SlideShare a Scribd company logo
Table of Integrals∗
                             Basic Forms                                                          Integrals with Roots

                                     1                                                           √               2
                          xn dx =       xn+1 + c                    (1)                              x − adx =     (x − a)3/2 + C             (17)
                                    n+1                                                                          3
                              1                                                                         1        √
                                dx = ln x + c                       (2)                            √       dx = 2 x ± a + C                   (18)
                              x                                                                        x±a
                                                                                                        1        √
                             udv = uv −     vdu                     (3)                            √       dx = 2 a − x + C                   (19)
                                                                                                       a−x
                       1        1
                            dx = ln |ax + b| + c                    (4)
                     ax + b     a                                                  √         2             2
                                                                                  x x − adx = a(x − a)3/2 + (x − a)5/2 + C                    (20)
                                                                                             3             5
              Integrals of Rational Functions
                                                                                         √                   2b   2x     √
                            1             1                                                  ax + bdx =         +            ax + b + C       (21)
                                  dx = −     +c                     (5)                                      3a    3
                         (x + a)2        x+a
                                                                                                                  2
                            (x + a)n+1                                                     (ax + b)3/2 dx =         (ax + b)5/2 + C           (22)
                         n
               (x + a) dx =            + c, n = −1                  (6)                                          5a
                               n+1
                                                                                                  x      2        √
                                                                                             √       dx = (x ± 2a) x ± a + C                  (23)
                                                                                                 x±a     3
                          (x + a)n+1 ((n + 1)x − a)
           x(x + a)n dx =                           +c              (7)
                               (n + 1)(n + 2)
                                                                                               x
                             1                                                                    dx = −         x(a − x)
                                 dx = tan−1 x + c                   (8)                       a−x
                          1 + x2
                                                                                                                       x(a − x)
                                                                                                          − a tan−1             +C            (24)
                         1        1     x                                                                              x−a
                              dx = tan−1 + c                        (9)
                      a2 + x2     a     a
                         x        1                                                            x
                              dx = ln |a2 + x2 | + c               (10)                           dx =         x(a + x)
                    a2   +x 2     2                                                           a+x
                                                                                                                 √     √
                         x2                   x                                                           − a ln x + x + a + C                (25)
                              dx = x − a tan−1 + c                 (11)
                    a2   +x 2                 a
                   x3       1    1                                                       √
                        dx = x2 − a2 ln |a2 + x2 | + c             (12)
              a2   + x2     2    2                                                      x ax + bdx =
                                                                                          2                         √
           1                2             2ax + b                                           2
                                                                                              (−2b2 + abx + 3a2 x2 ) ax + b + C               (26)
                   dx = √          tan−1 √          + C (13)                             15a
     ax 2 + bx + c               2
                          4ac − b          4ac − b2

                   1              1    a+x                                                                  1
                            dx =    ln     , a=b                   (14)             x(ax + b)dx =               (2ax + b) ax(ax + b)
             (x + a)(x + b)      b−a b+x                                                                 4a3/2
                                                                                                               √
                   x            a                                                                      −b2 ln a x + a(ax + b) + C             (27)
                        2
                          dx =     + ln |a + x| + C                (15)
                (x + a)        a+x

           x             1                                                                               b     b2  x
                   dx =    ln |ax2 + bx + c|                                      x3 (ax + b)dx =          − 2 +       x3 (ax + b)
    ax2   + bx + c      2a                                                                             12a 8a x 3
                             b               2ax + b                                                   b3       √
                      − √            tan−1 √           + C (16)                                      + 5/2 ln a x + a(ax + b) + C (28)
                        a 4ac − b  2          4ac − b2                                                8a
   ∗ c 2007. From http://integral-table.com, last revised December 6, 2007. This material is provided as is without warranty or representation

about the accuracy, correctness or suitability of this material for any purpose. Some restrictions on use and distribution may apply, including the
terms of the Creative Commons Attribution-Noncommercial-Share Alike 3.0 Unported License. See the web site for details. The formula numbers
on this document may be different from the formula numbers on the web page.


                                                                          1
Integrals with Logarithms
                               1
              x2 ± a2 dx =       x x2 ± a2
                               2                                                           ln axdx = x ln ax − x + C                (41)
                               1
                              ± a2 ln x + x2 ± a2 + C          (29)
                               2                                                           ln ax     1       2
                                                                                                 dx = (ln ax) + C                   (42)
                                                                                             x       2
                               1
               a2 − x2 dx =      x a2 − x2                                                         b
                               2                                          ln(ax + b)dx =      x+       ln(ax + b) − x + C, a = 0 (43)
                               1             x                                                     a
                              + a2 tan−1 √         +C          (30)
                               2           a2 − x2


                                    1 2          3/2                            ln a2 x2 ± b2 dx = x ln a2 x2 ± b2
               x    x2 ± a2 dx =      x ± a2           +C      (31)
                                    3                                                                      2b       ax
                                                                                                       +      tan−1    − 2x + C     (44)
                   1                                                                                       a         b
              √          dx = ln x +         x2 ± a2 + C       (32)
                x 2 ± a2


