- Linked lists can be used to implement queue data structures. A linear queue uses linked list nodes with a front and rear pointer to track the first and last elements.
- The insert method creates a new node, assigns it the data value, and links it to the end of the queue by updating the rear pointer and rear node's next pointer. This takes O(1) time.
- Other common queue operations like deletion from the front and traversal can also be implemented in O(1) time by manipulating the front and rear pointers of the linked list.
This presentations gives an introduction to the data structure linked-lists. I discuss the implementation of header-based linked-lists in C. The presentation runs through the code and provides the visualization of the code w.r.t pointers.
Linked List Static and Dynamic Memory AllocationProf Ansari
Static variables are declared and named while writing the program. (Space for them exists as long as the program, in which they are declared, is running.) Static variables cannot be created or destroyed during execution of the program in which they are declared.
Dynamic variables are created (and may be destroyed) during program execution since dynamic variables do not exist while the program is compiled, but only when it is run, they cannot be assigned names while it is being written. The only way to access dynamic variables is by using pointers. Once it is created, however, a dynamic variable does contain data and must have a type like any other variable. If a dynamic variable is created in a function, then it can continue to exist even after the function terminates.
Linked Linear List
We saw in previous chapters how static representation of linear ordered list through Array leads to wastage of memory and in some cases overflows. Now we don't want to assign memory to any linear list in advance instead we want to allocate memory to elements as they are inserted in list. This requires Dynamic Allocation of memory and it can be achieved by using malloc() or calloc() function.
But memory assigned to elements will not be contiguous, which is a requirement for linear ordered list, and was provided by array representation. How we could achieve this?
Doubly Linked List || Operations || AlgorithmsShubham Sharma
Doubly linked list and operations on it. Insertion, Deletion, Traversing at all locations- First, Last, Middle.
Basic definitions and structured example.
Algorithms for all the operations.
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
This presentations gives an introduction to the data structure linked-lists. I discuss the implementation of header-based linked-lists in C. The presentation runs through the code and provides the visualization of the code w.r.t pointers.
Linked List Static and Dynamic Memory AllocationProf Ansari
Static variables are declared and named while writing the program. (Space for them exists as long as the program, in which they are declared, is running.) Static variables cannot be created or destroyed during execution of the program in which they are declared.
Dynamic variables are created (and may be destroyed) during program execution since dynamic variables do not exist while the program is compiled, but only when it is run, they cannot be assigned names while it is being written. The only way to access dynamic variables is by using pointers. Once it is created, however, a dynamic variable does contain data and must have a type like any other variable. If a dynamic variable is created in a function, then it can continue to exist even after the function terminates.
Linked Linear List
We saw in previous chapters how static representation of linear ordered list through Array leads to wastage of memory and in some cases overflows. Now we don't want to assign memory to any linear list in advance instead we want to allocate memory to elements as they are inserted in list. This requires Dynamic Allocation of memory and it can be achieved by using malloc() or calloc() function.
But memory assigned to elements will not be contiguous, which is a requirement for linear ordered list, and was provided by array representation. How we could achieve this?
Doubly Linked List || Operations || AlgorithmsShubham Sharma
Doubly linked list and operations on it. Insertion, Deletion, Traversing at all locations- First, Last, Middle.
Basic definitions and structured example.
Algorithms for all the operations.
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
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Every experience we have teach us about us and our beliefs. How we handle, each experience define our overall health and well-being. Learning to move forward, to let go and forgive is an important step to growing.
Print connecté pour booster ses ventesarvato France
Print vs Digital : S'il y en a deux qu'on croit s'entendre comme chien et chat, c'est bien eux, mais, comme Pif et Hercule, "ils ont (désormais) la formule pour vivre de nouvelles aventures" !
In C++Write a recursive function to determine whether or not a Lin.pdfflashfashioncasualwe
In C++
Write a recursive function to determine whether or not a Linked List is in sorted order (smallest
value to largest value).
Add the following function prototypes to your List class under the section for access functions,
then implement the functions below the class definition:
public:
/**Access Functions*/
bool isSorted();
//Wrapper function that calls the isSorted helper function to determine whether
//a list is sorted in ascending order.
//We will consider that a list is trivially sorted if it is empty.
//Therefore, no precondition is needed for this function
private:
bool isSorted(Nodeptr node);
//Helper function for the public isSorted() function.
//Recursively determines whether a list is sorted in ascending order.
#include //for NULL
#include
#include
using namespace std;
template //list stores generic list data, not any specific C++ type
class List
{
private:
struct Node
{
listdata data;
Node* next;
Node* previous;
Node(listdata data): data(data), next(NULL), previous(NULL){}
};
typedef struct Node* Nodeptr;
Nodeptr first;
Nodeptr last;
Nodeptr iterator;
int size;
public:
/**Constructors and Destructors*/
List();
//Default constructor; initializes and empty list
//Postcondition: numeric values equated to zero, or strings should be empty.
List(const List &list);
~List();
//Destructor. Frees memory allocated to the list
//Postcondition: position NodePtr at next Node
/**Accessors*/
listdata getFirst();
//Returns the first element in the list
//Precondition:NodePtr points to the first node on list
listdata getLast();
//Returns the last element in the list
//Precondition: make new node first on the list
listdata getIterator();
bool isEmpty();
//Determines whether a list is empty.
int getSize();
//Returns the size of the list
/**Manipulation Procedures*/
void startIterator();
void advanceIterator();
void removeLast();
//Removes the value of the last element in the list
//Precondition: list is not empty, not the first element.
