CHAPTER 6 INVERSES & ONE-to-ONE Functions
Inverse Functions Example Also,  f   [ g (12)] = 12. For these functions, it can be  shown that  for any value of  x . These functions are  inverse functions   of each other.
Only functions that are one-to-one have inverses. One-to-One Functions A function  f   is a  one-to-one   function  if, for elements  a  and  b  from the domain of  f ,  a      b   implies  f   ( a )     f   ( b ).
One-to-One Functions Example  Decide whether each function is one-to-one. (a)   (b)  Solution (a)  For this function, two different  x -values produce two different  y -values. (b) If we choose  a  = 3 and  b  =  –3, then 3    –3, but
Horizontal Line Test Example   Use the horizontal line test to determine  whether the graphs are graphs of one-to-one functions. (a)   (b) If every horizontal line intersects the graph of a function at no more than one point, then the function is one-to-one. Not one-to-one One-to-one
Inverse Functions Example are inverse functions of each other. Let  f  be a one-to-one function. Then,  g  is the  inverse   function  of  f  and  f   is the inverse of  g  if
Finding an Equation for the Inverse  Function . Finding the Equation of the Inverse of  y  =  f ( x ) For a one-to-one function  f  defined by an equation  y  =  f ( x ) , find the defining equation of the inverse as follows.  ( Any restrictions on  x  and  y  should be considered.) 1.  Interchange  x  and  y. 2.  Solve for  y. 3 . Replace  y  with  f   -1 ( x ).
Example of Finding  f   -1 ( x ) Example Find the inverse, if it exists, of Solution Write  f   ( x ) =  y . Interchange  x  and  y . Solve for  y . Replace  y  with  f   -1 ( x ).
The Graph of  f   -1 ( x ) f  and  f   -1 ( x ) are inverse functions, and  f   ( a ) =  b  for real numbers  a  and  b . Then  f   -1 ( b ) =  a .  If the point ( a , b ) is on the graph of  f , then the point ( b , a ) is on the graph of  f   -1 . If a function is one-to-one, the graph of its inverse  f  -1 ( x ) is a reflection of the graph of  f  across the line  y  =  x .
Finding the Inverse of a Function  with a Restricted Domain Example Let  Solution Notice that the domain of  f  is restricted  to [ – 5,  ), and its range is [0,   ). It is one-to-one and  thus has an inverse. The range of  f  is the domain of  f   -1 , so its inverse is
Important Facts About Inverses If  f  is one-to-one, then  f   -1  exists. The domain of  f  is the range of  f   -1 , and the range of  f   is the domain of  f   -1 . If the point ( a , b ) is on the graph of  f , then the point ( b , a ) is on the graph of  f   -1 , so the graphs of  f  and  f   -1  are reflections of each other across the line  y  =  x .
Application of Inverse Functions Example   Use the one-to-one function  f   ( x ) = 3 x  + 1 and the  numerical values in the table to code the message BE VERY CAREFUL. A 1 F 6 K  11 P  16 U 21 B  2 G  7 L  12 Q  17 V 22 C  3 H  8 M  13 R  18 W 23 D 4 I  9 N  14 S  19 X 24 E  5 J  10 O  15  T  20 Y  25 Z  26 Solution BE VERY CAREFUL would be encoded as 7  16  67  16  55  76  10  4  55  16  19  64  37  because B corresponds to 2, and  f   (2) = 3(2) + 1 = 7, and so on.

Inverses & One-to-One

  • 1.
    CHAPTER 6 INVERSES& ONE-to-ONE Functions
  • 2.
    Inverse Functions ExampleAlso, f [ g (12)] = 12. For these functions, it can be shown that for any value of x . These functions are inverse functions of each other.
  • 3.
    Only functions thatare one-to-one have inverses. One-to-One Functions A function f is a one-to-one function if, for elements a and b from the domain of f , a  b implies f ( a )  f ( b ).
  • 4.
    One-to-One Functions Example Decide whether each function is one-to-one. (a) (b) Solution (a) For this function, two different x -values produce two different y -values. (b) If we choose a = 3 and b = –3, then 3  –3, but
  • 5.
    Horizontal Line TestExample Use the horizontal line test to determine whether the graphs are graphs of one-to-one functions. (a) (b) If every horizontal line intersects the graph of a function at no more than one point, then the function is one-to-one. Not one-to-one One-to-one
  • 6.
    Inverse Functions Exampleare inverse functions of each other. Let f be a one-to-one function. Then, g is the inverse function of f and f is the inverse of g if
  • 7.
    Finding an Equationfor the Inverse Function . Finding the Equation of the Inverse of y = f ( x ) For a one-to-one function f defined by an equation y = f ( x ) , find the defining equation of the inverse as follows. ( Any restrictions on x and y should be considered.) 1. Interchange x and y. 2. Solve for y. 3 . Replace y with f -1 ( x ).
  • 8.
    Example of Finding f -1 ( x ) Example Find the inverse, if it exists, of Solution Write f ( x ) = y . Interchange x and y . Solve for y . Replace y with f -1 ( x ).
  • 9.
    The Graph of f -1 ( x ) f and f -1 ( x ) are inverse functions, and f ( a ) = b for real numbers a and b . Then f -1 ( b ) = a . If the point ( a , b ) is on the graph of f , then the point ( b , a ) is on the graph of f -1 . If a function is one-to-one, the graph of its inverse f -1 ( x ) is a reflection of the graph of f across the line y = x .
  • 10.
    Finding the Inverseof a Function with a Restricted Domain Example Let Solution Notice that the domain of f is restricted to [ – 5,  ), and its range is [0,  ). It is one-to-one and thus has an inverse. The range of f is the domain of f -1 , so its inverse is
  • 11.
    Important Facts AboutInverses If f is one-to-one, then f -1 exists. The domain of f is the range of f -1 , and the range of f is the domain of f -1 . If the point ( a , b ) is on the graph of f , then the point ( b , a ) is on the graph of f -1 , so the graphs of f and f -1 are reflections of each other across the line y = x .
  • 12.
    Application of InverseFunctions Example Use the one-to-one function f ( x ) = 3 x + 1 and the numerical values in the table to code the message BE VERY CAREFUL. A 1 F 6 K 11 P 16 U 21 B 2 G 7 L 12 Q 17 V 22 C 3 H 8 M 13 R 18 W 23 D 4 I 9 N 14 S 19 X 24 E 5 J 10 O 15 T 20 Y 25 Z 26 Solution BE VERY CAREFUL would be encoded as 7 16 67 16 55 76 10 4 55 16 19 64 37 because B corresponds to 2, and f (2) = 3(2) + 1 = 7, and so on.