                             1               x                                  ln a2 − b2 x2 dx = x ln ar − b2 x2
                       √           dx = sin−1 + C              (33)
                           a2 − x2           a
                                                                                                           2a       bx
                                                                                                       +      tan−1    − 2x + C     (45)
                          x                                                                                 b        a
                    √           dx =      x2 ± a2 + C          (34)
                        x2 ± a2
                         x                                                                             1                    2ax + b
                   √           dx = −      a2 − x2 + C         (35)        ln ax2 + bx + c dx =             4ac − b2 tan−1 √
                       a2 − x2                                                                         a                     4ac − b2
                                                                                           b
                                                                             − 2x +          + x ln ax2 + bx + c + C                (46)
                                                                                          2a
              x2         1
          √          dx = x x2 ± a2
            x 2 ± a2     2
                         1 2                                                                    bx 1 2
                           a ln x + x2 ± a2 + C                (36)         x ln(ax + b)dx =      − x
                         2                                                                      2a 4
                                                                                                1     b2
                                                                                              +   x2 − 2         ln(ax + b) + C     (47)
                                                                                                2     a
                                b + 2ax
    ax2 + bx + cdx =                       ax2 + bx + c
                                   4a
                                                                                                1
        4ac − b2                                                          x ln a2 − b2 x2 dx = − x2 +
+                ln 2ax + b + 2           a(ax2 + bx+ c) + C   (37)                             2
         8a3/2
                                                                                            1       a2
                                                                                               x2 − 2           ln a2 − b2 x2 + C (48)
                                                                                            2       b
                     1      √
x    ax2 + bx + c =   5/2
                          2 a ax2 + bx + c                                          Integrals with Exponentials
                   48a
− 3b2 + 2abx + 8a(c + ax2 )
                            √                                                                              1 ax
                                                                                              eax dx =       e +C                   (49)
+3(b3 − 4abc) ln b + 2ax + 2 a ax2 + bx + x                    (38)                                        a

                                                                                                       √
                                                                              √     ax    1 √ ax      i π      √
                    1                                                             xe dx =    xe + 3/2 erf i ax + C,
          √                  dx =                                                         a          2a
                                                                                                             x
              ax2   + bx + c                                                                            2         2

           1                                                                            where erf(x) = √       e−t dtet             (50)
          √ ln 2ax + b + 2           a(ax2 + bx + c) + C       (39)                                      π 0
            a
                                                                                            xex dx = (x − 1)ex + C                  (51)
              x             1
    √                  dx =         ax2 + bx + c                                                       x   1
        ax2   + bx + c      a                                                            xeax dx =       −        eax + C           (52)
       b                                                                                               a a2
    + 3/2 ln 2ax + b + 2               a(ax2 + bx + c) + C     (40)
     2a
                                                                                         x2 ex dx = x2 − 2x + 2 ex + C              (53)


                                                                      2
x2  2x   2                                                                1
       x2 eax dx =            − 2 + 3      eax + C       (54)                     sin2 x cos xdx =     sin3 x + C         (68)
                           a   a   a                                                                 3

       x3 ex dx = x3 − 3x2 + 6x − 6 ex + C               (55)                                cos[(2a − b)x] cos bx
                                                                         cos2 ax sin bxdx =                 −
                                                                                               4(2a − b)       2b
                                                                                             cos[(2a + b)x]
                       1                                                                   −                +C            (69)
      xn eax dx = (−1)n Γ[1 + n, −ax],                                                         4(2a + b)
                       a
                                       ∞
                   where Γ(a, x) =         ta−1 e−t dt   (56)                                         1
                                                                            cos2 ax sin axdx = −        cos3 ax + C       (70)
                                      x                                                              3a
                        √
                2      i π      √
             eax dx = − √ erf ix a                       (57)                            x sin 2ax sin[2(a − b)x]
                       2 a                                          sin2 ax cos2 bxdx =     −       −
                                                                                         4      8a       16(a − b)
Integrals with Trigonometric Functions                                                   sin 2bx sin[2(a + b)x]
                                                                                       +        −               +C        (71)
                                                                                            8b     16(a + b)
                         1
             sin axdx = − cos ax + C                     (58)                                        x sin 4ax
                         a                                                 sin2 ax cos2 axdx =         −       +C         (72)
                                                                                                     8   32a
                             x sin 2ax
            sin2 axdx =        −       +C                (59)                                 1
                             2    4a                                              tan axdx = − ln cos ax + C              (73)
                                                                                              a
                                                                                                      1
        n                                                                     tan2 axdx = −x +          tan ax + C        (74)
      sin axdx =                                                                                      a
       1                    1 1−n 3
      − cos ax      2 F1      ,   , , cos2 ax + C        (60)                             tann+1 ax
       a                    2   2  2                                       tann axdx =                ×
                                                                                            a(1 + n)
                           3 cos ax cos 3ax                                        n+1      n+3
       sin3 axdx = −               +        +C           (61)              2 F1        , 1,       , − tan2 ax + C         (75)
                              4a      12a                                           2         2
                               1                                                         1              1
              cos axdx =         sin ax + C              (62)            tan3 axdx =       ln cos ax +    sec2 ax + C     (76)
                               a                                                         a             2a
                             x sin 2ax
            cos2 axdx =        +       +C                (63)
                             2    4a
                                                                              sec xdx = ln | sec x + tan x| + C
                                                                                                           x
                        1                                                               = 2 tanh−1 tan       +C           (77)
cosp axdx = −                cos1+p ax×                                                                    2
                    a(1 + p)
                    1+p 1 3+p                                                                    1
            2 F1          , ,       , cos2 ax + C        (64)                      sec2 axdx =     tan ax + C             (78)
                      2    2    2                                                                a