//Postcondition: one remaining node
void removeIterator();
void removeFirst();
//Removes the value of the first element in the list
//Precondition: list is not empty
//Postcondition: no nodes left
void insertLast(listdata data);
//Inserts a new element at the end of the list
//If the list is empty, the new element becomes both first and last
//Postcondition: next equal to null
void insertFirst(listdata data);
//Inserts a new element at the start of the list
//If the list is empty, the new element becomes both first and last
//Postcondition:point nodePtr next node on list
/**Additional List Operations*/
bool offEnd();
void printList();
//Prints to the console the value of each element in the list sequentially
//and separated by a blank space
//Prints nothing if the list is empty
void insertIterator(listdata data);
bool operator==(const List &list);
};
// constructor definition
template
List::List(): first(NULL), last(NULL), iterator(NULL), size(0) {}
template
List::List(const List &list): size(list.size)
{
if(list..
Note Given Code modified as required and required met.pdfAnkitchhabra28
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void setData(String data)
{
this.data = data;
}
// method to get the next data
public Node getNext()
{
return next;
}
// method to set the next data
public void setNext(Node next)
{
this.next = next;
}
}
// class for a linked list
class MyLInkedList
{
Node head;alue into a list
// method to add the v
public void add(String num)
{
if (head == null)
{
head = new Node(num);
}
else{
Node temp = new Node(num);
Node current = head;
if (current != null) {
while (current.getNext() != null) {
current = current.getNext();
}
current.setNext(temp);
}
}
}
// method to search a value from a list
public void search(String num)
{
Node current = head;
boolean flag=true;
if (current != null)
{
while (current != null)
{
if(current.getData() == num)
{
System.out.println(\"Search value \"+
current.getData()+\" is available\");
flag=false;
}
current = current.getNext();
}
if (flag==true)
{
System.out.println(\"Search value \"+
current.getData()+\" is not available\");
}
}
else
{
System.out.println(\"Linked list is empty\");
}
}
// method to delete a value from a list
public void delete(String num)
{
//Node current = head;
boolean flag=true;
if (head == null)
{
System.out.println(\"Can\'t Delete, Linked list is
empty\");
return;
}
if(head.getData() == num)
{
head=head.getNext();
return;
}
Node temp = new Node(num);
Node cr = head;
Node prev=null;
while ((cr != null) && !(cr.getData() == num))
{
prev=cr;
cr = cr.getNext();
}
prev.setNext(cr.getNext());
}
// method to print the list
public void print()
{
Node current = head;
if (current != null) {
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
}
}
// method to test the class
public class MyLInkedListTester
{
// main method to perform the linked list operatrions
public static void main(String args[])
{
MyLInkedList llist = new MyLInkedList();
// insert the values into list
llist.add(\"1\");
llist.add(\"2\");
llist.add(\"3\");
llist.add(\"4\");
// print the list values
llist.print();
// sear the values in a list
llist.search(\"1\");
llist.print();
// delete the value from a list
llist.delete(\"4\");
System.out.println(\"List after deletion:\");
llist.print();
}
}
Result:
1
2
3
4
Search value 1 is available
1
2
3
4
List after deletion:
1
2
3
Solution
Note:
Given Code modified as required and required methods added.
Code:
// class node
class Node
{
// declare the required variable
String data;
Node next;
// constructor
Node(){}
// constructor with arguments
Node(String data)
{
this.data = data;
next = null;
}
// method to get the data
public String getData()
{
return data;
}
// method to set the data
public void se.
Using the provided table interface table.h and the sample linked lis.pdfconnellalykshamesb60
Using the provided table interface table.h and the sample linked list code linkedList.c, complete
an implementation of the Table ADT. Make sure that you apply the concepts of design by
contract (DbC) to your implementation.
Once you have fully implemented the table, create a main.c file that implements a testing
framework for your table.
Your table implementation must ensure that values inserted are unique, and internally sorted
within a linked list.
table.h
linkedList.c
Solution
khsdg
#include
#include
typedef enum BOOL { false, true } bool;
// Linked list node definition
typedef struct Node node;
struct Node
{
int number;
node *next;
};
static node *top = NULL;
// used to track where we are for the list traversal methods
static node *traverseNode = NULL;
// \"destroy\" will deallocate all nodes in a linked list object
// and will set \"top\" to NULL.
void destroy()
{
node *curr = top;
node *temp = NULL;
while ( curr != NULL )
{
// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// \"build\" will create an ordered linked list consisting
// of the first \"size\" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don\'t have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}
// gets the data at the current traversal node and increments the traversal.
// returns false if we\'re at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// \"print\" will output an object\'s entire linked list
// to the standard output device -- one \"number\" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( \"%d\ \", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;
}.
How do you stop infinite loop Because I believe that it is making a.pdffeelinggift
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
In C++ I need help with this method that Im trying to write fillLi.pdffantoosh1
In C++ I need help with this method that I'm trying to write: fillListFromFile( ) : void -- this
method will add elements to the list from a file called linkedListData1.txt HINT: this is where
you will keep track of the number of elements in the list
I have all of the other methods, but I'm stuck on this one and I've added it as the last method in
the application. The code I have so far is below.
