been elapsed undergoing repair. Viewing the nature of the problem, we obtain the following set of difference-differential equations: 3 2 2 3 0 0 3 ( ) (y, ) (y) y ( , ) ( )F e N i Nf f f P t P t r d P z t r z dz t ∞ ∞  ∂ ′+ + + = +  ∂  ∫ ∫ 3 1 4 0 0 ( , ) ( ) ( , ) ( )i EP x t r x dx P t r dα α α ∞ ∞ + +∫ ∫ (1.1) 2 22 (y) (y, ) 0 y Nf f r P t t  ∂ ∂ ′+ + + + =  ∂ ∂  (1.2) 3 ( ) ( , ) 0F Nr z P z t t z  ∂ ∂ + + =  ∂ ∂  (1.3) 3 1( ) ( , ) 0ir z P x t t x  ∂ ∂ + + =  ∂ ∂  (1.4) 2 2 2 (y) (y, ) (y, ) y i Nr P t f P t t  ∂ ∂ + + =  ∂ ∂  (1.5) 4 ( ) ( , ) 0Er P t t α α α  ∂ ∂ + + =  ∂ ∂  (1.6) Boundary Conditions: 2 3 (0, ) 3 ( )N NP t f P t′= (1.7) 2 (0, ) 2 ( )F N NP t f P t′= (1.8) 3 3 2 20 (0, ) ( ) (y, ) (y) yi N iP t f P t P t r d ∞ = + ∫ (1.9) 2 (0, ) 0iP t = (2.0) 3 (0, ) ( )i e NP t f P t= (2.1) Initial Condition 3 (0) 1NP = , otherwise zero (2.2) 5. SOLUTION OF MATHEMATICAL MODEL Taking Laplace transforms of equations (1.1) through (2.1) and using initial conditions one may obtain: [ ] 3 2 2 30 0 3 ( ) 1 (y, ) (y) y ( , ) ( ) F N N Nes f f f P s P s r d P z s r z dz ∞ ∞ ′+ + + = + +∫ ∫ 3 1 40 0 ( , ) ( ) ( , ) ( )N EP x s r x dx P s r dα α α ∞ ∞ + +∫ ∫ (2.3) 2 22 (y) (y, ) 0 y Ns f r P s  ∂ ′+ + + = ∂  (2.4)
  • 4. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 218 3 ( ) ( , ) 0 F Ns r z P z s z ∂  + + = ∂  (2.5) 3 1 ( ) ( , ) 0is r z P x s x ∂  + + = ∂  (2.6) 2 2 2 (y) (y, ) (y, ) y i Ns r P s f P s  ∂ + + = ∂  (2.7) 4 ( ) ( , ) 0Es r P sα α α ∂  + + = ∂  (2.8) 2 3 (0, ) 3 ( )N NP s f P s′= (2.9) 2 (0, ) 2 ( ) F N NP s f P s′= (3.0) 3 3 2 20 (0, ) ( ) (y, ) (y) yi N iP s f P s P s r d ∞ = + ∫ (3.1) 2 (0, ) 0iP s = (3.2) 3 (0, ) ( )E NeP s f P s= (3.3) After solving the above equations, we get finally 3 1 ( ) ( ) NP s A s = (3.4) 2 2 3 ( ) ( 2 ) ( ) N r f P s D s f f A s ′ ′= + + (3.5) 2 3 2 6 ( ) ( 2 ) ( ) ( ) F N r r f P s D s f f D s A s ′ ′= + + (3.6) 2 2 2 3 ( ) ( ) ( 2 ) (2 ) ( ) i r r f f P s D s D s f f f f A s ′  ′= − + + ′ + (3.7) { }2 2 3 3 ( ) 1 ( ) ( 2 ) ( ) ( ) 2 i r r f f P s S s S s f f D s A s f f η ′  ′= + + + ′+  (3.8) 4 ( ) ( ) ( ) e E r f P s D s A s = (3.9) Where, 2 32 ( ) 3 3 ( 2 ) 6 ( 2 ) ( )r re rA s s f f f f S s f f f D s f f S s′ ′ ′ ′ ′= + + + − + + − + + { }2 2 4 3 1 ( ) ( 2 ) ( ) ( ) 2 r r re f f S s S s f f S s f S s f f η ′  ′− + − + + − ′ +  (4.0) It is interesting to note that sum of relation (3.4) through (3.9) = 1 s
  • 5. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 219 6. ERGODIC BEHAVIOUR OF THE SYSTEM Using Abel’s Lemma 0 lim ( ) lim ( ) (say) s t s F s F t F → → ∞ = = , provided the limit on the R.H.S. exists, the time independent probabilities are obtained as follows by making use above lemma in the relations (3.4) through (3.9) 3 1 (0) NP A = ′ (4.1) 2 2 3 (2 ) (0) N r f P D f f A ′ ′= + ′ (4.2) 2 3 6 (2 ) (0) F N r r f P D f f M A ′ ′= + ′ (4.3) 3 2 2 3 (2 ) (2 ) (0) i r r ff P M D f f f f A ′  ′= − + ′ ′+ (4.4) 3 (0) i f P M A η= ′ (4.5) 4 (0) e E r f P M A = ′ (4.6) Where, 0 (0) ( ) s d A A s ds =  ′ =     and kM = Mean time to repair kth unit 7. EVALUATION OF UP AND DOWN STATE PROBABILITIES We have, 1 3 ( ) 1 3 2 up e f P s s f f f s f f ′  = + ′ ′+ + + + +  (4.7) Taking inverse on both sides, we get { } { } 3 3 ( ) 1 exp (3 ) exp (2 )up e e e f f P t f f f t f f t f f f f ′ ′  ′ ′= − − + + + − +  ′ ′+ +  (4.8) and ( ) 1 ( )down upP t P t= − (4.9) 8. COST PROFIT ANALYSIS FUNCTION The cost profit function is defined as, 1 20 ( ) ( ) t upG t C P t dt C t= −∫ (5.0) Where, G(t) = Expected cost for total time, C1 = Revenue cost per unit up time and C2 = Service cost per unit time Putting the value of Pup(t) in equation (5.0), we get { } { } 1 1 2 1 exp (3 ) 1 exp (2 )3 3 ( ) 1 3 2 e e e e f f f t f f tf f G t C C C t f f f f f f f f f ′ ′ − − + + − − + ′ ′    = − + −       ′ ′ ′ ′+ + + + +        (5.1)