                           3 sin ax sin 3ax
        cos3 axdx =                +        +C           (65)                     1              1
                              4a      12a                           sec3 xdx =      sec x tan x + ln | sec x tan x| + C   (79)
                                                                                  2              2

                              cos[(a − b)x]
       cos ax sin bxdx =                    −                                       sec x tan xdx = sec x + C             (80)
                                 2(a − b)
                           cos[(a + b)x]
                                         + C, a = b      (66)                                        1
                             2(a + b)                                             sec2 x tan xdx =     sec2 x + C         (81)
                                                                                                     2
                                                                                               1
  2                 sin[(2a − b)x]                                         secn x tan xdx =      secn x + C, n = 0        (82)
sin ax cos bxdx = −                                                                            n
                       4(2a − b)
                  sin bx sin[(2a + b)x]
                +        −              +C               (67)                          x
                    2b       4(2a + b)                              csc xdx = ln tan     + C = ln | csc x − cot x| + C    (83)
                                                                                       2

                                                                3
Products of Trigonometric Functions and
                     2        1                                                    Exponentials
                  csc axdx = − cot ax + C                (84)
                              a
                                                                                             1 x
                                                                              ex sin xdx =     e (sin x − cos x) + C         (99)
               1             1                                                               2
   csc3 xdx = − cot x csc x + ln | csc x − cot x| + C (85)
               2             2
                                                                                        1
                                                                    ebx sin axdx =           ebx (b sin ax − a cos bx) + C (100)
                                 1                                                   a2 + b2
           cscn x cot xdx = −      cscn x + C, n = 0     (86)
                                 n                                                           1 x
                                                                              ex cos xdx =     e (sin x + cos x) + C        (101)
                                                                                             2
                 sec x csc xdx = ln | tan x| + C         (87)
                                                                                        1
                                                                    ebx cos axdx =           ebx (a sin ax + b cos ax) + C (102)
Products of Trigonometric Functions and Monomials                                    a2 + b2

                                                                                     1 x
                                                                     xex sin xdx =     e (cos x − x cos x + x sin x) + C    (103)
                x cos xdx = cos x + x sin x + C          (88)                        2

                          1          x                                               1 x
           x cos axdx =      cos ax + sin ax + C         (89)        xex cos xdx =     e (x cos x − sin x + x sin x) + C    (104)
                          a2         a                                               2
                                                                           Integrals of Hyperbolic Functions
          2                           2
         x cos xdx = 2x cos x + x − 2 sin x + C          (90)
                                                                                                 1
                                                                                  cosh axdx =      sinh ax + C              (105)
                                                                                                 a
                                    2 2
                     2x cos ax a x − 2
     x2 cos axdx =            +        sin ax + C        (91)
                        a2        a3
                                                                     eax cosh bxdx =
                                                                          ax
                                                                          e      [a cosh bx − b sinh bx] + C      a=b
                        1                                                 2
                                                                           a − b2
           xn cosxdx = − (i)n+1 [Γ(n + 1, −ix)                              2ax                                             (106)
                        2                                                e       x
                                                                               + +C                               a=b
                     +(−1)n Γ(n + 1, ix)] + C            (92)               4a     2
                                                                                                 1
                                                                                  sinh axdx =      cosh ax + C              (107)
                                                                                                 a
                       1
       xn cosaxdx =      (ia)1−n [(−1)n Γ(n + 1, −iax)
                       2                                            eax sinh bxdx =
                     −Γ(n + 1, ixa)] + C                 (93)            ax
                                                                         e
                                                                         2       [−b cosh bx + a sinh bx] + C     a=b
                                                                           a − b2                                           (108)
                                                                            2ax
                                                                        e        x
                x sin xdx = −x cos x + sin x + C         (94)                  − +C                               a=b
                                                                            4a    2

                               x cos ax sin ax
              x sin axdx = −           +       +C        (95)       eax tanh bxdx =
                                  a       a2
                                                                     (a+2b)x
                                                                    e                  a             a     2bx
                                                                     (a + 2b) 2 F1 1 + 2b , 1, 2 + 2b , −e
                                                                    
         x2 sin xdx = 2 − x2 cos x + 2x sin x + C
                                                                    
                                                         (96)       
                                                                    
                                                                               1         a
                                                                             − eax 2 F1      , 1, 1E, −e2bx + C     a = b (109)
                                                                              a −1 ax 2b
                                                                     eax − 2 tan [e ]
                                                                    
                                                                    
                     2 − a2 x2                                                           +C                         a=b
                                                                    
                                        2x sin ax                   
     x2 sin axdx =        3
                               cos ax +           +C     (97)                  a
                        a                  a3
                                                                                                1
                                                                                 tanh bxdx =      ln cosh ax + C            (110)
                                                                                                a
                         1
           xn sin xdx = − (i)n [Γ(n + 1, −ix)                                                     1
                         2                                                cos ax cosh bxdx =            [a sin ax cosh bx
                      −(−1)n Γ(n + 1, −ix)] + C          (98)                                  a2 + b2
                                                                                             +b cos ax sinh bx] + C         (111)


