Chapter10 section03 Percent Composition and Chemical Formulas By Hamdy Karim.Hamdy Karim
Students will learn about the Percent Composition and Chemical Formulas, also they will learn the difference between the empirical and molecular formulae!
Percent composition is the percent by mass of each element in a compound, calculated by taking the mass of an element divided by the total mass of the compound and multiplying by 100. To calculate percent composition, you write the compound formula, do an atom inventory and find the molar mass, then use the formula: % composition of element = mass of element x 100% / mass of compound. For compounds with multiple elements, separate calculations must be done for each element. As an example, the percent composition of hydrogen in water is 11.1% and oxygen is 88.9%, which should total very closely to 100%.
Percent composition is calculated by finding the molar mass of a compound using the periodic table, determining the mass contributed by the component of interest, and dividing that mass by the total molar mass of the compound before multiplying by 100. This allows you to determine the percentage of a compound's total mass made up of a particular component by mass. The document provides an example calculating the percent composition of carbon in carbon dioxide (CO2).
This document provides steps for calculating empirical and molecular formulas from percent composition data and molar mass. It presents an example calculation showing that a compound that is 43.7% P and 56.3% O with a molar mass of 283.88 g/mol has an empirical formula of P2O5 and a molecular formula of P4O10. Several practice problems are provided for students to determine empirical and molecular formulas.
The document discusses empirical and molecular formulas. An empirical formula shows the simplest whole number ratio of atoms in a compound, while a molecular formula shows the exact number of each atom. To calculate molecular formula from empirical formula: 1) make a table with elements, percentages, atomic masses, moles, and simplest ratios; 2) the empirical formula mass is the sum of the atoms' masses; 3) divide the molar mass by the empirical formula mass to get the common factor for the molecular formula. Two examples are given to calculate empirical and molecular formulas from percentage compositions and molar masses.
This document discusses empirical formulas and how to determine them from percentage composition or experimental data. It provides examples of calculating empirical formulas from the mass percentages of elements in a compound or the grams of elements in a sample. It also explains how to determine the molecular formula of a compound from the empirical formula and experimental molar mass. Key steps include converting percentages to grams of elements, calculating moles of each element, and dividing by the smallest ratio of elements to give whole number ratios in the empirical formula. The molecular formula is found by dividing the experimental molar mass by the molar mass of the empirical formula.
Chapter 7.4 : Determining Chemical FormulasChris Foltz
This document discusses determining chemical formulas, including:
1) Defining empirical and molecular formulas, and how to calculate empirical formulas from percentage or mass composition data.
2) Explaining how to determine a molecular formula from an empirical formula using the relationship between molecular formula mass and empirical formula mass.
3) Providing examples of calculating empirical formulas from composition data and determining molecular formulas from empirical formulas and molar masses.
Chapter10 section03 Percent Composition and Chemical Formulas By Hamdy Karim.Hamdy Karim
Students will learn about the Percent Composition and Chemical Formulas, also they will learn the difference between the empirical and molecular formulae!
Percent composition is the percent by mass of each element in a compound, calculated by taking the mass of an element divided by the total mass of the compound and multiplying by 100. To calculate percent composition, you write the compound formula, do an atom inventory and find the molar mass, then use the formula: % composition of element = mass of element x 100% / mass of compound. For compounds with multiple elements, separate calculations must be done for each element. As an example, the percent composition of hydrogen in water is 11.1% and oxygen is 88.9%, which should total very closely to 100%.
Percent composition is calculated by finding the molar mass of a compound using the periodic table, determining the mass contributed by the component of interest, and dividing that mass by the total molar mass of the compound before multiplying by 100. This allows you to determine the percentage of a compound's total mass made up of a particular component by mass. The document provides an example calculating the percent composition of carbon in carbon dioxide (CO2).
This document provides steps for calculating empirical and molecular formulas from percent composition data and molar mass. It presents an example calculation showing that a compound that is 43.7% P and 56.3% O with a molar mass of 283.88 g/mol has an empirical formula of P2O5 and a molecular formula of P4O10. Several practice problems are provided for students to determine empirical and molecular formulas.
The document discusses empirical and molecular formulas. An empirical formula shows the simplest whole number ratio of atoms in a compound, while a molecular formula shows the exact number of each atom. To calculate molecular formula from empirical formula: 1) make a table with elements, percentages, atomic masses, moles, and simplest ratios; 2) the empirical formula mass is the sum of the atoms' masses; 3) divide the molar mass by the empirical formula mass to get the common factor for the molecular formula. Two examples are given to calculate empirical and molecular formulas from percentage compositions and molar masses.