.cpp file:
.h file:
main:
#include
#include
#include
#include "Node.h"
using namespace std;
void displayList(Node*);
void insertFront(Node** head, int value);
void insertBack(Node** ptrToHead, int value);
void insertAfter(Node* previous, int value);
void deleteAtN(Node** ptrToHead, int n);
void deleteNode(Node** ptrToHead, int searchVal);
void clearList(Node**);
bool searchVal(Node** head, int value);
int countFrequencyOf(Node** ptrTohead, int value);
int size(Node** ptrTohead);
void displayFromFrontToN(Node** ptrToHead, int n);
void displayFromNToEnd(Node** ptrToHead, int n);
void insertInOrder(Node** head, Node* ptrToHead);
void displayInRows(Node** ptrToHead);
int main()
{
Node* node1 = new Node();
node1->setValue(10);
Node* node2 = new Node();
node2->setValue(20);
Node* node3 = new Node();
node3->setValue(30);
node1->next = node2;
node2->next = node3;
Node* head = node1;
displayList(head);
insertFront(&head, 5);
displayList(head);
insertBack(&head, 50);
displayList(head);
insertBack(&head, 60);
displayList(head);
insertAfter(node2, 25);
displayList(head);
deleteAtN(&head, 2);
displayList(head);
deleteNode(&head, 50);
displayList(head);
clearList(&head);
displayList(head);
insertFront(&head, 5);
insertFront(&head, 10);
insertFront(&head, 20);
insertBack(&head, 50);
searchVal(&head, 50);
displayList(head);
countFrequencyOf(&head, 25);
displayList(head);
insertBack(&head, 25);
insertFront(&head, 25);
countFrequencyOf(&head, 25);
displayList(head);
size(&head);
cout << "add one item to list" << endl;
insertBack(&head, 25);
size(&head);
displayList(head);
cout << "Display From Front To N" << endl;
displayFromFrontToN(&head, 4);
cout << "Display From N To End" << endl;
displayFromNToEnd(&head, 3);
cout << "Display In Rows" << endl;
displayInRows(&head);
insertFront(&head, 12);
insertFront(&head, 17);
insertFront(&head, 22);
insertBack(&head, 58);
cout << "Display In Rows" << endl;
displayInRows(&head);//call displayInRows()
return 0;
}//end main()
void displayList(Node* ptr) {
if (ptr == nullptr)
cout << "empty list" << endl;
else {
while (ptr != nullptr) {
cout << ptr->getValue() << endl;
ptr = ptr->next;
}
}
cout << "---------------------------" << endl;
}//end displayList()
void insertFront(Node** head, int value) {
Node* newNode = new Node();
newNode->setValue(value);
//cout<< newNode->getValue() << endl;
newNode->next = *head;
*head = newNode;
}
void insertBack(Node** ptrToHead, int value) {
Node* newNode = new Node();
newNode->setValue(value);
newNode->next = nullptr;
if (*ptrToHead == nullptr)
{
*ptrToHead = newNode;
}//end if
else
{
Node* last .
Social Media - Introduction, Importance and our Responsibility to spread IslamSyeda Javeria
Brief introduction and importance of facebook, twitter, blogging and their effective use to spread the truth of Islam (and the activities of Jamaat-e-Islami Pakistan).
(In urdu + english mix)
Why You Should Replace Windows 11 with Nitrux Linux 3.5.0 for enhanced perfor...SOFTTECHHUB
The choice of an operating system plays a pivotal role in shaping our computing experience. For decades, Microsoft's Windows has dominated the market, offering a familiar and widely adopted platform for personal and professional use. However, as technological advancements continue to push the boundaries of innovation, alternative operating systems have emerged, challenging the status quo and offering users a fresh perspective on computing.
One such alternative that has garnered significant attention and acclaim is Nitrux Linux 3.5.0, a sleek, powerful, and user-friendly Linux distribution that promises to redefine the way we interact with our devices. With its focus on performance, security, and customization, Nitrux Linux presents a compelling case for those seeking to break free from the constraints of proprietary software and embrace the freedom and flexibility of open-source computing.
Epistemic Interaction - tuning interfaces to provide information for AI supportAlan Dix
Paper presented at SYNERGY workshop at AVI 2024, Genoa, Italy. 3rd June 2024
https://alandix.com/academic/papers/synergy2024-epistemic/
As machine learning integrates deeper into human-computer interactions, the concept of epistemic interaction emerges, aiming to refine these interactions to enhance system adaptability. This approach encourages minor, intentional adjustments in user behaviour to enrich the data available for system learning. This paper introduces epistemic interaction within the context of human-system communication, illustrating how deliberate interaction design can improve system understanding and adaptation. Through concrete examples, we demonstrate the potential of epistemic interaction to significantly advance human-computer interaction by leveraging intuitive human communication strategies to inform system design and functionality, offering a novel pathway for enriching user-system engagements.
A tale of scale & speed: How the US Navy is enabling software delivery from l...sonjaschweigert1
Rapid and secure feature delivery is a goal across every application team and every branch of the DoD. The Navy’s DevSecOps platform, Party Barge, has achieved:
- Reduction in onboarding time from 5 weeks to 1 day
- Improved developer experience and productivity through actionable findings and reduction of false positives
- Maintenance of superior security standards and inherent policy enforcement with Authorization to Operate (ATO)
Development teams can ship efficiently and ensure applications are cyber ready for Navy Authorizing Officials (AOs). In this webinar, Sigma Defense and Anchore will give attendees a look behind the scenes and demo secure pipeline automation and security artifacts that speed up application ATO and time to production.
We will cover:
- How to remove silos in DevSecOps
- How to build efficient development pipeline roles and component templates
- How to deliver security artifacts that matter for ATO’s (SBOMs, vulnerability reports, and policy evidence)
- How to streamline operations with automated policy checks on container images
UiPath Test Automation using UiPath Test Suite series, part 6DianaGray10
Welcome to UiPath Test Automation using UiPath Test Suite series part 6. In this session, we will cover Test Automation with generative AI and Open AI.