                                                                4
1                                                            1
 cos ax sinh bxdx =          [b cos ax cosh bx+               sinh ax cosh axdx =      [−2ax + sinh 2ax] + C    (115)
                      a2+ b2                                                        4a
                 a sin ax sinh bx] + C          (112)

                                                                                         1
                       1                                         sinh ax cosh bxdx =          [b cosh bx sinh ax
sin ax cosh bxdx =          [−a cos ax cosh bx+                                       b2 − a2
                    a2 + b2
                                                                                    −a cosh ax sinh bx] + C      (116)
                b sin ax sinh bx] + C           (113)

                       1
 sin ax sinh bxdx =          [b cosh bx sin ax−
                    a2 + b2
                 a cos ax sinh bx] + C            (114)




                                                          5

More Related Content

What's hot

Algebra formulas
Algebra formulas Algebra formulas
Algebra formulas
Matthew McKenzie
 
solucionario de purcell 3
solucionario de purcell 3solucionario de purcell 3
solucionario de purcell 3
José Encalada
 
Gamma beta functions-1
Gamma   beta functions-1Gamma   beta functions-1
Gamma beta functions-1
Selvaraj John
 
Math34 Trigonometric Formulas
Math34 Trigonometric  FormulasMath34 Trigonometric  Formulas
Math34 Trigonometric Formulas
TopTuition
 
Struktur data 09 (double ended heap)
Struktur data 09 (double ended heap)Struktur data 09 (double ended heap)
Struktur data 09 (double ended heap)Sunarya Marwah
 
GRUP STRUKTUR ALJABAR
GRUP STRUKTUR ALJABARGRUP STRUKTUR ALJABAR
GRUP STRUKTUR ALJABAR
Fely Ramury
 
Conic Section - Parabola - Ellipse - Hyperbola
Conic Section - Parabola - Ellipse - HyperbolaConic Section - Parabola - Ellipse - Hyperbola
Conic Section - Parabola - Ellipse - Hyperbola
satish kumar
 
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014) DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
Panchal Anand
 
Integral fungsi rasional1
Integral fungsi rasional1Integral fungsi rasional1
Integral fungsi rasional1Zhand Radja
 
Aljabar Vektor
Aljabar Vektor Aljabar Vektor
Aljabar Vektor
IrvanDzaki
 
Matematika sistem
Matematika sistemMatematika sistem
Matematika sistem
petrus fendiyanto
 
Inverse trigonometric functions
Inverse trigonometric functionsInverse trigonometric functions
Inverse trigonometric functionsLeo Crisologo
 
Interpolasi Newton
Interpolasi  NewtonInterpolasi  Newton
Interpolasi Newton
Ratih Vihafsari
 
14257017 metode-frobenius (1)
14257017 metode-frobenius (1)14257017 metode-frobenius (1)
14257017 metode-frobenius (1)
Sanre Tambunan
 
Ordinary Differential Equations: Variable separation method
Ordinary Differential Equations: Variable separation method  Ordinary Differential Equations: Variable separation method
Ordinary Differential Equations: Variable separation method
AMINULISLAM439
 
Lesson 17: Inverse Trigonometric Functions
Lesson 17: Inverse Trigonometric FunctionsLesson 17: Inverse Trigonometric Functions
Lesson 17: Inverse Trigonometric Functions
Matthew Leingang
 

What's hot (20)

Algebra formulas
Algebra formulas Algebra formulas
Algebra formulas
 
solucionario de purcell 3
solucionario de purcell 3solucionario de purcell 3
solucionario de purcell 3
 
Gamma beta functions-1
Gamma   beta functions-1Gamma   beta functions-1
Gamma beta functions-1
 
Bab 6
Bab 6Bab 6
Bab 6
 
Math34 Trigonometric Formulas
Math34 Trigonometric  FormulasMath34 Trigonometric  Formulas
Math34 Trigonometric Formulas
 
Integral table
Integral tableIntegral table
Integral table
 
Struktur data 09 (double ended heap)
Struktur data 09 (double ended heap)Struktur data 09 (double ended heap)
Struktur data 09 (double ended heap)
 
GRUP STRUKTUR ALJABAR
GRUP STRUKTUR ALJABARGRUP STRUKTUR ALJABAR
GRUP STRUKTUR ALJABAR
 
Conic Section - Parabola - Ellipse - Hyperbola
Conic Section - Parabola - Ellipse - HyperbolaConic Section - Parabola - Ellipse - Hyperbola
Conic Section - Parabola - Ellipse - Hyperbola
 
Integral table
Integral tableIntegral table
Integral table
 
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014) DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
DOUBLE INTEGRALS PPT GTU CALCULUS (2110014)
 
Integral fungsi rasional1
Integral fungsi rasional1Integral fungsi rasional1
Integral fungsi rasional1
 
Aljabar Vektor
Aljabar Vektor Aljabar Vektor
Aljabar Vektor
 
Matematika sistem
Matematika sistemMatematika sistem
Matematika sistem
 
Inverse trigonometric functions
Inverse trigonometric functionsInverse trigonometric functions
Inverse trigonometric functions
 
Interpolasi Newton
Interpolasi  NewtonInterpolasi  Newton
Interpolasi Newton
 
Met num 10
Met num 10Met num 10
Met num 10
 
14257017 metode-frobenius (1)
14257017 metode-frobenius (1)14257017 metode-frobenius (1)
14257017 metode-frobenius (1)
 