This document discusses empirical formulas and how to determine them from percentage composition or experimental data. It provides examples of calculating empirical formulas from the mass percentages of elements in a compound or the grams of elements in a sample. It also explains how to determine the molecular formula of a compound from the empirical formula and experimental molar mass. Key steps include converting percentages to grams of elements, calculating moles of each element, and dividing by the smallest ratio of elements to give whole number ratios in the empirical formula. The molecular formula is found by dividing the experimental molar mass by the molar mass of the empirical formula.
Chapter 7.4 : Determining Chemical FormulasChris Foltz
This document discusses determining chemical formulas, including:
1) Defining empirical and molecular formulas, and how to calculate empirical formulas from percentage or mass composition data.
2) Explaining how to determine a molecular formula from an empirical formula using the relationship between molecular formula mass and empirical formula mass.
3) Providing examples of calculating empirical formulas from composition data and determining molecular formulas from empirical formulas and molar masses.
This document provides information and examples for calculating percent composition, empirical formulas, and molecular formulas of compounds. It defines key terms like percent composition and empirical formula. It then works through examples of calculating the percent composition of magnesium and oxygen that form a compound, the percent composition and mass of carbon in propane, and determining empirical formulas from elemental percentages or mole ratios. The document explains how to calculate molecular formulas from empirical formulas and molar masses. Finally, it provides practice problems for the reader to work through.
The document provides information about atoms and their structure. It defines key terms like protons, neutrons, electrons, nucleus and isotopes. It explains that the number of protons determines the element and distinguishes one atom from another. The mole is also defined as 6.02x10^23 particles and is used to measure amounts of substances on a macroscopic scale. Formulas are given to calculate molar mass and empirical formulas.
This document discusses calculating formula masses, molar masses, and percentage compositions of chemical compounds. It provides examples of calculating the formula mass of compounds by adding the atomic masses of each element. Molar mass is defined as the mass of one mole of a compound and is numerically equal to formula mass. The document demonstrates using molar mass to convert between mass and moles of a compound. It also gives examples of calculating the percentage by mass of each element in compounds like copper(I) sulfide and sodium carbonate decahydrate.
2011 topic 01 lecture 2 - empirical and molecular formulaeDavid Young
The document discusses empirical and molecular formulas. It provides examples to show how to determine the empirical formula from percent composition data and how to then determine the molecular formula from the empirical formula and molar mass. Specifically, it shows how to calculate the empirical formula of adipic acid is C3H5O2 from its percent composition by mass. It then shows that if the molar mass of adipic acid is 146 g/mol, and the molar mass of C3H5O2 is 73.08 g/mol, then the molecular formula of adipic acid must be C6H10O4.
The researchers used molecular dynamics simulations to model asphaltene aggregate behavior in crude oil. They developed a simulation model using the MDynaMix program to model aggregates of 6 asphaltene molecules and 8 resin molecules in hexane solvent. Simulations of 2-32 nanoseconds found the asphaltene aggregates form stacked sheets with a distance of 3.74 angstroms between sheets. The aggregates had a density of 0.69 g/cm3 and limited mobility, diffusing around 3 times slower than hexane. The simulations provide insight into asphaltene aggregation and behavior in crude oil recovery.
The document discusses key concepts related to moles, including:
1) A mole is defined as 6.02x1023 representative particles of a substance, which can be used to convert between the number of particles and moles.
2) The mass of one mole of a substance is its molar mass, which can be used to convert between mass and moles.
3) One mole of an ideal gas occupies a volume of 22.4L at STP, which can be used to convert between moles and volume.
4) Percent composition by mass and molar mass can be used to determine empirical and molecular formulas of compounds.
The document discusses methods for calculating percent composition and molecular formulas from empirical data. It provides examples of calculating percent composition from mass percentages of elements in compounds and from experimental analysis of sample masses. It also demonstrates calculating empirical formulas from percent compositions or measured element masses and determining molecular formulas from empirical formulas and molar masses.
