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LINEAR EQUATION IN
ONE VARIABLE
Prepared by:
SHARDA CHAUHAN
TGT MATHEMATICS
A statement which states that two algebraic expressions are equal is called
an equation.
3x  2y  8
6  x  x  9
3X2
 5  X 
5
The equation involving only one variable in first order is called a linear
equation in one variable.
3x50
8y 2
7a153a
PROPERTIES OF AN EQUATION
•If same quantity is added to both sides of the equation,
the sums are equal.
Thus: x=7 => x+a=7+a
•If same quantity is subtracted from both sides of an
equation, the differences are equal
Thus: x=7 => x-a=7-a
•If both the sides of an equation are multiplied by the
same quantity, the products are equal.
Thus: x=7 => ax=7a
•If both the sides of an equation are divided by the same
quantity, the quotients are equal.
Thus: x=7 => x÷a=7÷a
TO SOLVE AN EQUATION
1.To solve an equation of the form x+a=b
=> x+4-4=10-4 (subtracting 4 from both the
E.g.: Solve x+4=10
Solution: x+4=10
sides)
=> x=6
2.To solve an equation of the form x-a=b
E.g.: Solve y-6=5 equal.
Solution: y-6=5 (adding 6 to both sides)
=> y-6+6=5+6
=> y=11
3.TO SOLVE AN EQUATION OF THE
FORM AX=B
E.G.: SOLVE
3X=9
SOLUTION: 3X=9
4. To solve an equation of the form x/a=b
E.g.: Solve = 6
Solution: ×=6×2
3
=> x =
x
2
=> x=12
SHORT- CUT METHOD (SOLVING AN
EQUATION BY TRANSPOSING TERMS)
1.In an equation, an added term is transposed (taken) from one side to the
other, it is subtracted.
i.e., x+4=10
=> x=10-4=6 (4 is transposed)
2. In an equation, a subtracted term is transposed to the other side, it is added.
i.e., y-6=5
=>y=5+6=11
3. In an equation, a term in multiplication is transposed to the other side, it is
divided.
i.e., 3x=12
=>x=12/3=4
4. In an equation a term in division is taken to the other side it is multiplied.
i.e
=> y=6×4=24 (4 is transposed)
x
(6 is transposed)
(3 is transposed)
TO SOLVE EQUATIONS USING MORE THAN ONE
PROPERTY
Solve: (1) 3x+8=14
Solution: (transposing 8)
3x=14-8
=> 3x=6
=> x=6/3 (transposing 3)
=>x=2
(2)2A-3=5
Solution: (transposing 3)
(transposing2)
2a=5+3
=> 2a=8
=> a = 8/2
=> a = 4
(3) 5N/8 =20
Solution: 5n=20×8
=> n =204×8/51
=> n=4×8=32
SOL
VINGANEQUA
TIONWITHV
ARIABLEON
BOTHTHESIDES
Transpose the terms containing the variable, to one
side and the constants to the other side
.
E.g.: (1) Solve 10y-3=7y+9
Solution: 10y-7y = 9+3 (transposing 7y to the
left & 3 to the right)
=> 3y = 12
=> y = 12/3
=> y = 4
(2) Solve 2(x-5) + 3(x-2) = 8+7(x-4)
Solution: 2x-10+3x-6=8+7x-28
(removing the brackets)
=> 5x-16 = 7x-20
=> 5x-7x = -20+16
=>
=>
=>
-2x = -4
x = -4/-2
x = 2
SOLVING WORD PROBLEMS
•A number increased by 8 equal 15. Find
the number?
Solution: Let the number be ‘x’
Given, the number increased by 8 equal 15.
=> x+8 = 15
=> x = 15-8
=> x = 7
•A number is decreased by 15 and the new number
so obtained is multiplied by 3; the result is 81.Find
the number?
Solution: Let the number be ‘x’
The number decreased by 15 = x-15
The new number (x-15) multiplied by 3 = 3(x-15)
Given 3(x-15) = 81
=> 3x-45 = 81
=> 3x = 81 + 45
=> 3x = 126
=> x
3
=> x = 42
= 126
3) A MAN IS 26 YEARS OLDER THAN HIS SON.
AFTER 10 YEARS, HE WILL BE THREE TIMES AS
OLD AS HIS SON. FIND THEIR PRESENT AGES?
• Solution: let son’s present age= x years Then father’s age =
x+26
• After ten years,
• Son’s age = x+10
• Father’s age = x+26+10 =x+36
Given, x+36 = 3(x+10)
=> x+36 =3x+30
=> x-3x =30-36
=> -2x =-6
=> x =
=>x=3
•Son’s age = 3 years
•Father’s age = 3 + 26=29years
Any Questions?