Ordinary Differential Equations: Variable separation method
Ordinary Differential Equations: Variable separation method  Ordinary Differential Equations: Variable separation method
Ordinary Differential Equations: Variable separation method
 
Lesson 17: Inverse Trigonometric Functions
Lesson 17: Inverse Trigonometric FunctionsLesson 17: Inverse Trigonometric Functions
Lesson 17: Inverse Trigonometric Functions
 

Similar to Integral table

Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
Drradz Maths
 
Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
Drradz Maths
 
Derivadas
DerivadasDerivadas
Derivadas
romgarcia
 
Formulario de calculo
Formulario de calculoFormulario de calculo
Formulario de calculoHenry Romero
 
Antiderivatives
AntiderivativesAntiderivatives
AntiderivativesSilvius
 
Funções trigonométricas
Funções trigonométricasFunções trigonométricas
Funções trigonométricasPedro Dias
 
Emat 213 study guide
Emat 213 study guideEmat 213 study guide
Emat 213 study guideakabaka12
 
S101-52國立新化高中(代理)
S101-52國立新化高中(代理)S101-52國立新化高中(代理)
S101-52國立新化高中(代理)yustar1026
 
Common derivatives integrals_reduced
Common derivatives integrals_reducedCommon derivatives integrals_reduced
Common derivatives integrals_reduced
Kyro Fitkry
 
Calculus Final Exam
Calculus Final ExamCalculus Final Exam
Calculus Final Exam
Kuan-Lun Wang
 

Similar to Integral table (20)

Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
 
Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
 
Regras diferenciacao
Regras diferenciacaoRegras diferenciacao
Regras diferenciacao
 
01 regras diferenciacao
01   regras diferenciacao01   regras diferenciacao
01 regras diferenciacao
 
Derivadas
DerivadasDerivadas
Derivadas
 
Lista de derivadas e integrais
Lista de derivadas e integraisLista de derivadas e integrais
Lista de derivadas e integrais
 
Formulario de calculo
Formulario de calculoFormulario de calculo
Formulario de calculo
 
Sect1 4
Sect1 4Sect1 4
Sect1 4
 
Antiderivatives
AntiderivativesAntiderivatives
Antiderivatives
 
Funções trigonométricas
Funções trigonométricasFunções trigonométricas
Funções trigonométricas
 
calculo vectorial
calculo vectorialcalculo vectorial
calculo vectorial
 
Emat 213 study guide
Emat 213 study guideEmat 213 study guide
Emat 213 study guide
 
S101-52國立新化高中(代理)
S101-52國立新化高中(代理)S101-52國立新化高中(代理)
S101-52國立新化高中(代理)
 
Common derivatives integrals_reduced
Common derivatives integrals_reducedCommon derivatives integrals_reduced
Common derivatives integrals_reduced
 
Cs 601
Cs 601Cs 601
Cs 601
 
Calculus Final Exam
Calculus Final ExamCalculus Final Exam
Calculus Final Exam
 
Sect1 5
Sect1 5Sect1 5
Sect1 5
 
Lista exercintegrais
Lista exercintegraisLista exercintegrais
Lista exercintegrais
 
Figures
FiguresFigures
Figures
 
Figures
FiguresFigures
Figures
 

Recently uploaded

Honest Reviews of Tim Han LMA Course Program.pptx
Honest Reviews of Tim Han LMA Course Program.pptxHonest Reviews of Tim Han LMA Course Program.pptx
Honest Reviews of Tim Han LMA Course Program.pptx
timhan337
 
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
Levi Shapiro
 
The Challenger.pdf DNHS Official Publication
The Challenger.pdf DNHS Official PublicationThe Challenger.pdf DNHS Official Publication
The Challenger.pdf DNHS Official Publication
Delapenabediema
 
Polish students' mobility in the Czech Republic
Polish students' mobility in the Czech RepublicPolish students' mobility in the Czech Republic
Polish students' mobility in the Czech Republic
Anna Sz.
 
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxChapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
Mohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
 
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
Nguyen Thanh Tu Collection
 
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and ResearchDigital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Vikramjit Singh
 
The geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideasThe geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideas
GeoBlogs
 
special B.ed 2nd year old paper_20240531.pdf
special B.ed 2nd year old paper_20240531.pdfspecial B.ed 2nd year old paper_20240531.pdf
special B.ed 2nd year old paper_20240531.pdf
Special education needs
 
Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345
beazzy04
 
Model Attribute Check Company Auto Property
Model Attribute  Check Company Auto PropertyModel Attribute  Check Company Auto Property
Model Attribute Check Company Auto Property
Celine George
 
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXXPhrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
MIRIAMSALINAS13
 
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe..."Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
SACHIN R KONDAGURI
 
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp NetworkIntroduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
TechSoup
 
Supporting (UKRI) OA monographs at Salford.pptx
Supporting (UKRI) OA monographs at Salford.pptxSupporting (UKRI) OA monographs at Salford.pptx
Supporting (UKRI) OA monographs at Salford.pptx
Jisc
 
Guidance_and_Counselling.pdf B.Ed. 4th Semester
Guidance_and_Counselling.pdf B.Ed. 4th SemesterGuidance_and_Counselling.pdf B.Ed. 4th Semester
Guidance_and_Counselling.pdf B.Ed. 4th Semester
Atul Kumar Singh
 