  • 6. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 220 9. NUMERICAL COMPUTATION Substituting 1 20.001, 0.002, 0.003, 2, 1ef f f C C′= = = = = and all repair rates are zero. 1. Availability ( ) 0.2 exp ( 0.010 ) 1.2exp ( 0.005 )upP t t t= − − + − 2. Cost Analysis function 1 exp ( 0.010 ) 1 exp ( 0.005 ) ( ) 0.4 2.4 0.010 0.005 t t G t t − − − −    = − + −        10. INTERPRETATION 10.1 Table 1 outlines the variation of availability of the model with time and their corresponding curve S.No. t Pup(t) 1 0 1 2 1 0.996005 3 2 0.9920201 4 3 0.9880452 5 4 0.9840805 6 5 0.980126 7 6 0.9761817 8 7 0.9722477 9 8 0.9683241 10 9 0.9644107 11 10 0.9605078 12 11 0.9566154 13 12 0.9527334 14 13 0.9488619 15 14 0.9450009 16 15 0.9411506 Table 1: Availability as function of time Figure 2: Availability as function of time Availability V/S Time
  • 7. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 221 10.2 Table 2 exhibits expected cost function with respect to time and their corresponding curve 11. CONCLUSION Table 1 and Figure 2 provide information how availability of the complex engineering repairable system changes with respect to the time when failure rate increases availability of the system decreases. Table 2 and Figure 3 when revenue cost per unit time C1 and C2 are fixed, then one can conclude by observing this graph that as cost increases, when time increases. S.No. t G(t) 1 0 0 2 1 0.9960033 3 2 1.9840267 4 3 2.9640903 5 4 3.9362144 6 5 4.9004192 7 6 5.8567252 8 7 6.805153 9 8 7.7457231 10 9 8.6784561 11 10 9.603373 12 11 10.520494 13 12 11.429841 14 13 12.331435 15 14 13.225296 16 15 14.111446 Table 2: Cost Profit as function of time Figure 3: Cost Profit as function of time Cost Profit V/S timeCost function V/S Time
  • 8. International Journal of Modern Trends in Engineering and Research (IJMTER) Volume 01, Issue 06, [December - 2014] e-ISSN: 2349-9745, p-ISSN: 2393-8161 @IJMTER-2014, All rights Reserved 222 Hence the present study clearly proves the importance of head-of line repair policy in comparison of [17-18] which seem to be possible in many engineering systems when it is analyzed with the help of the copula. The further research area is widely open, where one may think of the application of other members of copula family, MTTF and sensitivity analysis. 12. References [1]. Agnihotri, R. K., Khare, A., and Jain, S. (2008). Reliability analysis of a system of boiler used in eady- made garment industry, Journal of Reliability and Statistical Studies, 1(1), p. 33-41 [2]. Bae, I.-S. and Kim, J.-O. (2007). Reliability evaluation of distributed generation based on operation ode. IEEE Transactions on Power Systems, 22(2), p. 785-790. [3]. Carpaneto, E. and Chicco, G. (2004). Evaluation of the probability density functions of distributed system reliability indices with a characteristic functions-based approach. IEEE Transactions on Power Systems, 19(2), p.724-734. [4]. Pandey. S. B., Singh, S. B. and Sharma, S. (2008). Reliability and cost analysis of a system with multiple components using copula, Journal of Reliability and Statistical Studies, 1(1), p. 25-32.