UiPath Test Automation with generative AI and Open AI webinar offers an in-depth exploration of leveraging cutting-edge technologies for test automation within the UiPath platform. Attendees will delve into the integration of generative AI, a test automation solution, with Open AI advanced natural language processing capabilities.
Throughout the session, participants will discover how this synergy empowers testers to automate repetitive tasks, enhance testing accuracy, and expedite the software testing life cycle. Topics covered include the seamless integration process, practical use cases, and the benefits of harnessing AI-driven automation for UiPath testing initiatives. By attending this webinar, testers, and automation professionals can gain valuable insights into harnessing the power of AI to optimize their test automation workflows within the UiPath ecosystem, ultimately driving efficiency and quality in software development processes.
What will you get from this session?
1. Insights into integrating generative AI.
2. Understanding how this integration enhances test automation within the UiPath platform
3. Practical demonstrations
4. Exploration of real-world use cases illustrating the benefits of AI-driven test automation for UiPath
Topics covered:
What is generative AI
Test Automation with generative AI and Open AI.
UiPath integration with generative AI
Speaker:
Deepak Rai, Automation Practice Lead, Boundaryless Group and UiPath MVP
LF Energy Webinar: Electrical Grid Modelling and Simulation Through PowSyBl -...DanBrown980551
Do you want to learn how to model and simulate an electrical network from scratch in under an hour?
Then welcome to this PowSyBl workshop, hosted by Rte, the French Transmission System Operator (TSO)!
During the webinar, you will discover the PowSyBl ecosystem as well as handle and study an electrical network through an interactive Python notebook.
PowSyBl is an open source project hosted by LF Energy, which offers a comprehensive set of features for electrical grid modelling and simulation. Among other advanced features, PowSyBl provides:
- A fully editable and extendable library for grid component modelling;
- Visualization tools to display your network;
- Grid simulation tools, such as power flows, security analyses (with or without remedial actions) and sensitivity analyses;
The framework is mostly written in Java, with a Python binding so that Python developers can access PowSyBl functionalities as well.
What you will learn during the webinar:
- For beginners: discover PowSyBl's functionalities through a quick general presentation and the notebook, without needing any expert coding skills;
- For advanced developers: master the skills to efficiently apply PowSyBl functionalities to your real-world scenarios.
Enchancing adoption of Open Source Libraries. A case study on Albumentations.AIVladimir Iglovikov, Ph.D.
Presented by Vladimir Iglovikov:
- https://www.linkedin.com/in/iglovikov/
- https://x.com/viglovikov
- https://www.instagram.com/ternaus/
This presentation delves into the journey of Albumentations.ai, a highly successful open-source library for data augmentation.
Created out of a necessity for superior performance in Kaggle competitions, Albumentations has grown to become a widely used tool among data scientists and machine learning practitioners.
This case study covers various aspects, including:
People: The contributors and community that have supported Albumentations.
Metrics: The success indicators such as downloads, daily active users, GitHub stars, and financial contributions.
Challenges: The hurdles in monetizing open-source projects and measuring user engagement.
Development Practices: Best practices for creating, maintaining, and scaling open-source libraries, including code hygiene, CI/CD, and fast iteration.
Community Building: Strategies for making adoption easy, iterating quickly, and fostering a vibrant, engaged community.
Marketing: Both online and offline marketing tactics, focusing on real, impactful interactions and collaborations.
Mental Health: Maintaining balance and not feeling pressured by user demands.
Key insights include the importance of automation, making the adoption process seamless, and leveraging offline interactions for marketing. The presentation also emphasizes the need for continuous small improvements and building a friendly, inclusive community that contributes to the project's growth.
Vladimir Iglovikov brings his extensive experience as a Kaggle Grandmaster, ex-Staff ML Engineer at Lyft, sharing valuable lessons and practical advice for anyone looking to enhance the adoption of their open-source projects.
Explore more about Albumentations and join the community at:
GitHub: https://github.com/albumentations-team/albumentations
Website: https://albumentations.ai/
LinkedIn: https://www.linkedin.com/company/100504475
Twitter: https://x.com/albumentations
GraphSummit Singapore | The Future of Agility: Supercharging Digital Transfor...Neo4j
Leonard Jayamohan, Partner & Generative AI Lead, Deloitte
This keynote will reveal how Deloitte leverages Neo4j’s graph power for groundbreaking digital twin solutions, achieving a staggering 100x performance boost. Discover the essential role knowledge graphs play in successful generative AI implementations. Plus, get an exclusive look at an innovative Neo4j + Generative AI solution Deloitte is developing in-house.
Securing your Kubernetes cluster_ a step-by-step guide to success !KatiaHIMEUR1
Today, after several years of existence, an extremely active community and an ultra-dynamic ecosystem, Kubernetes has established itself as the de facto standard in container orchestration. Thanks to a wide range of managed services, it has never been so easy to set up a ready-to-use Kubernetes cluster.
However, this ease of use means that the subject of security in Kubernetes is often left for later, or even neglected. This exposes companies to significant risks.
In this talk, I'll show you step-by-step how to secure your Kubernetes cluster for greater peace of mind and reliability.