CACJapan - GROUP Presentation 1- Wk 4.pdf
CACJapan - GROUP Presentation 1- Wk 4.pdfCACJapan - GROUP Presentation 1- Wk 4.pdf
CACJapan - GROUP Presentation 1- Wk 4.pdf
camakaiclarkmusic
 
Language Across the Curriculm LAC B.Ed.
Language Across the  Curriculm LAC B.Ed.Language Across the  Curriculm LAC B.Ed.
Language Across the Curriculm LAC B.Ed.
Atul Kumar Singh
 
678020731-Sumas-y-Restas-Para-Colorear.pdf
678020731-Sumas-y-Restas-Para-Colorear.pdf678020731-Sumas-y-Restas-Para-Colorear.pdf
678020731-Sumas-y-Restas-Para-Colorear.pdf
CarlosHernanMontoyab2
 
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with MechanismOverview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
DeeptiGupta154
 

Recently uploaded (20)

Honest Reviews of Tim Han LMA Course Program.pptx
Honest Reviews of Tim Han LMA Course Program.pptxHonest Reviews of Tim Han LMA Course Program.pptx
Honest Reviews of Tim Han LMA Course Program.pptx
 
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
 
The Challenger.pdf DNHS Official Publication
The Challenger.pdf DNHS Official PublicationThe Challenger.pdf DNHS Official Publication
The Challenger.pdf DNHS Official Publication
 
Polish students' mobility in the Czech Republic
Polish students' mobility in the Czech RepublicPolish students' mobility in the Czech Republic
Polish students' mobility in the Czech Republic
 
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxChapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
 
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
 
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and ResearchDigital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
 
The geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideasThe geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideas
 
special B.ed 2nd year old paper_20240531.pdf
special B.ed 2nd year old paper_20240531.pdfspecial B.ed 2nd year old paper_20240531.pdf
special B.ed 2nd year old paper_20240531.pdf
 
Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345
 
Model Attribute Check Company Auto Property
Model Attribute  Check Company Auto PropertyModel Attribute  Check Company Auto Property
Model Attribute Check Company Auto Property
 
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXXPhrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
 
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe..."Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
 
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp NetworkIntroduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
 
Supporting (UKRI) OA monographs at Salford.pptx
Supporting (UKRI) OA monographs at Salford.pptxSupporting (UKRI) OA monographs at Salford.pptx
Supporting (UKRI) OA monographs at Salford.pptx
 
Guidance_and_Counselling.pdf B.Ed. 4th Semester
Guidance_and_Counselling.pdf B.Ed. 4th SemesterGuidance_and_Counselling.pdf B.Ed. 4th Semester
Guidance_and_Counselling.pdf B.Ed. 4th Semester
 
CACJapan - GROUP Presentation 1- Wk 4.pdf
CACJapan - GROUP Presentation 1- Wk 4.pdfCACJapan - GROUP Presentation 1- Wk 4.pdf
CACJapan - GROUP Presentation 1- Wk 4.pdf
 
Language Across the Curriculm LAC B.Ed.
Language Across the  Curriculm LAC B.Ed.Language Across the  Curriculm LAC B.Ed.
Language Across the Curriculm LAC B.Ed.
 
678020731-Sumas-y-Restas-Para-Colorear.pdf
678020731-Sumas-y-Restas-Para-Colorear.pdf678020731-Sumas-y-Restas-Para-Colorear.pdf
678020731-Sumas-y-Restas-Para-Colorear.pdf
 
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with MechanismOverview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
 