Percent composition is a calculation that determines the percentage by mass of each element in a compound. It is calculated by taking the mass of one element, dividing it by the total mass of the compound, and multiplying by 100. For example, water (H2O) has a percent composition of 89.9% oxygen because oxygen has a mass of 16.0 grams in water's total mass of 18.0 grams. Percent composition provides information about the elemental makeup of compounds.
chemical composition education "komposisi reaksi kimia"chusnaqumillaila
pada materi ini disajikan sebuah materi tentang komposisi reaksi kimia pada saat terjadinya peristiwa kimia. materi ini dibuat bertujuan untuk diberikan kepada para mahasiswa dan pelajar yang sedang mencari dan belajar memperdalam tentang materi komposisi kimia. semoga materi ini bermanfaat untuk semuanya
This document discusses concepts related to stoichiometry including empirical formulas, molecular formulas, percentage composition, and hydrates. It provides examples of calculating empirical formulas from mass percentages of elements in compounds and using mole ratios. It also distinguishes between empirical formulas that give the lowest whole number ratio of atoms in a compound and molecular formulas that give the actual ratio in compounds.
The document contains examples and explanations of concepts related to chemistry calculations including:
- Percentage composition problems calculating the percent by mass of elements in compounds.
- Empirical formula problems finding the lowest whole number ratio of atoms in a compound from percentage or mole composition data.
- Molecular formula problems relating the empirical formula to molar mass to determine the actual formula.
- Hydrate problems using the formula for hydrated compounds to determine the amount of water bonded in the crystal structure from percentage or mass composition data.
This document discusses how to calculate the percentage composition of compounds from their chemical formulas. It explains that the chemical formula tells the number of moles of each element in one mole of the compound. It then provides steps to calculate percentage composition: write the chemical formula, find the molar mass of the compound and each element, divide the molar mass of each element by the total molar mass and multiply by 100. Examples are given for potassium chlorate and ammonium phosphate.
The document discusses methods for determining the percentage composition, empirical formula, and molecular formula of chemical compounds from experimental data. It provides examples of calculating percentage composition from mass data and determining the empirical and molecular formulas of samples. The key steps outlined are calculating percentage composition from element masses, determining moles of each element and reducing ratios to simplest whole numbers for empirical formulas, and relating molecular mass to empirical formula mass to derive molecular formulas.
This chapter discusses stoichiometry, including atomic masses, the mole concept, molar masses, percent composition of compounds, determining empirical and molecular formulas, writing and balancing chemical equations, and stoichiometric calculations involving amounts of reactants and products. Key aspects covered are determining the limiting reagent, using balanced equations to determine mole ratios, and calculating mass relationships in chemical reactions based on these mole ratios.
The document provides information to determine the empirical and molecular formulas of several compounds: melamine has an empirical formula of C3H6N6 and molecular formula of C3H6N6; the empirical formula of an iron oxide is FeO; the formula of aluminum oxide formed from the burning of aluminum is Al2O3; the molecular formula of a compound with an empirical formula of (CH3)n and molecular formula mass of 30 is C2H6; the molecular formula of benzene which has an empirical formula of CH and relative molecular mass of 78 is C6H6.
The mole concept and chemical compounds.
Ethyl mercaptan, C2H6S, is added to natural gas to make gas leaks detectable.
The colorless, volatile liquid halothane has been used as a fire extinguisher and also as an inhalation anesthetic.
Dibutyl succinate is an insect repellent used against household ants and roaches.
The document discusses percent composition of compounds. It defines percent composition as the relative amounts of elements in a compound determined by comparing the mass of each element present in 1 mole to the total mass of 1 mole of the compound. Three examples are provided to demonstrate calculating percent composition by taking the mass of an element, dividing by the molar mass of the compound, and multiplying by 100. The final example shows calculating the mass of each element in a sample based on its given percent composition.
Stoichiometry is the quantitative study of reactants and products in chemical reactions. Given the amount of one reactant, stoichiometry can be used to determine the amount of products that can be formed. The key steps involve balancing the chemical equation, converting between moles and mass using molar ratios and molar masses, and setting up and solving mole ratios from the balanced equation and problem statement.
The document provides information about moles, molar mass, empirical and molecular formulas, percentage composition of compounds, and analytical techniques like mass spectrometry and combustion analysis. It includes examples of calculations involving moles, molar mass, empirical formulas from percentage composition data, determining molecular formulas from empirical formulas and molar masses, and calculating hydration in salts.
Lecture 12.3- Limiting Reagents and Percent YieldMary Beth Smith
The document discusses key concepts in chemistry including:
1) Limiting reagents and how the amount of one reactant determines how much product can be formed in a reaction.
2) Theoretical yield refers to the maximum product that can form based on stoichiometry while actual yield is what is obtained in the lab.
3) Percent yield compares the actual yield to the theoretical yield and indicates the reaction's efficiency. It is never higher than 100%.
The document discusses mole conversions between number of atoms/molecules, moles, and grams. It provides shortcuts for common conversions between these units and works through sample problems converting between atoms, molecules, moles, and grams of various substances using their molar masses.
