The document discusses the characteristics and operation of an ideal diode, including analyzing simple circuits involving diodes. It examines the current-voltage relationship of diodes and how rectifier circuits use diodes to produce a voltage waveform from a sinusoidal input. Examples are provided to determine the conduction angle, peak diode current, and maximum reverse bias voltage for a rectifier circuit charging a battery from a sinusoidal source.

1. PRESENTATION TOPIC
IDEAL DIODE
SYED HASHIR AHMED
ROLL# 130

2. Objectives
 Understand the characteristics of an ideal diode.
 Analyze simple circuits involving ideal diodes.

3. Current-Voltage Characteristic
Forward/Reverse Bias

4. Computing iD and vD
What is the current through the diode (iD) and the voltage
across the diode (vD) for the following two circuits?

5. Rectifier Circuit
What voltage waveform would we observe across the
output of this circuit?

6. Rectifier Circuit Operation

7. Rectifier Circuit Operation (Cont’d)
What voltage waveform would we observe across the diode vD?

8. Voltage Transfer Characteristic of the Rectifier
Circuit

9. The source vS is a sinusoid with a 24 Vpeak amplitude. The diode is used to charge
a 12 V battery and the 100 resistor limits the current.
We want to determine the fraction of each cycle during which the diode
conducts. We also wish to find the peak-value of the diode current and the
maximum reverse-bias voltage that appears across the diode.

10. Solution
We reason that the diode will not begin to conduct until vS exceeds 12 V. Likewise, the
diode will stop conducting once vS again reaches 12 V.
This defines the conduction angle, 2 (i.e., the fraction of the sinusoidal cycle over which
the diode conducts). Hence, we reason that the diode will conduct provided that 24V sin
12 V. Or 30o ≤ ≤ 150o (or 1/3 of a cycle).
24V 12V
The peak value of the diode current is I D 0.12 Amps
100

11. Solution (Cont’d)
The maximum reverse-bias voltage that appears across the diode is simply:
24 V + 12 V = 36 V

12. Let’s begin by assuming that diodes D1 and D2 are conducting:
10 0
I D2 1mA
10k
KCL (node B):
0 ( 10)
I 1mA I 1mA
5k
For this second circuit the same assumption gives
nonsensical results (verify this) 
We assume that D1 is OFF and D2 is ON.
Consequently, VB = 3.3 V (verify).

13. FEEDBACK
syedhashir@ymail.com
Contect:03133116593