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LEAST MASTERED SKILLS
Determining the Center and the Radius of a Circle
Given its Equation and Vice-Versa
LC CODE: M10GE-IIh-2
OBJECTIVES:
1. Identify the standard form of the equation
of a circle
2. Determine the center and the radius of a
circle given its equation and vice versa
3. Solve real-life problems using equation of a
circle
LEAST MASTERED SKILLS
Determining the Center and the Radius of a Circle
Given its Equation and Vice-Versa
LC CODE: M10GE-IIh-2
OBJECTIVES:
1. Identify the standard form of the equation
of a circle
2. Determine the center and the radius of a
circle given its equation and vice versa
3. Solve real-life problems using equation of a
circle
As you go through this lesson,
think of this important question:
Perform each activity to find the answer
“How does the equation of a circle facilitates in
finding solutions and making wise decision?”
Before you turn the next page,
try to answer the short quiz below...
1. Transform the equation into its standard form.
x2
+y2
+10x+4y-7=0
2. Determine the center and the radius of the following
equation.
1. x2
+ y2
=32
2. x+5)2
+ (y+9)2
=102
3. x2
+y2
+4x-4y-28=0
The standard equation of a circle with center at (h,k)
and a radius of r units is (x-h)2 + (y-k)2 =r2 .
If the center o the circle is at the
origin, the equation of the circle is
x2 + y2 =r2 .
The equation of a circle with center
at (1,3) and radius 5 is
(x-1)2 + (y-3)2 =52
or
(x-1)2 + (y-3)2 =25
The equation of a circle with center
at the origin and a radius of 3 is
x2 + y2 =32
or
x2 + y2 =9
The equation of a circle with center at
(-5, -9) and radius 10 is
(x+5)2
+ (y+9)2
=102
or
(x+5)2
+ (y+9)2
=100
The equation of a circle
with center at the origin
and a radius of 3 is
x2
+ y2
=32
or
x2
+ y2
=9
The equation of a circle with
center at
(0, -9) and radius 10 is
x2
+ (y+9)2
=102
or
x2
+ (y+9)2
=100
The equation of a circle with center at
(5, 0) and a radius of 4 is
(x-5)2
+ y2
=32
or
(x-5)2
+ y2
=9
Suppose two circles have the same center.
Should the equations defining these circles
be the same? Why?
The center and the radius of the
circle can be found given the
equation.
To do this, transform the equation
to its standard form. Remember
that the equation will be
(x-h)2
+ (y-k)2
=r2
if the center is
(h, k), or x2
+ y2
=r2
if the center of
the circle is at the origin.
Find the center and the radius of the
circle
x2
+ y2
=100.
Solution:
The equation x2
+ y2
=100 has its center
at the origin. Hence it can be trans-
formed to the form
x2
+ y2
= r2
x2
+ y2
= 102
Then the center is at (0, 0) and its radius
is 10.
Determine the center and the radius of the
circle (x-5)2
+ (y-8)2
=52
.
The equation (x-5)2
+ (y-8)2
=52
can be written
in the form
(x-h)2
+ (y-k)2
=r2
(x-5)2
+ (y-8)2
=52
(x-5)2
+ (y-8)2
=25
Then the center is at (5, 8) and the radius
is 5.
What is the center and the
radius of the circle
x2
+y2
-6x-10y+18=0?
The equation
x2
+y2
-6x-10y+18=0 is written
in general form.
x2
+y2
-6x-10y+18=0
x2
-6x+y2
-10y=-18
Add to both side of the equation:
½(-6)=-3; (-3) 2
=9
and
½(-10)=5; (-5) 2
= 25
Then
x2
-6x+9+y2
-10y+25=-18+9+25
(x2
-6x+9)+(y2
-10y+25)=16
Rewriting, we obtain
(x-3)2
+(y-5)2
=42
Therefore the center is at
(3, 5) and its radius is 4.
Write the standard form equation of each of the following circles
given the center and the radius.
Center Radius
1 (3, 8) 1
2 (-6, 4) 3
3 (9, -3) 5
4 (-1, -6) 7
5 (0, 0) 6
6 (0, 5) 4
7 (8, 0) 2
Transform the following equation to
standard form, then determine each
radius and center.
1. (x-2)2
+(y-2)2
-36=0
2. (x+4)2
+(y-9)2
-144=0
3. x2
+y2
-2x-8y-43=0
4. x2
+y2
+4x-4y-28=0
Question:
Is there a shorter way of transforming each equation
to standard form? Share your way.
Solve.
The diameter of the circle is 1 unit and its center
is at (-3, 8). What is the equation of the circle?
Write the equation in standard form.
I. Write the equation of the following
circles given the center and the radius.
