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The equation of a circle with center (h, k) and
radius r is (x – h)2 + (y – k)2 = r2
Putting, - 2h = 2g, - 2k = 2f and (h2 + k2 – r2 ) = c,
then
x2 + y2 + 2gx + 2fy + c = 0 This is the general equation of a
circle
Now, simplifying this equation
or, x2 – 2hx + h2 + y2 - 2ky + k2 = r2
or, x2 + y2 – 2hx – 2ky + h2 + k2 – r2 = 0
Some Examples
x2 + y2 - 10x – 2y + 10 = 0 X2 + y2 + 10x – 2y + 17 = 0
• The general equation of a circle is
• x2 + y2 + 2gx + 2fy + c = 0
• or, x2 + 2gx + y2 + 2fy = - c
• or, x2 + 2.x.g + g2 + y2 + 2.y.f2 + f2 = g2 + f2 – c
• or, (x + g)2 + (y + f)2 = g2 + f2 – c
Comparing this equation with the equation
(x – h)2 + (y – k)2 = r2, we get Hence, the center of the circle (h, k) = (- g, - f)
Find the center and radius of the circle
represented by x2 + y2 + 4x – 6y + 4 = 0
• The equation of a circle is x2 + y2 + 4x – 6y + 4
= 0
• Comparing with the equation x2 + y2 + 2gx +
2fy + c = 0, we get
• 2g = 4 i.e. g = 2; 2f = - 6 i.e. f = - 3 and c = 4
Therefore, center (h,k) = (-g,-f) = (-2, -(-3) = (-2,3)
=
= 3 units

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General equation of a circle

  • 1. The equation of a circle with center (h, k) and radius r is (x – h)2 + (y – k)2 = r2 Putting, - 2h = 2g, - 2k = 2f and (h2 + k2 – r2 ) = c, then x2 + y2 + 2gx + 2fy + c = 0 This is the general equation of a circle Now, simplifying this equation or, x2 – 2hx + h2 + y2 - 2ky + k2 = r2 or, x2 + y2 – 2hx – 2ky + h2 + k2 – r2 = 0
  • 2. Some Examples x2 + y2 - 10x – 2y + 10 = 0 X2 + y2 + 10x – 2y + 17 = 0
  • 3. • The general equation of a circle is • x2 + y2 + 2gx + 2fy + c = 0 • or, x2 + 2gx + y2 + 2fy = - c • or, x2 + 2.x.g + g2 + y2 + 2.y.f2 + f2 = g2 + f2 – c • or, (x + g)2 + (y + f)2 = g2 + f2 – c Comparing this equation with the equation (x – h)2 + (y – k)2 = r2, we get Hence, the center of the circle (h, k) = (- g, - f)
  • 4. Find the center and radius of the circle represented by x2 + y2 + 4x – 6y + 4 = 0 • The equation of a circle is x2 + y2 + 4x – 6y + 4 = 0 • Comparing with the equation x2 + y2 + 2gx + 2fy + c = 0, we get • 2g = 4 i.e. g = 2; 2f = - 6 i.e. f = - 3 and c = 4 Therefore, center (h,k) = (-g,-f) = (-2, -(-3) = (-2,3) = = 3 units