Unlocking Productivity: Leveraging the Potential of Copilot in Microsoft 365, a presentation by Christoforos Vlachos, Senior Solutions Manager – Modern Workplace, Uni Systems
Communications Mining Series - Zero to Hero - Session 1DianaGray10
This session provides introduction to UiPath Communication Mining, importance and platform overview. You will acquire a good understand of the phases in Communication Mining as we go over the platform with you. Topics covered:
• Communication Mining Overview
• Why is it important?
• How can it help today’s business and the benefits
• Phases in Communication Mining
• Demo on Platform overview
• Q/A
GraphSummit Singapore | The Art of the Possible with Graph - Q2 2024Neo4j
Neha Bajwa, Vice President of Product Marketing, Neo4j
Join us as we explore breakthrough innovations enabled by interconnected data and AI. Discover firsthand how organizations use relationships in data to uncover contextual insights and solve our most pressing challenges – from optimizing supply chains, detecting fraud, and improving customer experiences to accelerating drug discoveries.
Pushing the limits of ePRTC: 100ns holdover for 100 daysAdtran
At WSTS 2024, Alon Stern explored the topic of parametric holdover and explained how recent research findings can be implemented in real-world PNT networks to achieve 100 nanoseconds of accuracy for up to 100 days.
Dr. Sean Tan, Head of Data Science, Changi Airport Group
Discover how Changi Airport Group (CAG) leverages graph technologies and generative AI to revolutionize their search capabilities. This session delves into the unique search needs of CAG’s diverse passengers and customers, showcasing how graph data structures enhance the accuracy and relevance of AI-generated search results, mitigating the risk of “hallucinations” and improving the overall customer journey.
Generative AI Deep Dive: Advancing from Proof of Concept to ProductionAggregage
Join Maher Hanafi, VP of Engineering at Betterworks, in this new session where he'll share a practical framework to transform Gen AI prototypes into impactful products! He'll delve into the complexities of data collection and management, model selection and optimization, and ensuring security, scalability, and responsible use.
Removing Uninteresting Bytes in Software FuzzingAftab Hussain
Imagine a world where software fuzzing, the process of mutating bytes in test seeds to uncover hidden and erroneous program behaviors, becomes faster and more effective. A lot depends on the initial seeds, which can significantly dictate the trajectory of a fuzzing campaign, particularly in terms of how long it takes to uncover interesting behaviour in your code. We introduce DIAR, a technique designed to speedup fuzzing campaigns by pinpointing and eliminating those uninteresting bytes in the seeds. Picture this: instead of wasting valuable resources on meaningless mutations in large, bloated seeds, DIAR removes the unnecessary bytes, streamlining the entire process.
In this work, we equipped AFL, a popular fuzzer, with DIAR and examined two critical Linux libraries -- Libxml's xmllint, a tool for parsing xml documents, and Binutil's readelf, an essential debugging and security analysis command-line tool used to display detailed information about ELF (Executable and Linkable Format). Our preliminary results show that AFL+DIAR does not only discover new paths more quickly but also achieves higher coverage overall. This work thus showcases how starting with lean and optimized seeds can lead to faster, more comprehensive fuzzing campaigns -- and DIAR helps you find such seeds.
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Essentials of Automations: The Art of Triggers and Actions in FMESafe Software
In this second installment of our Essentials of Automations webinar series, we’ll explore the landscape of triggers and actions, guiding you through the nuances of authoring and adapting workspaces for seamless automations. Gain an understanding of the full spectrum of triggers and actions available in FME, empowering you to enhance your workspaces for efficient automation.
We’ll kick things off by showcasing the most commonly used event-based triggers, introducing you to various automation workflows like manual triggers, schedules, directory watchers, and more. Plus, see how these elements play out in real scenarios.
Whether you’re tweaking your current setup or building from the ground up, this session will arm you with the tools and insights needed to transform your FME usage into a powerhouse of productivity. Join us to discover effective strategies that simplify complex processes, enhancing your productivity and transforming your data management practices with FME. Let’s turn complexity into clarity and make your workspaces work wonders!
Essentials of Automations: The Art of Triggers and Actions in FME
Link list
1.
2. LINKED LIST
PRESENTED BY:
Javeria
(11-arid-3303)
MIT-3
University Institute of Information
Technology,
Rawalpindi (UIIT, UAAR)
3. INTRODUTION
Link List is an ordered collection of elements
called nodes. The nodes are connected by
pointer.
Each node has two parts
1) Data Field – Stores data of the node. Same data
type
2) Link Field – Store address of the next node
( i.e. Link to the next node)
NEXT
NODE :
DATA
4. ARRAY VS. LINK LIST
Aspect Array Link List
Size Fixed size. Grow and contract
according to insertions
and deletions.
Storage Static: It’s location is Dynamic: It’s node is
capacity allocated during compile located during run time.
time.
Accessing the Direct or random access Sequential access
element method. method.
Specify the array index or Traverse starting from the
subscript. first node in the list by
pointer.
