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Subject Name: Theory of Structures
Topic Name:DEGREE OF INDETERMENCY OF SPACE TRUSS
Lecture No: 5
Dr.Omprakash Netula
Professor & HOD
Department of Civil Engineering
7/24/2017 Lecture Number, Unit Number 1
• If inextensibility of members is considered i.e. axial deformation of members is
neglected, the no. of constraints or the no. of compatibility equations due to
inextensibility of the members is equal to the no. of members.
Dkand = Degree of kinematic indeterminacy neglecting axial deformations.
Dkand = 2j – (R + m) … for plane truss
Dkand = 3j – (R + m) … for space truss
Dkand = 3j – (R + m) … for plane frame
Dkand = 6j – (R + m) … for space frame
• In case of beams & plane frame with internal hinge or link:
Dk = 3(j + j’) – R + rr
DEGREE OF REDUNDANCY OF SPACE TRUSS
Example:
R = 3 + 1 + 2 = 6
m = 10
J = 9
Dkand = 3j – (R + m)
= 3 x 9 – (6 + 10)
= 11
PRINCIPLE OF SUPERPOSITION:
• Super position allows us to
separate the loads in any
desired way, analyse the
structure for a separate set of
loads & find the result for the
sum of loads by adding
individual load effects.
• Superposition applies equally to
forces , stresses, strains &
displacements.
Example:
R = 3 + 1 + 2 = 6
m = 10
J = 9
Dkand = 3j – (R + m)
= 3 x 9 – (6 + 10)
= 11
PRINCIPLE OF SUPERPOSITION:
• Super position allows us to
separate the loads in any
desired way, analyse the
structure for a separate set of
loads & find the result for the
sum of loads by adding
individual load effects.
• Superposition applies equally to
forces , stresses, strains &
displacements.

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L5

  • 1. Subject Name: Theory of Structures Topic Name:DEGREE OF INDETERMENCY OF SPACE TRUSS Lecture No: 5 Dr.Omprakash Netula Professor & HOD Department of Civil Engineering 7/24/2017 Lecture Number, Unit Number 1
  • 2. • If inextensibility of members is considered i.e. axial deformation of members is neglected, the no. of constraints or the no. of compatibility equations due to inextensibility of the members is equal to the no. of members. Dkand = Degree of kinematic indeterminacy neglecting axial deformations. Dkand = 2j – (R + m) … for plane truss Dkand = 3j – (R + m) … for space truss Dkand = 3j – (R + m) … for plane frame Dkand = 6j – (R + m) … for space frame • In case of beams & plane frame with internal hinge or link: Dk = 3(j + j’) – R + rr DEGREE OF REDUNDANCY OF SPACE TRUSS
  • 3. Example: R = 3 + 1 + 2 = 6 m = 10 J = 9 Dkand = 3j – (R + m) = 3 x 9 – (6 + 10) = 11
  • 4. PRINCIPLE OF SUPERPOSITION: • Super position allows us to separate the loads in any desired way, analyse the structure for a separate set of loads & find the result for the sum of loads by adding individual load effects. • Superposition applies equally to forces , stresses, strains & displacements.
  • 5. Example: R = 3 + 1 + 2 = 6 m = 10 J = 9 Dkand = 3j – (R + m) = 3 x 9 – (6 + 10) = 11
  • 6. PRINCIPLE OF SUPERPOSITION: • Super position allows us to separate the loads in any desired way, analyse the structure for a separate set of loads & find the result for the sum of loads by adding individual load effects. • Superposition applies equally to forces , stresses, strains & displacements.