Center Radius
1 (5, 9) 49
2 (-9, 12) 64
3 (8, -25) 121
4 (-3, -27) 36
5 (0, 0) 81
6 (0, -7) 169
7 (11, 0) 144
II. Find the center and the radius of
the following circles.
1. (x-7)2
+(y+2)2
=9
2. x2
+(y+2)2
=25
3. (x-5)2
+y2
=36
4. x2
+y2
=49
III. Transform the following equations in
standard form then determine the center
and the radius.
1. x2
+y2
+10x+4y-7=0
2. x2-y2
-6x-8y-24=0
A radio signal can transmit messages up to a
distance of 3km. If the radio signal’s origin is located at a point
whose coordinates are (4,9), what is the equation of the circle
that defines the boundary up to which the messages can be
transmitted? Write the equation in standard form.
I. What defines me?
1. (x-3)2+(y-8)2=12
2. (x+6)2+(y-4)2=32
3. (x-9)2+(y+3)2=52
4. (x+1)2+(y+6)2=72
5. x2+y2=62
6. x2+(y-5)2=42
7. (x-8)2+y2=22
II. Find my Center
and Radius
1. (2, 2);6
2. (-4,9); 12
3. (2, 4); 8
4. (-2, 2); 6
III. Find Out More!
1. (x+3)2+(y-8)2=12
I.
1. (x-5)2+(y-9)2=72
2. (x+9)2+(y-9)2=82
3. (x-8)2+(y+25)2=112
4. (x+2)2+(y+27)2=62
5. x2+y2=92
6. x2+(y+7)2=132
7. (x-11)2+y2=122
II.
1. (7, -2);3
2. (0,-2); 5
3. (5, 0); 6
4. (0,0); 7
III.
1. (-5, -2); 6
2. (3, 4); 7
Enrichment
1. (x-5)2+(y-9)2=72
1. Transform the equation into its standard form.
x2
+y2
+10x+4y-7=0
2. Determine the center and the radius of the following
equation.
1. x2
+ y2
=32
2. x+5)2
+ (y+9)2
=102
3. x2
+y2
+4x-4y-28=0
Let’s check your pre-test ...
1.(x+5)2+(y+2)2=62
2. a. (0, 0);3
b. (-5, -9); 10
c. (2, -2); 6
http://tulyn.com/wordproblems/circle_equation.htm
https://www.wyckoffps.org/cms/lib/NJ01000588/Centricity/
Domain/161/11.3_Real-World%20Problems%20Circles.pdf
https://www.algebra.com/algebra/homework/word/
You are now
ready for the
next lesson ….
Determining the center and the radius of a circle

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Determining the center and the radius of a circle

  • 1.
  • 2. LEAST MASTERED SKILLS Determining the Center and the Radius of a Circle Given its Equation and Vice-Versa LC CODE: M10GE-IIh-2 OBJECTIVES: 1. Identify the standard form of the equation of a circle 2. Determine the center and the radius of a circle given its equation and vice versa 3. Solve real-life problems using equation of a circle
  • 3. LEAST MASTERED SKILLS Determining the Center and the Radius of a Circle Given its Equation and Vice-Versa LC CODE: M10GE-IIh-2 OBJECTIVES: 1. Identify the standard form of the equation of a circle 2. Determine the center and the radius of a circle given its equation and vice versa 3. Solve real-life problems using equation of a circle
  • 4. As you go through this lesson, think of this important question: Perform each activity to find the answer “How does the equation of a circle facilitates in finding solutions and making wise decision?”
  • 5. Before you turn the next page, try to answer the short quiz below... 1. Transform the equation into its standard form. x2 +y2 +10x+4y-7=0 2. Determine the center and the radius of the following equation. 1. x2 + y2 =32 2. x+5)2 + (y+9)2 =102 3. x2 +y2 +4x-4y-28=0
  • 6. The standard equation of a circle with center at (h,k) and a radius of r units is (x-h)2 + (y-k)2 =r2 .
  • 7. If the center o the circle is at the origin, the equation of the circle is x2 + y2 =r2 .
  • 8. The equation of a circle with center at (1,3) and radius 5 is (x-1)2 + (y-3)2 =52 or (x-1)2 + (y-3)2 =25
  • 9. The equation of a circle with center at the origin and a radius of 3 is x2 + y2 =32 or x2 + y2 =9
  • 10. The equation of a circle with center at (-5, -9) and radius 10 is (x+5)2 + (y+9)2 =102 or (x+5)2 + (y+9)2 =100
  • 11. The equation of a circle with center at the origin and a radius of 3 is x2 + y2 =32 or x2 + y2 =9
  • 12. The equation of a circle with center at (0, -9) and radius 10 is x2 + (y+9)2 =102 or x2 + (y+9)2 =100
  • 13. The equation of a circle with center at (5, 0) and a radius of 4 is (x-5)2 + y2 =32 or (x-5)2 + y2 =9
  • 14. Suppose two circles have the same center. Should the equations defining these circles be the same? Why?