ASK!

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linear equations.pptx

  • 1. LINEAR EQUATION IN ONE VARIABLE Prepared by: SHARDA CHAUHAN TGT MATHEMATICS
  • 2. A statement which states that two algebraic expressions are equal is called an equation. 3x  2y  8 6  x  x  9 3X2  5  X  5 The equation involving only one variable in first order is called a linear equation in one variable. 3x50 8y 2 7a153a
  • 3. PROPERTIES OF AN EQUATION •If same quantity is added to both sides of the equation, the sums are equal. Thus: x=7 => x+a=7+a •If same quantity is subtracted from both sides of an equation, the differences are equal Thus: x=7 => x-a=7-a •If both the sides of an equation are multiplied by the same quantity, the products are equal. Thus: x=7 => ax=7a •If both the sides of an equation are divided by the same quantity, the quotients are equal. Thus: x=7 => x÷a=7÷a
  • 4. TO SOLVE AN EQUATION 1.To solve an equation of the form x+a=b => x+4-4=10-4 (subtracting 4 from both the E.g.: Solve x+4=10 Solution: x+4=10 sides) => x=6 2.To solve an equation of the form x-a=b E.g.: Solve y-6=5 equal. Solution: y-6=5 (adding 6 to both sides) => y-6+6=5+6 => y=11
  • 5. 3.TO SOLVE AN EQUATION OF THE FORM AX=B E.G.: SOLVE 3X=9 SOLUTION: 3X=9 4. To solve an equation of the form x/a=b E.g.: Solve = 6 Solution: ×=6×2 3 => x = x 2 => x=12
  • 6. SHORT- CUT METHOD (SOLVING AN EQUATION BY TRANSPOSING TERMS) 1.In an equation, an added term is transposed (taken) from one side to the other, it is subtracted. i.e., x+4=10 => x=10-4=6 (4 is transposed) 2. In an equation, a subtracted term is transposed to the other side, it is added. i.e., y-6=5 =>y=5+6=11 3. In an equation, a term in multiplication is transposed to the other side, it is divided. i.e., 3x=12 =>x=12/3=4 4. In an equation a term in division is taken to the other side it is multiplied. i.e => y=6×4=24 (4 is transposed) x (6 is transposed) (3 is transposed)
  • 7. TO SOLVE EQUATIONS USING MORE THAN ONE PROPERTY Solve: (1) 3x+8=14 Solution: (transposing 8) 3x=14-8 => 3x=6 => x=6/3 (transposing 3) =>x=2
  • 9. (3) 5N/8 =20 Solution: 5n=20×8 => n =204×8/51 => n=4×8=32
  • 10. SOL VINGANEQUA TIONWITHV ARIABLEON BOTHTHESIDES Transpose the terms containing the variable, to one side and the constants to the other side . E.g.: (1) Solve 10y-3=7y+9 Solution: 10y-7y = 9+3 (transposing 7y to the left & 3 to the right) => 3y = 12 => y = 12/3 => y = 4
  • 11. (2) Solve 2(x-5) + 3(x-2) = 8+7(x-4) Solution: 2x-10+3x-6=8+7x-28 (removing the brackets) => 5x-16 = 7x-20 => 5x-7x = -20+16 => => => -2x = -4 x = -4/-2 x = 2
  • 12. SOLVING WORD PROBLEMS •A number increased by 8 equal 15. Find the number? Solution: Let the number be ‘x’ Given, the number increased by 8 equal 15. => x+8 = 15 => x = 15-8 => x = 7
  • 13. •A number is decreased by 15 and the new number so obtained is multiplied by 3; the result is 81.Find the number? Solution: Let the number be ‘x’ The number decreased by 15 = x-15 The new number (x-15) multiplied by 3 = 3(x-15) Given 3(x-15) = 81 => 3x-45 = 81 => 3x = 81 + 45 => 3x = 126 => x 3 => x = 42 = 126
  • 14. 3) A MAN IS 26 YEARS OLDER THAN HIS SON. AFTER 10 YEARS, HE WILL BE THREE TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES? • Solution: let son’s present age= x years Then father’s age = x+26 • After ten years, • Son’s age = x+10 • Father’s age = x+26+10 =x+36 Given, x+36 = 3(x+10) => x+36 =3x+30 => x-3x =30-36 => -2x =-6 => x = =>x=3 •Son’s age = 3 years •Father’s age = 3 + 26=29years