Flip Flops
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Flip-Flops
• Latches are “transparent” (=> any change
on the inputs is seen at the outputs
immediately).
• This causes synchronization problems!
• Solution: use latches to create flip-flops that
can respond (update) ONLY at SPECIFIC
times (instead of ANY time).
D FLIP-FLOP
Flip flop can perform 3 operations
• Set the output to 1
• Reset the output to 0
• Complement the output
• D flip-flop can perform first two operations.
JK Flipflop
Characteristics Equation : D = JQ’ + K’Q
J=K=0; No Change
J=1,K=0, D=1, so Q = 1
J=0,K=1, D=0, so Q = 0
J=K=1, D= Q’, so Q = Q’
•It can perform all three operations.
•It has two inputs and a clock signal.
•It makes use of D flip-flop.
T (toggle) Flip-flop
• It’s a complementing flip-flop
• It can be made using JK flip-flop or D flip-
flop.
• If made using JK flip-flop
– Inputs J & K are tied together
– T=0, J=K=0, No Change in Q
– T=1, J=K=1, Q = Q’
• If made using D flip-flop
– Q = D = T XOR Q = TQ’ + T’Q
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Flipflops JK T SR D All FlipFlop Slides

  • 1.
    Flip Flops Join MeFor More: http://facebook.com/RjSidRehmani
  • 26.
    Flip-Flops • Latches are“transparent” (=> any change on the inputs is seen at the outputs immediately). • This causes synchronization problems! • Solution: use latches to create flip-flops that can respond (update) ONLY at SPECIFIC times (instead of ANY time).
  • 27.
  • 32.
    Flip flop canperform 3 operations • Set the output to 1 • Reset the output to 0 • Complement the output • D flip-flop can perform first two operations.
  • 33.
    JK Flipflop Characteristics Equation: D = JQ’ + K’Q J=K=0; No Change J=1,K=0, D=1, so Q = 1 J=0,K=1, D=0, so Q = 0 J=K=1, D= Q’, so Q = Q’ •It can perform all three operations. •It has two inputs and a clock signal. •It makes use of D flip-flop.
  • 35.
    T (toggle) Flip-flop •It’s a complementing flip-flop • It can be made using JK flip-flop or D flip- flop. • If made using JK flip-flop – Inputs J & K are tied together – T=0, J=K=0, No Change in Q – T=1, J=K=1, Q = Q’ • If made using D flip-flop – Q = D = T XOR Q = TQ’ + T’Q
  • 39.
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