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Slope Deflection Method for the Analysis of
Indeterminate Structures
By
Prof. Dr. Omprakash Netula
Slope Deflection Method
All structures must satisfy:
• Load-displacement relationship
• Equilibrium of forces
• Compatibility of displacements
Using the principle of superposition by considering
separately the moments developed at each support
of a typical prismatic beam (AB) shown in Fig. 1 of a
continuous beam, due to each of the displacements
, , and the applied loads. Assume
clockwise moments are +ive.
1. Assume ends A and B are fixed, i., e., the rotations
. This means that we have to apply
counterclockwise moment at end A and
clockwise moment at end B
due to the applied loads to cause zero
rotation at each of ends A and B. Table (1) gives
for different loading conditions.
Table (1)
2. Release end A against rotation at end A (rotates to its final
position ) by applying clockwise moment while far
end node B is held fixed as shown in Fig. 1.
3. Now, the clockwise moment - rotation relationship is:
4. The carry over moment at end B is:
5. In a similar manner, if end B of the beam rotates to its final
position , while end A is held fixed. The clockwise
moment – rotation relationship is:
6. The carry over moment at end A is:
7. If node B is displaced relative to as shown in Fig. (1), so that
the cord of the member rotates clockwise i., e., positive
displacement and yet both ends do not rotate, then equal
but anticlockwise moments are developed in the member
as shown in the figure.
Slope-Deflection Equation
Load-displacement relationship
If the end moments due to each displacement and the
loading are added together, the resultant moments at the
ends may then be written as:

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L10 slope deflection method for the analysis of indeterminate

  • 1. Slope Deflection Method for the Analysis of Indeterminate Structures By Prof. Dr. Omprakash Netula
  • 2. Slope Deflection Method All structures must satisfy: • Load-displacement relationship • Equilibrium of forces • Compatibility of displacements
  • 3. Using the principle of superposition by considering separately the moments developed at each support of a typical prismatic beam (AB) shown in Fig. 1 of a continuous beam, due to each of the displacements , , and the applied loads. Assume clockwise moments are +ive.
  • 4.
  • 5. 1. Assume ends A and B are fixed, i., e., the rotations . This means that we have to apply counterclockwise moment at end A and clockwise moment at end B due to the applied loads to cause zero rotation at each of ends A and B. Table (1) gives for different loading conditions.
  • 7. 2. Release end A against rotation at end A (rotates to its final position ) by applying clockwise moment while far end node B is held fixed as shown in Fig. 1. 3. Now, the clockwise moment - rotation relationship is:
  • 8. 4. The carry over moment at end B is: 5. In a similar manner, if end B of the beam rotates to its final position , while end A is held fixed. The clockwise moment – rotation relationship is:
  • 9. 6. The carry over moment at end A is: 7. If node B is displaced relative to as shown in Fig. (1), so that the cord of the member rotates clockwise i., e., positive displacement and yet both ends do not rotate, then equal but anticlockwise moments are developed in the member as shown in the figure.
  • 10. Slope-Deflection Equation Load-displacement relationship If the end moments due to each displacement and the loading are added together, the resultant moments at the ends may then be written as: