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INTRODUCTION TO STATISTICAL 
CONCEPT
STATISTICS 
the study of the collection, analysis, interpretation, 
presentation and organization of data. It deals with 
all aspects of data including the planning of data 
collection in terms of the design of surveys and 
experiments.
MEAN 
Set of observations is defined as the sum of the 
observations divided by the number of 
observations. 
In symbols, we write mean as: 
Mean = Σx/n 
Where Σ is read “the sum of” and n is the number of 
observations.
MEDIAN 
The middle value or item in a set of data arranged either in 
ascending or descending order. 
If the number of items or values in a given set of data is even, 
add the two middle scores and divide the sum by 2 to get the 
median. 
Example 
1. Determine the median for the set of scores: {15, 18, 31, 29, 
34, and 21} 
Solution: Arrange the elements of the set of scores in 
descending order. 
34, 31, 29, 21, 18, 15 
The middle scores are 29 and 21. The median of the given set of 
scores may calculated by 
Median (Md) = 19 + 21/2= 50/2= 25 
Hence, the median of six scores is 25.
MODE 
The value or item in a given set of data that occurs 
most frequently. 
Example 
1. Find the mode for the following data: 
36, 40, 73, 65, 36, 41, 36 
Solution: 
By inspection the mode is 36 (Mo = 36). It appears 
thrice in the set of data.
STANDARD DEVIATION 
Suppose you're given the data set 1,2,2,4,6. Work through each of 
the steps to find the standard deviation.Calculate the mean of 
your data set. 
The the mean of the data is (1+2+2+4+6)/5 = 15/5 = 3. 
Subtract the mean from each of the data values and list the 
differences.Subtract 3 from each of the values 1,2,2,4,6 
1-3 = -2 
2-3 = -1 
2-3 = -1 
4-3 = 1 
6-3 = 3 
Your list of differences is -2,-1,-1,1,3 
Square each of the differences from the previous step and make a 
list of the squares.You need to square each of the numbers -2,- 
1,-1,1,3 
Your list of differences is -2,-1,-1,1,3 
(-2)2 = 4 
(-1)2=1 
(-1)2=1 
12=1 
32=9
STANDARD DEVIATION 
Your list of squares is 4,1,1,1,9 
Add the squares from the previous step together.You need to 
add 4+1+1+1+9=16 
Subtract one from the number of data values you started 
with.You began this process (it may seem like awhile ago) 
with five data values. One less than this is 5-1 = 4. 
Divide the sum from step four by the number from step five.The 
sum was 16, and the number from the previous step was 4. 
You divide these two numbers 16/4 = 4. 
Take the square root of the number from the previous step. This 
is the standard deviation. 
Your standard deviation is the square root of 4, which is 2.
USE OF MEAN IN ASSESSMENT 
The most well-known statistic of summary is 
called the mean, which is the term we use for 
the arithmetic average score. When most 
people use the term 'average score,' what 
they're really referring to, technically, is what 
we call the mean. How do we calculate the 
mean? We simply add up all of the individual 
results, get the total, and then divide by the 
number of students in the class. In our 
example, you can see how this would look on 
the screen. If you add up the scores of 20 + 
17 + 16 and so on through all 20 students, 
you get a total score of 210. You divide 210 
by 20 (the number of students), and you get 
a mean of 10.5. You can see that this score, 
10.5, is a pretty representative score of the 
middle score for this class, so it works nicely 
as a summary.
IMPORTANCE OF STANDARD DEVIATION IN 
ASSESSMENT 
So why do we care about standard deviation at all? 
Well, a teacher would want to know this information 
because it might change how he or she teaches the 
material or how he or she constructs the test. Let's say 
that there's a small standard deviation because all of the 
scores clustered together right around the top, meaning 
almost all of the students got an A on the test. That 
would mean that the students all demonstrated mastery 
of the material. Or, it could mean that the test was just 
too easy! You could also get a small standard deviation 
if all of the scores clumped together on the other end, 
meaning most of the students failed the test. Again, this 
could be because the teacher did a bad job explaining 
the material or it could mean that the test is too difficult.
IMPORTANCE OF STANDARD DEVIATION IN 
ASSESSMENT 
Most teachers want to get a relatively large standard 
deviation because it means that the scores on the 
test varied from each other. This would indicate that 
a few students did really well, a few students failed, 
and a lot of the students were somewhere in the 
middle. When you have a large standard deviation, 
it usually means that the students got all the 
different possible grades (like As, Bs, Cs, Ds, and 
Fs). So, the teacher can know that he or she taught 
the material correctly (because at least some of the 
students got an A) and the test was neither too 
difficult nor too easy.