This document provides information and examples for calculating percent composition, empirical formulas, and molecular formulas of compounds. It defines key terms like percent composition and empirical formula. It then works through examples of calculating the percent composition of magnesium and oxygen that form a compound, the percent composition and mass of carbon in propane, and determining empirical formulas from elemental percentages or mole ratios. The document explains how to calculate molecular formulas from empirical formulas and molar masses. Finally, it provides practice problems for the reader to work through.
The document provides information about atoms and their structure. It defines key terms like protons, neutrons, electrons, nucleus and isotopes. It explains that the number of protons determines the element and distinguishes one atom from another. The mole is also defined as 6.02x10^23 particles and is used to measure amounts of substances on a macroscopic scale. Formulas are given to calculate molar mass and empirical formulas.
This document discusses calculating formula masses, molar masses, and percentage compositions of chemical compounds. It provides examples of calculating the formula mass of compounds by adding the atomic masses of each element. Molar mass is defined as the mass of one mole of a compound and is numerically equal to formula mass. The document demonstrates using molar mass to convert between mass and moles of a compound. It also gives examples of calculating the percentage by mass of each element in compounds like copper(I) sulfide and sodium carbonate decahydrate.
2011 topic 01 lecture 2 - empirical and molecular formulaeDavid Young
The document discusses empirical and molecular formulas. It provides examples to show how to determine the empirical formula from percent composition data and how to then determine the molecular formula from the empirical formula and molar mass. Specifically, it shows how to calculate the empirical formula of adipic acid is C3H5O2 from its percent composition by mass. It then shows that if the molar mass of adipic acid is 146 g/mol, and the molar mass of C3H5O2 is 73.08 g/mol, then the molecular formula of adipic acid must be C6H10O4.
The researchers used molecular dynamics simulations to model asphaltene aggregate behavior in crude oil. They developed a simulation model using the MDynaMix program to model aggregates of 6 asphaltene molecules and 8 resin molecules in hexane solvent. Simulations of 2-32 nanoseconds found the asphaltene aggregates form stacked sheets with a distance of 3.74 angstroms between sheets. The aggregates had a density of 0.69 g/cm3 and limited mobility, diffusing around 3 times slower than hexane. The simulations provide insight into asphaltene aggregation and behavior in crude oil recovery.
The document discusses key concepts related to moles, including:
1) A mole is defined as 6.02x1023 representative particles of a substance, which can be used to convert between the number of particles and moles.
2) The mass of one mole of a substance is its molar mass, which can be used to convert between mass and moles.
3) One mole of an ideal gas occupies a volume of 22.4L at STP, which can be used to convert between moles and volume.
4) Percent composition by mass and molar mass can be used to determine empirical and molecular formulas of compounds.
The document discusses methods for calculating percent composition and molecular formulas from empirical data. It provides examples of calculating percent composition from mass percentages of elements in compounds and from experimental analysis of sample masses. It also demonstrates calculating empirical formulas from percent compositions or measured element masses and determining molecular formulas from empirical formulas and molar masses.
Percent composition is a calculation that determines the percentage by mass of each element in a compound. It is calculated by taking the mass of one element, dividing it by the total mass of the compound, and multiplying by 100. For example, water (H2O) has a percent composition of 89.9% oxygen because oxygen has a mass of 16.0 grams in water's total mass of 18.0 grams. Percent composition provides information about the elemental makeup of compounds.
chemical composition education "komposisi reaksi kimia"chusnaqumillaila
pada materi ini disajikan sebuah materi tentang komposisi reaksi kimia pada saat terjadinya peristiwa kimia. materi ini dibuat bertujuan untuk diberikan kepada para mahasiswa dan pelajar yang sedang mencari dan belajar memperdalam tentang materi komposisi kimia. semoga materi ini bermanfaat untuk semuanya
This document discusses concepts related to stoichiometry including empirical formulas, molecular formulas, percentage composition, and hydrates. It provides examples of calculating empirical formulas from mass percentages of elements in compounds and using mole ratios. It also distinguishes between empirical formulas that give the lowest whole number ratio of atoms in a compound and molecular formulas that give the actual ratio in compounds.
The document contains examples and explanations of concepts related to chemistry calculations including:
- Percentage composition problems calculating the percent by mass of elements in compounds.
- Empirical formula problems finding the lowest whole number ratio of atoms in a compound from percentage or mole composition data.
- Molecular formula problems relating the empirical formula to molar mass to determine the actual formula.
- Hydrate problems using the formula for hydrated compounds to determine the amount of water bonded in the crystal structure from percentage or mass composition data.