Integral table

  • 1. Table of Integrals∗ Basic Forms Integrals with Roots 1 √ 2 xn dx = xn+1 + c (1) x − adx = (x − a)3/2 + C (17) n+1 3 1 1 √ dx = ln x + c (2) √ dx = 2 x ± a + C (18) x x±a 1 √ udv = uv − vdu (3) √ dx = 2 a − x + C (19) a−x 1 1 dx = ln |ax + b| + c (4) ax + b a √ 2 2 x x − adx = a(x − a)3/2 + (x − a)5/2 + C (20) 3 5 Integrals of Rational Functions √ 2b 2x √ 1 1 ax + bdx = + ax + b + C (21) dx = − +c (5) 3a 3 (x + a)2 x+a 2 (x + a)n+1 (ax + b)3/2 dx = (ax + b)5/2 + C (22) n (x + a) dx = + c, n = −1 (6) 5a n+1 x 2 √ √ dx = (x ± 2a) x ± a + C (23) x±a 3 (x + a)n+1 ((n + 1)x − a) x(x + a)n dx = +c (7) (n + 1)(n + 2) x 1 dx = − x(a − x) dx = tan−1 x + c (8) a−x 1 + x2 x(a − x) − a tan−1 +C (24) 1 1 x x−a dx = tan−1 + c (9) a2 + x2 a a x 1 x dx = ln |a2 + x2 | + c (10) dx = x(a + x) a2 +x 2 2 a+x √ √ x2 x − a ln x + x + a + C (25) dx = x − a tan−1 + c (11) a2 +x 2 a x3 1 1 √ dx = x2 − a2 ln |a2 + x2 | + c (12) a2 + x2 2 2 x ax + bdx = 2 √ 1 2 2ax + b 2 (−2b2 + abx + 3a2 x2 ) ax + b + C (26) dx = √ tan−1 √ + C (13) 15a ax 2 + bx + c 2 4ac − b 4ac − b2 1 1 a+x 1 dx = ln , a=b (14) x(ax + b)dx = (2ax + b) ax(ax + b) (x + a)(x + b) b−a b+x 4a3/2 √ x a −b2 ln a x + a(ax + b) + C (27) 2 dx = + ln |a + x| + C (15) (x + a) a+x x 1 b b2 x dx = ln |ax2 + bx + c| x3 (ax + b)dx = − 2 + x3 (ax + b) ax2 + bx + c 2a 12a 8a x 3 b 2ax + b b3 √ − √ tan−1 √ + C (16) + 5/2 ln a x + a(ax + b) + C (28) a 4ac − b 2 4ac − b2 8a ∗ c 2007. From http://integral-table.com, last revised December 6, 2007. This material is provided as is without warranty or representation about the accuracy, correctness or suitability of this material for any purpose. Some restrictions on use and distribution may apply, including the terms of the Creative Commons Attribution-Noncommercial-Share Alike 3.0 Unported License. See the web site for details. The formula numbers on this document may be different from the formula numbers on the web page. 1
  • 2. Integrals with Logarithms 1 x2 ± a2 dx = x x2 ± a2 2 ln axdx = x ln ax − x + C (41) 1 ± a2 ln x + x2 ± a2 + C (29) 2 ln ax 1 2 dx = (ln ax) + C (42) x 2 1 a2 − x2 dx = x a2 − x2 b 2 ln(ax + b)dx = x+ ln(ax + b) − x + C, a = 0 (43) 1 x a + a2 tan−1 √ +C (30) 2 a2 − x2 1 2 3/2 ln a2 x2 ± b2 dx = x ln a2 x2 ± b2 x x2 ± a2 dx = x ± a2 +C (31) 3 2b ax + tan−1 − 2x + C (44) 1 a b √ dx = ln x + x2 ± a2 + C (32) x 2 ± a2 1 x ln a2 − b2 x2 dx = x ln ar − b2 x2 √ dx = sin−1 + C (33) a2 − x2 a 2a bx + tan−1 − 2x + C (45) x b a √ dx = x2 ± a2 + C (34) x2 ± a2 x 1 2ax + b √ dx = − a2 − x2 + C (35) ln ax2 + bx + c dx = 4ac − b2 tan−1 √ a2 − x2 a 4ac − b2 b − 2x + + x ln ax2 + bx + c + C (46) 2a x2 1 √ dx = x x2 ± a2 x 2 ± a2 2 1 2 bx 1 2 a ln x + x2 ± a2 + C (36) x ln(ax + b)dx = − x 2 2a 4 1 b2 + x2 − 2 ln(ax + b) + C (47) 2 a b + 2ax ax2 + bx + cdx = ax2 + bx + c 4a 1 4ac − b2 x ln a2 − b2 x2 dx = − x2 + + ln 2ax + b + 2 a(ax2 + bx+ c) + C (37) 2 8a3/2 1 a2 x2 − 2 ln a2 − b2 x2 + C (48) 2 b 1 √ x ax2 + bx + c = 5/2 2 a ax2 + bx + c Integrals with Exponentials 48a − 3b2 + 2abx + 8a(c + ax2 ) √ 1 ax eax dx = e +C (49) +3(b3 − 4abc) ln b + 2ax + 2 a ax2 + bx + x (38) a √ √ ax 1 √ ax i π √ 1 xe dx = xe + 3/2 erf i ax + C, √ dx = a 2a x ax2 + bx + c 2 2 1 where erf(x) = √ e−t dtet (50) √ ln 2ax + b + 2 a(ax2 + bx + c) + C (39) π 0 a xex dx = (x − 1)ex + C (51) x 1 √ dx = ax2 + bx + c x 1 ax2 + bx + c a xeax dx = − eax + C (52) b a a2 + 3/2 ln 2ax + b + 2 a(ax2 + bx + c) + C (40) 2a x2 ex dx = x2 − 2x + 2 ex + C (53) 2