4
5. SINGLY LINK LIST
IMPLEMENTATION IN
STACKS:
A B C top
IMPLEMENTATION IN LINEAR
QUEUE:
front A B C rear
IMPLEMENTATION IN CIRCULAR QUEUE:
A B C rear
DOUBLY LINK LIST
A B C rear
13. Push method
void push(int x) ptr
{ x
node * ptr=new node;
top
ptr->data=x;
ptr->next=top;
top=ptr;
}
14. Push method
void push(int x) ptr
{ x
node * ptr=new node;
top
ptr->data=x;
ptr->next=top;
top=ptr;
}
15. Push method
void push(int x) ptr
{ x
node * ptr=new node;
top
ptr->data=x;
ptr->next=top;
top=ptr;
}
16. Push method
void push(int x)
{ top
ptr
node * ptr=new node;
ptr->data=x; x
ptr->next=top;
top=ptr;
}
17. - All nodes are connected to each other through
pointers
- Link of the first node is NULL pointer denoted by X
- Null pointer indicates the start of the stack list
top
D
C
B
A
18. Pop Method
int pop()
{
top
if(top==NULL)
{
cout<<"nlist emptyn"; D
return;
}
C
else
{
int temp=top->data;
node* ptr=top; B
top=top->next;
delete ptr;
return temp; A
}
}
19. Pop Method
int pop()
{ top temp=D
if(top==NULL)
{
cout<<"nlist emptyn"; D
return ;
}
C
else
{
int temp=top->data;
node* ptr=top; B
top=top->next;
delete ptr;
return temp; A
}
}
20. Pop Method
int pop()
ptr
{ top temp=D
if(top==NULL)
{
cout<<"nlist emptyn"; D
return ;
}
C
else
{
int temp=top->data;
node* ptr=top; B
top=top->next;
delete ptr;
return temp; A
}
}
21. Pop Method
int pop()
{ ptr
temp=D
if(top==NULL)
{ D
cout<<"nlist emptyn";
return ; top
}
C
else
{
int temp=top->data;
node* ptr=top; B
top=top->next;
delete ptr;
return temp; A
}
}
22. Pop Method
int pop()
{ ptr
temp=D
if(top==NULL)
{ D
cout<<"nlist emptyn";
return ; top
}
C
else
{
int temp=top->data;
node* ptr=top; B
top=top->next;
delete ptr;
return temp; A
}
}
23. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
24. Display Method
void display()
{
node * temp; tem
top
p
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
25. Display Method
void display()
{
node * temp; tem
top
p
temp=top; display D
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
26. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty"; tem
p
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
27. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty"; tem
p
return; C display C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
28. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
tem
while(temp!=NULL) p
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
29. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
tem
while(temp!=NULL) p display B
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
30. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
tem
temp=temp->next;
p
} A
}
31. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
tem
temp=temp->next;
p display A
} A
}
32. Display Method
void display()
{
node * temp;
top
temp=top;
if(top==NULL)
D
{
cout<<"stack empty";
return; C
}
while(temp!=NULL)
{ B
cout<<temp->data<<" ";
temp=temp->next;
} A
}
temp = NULL
33. Search Method
void search(int x)
{
int a=0; //index calculated from top
node * temp=top; x=B
while(temp!=NULL) a=0
{ top
if(temp->data==x)
{ D
cout<<"found at index "<<a;
break;
}
else C
{
temp=temp->next;
a++; B
}
}
if(temp==NULL)
cout<<“value not found"; A
}
};
34. Search Method
void search(int x)
{
int a=0; //index calculated from top
node * temp=top; x=B
while(temp!=NULL) tem
a=0
{ top
p
if(temp->data==x)
{ D
cout<<"found at index "<<a;
break;
}
else C
{
temp=temp->next;
a++; B
}
}
if(temp==NULL)
cout<<“value not found"; A
}
};
35. Search Method
void search(int x)
{
int a=0; //index calculated from top
node * temp=top; x=B
while(temp!=NULL) a=1
{ top
if(temp->data==x)
{ D
cout<<"found at index "<<a;
break; tem
} p
else C
{
temp=temp->next;
a++; B
}
}
if(temp==NULL)
cout<<“value not found"; A
}
};
36. Search Method
void search(int x)
{
int a=0; //index calculated from top
node * temp=top; x=B
while(temp!=NULL) a=2
{ top
if(temp->data==x)
{ D
cout<<"found at index "<<a;
break;
}
else C
{
tem
temp=temp->next;
p
a++; B
}
}
if(temp==NULL)
cout<<“value not found"; A
}
};
37. Search Method
void search(int x)
{
int a=0; //index calculated from top
node * temp=top; x=B
while(temp!=NULL) a=2
{ top
if(temp->data==x)
{ D
cout<<"found at index "<<a;
break;
}
else C
{
tem
temp=temp->next;
p
a++; found at B
} index 2
}
if(temp==NULL)
cout<<“value not found"; A
}
};
38. Main Method
case 2:
void main() y=s.pop();
{clrscr(); if(y!=NULL)
int n, a, y, z; cout<<"nvalue popped is: "<<y;
int e=0; break;
stack s; case 3:
do s.display();
{cout<<"npress 1 to push"; break;
cout<<"npress 2 to pop"; case 4:
cout<<"npress 3 to display"; cout<<“enter value to search?”;
cout<<“n press 4 to search”; cin>>z;
cout<<"npress 5to exitn"; s.search(z);
cin>>n; break;
switch(n) case 5:
{ e=1;
case 1: break;
cout<<"enter a number"; }
cin>>a; } while(e==0);
s.push(a); }
break;
39. TIME COMPLEXITY
“Time Complexity is a measure of the amount
of time required to execute an algorithm.”