This document discusses how to calculate the percentage composition of compounds from their chemical formulas. It explains that the chemical formula tells the number of moles of each element in one mole of the compound. It then provides steps to calculate percentage composition: write the chemical formula, find the molar mass of the compound and each element, divide the molar mass of each element by the total molar mass and multiply by 100. Examples are given for potassium chlorate and ammonium phosphate.
The document discusses methods for determining the percentage composition, empirical formula, and molecular formula of chemical compounds from experimental data. It provides examples of calculating percentage composition from mass data and determining the empirical and molecular formulas of samples. The key steps outlined are calculating percentage composition from element masses, determining moles of each element and reducing ratios to simplest whole numbers for empirical formulas, and relating molecular mass to empirical formula mass to derive molecular formulas.
This chapter discusses stoichiometry, including atomic masses, the mole concept, molar masses, percent composition of compounds, determining empirical and molecular formulas, writing and balancing chemical equations, and stoichiometric calculations involving amounts of reactants and products. Key aspects covered are determining the limiting reagent, using balanced equations to determine mole ratios, and calculating mass relationships in chemical reactions based on these mole ratios.
The document provides information to determine the empirical and molecular formulas of several compounds: melamine has an empirical formula of C3H6N6 and molecular formula of C3H6N6; the empirical formula of an iron oxide is FeO; the formula of aluminum oxide formed from the burning of aluminum is Al2O3; the molecular formula of a compound with an empirical formula of (CH3)n and molecular formula mass of 30 is C2H6; the molecular formula of benzene which has an empirical formula of CH and relative molecular mass of 78 is C6H6.
The mole concept and chemical compounds.
Ethyl mercaptan, C2H6S, is added to natural gas to make gas leaks detectable.
The colorless, volatile liquid halothane has been used as a fire extinguisher and also as an inhalation anesthetic.
Dibutyl succinate is an insect repellent used against household ants and roaches.
The document discusses percent composition of compounds. It defines percent composition as the relative amounts of elements in a compound determined by comparing the mass of each element present in 1 mole to the total mass of 1 mole of the compound. Three examples are provided to demonstrate calculating percent composition by taking the mass of an element, dividing by the molar mass of the compound, and multiplying by 100. The final example shows calculating the mass of each element in a sample based on its given percent composition.
Stoichiometry is the quantitative study of reactants and products in chemical reactions. Given the amount of one reactant, stoichiometry can be used to determine the amount of products that can be formed. The key steps involve balancing the chemical equation, converting between moles and mass using molar ratios and molar masses, and setting up and solving mole ratios from the balanced equation and problem statement.
The document provides information about moles, molar mass, empirical and molecular formulas, percentage composition of compounds, and analytical techniques like mass spectrometry and combustion analysis. It includes examples of calculations involving moles, molar mass, empirical formulas from percentage composition data, determining molecular formulas from empirical formulas and molar masses, and calculating hydration in salts.
Lecture 12.3- Limiting Reagents and Percent YieldMary Beth Smith
The document discusses key concepts in chemistry including:
1) Limiting reagents and how the amount of one reactant determines how much product can be formed in a reaction.
2) Theoretical yield refers to the maximum product that can form based on stoichiometry while actual yield is what is obtained in the lab.
3) Percent yield compares the actual yield to the theoretical yield and indicates the reaction's efficiency. It is never higher than 100%.
The document discusses mole conversions between number of atoms/molecules, moles, and grams. It provides shortcuts for common conversions between these units and works through sample problems converting between atoms, molecules, moles, and grams of various substances using their molar masses.
This document discusses factors that shape ecosystems, including climate, latitude, habitat, and community interactions. Climate is influenced by greenhouse gases and affects temperature and precipitation zones. Habitats are defined by biotic and abiotic factors. Community interactions include competition, predation, and symbiosis relationships. Ecosystems change over time through ecological succession as environments are disturbed or develop. The document also introduces different biomes defined by climate and includes examples of desert and tundra biomes.
This document provides an overview of meiosis and sexual life cycles by discussing:
- The transmission of traits from parents to offspring through inheritance of genes and chromosomes.
- The differences between asexual and sexual reproduction, and how meiosis and fertilization alternate in sexual life cycles.
- The three main types of sexual life cycles seen in animals, plants/algae, and fungi/protists with regards to timing of meiosis, fertilization, and diploid/haploid stages.
- Key cellular processes like meiosis, fertilization, mitosis and their roles in maintaining chromosome number and producing genetic variation in offspring.