  • 3. x2 2x 2 1 x2 eax dx = − 2 + 3 eax + C (54) sin2 x cos xdx = sin3 x + C (68) a a a 3 x3 ex dx = x3 − 3x2 + 6x − 6 ex + C (55) cos[(2a − b)x] cos bx cos2 ax sin bxdx = − 4(2a − b) 2b cos[(2a + b)x] 1 − +C (69) xn eax dx = (−1)n Γ[1 + n, −ax], 4(2a + b) a ∞ where Γ(a, x) = ta−1 e−t dt (56) 1 cos2 ax sin axdx = − cos3 ax + C (70) x 3a √ 2 i π √ eax dx = − √ erf ix a (57) x sin 2ax sin[2(a − b)x] 2 a sin2 ax cos2 bxdx = − − 4 8a 16(a − b) Integrals with Trigonometric Functions sin 2bx sin[2(a + b)x] + − +C (71) 8b 16(a + b) 1 sin axdx = − cos ax + C (58) x sin 4ax a sin2 ax cos2 axdx = − +C (72) 8 32a x sin 2ax sin2 axdx = − +C (59) 1 2 4a tan axdx = − ln cos ax + C (73) a 1 n tan2 axdx = −x + tan ax + C (74) sin axdx = a 1 1 1−n 3 − cos ax 2 F1 , , , cos2 ax + C (60) tann+1 ax a 2 2 2 tann axdx = × a(1 + n) 3 cos ax cos 3ax n+1 n+3 sin3 axdx = − + +C (61) 2 F1 , 1, , − tan2 ax + C (75) 4a 12a 2 2 1 1 1 cos axdx = sin ax + C (62) tan3 axdx = ln cos ax + sec2 ax + C (76) a a 2a x sin 2ax cos2 axdx = + +C (63) 2 4a sec xdx = ln | sec x + tan x| + C x 1 = 2 tanh−1 tan +C (77) cosp axdx = − cos1+p ax× 2 a(1 + p) 1+p 1 3+p 1 2 F1 , , , cos2 ax + C (64) sec2 axdx = tan ax + C (78) 2 2 2 a 3 sin ax sin 3ax cos3 axdx = + +C (65) 1 1 4a 12a sec3 xdx = sec x tan x + ln | sec x tan x| + C (79) 2 2 cos[(a − b)x] cos ax sin bxdx = − sec x tan xdx = sec x + C (80) 2(a − b) cos[(a + b)x] + C, a = b (66) 1 2(a + b) sec2 x tan xdx = sec2 x + C (81) 2 1 2 sin[(2a − b)x] secn x tan xdx = secn x + C, n = 0 (82) sin ax cos bxdx = − n 4(2a − b) sin bx sin[(2a + b)x] + − +C (67) x 2b 4(2a + b) csc xdx = ln tan + C = ln | csc x − cot x| + C (83) 2 3
  • 4. Products of Trigonometric Functions and 2 1 Exponentials csc axdx = − cot ax + C (84) a 1 x ex sin xdx = e (sin x − cos x) + C (99) 1 1 2 csc3 xdx = − cot x csc x + ln | csc x − cot x| + C (85) 2 2 1 ebx sin axdx = ebx (b sin ax − a cos bx) + C (100) 1 a2 + b2 cscn x cot xdx = − cscn x + C, n = 0 (86) n 1 x ex cos xdx = e (sin x + cos x) + C (101) 2 sec x csc xdx = ln | tan x| + C (87) 1 ebx cos axdx = ebx (a sin ax + b cos ax) + C (102) Products of Trigonometric Functions and Monomials a2 + b2 1 x xex sin xdx = e (cos x − x cos x + x sin x) + C (103) x cos xdx = cos x + x sin x + C (88) 2 1 x 1 x x cos axdx = cos ax + sin ax + C (89) xex cos xdx = e (x cos x − sin x + x sin x) + C (104) a2 a 2 Integrals of Hyperbolic Functions 2 2 x cos xdx = 2x cos x + x − 2 sin x + C (90) 1 cosh axdx = sinh ax + C (105) a 2 2 2x cos ax a x − 2 x2 cos axdx = + sin ax + C (91) a2 a3 eax cosh bxdx =  ax  e [a cosh bx − b sinh bx] + C a=b 1  2 a − b2 xn cosxdx = − (i)n+1 [Γ(n + 1, −ix) 2ax (106) 2 e x  + +C a=b +(−1)n Γ(n + 1, ix)] + C (92) 4a 2 1 sinh axdx = cosh ax + C (107) a 1 xn cosaxdx = (ia)1−n [(−1)n Γ(n + 1, −iax) 2 eax sinh bxdx = −Γ(n + 1, ixa)] + C (93)  ax  e  2 [−b cosh bx + a sinh bx] + C a=b a − b2 (108) 2ax e x x sin xdx = −x cos x + sin x + C (94)  − +C a=b 4a 2 x cos ax sin ax x sin axdx = − + +C (95) eax tanh bxdx = a a2  (a+2b)x e a a 2bx  (a + 2b) 2 F1 1 + 2b , 1, 2 + 2b , −e  x2 sin xdx = 2 − x2 cos x + 2x sin x + C  (96)   1 a − eax 2 F1 , 1, 1E, −e2bx + C a = b (109)  a −1 ax 2b  eax − 2 tan [e ]   2 − a2 x2 +C a=b  2x sin ax  x2 sin axdx = 3 cos ax + +C (97) a a a3 1 tanh bxdx = ln cosh ax + C (110) a 1 xn sin xdx = − (i)n [Γ(n + 1, −ix) 1 2 cos ax cosh bxdx = [a sin ax cosh bx −(−1)n Γ(n + 1, −ix)] + C (98) a2 + b2 +b cos ax sinh bx] + C (111) 4
  • 5. 1 1 cos ax sinh bxdx = [b cos ax cosh bx+ sinh ax cosh axdx = [−2ax + sinh 2ax] + C (115) a2+ b2 4a a sin ax sinh bx] + C (112) 1 1 sinh ax cosh bxdx = [b cosh bx sinh ax sin ax cosh bxdx = [−a cos ax cosh bx+ b2 − a2 a2 + b2 −a cosh ax sinh bx] + C (116) b sin ax sinh bx] + C (113) 1 sin ax sinh bxdx = [b cosh bx sin ax− a2 + b2 a cos ax sinh bx] + C (114) 5