Push
◦ Best Case: O(1)
◦ Worst Case: O(1)
Pop
◦ Best Case: O(1)
◦ Worst Case: O(1)
Search
◦ Best Case: O(1)
◦ Worst Case: O(n)
49. Insert Method
void insert(int x)
{
node * ptr=new
node;
ptr->data=x;
if(rear==NULL)
{
front=ptr;
}
else
rear
{ front ptr
rear->next=ptr;
} A ptr x
ptr->next=NULL;
rear=ptr;
}
50. Insert Method
void insert(int x)
{
node * ptr=new
node;
ptr->data=x;
if(rear==NULL)
{
front=ptr;
}
else
rear
{ front ptr
rear->next=ptr;
} A x
ptr->next=NULL;
rear=ptr;
}
51. Insert Method
void insert(int x)
{
node * ptr=new
node;
ptr->data=x;
if(rear==NULL)
{
front=ptr;
}
else
rear
{ front ptr
rear->next=ptr;
} A ptr x
ptr->next=NULL;
rear=ptr;
}
52. Insert Method
void insert(int x)
{
node * ptr=new
node;
ptr->data=x;
if(rear==NULL)
{
front=ptr;
}
else rear
{ front ptr
rear->next=ptr;
} A ptr x
ptr->next=NULL;
rear=ptr;
}
53. Remove Method
int remove()
{ if(rear==NULL)
{ rear temp= A
front
cout<<"nlist emptyn";
return 0; A
}
else
{
int temp=front->data;
node* ptr=front;
if(front->next==NULL)
{ rear=NULL; }
else
{ front=ptr->next; }
delete ptr;
return temp;
}
}
54. Remove Method
int remove()
temp= A
{ if(rear==NULL) ptr
{ rear
front
cout<<"nlist emptyn";
return 0; A
}
else
{
int temp=front->data;
node* ptr=front;
if(front->next==NULL)
{ rear=NULL; }
else
{ front=ptr->next; }
delete ptr;
return temp;
}
}
55. Remove Method
int remove()
temp= A
{ if(rear==NULL)
ptr
{
front rear
cout<<"nlist emptyn";
return 0; A
}
else
{
int temp=front->data;
node* ptr=front;
if(front->next==NULL)
{ rear=NULL; }
else
{ front=ptr->next; }
delete ptr;
return temp;
}
}
56. Remove Method
int remove()
temp= A
{ if(rear==NULL)
ptr
{
front rear
cout<<"nlist emptyn";
return 0; A
}
else
{
int temp=front->data;
node* ptr=front;
if(front->next==NULL)
{ rear=NULL; }
else
{ front=ptr->next; }
delete ptr;
return temp;
}
}
57. Remove Method
int remove()
{ if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
{
int temp=front->data; temp=A
node* ptr=front;
if(front->next==NULL)
ptr
{ rear=NULL; } front rear
else
A B
{ front=ptr->next; }
delete ptr;
return temp;
}
}
58. Remove Method
int remove()
{ if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
{
int temp=front->data; temp=A
node* ptr=front;
if(front->next==NULL) front
ptr
{ rear=NULL; } rear
else
A B
{ front=ptr->next; }
delete ptr;
return temp;
}
}
59. Remove Method
int remove()
{ if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
{
int temp=front->data; temp=A
node* ptr=front;
if(front->next==NULL) front
ptr
{ rear=NULL; } rear
else
A B
{ front=ptr->next; }
delete ptr;
return temp;
}
}
60. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL)
{
cout<<temp->data<<" ";
temp=temp->next;
front rear
}
A B C
}
61. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL)
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
62. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL) display A
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
63. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL)
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
64. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL) display B
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
65. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL)
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
66. Display Method
void display()
{
if(rear==NULL)
{
cout<<"list empty";
return;
}
cout<<"data in nodes of link
list:t";
node *temp=front;
while(temp!=NULL) display C
{
cout<<temp->data<<" ";
temp=temp->next; temp
front rear
}
A B C
}
67. Search Method
void search(int x)
{
int a=0;
node * temp=front;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=0
else
{
temp=temp->next; front rear
a++;
} A B C
}
if(temp==NULL)
cout<<“value not found";
}
};
68. Search Method
void search(int x)
{
int a=0;
node * temp=front;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=0
else
{ temp
temp=temp->next; front rear
a++;
} A B C
}
if(temp==NULL)
cout<<“value not found";
}
};
69. Search Method
void search(int x)
{
int a=0;
node * temp=front;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=1
else
{
temp
temp=temp->next; front rear
a++;
} A B C
}
if(temp==NULL)
cout<<“value not found";
}
};
70. Search Method
void search(int x)
{
int a=0;
node * temp=front;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=2
else
{ temp
temp=temp->next; front rear
a++;
} A B C
}
if(temp==NULL)
cout<<“value not found";
}
};
71. Search Method
void search(int x)
{
int a=0;
node * temp=front;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=2
else
{ temp
temp=temp->next; front rear
a++;
} A B C
}
found at
if(temp==NULL)
index 2
cout<<“value not found";
}
};
72. Main Method
case 2:
void main() y=q.pop();
{clrscr(); if(y!=NULL)
int n, a, y, z; cout<<"nvalue popped is: "<<y;
int e=0; break;
linearQueue q; case 3:
do q.display();
{cout<<"npress 1 to push"; break;
cout<<"npress 2 to pop"; case 4:
cout<<"npress 3 to display"; cout<<“enter value to search?”;
cout<<“n press 4 to search”; cin>>z;
cout<<"npress 5 to exitn"; q.search(z);
cin>>n; break;
switch(n) case 5:
{ e=1;
case 1: break;
cout<<"enter a number"; }
cin>>a; } while(e==0);
q.push(a); }
break;
73. TIME COMPLEXITY
Insert
◦ Best Case: O(1)
◦ Worst Case: O(1)
Remove
◦ Best Case: O(1)
◦ Worst Case: O(1)
Search
◦ Best Case: O(1)
◦ Worst Case: O(n)
86. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0; rear
}
else A Address
of itself
{
int temp=rear->next->data;
node* ptr=rear->next;
if(rear==rear->next)
{ rear=NULL;
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
87. Remove
Method
int remove()
{
if(rear==NULL) temp=A
{
cout<<"nlist emptyn";
return 0; rear
}
else A Address
of itself
{
int temp=rear->next->data;
node* ptr=rear->next;
if(rear==rear->next)
{ rear=NULL;
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
88. Remove
Method
int remove()
{
if(rear==NULL) temp=A
{
cout<<"nlist emptyn"; ptr
return 0; rear
}
else A Address
of itself
{
int temp=rear->next->data;
node* ptr=rear->next;
if(rear==rear->next)
{ rear=NULL;
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
89. Remove
Method
int remove()
{
if(rear==NULL) temp=A
{
cout<<"nlist emptyn"; ptr
return 0;
}
else A Address
of itself
{
int temp=rear->next->data;
node* ptr=rear->next; rear
if(rear==rear->next)
{ rear=NULL;
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
90. Remove
Method
int remove()
{
if(rear==NULL) temp=A
{
cout<<"nlist emptyn"; ptr
return 0;
}
else A Address
of itself
{
int temp=rear->next->data;
node* ptr=rear->next; rear
if(rear==rear->next)
{ rear=NULL;
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
91. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
{
int temp=rear->next->data;
node* ptr=rear->next; rear
if(rear==rear->next)
{ rear=NULL; A B C
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
92. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
temp=A
{
int temp=rear->next->data;
node* ptr=rear->next; rear
if(rear==rear->next)
{ rear=NULL; A B C
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
93. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
temp=A
{
int temp=rear->next->data;
node* ptr=rear->next; ptr rear
if(rear==rear->next)
{ rear=NULL; A B C
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
94. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
temp=A
{
int temp=rear->next->data;
node* ptr=rear->next; ptr rear
if(rear==rear->next)
{ rear=NULL; A B C
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
95. Remove
Method
int remove()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return 0;
}
else
temp=A
{
int temp=rear->next->data;
node* ptr=rear->next; ptr rear
if(rear==rear->next)
{ rear=NULL; A B C
}
else
{rear->next=rear->next->next;
}
delete ptr;
return temp;
}
}
96. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{
cout<<temp->data<<" ";
temp=temp->next;
}while(temp!=rear->next); rear
}
A B C
.
97. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{
cout<<temp->data<<" ";
temp=temp->next;
}while(temp!=rear->next);
temp rear
}
. A B C
98. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{ display A
cout<<temp->data<<" ";
temp=temp->next;
}while(temp!=rear->next);
temp rear
}
. A B C
99. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{
cout<<temp->data<<" ";
temp=temp->next;
}while(temp!=rear->next); temp rear
}
A B C
.
100. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{ display B
cout<<temp->data<<" ";
temp=temp->next;
}while(temp!=rear->next); temp rear
}
A B C
.
101. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{
cout<<temp->data<<" ";
temp=temp->next; temp
}while(temp!=rear->next); rear
}
A B C
.
102. Display Method
void display()
{
if(rear==NULL)
{
cout<<"nlist emptyn";
return;
}
node * temp=rear->next;
do
{ display C
cout<<temp->data<<" ";
temp=temp->next; temp
}while(temp!=rear->next); rear
}
A B C
.
103. Search Method
void search(int x)
{
int a=0;
node * temp= rear->next
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=0
else
{
temp=temp->next;
a++; rear
} C
} A B
if(temp==NULL)
cout<<“value not found";
}
};
104. Search Method
void search(int x)
{
int a=0;
node * temp=rear->next;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=0
else
{
temp=temp->next; temp
a++; rear
} C
} A B
if(temp==NULL)
cout<<“value not found";
}
};
105. Search Method
void search(int x)
{
int a=0;
node * temp=rear->next;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=1
else
{
temp=temp->next; temp
a++; rear
} C
} A B
if(temp==NULL)
cout<<“value not found";
}
};
106. Search Method
void search(int x)
{
int a=0;
node * temp=rear->next;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=2
else
{
temp=temp->next; temp
a++; rear
} C
} A B
if(temp==NULL)
cout<<“value not found";
}
};
107. Search Method
void search(int x)
{
int a=0;
node * temp=rear->next;
while(temp!=NULL)
{
if(temp->data==x)
{
cout<<"found at index "<<a;
break; x=C
} a=2
else
{
temp=temp->next; temp
a++; rear
} C
} A B
found at
if(temp==NULL)
index 2
cout<<“value not found";
}
};
108. Main Method
case 2:
void main() y=q.pop();
{clrscr(); if(y!=NULL)
int n, a, y, z; cout<<"nvalue popped is: "<<y;
int e=0; break;
circularQueue q; case 3:
do q.display();
{cout<<"npress 1 to push"; break;
cout<<"npress 2 to pop"; case 4:
cout<<"npress 3 to display"; cout<<“enter value to search?”;
cout<<“n press 4 to search”; cin>>z;
cout<<"npress 5 to exitn"; q.search(z);
cin>>n; break;
switch(n) case 5:
{ e=1;
case 1: break;
cout<<"enter a number"; }
cin>>a; } while(e==0);
q.push(a); }
break;
109. TIME COMPLEXITY
Insert
◦ Best Case: O(1)
◦ Worst Case: O(1)
Remove
◦ Best Case: O(1)
◦ Worst Case: O(1)
Search
◦ Best Case: O(1)
◦ Worst Case: O(n)