A-level Physics



Unit G484:
The Newtonian
World




Centripetal force &
acceleration
Circular motion
Lesson focus
  • Centripetal acceleration and force


  Learning objectives
  At the end of the lesson you will be able to:

  • use the equation for centripetal acceleration a = v2/r ;

  • use the equation for centripetal force F = ma = mv2/r .




Circular motion
Learning outcomes

  All of you should be able to
  • recall the equation for centripetal acceleration;
  • recall the equation for centripetal force;
  • solve basic problems using these equations.


  Most of you will be able to
  • solve more complex problems using these equations.




Circular motion
Deriving the equation for centripetal acceleration               LOs




       u                v
               x
                                                             x - arc length
                   θ                    x
           r
                                    θ =          (1)         r - radius
                                        r
                                                             θ - angle (in radians)
                                                                 subtended by
                                                                 arc length x


                       v
                        θ                Δv                               (2)
    Δv = v - u                       θ ≈               i.e. Δv ≈ θv
                            -u            v




Circular motion                        LO 1: use the equation for centripetal acceleration
Deriving the equation for centripetal acceleration                   LOs



      u               v
              x
                                                 v                    x         (1)
                  θ                                               θ =
          r                                       θ                   r
                                   Δv = v - u         -u
                                                                  Δv ≈ θv        (2)




   Combining (1)                  xv                  i.e.   Δv     v2
                             Δv ≈                                 ≈
   and (2) gives                  r                          t      r

                                 v2t                                           (as t and θ
   but x = vt              Δv ≈                      i.e.   a =     v2         become
                                 r                                   r          very small)



Circular motion                          LO 1: use the equation for centripetal acceleration
Deriving the equation for centripetal acceleration                       LOs




             u               v
                     x
                                                        v
                         θ
                 r                                       θ
                                           Δv = v - u        -u




                                 a = v2
                                     r

                                F = mv2           since F = ma
                                      r


Circular motion                       LO 1: use the equation for centripetal acceleration

Cm 3 centripetal force & acceleration (shared)

  • 1.
    A-level Physics Unit G484: TheNewtonian World Centripetal force & acceleration Circular motion
  • 2.
    Lesson focus • Centripetal acceleration and force Learning objectives At the end of the lesson you will be able to: • use the equation for centripetal acceleration a = v2/r ; • use the equation for centripetal force F = ma = mv2/r . Circular motion
  • 3.
    Learning outcomes All of you should be able to • recall the equation for centripetal acceleration; • recall the equation for centripetal force; • solve basic problems using these equations. Most of you will be able to • solve more complex problems using these equations. Circular motion
  • 4.
    Deriving the equationfor centripetal acceleration LOs u v x x - arc length θ x r θ = (1) r - radius r θ - angle (in radians) subtended by arc length x v θ Δv (2) Δv = v - u θ ≈ i.e. Δv ≈ θv -u v Circular motion LO 1: use the equation for centripetal acceleration
  • 5.
    Deriving the equationfor centripetal acceleration LOs u v x v x (1) θ θ = r θ r Δv = v - u -u Δv ≈ θv (2) Combining (1) xv i.e. Δv v2 Δv ≈ ≈ and (2) gives r t r v2t (as t and θ but x = vt  Δv ≈ i.e. a = v2 become r r very small) Circular motion LO 1: use the equation for centripetal acceleration
  • 6.
    Deriving the equationfor centripetal acceleration LOs u v x v θ r θ Δv = v - u -u a = v2 r  F = mv2 since F = ma r Circular motion LO 1: use the equation for centripetal acceleration