This document contains slides from a Pearson Prentice Hall chemistry textbook about percent composition and chemical formulas. The objectives covered are calculating percent composition from chemical formulas, calculating empirical formulas from percent composition, and calculating molecular formulas from molar mass. Several examples are provided to show how to calculate these values through problems involving finding the percent of elements in compounds, determining empirical formulas, and deriving molecular formulas.
The document is a slide presentation on the mole as a unit of measurement in chemistry. It discusses how chemists measure the amount of a substance using moles, which relates the number of particles to mass. A mole is defined as 6.02x1023 representative particles of a substance, whether atoms, molecules, or formula units. The mass of a mole of a pure element is known as its molar mass and is equal to its atomic mass in grams. The molar mass of a compound is calculated by adding together the masses of the individual elements that make up one mole of the compound.
Attacking the TEKS: Focus on Gases presented by Jane Smith, ACT2 2010
This session will expose you to the new TEKS and College Readiness Standards. Ideas for sequencing and planning the unit will be shared along with tips for appropriate demos, labs, and assessments. The intended audience is for teachers with 3 or less years of experience or anyone who wants to delve deeper into the new standards.
The document summarizes key concepts from Chapter 14 on the ideal gas law and kinetic theory. Section 1 discusses molecular mass, the mole, and Avogadro's number. Section 2 covers the ideal gas law and how pressure, volume, temperature, and moles are related. Section 3 introduces the kinetic theory model, which describes gases as large numbers of constantly moving particles and explains gas properties and behaviors in terms of particle collisions and kinetic energy.
A brief introduction to the mole conceptawaisaazoumi
1. The document discusses different units used to measure amount of substance, including moles, grams, particles, and liters at STP.
2. A mole is defined as 6.02 x 1023 representative particles and is used to quantify atoms, molecules, ions, and formula units.
3. Conversions between moles, mass in grams, number of particles, and volume in liters can be performed using appropriate conversion factors and molar masses.
The document discusses the mole, which relates the number of particles in a substance to its mass in grams. It defines one mole as 6.02 x 10^23 particles, known as Avogadro's number. It provides examples of calculating moles, mass, and number of particles using molar mass and unit conversion with moles. Key relationships discussed are mass=moles×molar mass and number of particles=moles×Avogadro's number.
This document discusses pneumatic and electro-pneumatic systems. It covers the properties of air and gases, including the ideal gas laws of Boyle's law, Charles' law, Avogadro's law, and Dalton's law of partial pressures. It also discusses key components of pneumatic systems like compressors, filters, regulators, valves and actuators. The document introduces electro-pneumatic systems and their elements, as well as pneumatic logic circuits.
Question 1. Two parallel flocculation basins are to be used to tre.docxIRESH3
Question 1. Two parallel flocculation basins are to be used to treat water flow of 150m3/s. If the design detention time is 20minute, what is the volume of each tank? If the average velocity gradient in these two tanks is 124/s, calculate the velocity gradient is each basin if the gradient in second basin is half of the first one.
Question 2. Determine the volume of the aeration tank for the following operating conditions:
Influent BOD5 concentration after the primary is = 150mg/L
Wastewater flow rate = 10MGD
F/M ratio = 0.2/d
Mixed Liquor volatile suspended solid concentration = 2200mg/L
Question 3. Given below is the wastewater characteristics, determine the F/M ratio? (10 Points)
Influent BOD5 concentration = 84mg/L
Wastewater flow rate = 0.150m3/s
Volume of the aeration tanks = 970m3
Mixed Liquor volatile suspended solid concentration = 2000mg/L
Question 4. What is the terminal settling velocity of a particle with a specific gravity of 1.4 and a diameter of 0.010mm in 20oC water? Would this particle be completely removed in a settling basin with a width of 10.0m, depth of 3.0m, a length of 30.0m, and a flow rate of 7500m3/d? What is the smallest diameter particle of specific gravity 1.4 that would be removed in the sedimentation basin described above?
Question 5. Will grit particle with a radius of 0.04mm and a specific gravity of 2.65 be collected in a horizontal grit chamber that is 13.5m in length if the average grit-chamber flow is 0.15m3/s, the width of the chamber is 0.56m, and the horizontal velocity is 0.25m/s? The wastewater temperature is 22oC.
Question 6. Wastewater treatment plant flow rate is 20MGD. Chlorine dosage is 10mg/L. Determine chlorine requirement (lb/day)
Question 7. If a particle having a 0.0170-cm radius and density of 1.95g/cm3 is allowed to fall into quiescent water having a temperature of 4oC, what will be the terminal settling velocity? Assume the density of water = 1000kg/m3. Assume Stoke’s law applies?
