198213
JONISHA
• WHAT IS HYBRIDISATION
HYBRIDISATION IS A
PROCESS IN WHICH TWO OR
MORE ATOMIC ORBITALS OF
VALENCE SHELL OF AN ATOM
MIX UP TO FORM THE SAME
NUMBER OF IDENTICAL
ORBITALS OF EQUAL ENERGY.
PURPOSE OF HYBRIDISATION
• THE PURPOSE OF HYBRIDISATION IS TO SEE THE
TYPES OF BONDS THAT THE ATOMS SHARE WITH
EACH OTHER, IT MAY BE SIGMA OR PI BONDS
• THE DIFFERENT TYPES OF BONDS ALLOW
DIFFERENT PROPERTIES LIKE HOW PI BONDS DO
NOT ALLOW ROTATION WHEREAS SIGMA
BONDS ARE ROTATIONAL
 FEATURES OF HYBRIDISATION :
• THE HYBRID ORBITALS ARE EQUIVALENT IN ENERGY AND
SHAPE
• THE ORBITALS TAKING PART IN HYBRIDISATION MUST HAVE
ONLY SMALL DIFFERNCE IN ENERGY
• THE NUMBER OF HYBRID ORBITALS IS THE SAME AS THE
NUMBER OF ATOMIC ORBITALS THAT UNDERGO
HYBRIDISATION
• BOTH HALF FILLED AND COMPLETELY FILLED TAKE PART IN
HYBRIDISATION
• HYBRID ORBITALS FORM MORE STABLE BONDS
• THE TYPE OF HYBRIDISATION GIVES THE SHAPE OF
MOLECULES
sp HYBRIDISATION : LINIER
sp2 HYBRIDISATION : TRIANGULAR
sp3HYBRIDISATION : TETRAHEDRAL
dsp2 HYBRIDISATION : SQUARE PLANAR
dsp3 HYBRIDISATION : TRIGONAL BI PYRAMIDAL
d2sp3 HYBRIDISATION : OCTAHEDRAL
d3sp3 HYBRIDISATION : PENTAGONAL BIPYRAMIDAL
 SP HYBRIDISATION
• IT INVOLVES THE MIXING OF ONE s AND
ONE p ORBITAL TO PRODUCE TWO
IDENTICAL ORBITALS CALLED sp HYBRID
ORBITALS
 STRUCTURE OF BERYLLIUM CHLORIDE (Becl2) sp HYBRIDISATION
• BERILIYUM CHLORIDE , MOLECULE HAS ONE BERILIYUM ATOM AND
TWO CHLORINE ATOMS
• BERILIYUM HAS TWO VELENCY ELECTRONS AND CHLORINE HAS ONE
VELENCY ELECTRON FOR SHARING
Be (4) : [ He] 2s22p0 Cl (17) : [He] 2s22p63s23p6
Be (Excited state) : [He] 2s1 2px
1 2py
0 2pz
0
BeCl2 : [He]
Sp HYBRIDISATION
• DURING THE FORMATION OF BeCl2, 2s AND 2px ORBITALS OF Be
UNDERGO Sp HYBRIDISATION TO FORM TWO IDENTICAL HYBRID
ORBITALS
• THEY ARE ORIENTED LINERLY IN OPPOSITE DIRECTION AT AN ANGLE
OF 180O
• HENCE BeCl2 HAS LINER STRCTURE DUE TO Sp
HYBRIDISATION
SP2 HYBRIDISATION
• IT INVOLVES THE MIXING OF ONE s
ORBITAL AND 2p ORBITAL TO PRODUCE 3
IDENTICAL ORBITALS CALLED Sp2 HYBRID
ORBITALS
 STRUCTURE OF BORON TRIFLORIDE(BF3)
Sp2 HYBRIDISATION
• A MOLECULE OF BORON TRIFLORIDE CONTAINS ONE
BORON ATOM AND THREE FLORINE ATOMS
• ELECTRONIC CONFIGURATION OF FLORINE
1s2 2s2 2Px2 2Py2 2Pz1
• BORON (ground state) : 1s2 2s2 2p1
• BORON (excited state) : 1s2 2s2 2px1 2py1 2pz0
• 2s 2px AND 2py ORBITALS OF BORON UNDERGO SP2
HYBRIDISATION TO FORM 3Sp2 HYBRID ORBITALS
• THESE ORBITALS OVERLAP WITH 2PZ ORBITALS OF
FLORINE ATOM TO FORM THREE SIGMA BONDS
• HENCE BORON TRIFLORIDE HAS A TRI TRIANGULAR
SHAPE
• THE FLORINE ATOM LIVE AT THE CORNERS OF
EQUILATERAL TRIANGLE
• THE BOND ANGE IN BF3 IS 120O
 SP3 HYBRIDISATION
• IT INVOLVES THE MIXING OF 1S ORBITAL AND 3p
ORBITALS TO PRODUCE FOUR IDETICAL
ORBITALS CALLED Sp3 HYBRID ORBITALS
 STRUCTURE OF METHANE CH4
• ONE MOLECULE OF METHANE HAS ONE
CARBON ATOM AND FOUR HYDROGEN ATOMS
• ELECTRONIC CONFIGURATION OF CARBON :
1s2 2s2 2px1 2Py1 2pz0
• C(excited state) 1s2 2s1 2px1 2Py1 2pz1
• 12s ORIBITAL AND 32p ORBITAL OF CARBON
ATOM UNDERGO SP3 HYBRIDISATION TO
FORM 4 IDENTICAL HYBRID ORBITALS
• THESE ORBITALS ARE ORIENTED TOWARDS 4
ORNERS OF A REGULAR TETRAHEDRON Cs
• THE FOUR Sp3 HYBRIDE ORBITALS OVERLAP
WITH THE 1s ATOMIC ORBITALS OF FOUR
HYDROGEN ATOMS TO FORM SIGMA BONDS
• HENCE METHANE THERE ARE FOUR C-H
SIGMA BONDS
BeCl2
 WHY DO WE NEED HYBRIDISATION?