~ THE END ~

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Edward diaz bse math3a

  • 2. STATISTICS the study of the collection, analysis, interpretation, presentation and organization of data. It deals with all aspects of data including the planning of data collection in terms of the design of surveys and experiments.
  • 3. MEAN Set of observations is defined as the sum of the observations divided by the number of observations. In symbols, we write mean as: Mean = Σx/n Where Σ is read “the sum of” and n is the number of observations.
  • 4. MEDIAN The middle value or item in a set of data arranged either in ascending or descending order. If the number of items or values in a given set of data is even, add the two middle scores and divide the sum by 2 to get the median. Example 1. Determine the median for the set of scores: {15, 18, 31, 29, 34, and 21} Solution: Arrange the elements of the set of scores in descending order. 34, 31, 29, 21, 18, 15 The middle scores are 29 and 21. The median of the given set of scores may calculated by Median (Md) = 19 + 21/2= 50/2= 25 Hence, the median of six scores is 25.
  • 5. MODE The value or item in a given set of data that occurs most frequently. Example 1. Find the mode for the following data: 36, 40, 73, 65, 36, 41, 36 Solution: By inspection the mode is 36 (Mo = 36). It appears thrice in the set of data.
  • 6. STANDARD DEVIATION Suppose you're given the data set 1,2,2,4,6. Work through each of the steps to find the standard deviation.Calculate the mean of your data set. The the mean of the data is (1+2+2+4+6)/5 = 15/5 = 3. Subtract the mean from each of the data values and list the differences.Subtract 3 from each of the values 1,2,2,4,6 1-3 = -2 2-3 = -1 2-3 = -1 4-3 = 1 6-3 = 3 Your list of differences is -2,-1,-1,1,3 Square each of the differences from the previous step and make a list of the squares.You need to square each of the numbers -2,- 1,-1,1,3 Your list of differences is -2,-1,-1,1,3 (-2)2 = 4 (-1)2=1 (-1)2=1 12=1 32=9
  • 7. STANDARD DEVIATION Your list of squares is 4,1,1,1,9 Add the squares from the previous step together.You need to add 4+1+1+1+9=16 Subtract one from the number of data values you started with.You began this process (it may seem like awhile ago) with five data values. One less than this is 5-1 = 4. Divide the sum from step four by the number from step five.The sum was 16, and the number from the previous step was 4. You divide these two numbers 16/4 = 4. Take the square root of the number from the previous step. This is the standard deviation. Your standard deviation is the square root of 4, which is 2.
  • 8. USE OF MEAN IN ASSESSMENT The most well-known statistic of summary is called the mean, which is the term we use for the arithmetic average score. When most people use the term 'average score,' what they're really referring to, technically, is what we call the mean. How do we calculate the mean? We simply add up all of the individual results, get the total, and then divide by the number of students in the class. In our example, you can see how this would look on the screen. If you add up the scores of 20 + 17 + 16 and so on through all 20 students, you get a total score of 210. You divide 210 by 20 (the number of students), and you get a mean of 10.5. You can see that this score, 10.5, is a pretty representative score of the middle score for this class, so it works nicely as a summary.
  • 9. IMPORTANCE OF STANDARD DEVIATION IN ASSESSMENT So why do we care about standard deviation at all? Well, a teacher would want to know this information because it might change how he or she teaches the material or how he or she constructs the test. Let's say that there's a small standard deviation because all of the scores clustered together right around the top, meaning almost all of the students got an A on the test. That would mean that the students all demonstrated mastery of the material. Or, it could mean that the test was just too easy! You could also get a small standard deviation if all of the scores clumped together on the other end, meaning most of the students failed the test. Again, this could be because the teacher did a bad job explaining the material or it could mean that the test is too difficult.
  • 10. IMPORTANCE OF STANDARD DEVIATION IN ASSESSMENT Most teachers want to get a relatively large standard deviation because it means that the scores on the test varied from each other. This would indicate that a few students did really well, a few students failed, and a lot of the students were somewhere in the middle. When you have a large standard deviation, it usually means that the students got all the different possible grades (like As, Bs, Cs, Ds, and Fs). So, the teacher can know that he or she taught the material correctly (because at least some of the students got an A) and the test was neither too difficult nor too easy.