  • 15. The center and the radius of the circle can be found given the equation. To do this, transform the equation to its standard form. Remember that the equation will be (x-h)2 + (y-k)2 =r2 if the center is (h, k), or x2 + y2 =r2 if the center of the circle is at the origin.
  • 16. Find the center and the radius of the circle x2 + y2 =100. Solution: The equation x2 + y2 =100 has its center at the origin. Hence it can be trans- formed to the form x2 + y2 = r2 x2 + y2 = 102 Then the center is at (0, 0) and its radius is 10.
  • 17. Determine the center and the radius of the circle (x-5)2 + (y-8)2 =52 . The equation (x-5)2 + (y-8)2 =52 can be written in the form (x-h)2 + (y-k)2 =r2 (x-5)2 + (y-8)2 =52 (x-5)2 + (y-8)2 =25 Then the center is at (5, 8) and the radius is 5.
  • 18. What is the center and the radius of the circle x2 +y2 -6x-10y+18=0? The equation x2 +y2 -6x-10y+18=0 is written in general form. x2 +y2 -6x-10y+18=0 x2 -6x+y2 -10y=-18 Add to both side of the equation: ½(-6)=-3; (-3) 2 =9 and ½(-10)=5; (-5) 2 = 25 Then x2 -6x+9+y2 -10y+25=-18+9+25 (x2 -6x+9)+(y2 -10y+25)=16 Rewriting, we obtain (x-3)2 +(y-5)2 =42 Therefore the center is at (3, 5) and its radius is 4.
  • 19. Write the standard form equation of each of the following circles given the center and the radius. Center Radius 1 (3, 8) 1 2 (-6, 4) 3 3 (9, -3) 5 4 (-1, -6) 7 5 (0, 0) 6 6 (0, 5) 4 7 (8, 0) 2
  • 20. Transform the following equation to standard form, then determine each radius and center. 1. (x-2)2 +(y-2)2 -36=0 2. (x+4)2 +(y-9)2 -144=0 3. x2 +y2 -2x-8y-43=0 4. x2 +y2 +4x-4y-28=0 Question: Is there a shorter way of transforming each equation to standard form? Share your way.
  • 21. Solve. The diameter of the circle is 1 unit and its center is at (-3, 8). What is the equation of the circle? Write the equation in standard form.
  • 22. I. Write the equation of the following circles given the center and the radius. Center Radius 1 (5, 9) 49 2 (-9, 12) 64 3 (8, -25) 121 4 (-3, -27) 36 5 (0, 0) 81 6 (0, -7) 169 7 (11, 0) 144
  • 23. II. Find the center and the radius of the following circles. 1. (x-7)2 +(y+2)2 =9 2. x2 +(y+2)2 =25 3. (x-5)2 +y2 =36 4. x2 +y2 =49
  • 24. III. Transform the following equations in standard form then determine the center and the radius. 1. x2 +y2 +10x+4y-7=0 2. x2-y2 -6x-8y-24=0
  • 25. A radio signal can transmit messages up to a distance of 3km. If the radio signal’s origin is located at a point whose coordinates are (4,9), what is the equation of the circle that defines the boundary up to which the messages can be transmitted? Write the equation in standard form.
  • 26. I. What defines me? 1. (x-3)2+(y-8)2=12 2. (x+6)2+(y-4)2=32 3. (x-9)2+(y+3)2=52 4. (x+1)2+(y+6)2=72 5. x2+y2=62 6. x2+(y-5)2=42 7. (x-8)2+y2=22 II. Find my Center and Radius 1. (2, 2);6 2. (-4,9); 12 3. (2, 4); 8 4. (-2, 2); 6 III. Find Out More! 1. (x+3)2+(y-8)2=12
  • 27. I. 1. (x-5)2+(y-9)2=72 2. (x+9)2+(y-9)2=82 3. (x-8)2+(y+25)2=112 4. (x+2)2+(y+27)2=62 5. x2+y2=92 6. x2+(y+7)2=132 7. (x-11)2+y2=122 II. 1. (7, -2);3 2. (0,-2); 5 3. (5, 0); 6 4. (0,0); 7 III. 1. (-5, -2); 6 2. (3, 4); 7 Enrichment 1. (x-5)2+(y-9)2=72
  • 28. 1. Transform the equation into its standard form. x2 +y2 +10x+4y-7=0 2. Determine the center and the radius of the following equation. 1. x2 + y2 =32 2. x+5)2 + (y+9)2 =102 3. x2 +y2 +4x-4y-28=0 Let’s check your pre-test ...
  • 29. 1.(x+5)2+(y+2)2=62 2. a. (0, 0);3 b. (-5, -9); 10 c. (2, -2); 6