• CARBON HAS FOUR UNPAIRED ELECTRONS
IT CAN HAVE FOUR EQUAL ENERGY BONDS.
• THE HYBRIDISATION OF ORBITALS IS ALSO
GREATLY FAVOURED BECASUSE HYBRIDISED
ORBITALS ARE LOWER IN ENERGY COMPARE
TO THEIR SEPARATED, UNHYBRIDISED
COUNTERPARTS
• THIS RESULTS IN MORE STABLE
COMPOUNDS WHEN HYBRIDISATION
OCCURES
ADVANTAGE OF HYBRIDISATION
• THE MOST IMPORTANT ADVANTAGE IS
THE DETERMINATION OF SHAPE AND
GEOMETRY OF THE MOLECULE
• IT DETERMINES THE POSITION AND
STRUCTURE OF THE COMPOUND
• IT EXPLAINS THE VARIOUS
PROBABILITIES OF PHYSICAL AND
CHEMICAL BEHAVIOR
 CONCLUSION
• IN CHEMISTRY, ORBITAL
HYBRIDISATTION IS CONCEPT OF
MIXING ATOMIC ORBITALS INTO NEW
HYBRID ORBITALS
• IT IS SUITABLE FOR PAIRING OF
ELECTRONS TO FORM CHEMICAL
BONDS IN VALANCE BOND THEORY
Hybridisation - Jonisha

Hybridisation - Jonisha

  • 1.
  • 2.
    • WHAT ISHYBRIDISATION HYBRIDISATION IS A PROCESS IN WHICH TWO OR MORE ATOMIC ORBITALS OF VALENCE SHELL OF AN ATOM MIX UP TO FORM THE SAME NUMBER OF IDENTICAL ORBITALS OF EQUAL ENERGY.
  • 3.
    PURPOSE OF HYBRIDISATION •THE PURPOSE OF HYBRIDISATION IS TO SEE THE TYPES OF BONDS THAT THE ATOMS SHARE WITH EACH OTHER, IT MAY BE SIGMA OR PI BONDS • THE DIFFERENT TYPES OF BONDS ALLOW DIFFERENT PROPERTIES LIKE HOW PI BONDS DO NOT ALLOW ROTATION WHEREAS SIGMA BONDS ARE ROTATIONAL
  • 4.
     FEATURES OFHYBRIDISATION : • THE HYBRID ORBITALS ARE EQUIVALENT IN ENERGY AND SHAPE • THE ORBITALS TAKING PART IN HYBRIDISATION MUST HAVE ONLY SMALL DIFFERNCE IN ENERGY • THE NUMBER OF HYBRID ORBITALS IS THE SAME AS THE NUMBER OF ATOMIC ORBITALS THAT UNDERGO HYBRIDISATION • BOTH HALF FILLED AND COMPLETELY FILLED TAKE PART IN HYBRIDISATION • HYBRID ORBITALS FORM MORE STABLE BONDS • THE TYPE OF HYBRIDISATION GIVES THE SHAPE OF MOLECULES sp HYBRIDISATION : LINIER sp2 HYBRIDISATION : TRIANGULAR sp3HYBRIDISATION : TETRAHEDRAL dsp2 HYBRIDISATION : SQUARE PLANAR dsp3 HYBRIDISATION : TRIGONAL BI PYRAMIDAL d2sp3 HYBRIDISATION : OCTAHEDRAL d3sp3 HYBRIDISATION : PENTAGONAL BIPYRAMIDAL
  • 5.
     SP HYBRIDISATION •IT INVOLVES THE MIXING OF ONE s AND ONE p ORBITAL TO PRODUCE TWO IDENTICAL ORBITALS CALLED sp HYBRID ORBITALS
  • 6.