Question 8. If the terminal settling velocity of a particle falling in quiescent water having a temperature of 15oC is 0.0950cm/s, what is its diameter? Assume a particle density of 2.05g/cm3 and density of water equal to 1000kg/m3.
µ@15oC = 1.139 mPa-s
ρ @15oC = 999.103kg/m3
Question 9. Determine the diameter of a single-stage rock media filter to reduce an applied BOD5 of 125mg/L to 25mg/L. Use a flow rate of 0.14m3/s, a recirculation ratio of 12.0 and a filter depth of 1.83m. Assume the NRC equations apply and that the wastewater temperature is 20oC?
Question 10. Bacterial kill rate typically follows Chick’s law. If the first-order kill rate for a certain weak disinfectant is 0.067/h. Determine the time it will take to reduce the bacterial population to half of its original concentration?
Question 11. A town discharges 17,360 m3/d of treated wastewater into the Creek. The Creek has a flow rate of 0.43m3/s and the DO of the creek is 6.5 mg/L and DO of the wastewater is 1.0 mg/L. Compute the DO?
Questio ...
Wk 6 p3 wk 7-p8_1.2-1.3 & 10.1-10.3_ideal gaseschris lembalemba
The document discusses Avogadro's constant and its relationship to moles. It defines a mole as the amount of a substance containing 6.02x1023 particles, which may be atoms, molecules, or ions. It then discusses how molar quantities allow expressing amounts of substances in moles rather than grams. For example, one can refer to the molar volume or molar mass of a gas. The document also discusses the kinetic theory of gases and how it relates the pressure and temperature of a gas to the motion of its molecules.
The document discusses Avogadro's law and how it relates the volume and amount of a gas. It states that at standard temperature and pressure, the molar volume of a gas is 22.4 L. It provides examples of using molar volume to convert between the mass, moles, and volume of gases. The key points are that at a constant temperature and pressure, the volume of a gas is directly proportional to the number of moles, and that 1 mole of any gas occupies 22.4 L of volume at STP.
This document describes the development of a new computer model called the Thole-Type Model (TTM) to characterize the interactions between water and guest molecules like methane in clathrate hydrates. TTM uses ab initio methods to accurately model methane hydrates at a low computational cost. The model fits interaction energies using Buckingham potentials and includes polarization and atomic charges to represent many-body effects. Initial tests of TTM on methane-water dimers show promising results.
This study used a new Diethylene Glycol (DEG) Scanning Mobility Particle Spectrometer (SMPS) to measure soot particle size distributions down to 1 nm in a premixed ethylene flame, expanding on previous instruments' lower detection limit of 3 nm. A burner-stabilized stagnation probe sampled particles from the flame at varying distances and fed them to the DEG SMPS and a commercial 3936 SMPS. A bimodal distribution was observed for distances over 0.6 cm, characterized by a relatively stable first peak from 1.9 to 2.9 nm and a larger second peak. This provides new insights into soot nucleation below 3 nm not seen in prior work.
This document discusses the mole concept in chemistry. It defines key terms like mole, molar mass, relative atomic mass, and Avogadro's number. The main points are:
- A mole is the unit used to measure the number of elementary particles in a substance and represents 6.022x10^23 particles.
- The molar mass of a substance is the mass in grams of 1 mole of that substance. It can be used to convert between moles and mass.
- Formulas are given to calculate moles, mass, or volume of a substance using molar mass and moles as conversion factors between units.
- Examples show how to use these formulas and factor-
This document contains slides from a chapter on gases in a general chemistry textbook. It covers various gas laws including Boyle's law, Charles' law, Avogadro's law, Dalton's law of partial pressures, and the kinetic molecular theory. Concepts discussed include pressure, the relationship between volume and pressure, temperature and volume, molar volume, the ideal gas equation, real gases, and applications of gas laws such as molar mass determination and gas density. Diagrams illustrate gas behavior and experimental determinations of gas properties.
Chemistry zimsec chapter 2 atoms, molecules and stoichiometryalproelearning
This document provides an overview of Chapter 2 in a chemistry textbook, which covers topics including:
- The mass of atoms and molecules, including relative atomic mass and molecular mass
- Using a mass spectrometer to determine relative isotopic masses and abundances
- The mole concept and amount of substance in relation to mass, volume of gases, and concentration of solutions
- Calculating empirical formulas from combustion data or elemental composition by mass and deducing molecular formulas
- Stoichiometry, including writing balanced chemical equations and ionic equations
Chemistry - Chp 14 - The Behavior of Gases - PowerPointMr. Walajtys
1) Gases are easily compressed and expand to fill their container due to the empty space between particles and their ability to move around.