     STRUCTURE OFBERYLLIUM CHLORIDE (Becl2) sp HYBRIDISATION • BERILIYUM CHLORIDE , MOLECULE HAS ONE BERILIYUM ATOM AND TWO CHLORINE ATOMS • BERILIYUM HAS TWO VELENCY ELECTRONS AND CHLORINE HAS ONE VELENCY ELECTRON FOR SHARING Be (4) : [ He] 2s22p0 Cl (17) : [He] 2s22p63s23p6 Be (Excited state) : [He] 2s1 2px 1 2py 0 2pz 0 BeCl2 : [He] Sp HYBRIDISATION • DURING THE FORMATION OF BeCl2, 2s AND 2px ORBITALS OF Be UNDERGO Sp HYBRIDISATION TO FORM TWO IDENTICAL HYBRID ORBITALS • THEY ARE ORIENTED LINERLY IN OPPOSITE DIRECTION AT AN ANGLE OF 180O • HENCE BeCl2 HAS LINER STRCTURE DUE TO Sp HYBRIDISATION
  • 7.
    SP2 HYBRIDISATION • ITINVOLVES THE MIXING OF ONE s ORBITAL AND 2p ORBITAL TO PRODUCE 3 IDENTICAL ORBITALS CALLED Sp2 HYBRID ORBITALS
  • 8.
     STRUCTURE OFBORON TRIFLORIDE(BF3) Sp2 HYBRIDISATION • A MOLECULE OF BORON TRIFLORIDE CONTAINS ONE BORON ATOM AND THREE FLORINE ATOMS • ELECTRONIC CONFIGURATION OF FLORINE 1s2 2s2 2Px2 2Py2 2Pz1 • BORON (ground state) : 1s2 2s2 2p1 • BORON (excited state) : 1s2 2s2 2px1 2py1 2pz0 • 2s 2px AND 2py ORBITALS OF BORON UNDERGO SP2 HYBRIDISATION TO FORM 3Sp2 HYBRID ORBITALS • THESE ORBITALS OVERLAP WITH 2PZ ORBITALS OF FLORINE ATOM TO FORM THREE SIGMA BONDS • HENCE BORON TRIFLORIDE HAS A TRI TRIANGULAR SHAPE • THE FLORINE ATOM LIVE AT THE CORNERS OF EQUILATERAL TRIANGLE • THE BOND ANGE IN BF3 IS 120O
  • 10.
     SP3 HYBRIDISATION •IT INVOLVES THE MIXING OF 1S ORBITAL AND 3p ORBITALS TO PRODUCE FOUR IDETICAL ORBITALS CALLED Sp3 HYBRID ORBITALS
  • 11.
     STRUCTURE OFMETHANE CH4 • ONE MOLECULE OF METHANE HAS ONE CARBON ATOM AND FOUR HYDROGEN ATOMS • ELECTRONIC CONFIGURATION OF CARBON : 1s2 2s2 2px1 2Py1 2pz0 • C(excited state) 1s2 2s1 2px1 2Py1 2pz1 • 12s ORIBITAL AND 32p ORBITAL OF CARBON ATOM UNDERGO SP3 HYBRIDISATION TO FORM 4 IDENTICAL HYBRID ORBITALS • THESE ORBITALS ARE ORIENTED TOWARDS 4 ORNERS OF A REGULAR TETRAHEDRON Cs • THE FOUR Sp3 HYBRIDE ORBITALS OVERLAP WITH THE 1s ATOMIC ORBITALS OF FOUR HYDROGEN ATOMS TO FORM SIGMA BONDS • HENCE METHANE THERE ARE FOUR C-H SIGMA BONDS
  • 13.
  • 14.
     WHY DOWE NEED HYBRIDISATION? • CARBON HAS FOUR UNPAIRED ELECTRONS IT CAN HAVE FOUR EQUAL ENERGY BONDS. • THE HYBRIDISATION OF ORBITALS IS ALSO GREATLY FAVOURED BECASUSE HYBRIDISED ORBITALS ARE LOWER IN ENERGY COMPARE TO THEIR SEPARATED, UNHYBRIDISED COUNTERPARTS • THIS RESULTS IN MORE STABLE COMPOUNDS WHEN HYBRIDISATION OCCURES
  • 15.
    ADVANTAGE OF HYBRIDISATION •THE MOST IMPORTANT ADVANTAGE IS THE DETERMINATION OF SHAPE AND GEOMETRY OF THE MOLECULE • IT DETERMINES THE POSITION AND STRUCTURE OF THE COMPOUND • IT EXPLAINS THE VARIOUS PROBABILITIES OF PHYSICAL AND CHEMICAL BEHAVIOR
  • 16.
     CONCLUSION • INCHEMISTRY, ORBITAL HYBRIDISATTION IS CONCEPT OF MIXING ATOMIC ORBITALS INTO NEW HYBRID ORBITALS • IT IS SUITABLE FOR PAIRING OF ELECTRONS TO FORM CHEMICAL BONDS IN VALANCE BOND THEORY