2) The behavior of gases is described by gas laws relating pressure, volume, temperature, and amount of gas. These include Boyle's law, Charles's law, Gay-Lussac's law, Dalton's law of partial pressures, and Graham's law.
3) The ideal gas law combines these relationships and allows for calculations involving gases assuming they behave ideally. Real gases deviate from ideal behavior at high pressures and low temperatures.
Dynamic Modeling for Gas Phase Propylene Copolymerization in a Fluidized Bed ...IJRES Journal
The document presents a dynamic two-phase model for a fluidized bed reactor used to produce polypropylene. The model divides the reactor into an emulsion phase and bubble phase, with reaction assumed to occur in both phases. Simulation results show the temperature profile is lower than previous single-phase models due to considering both phases. Approximately 13% of the produced polymer comes from the bubble phase, demonstrating the importance of accounting for both phases.
THIS EBOOK WAS PREPARED
AS A PART OF THE COMENIUS PROJECT
WHY MATHS?
by the students and the teachers from:
BERKENBOOM HUMANIORA BOVENBOUW, IN SINT-NIKLAAS
( BELGIUM)
EUREKA SECONDARY SCHOOL IN KELLS (IRELAND)
LICEO CLASSICO STATALE CRISTOFORO COLOMBO IN GENOA (ITALY)
GIMNAZJUM IM. ANNY WAZÓWNY IN GOLUB-DOBRZYŃ (POLAND)
ESCOLA SECUNDARIA COM 3.º CICLO D. MANUEL I IN BEJA (PORTUGAL)
IES ÁLVAREZ CUBERO IN PRIEGO DE CÓRDOBA (SPAIN)
Interaction of Components in Molecular Optoelectronics for the Next Generati...Scientific Review SR
The interaction of molecular optoelectronic components on the molecular scale were studied where
the solvent shell indicating the influence of the medium was found to be surprisingly small. The transport of
energy as resonant energy transfer covers distances of about 5 nm and was shown not to proceed by a simple to
dipole dipole interaction with typical restrictions, but by a more complex mechanism. Furthermore, a novel -type of
far-reaching interactions of electronically excited structures until macroscopic dimensions were fond and may be
applied for addressing molecular structures by conventional electronics
Similar to Chapter10 section02 Mole–Mass and Mole–Volume Relationships By Hamdy Karim (20)
Chapter17 section02 Measuring and Expresing Enthalpy Changes By Hamdy karimHamdy Karim
Students will learn about Heat Enthalpy during the Endothermic and Exothermic Reactions, also they will learn about the Thermochemical Reactions and how they can write their chemical equations!
Chapter03 section03 Solving Conversion Problems By Hamdy Karim.Hamdy Karim
This document appears to be a series of slides from a chemistry textbook or online course covering the topic of conversion problems and dimensional analysis. It introduces key concepts like conversion factors, which are ratios that allow measurements to be converted between equivalent units while keeping the quantity the same. It provides examples of using conversion factors and dimensional analysis to solve conversion problems involving units like meters, centimeters, grams, and more. It also addresses converting between complex units and solving multi-step problems that require using multiple conversion factors.
Chapter03 section01 Scientific Measurements By Hamdy KarimHamdy Karim
Students will learn about the accuracy, Precision and Errors. Also they will learn about the Significant Numbers and their importance in Science in addition to Math.
Chapter11 Sec. 3 Reactions in Aqueous Solution By Hamdy Karim.Hamdy Karim
The document is a series of slides from a chemistry textbook discussing reactions in aqueous solutions. It introduces the topics of net ionic equations, which show only the particles directly involved in chemical reactions, and predicting the formation of precipitates based on solubility rules. An example reaction is used to demonstrate a net ionic equation. The document provides guidance on identifying spectator ions and writing balanced net ionic equations. It poses sample problems asking students to predict whether precipitates will form from double displacement reactions based on solubility rules.
Ch. 11, Sec. 2 Types of Chemical Reactions by Hamdy KarimHamdy Karim
Students will learn about the different types of Chemical Reactions and will be able to predict the products of any chemical reaction when they know the name of reactants!
Chapter11 section01 Describing Chemical Reactions By Hamdy Karim.Hamdy Karim
The document appears to be a series of slides from a chemistry textbook or online course covering the topic of describing and writing chemical reactions. It discusses writing word equations and skeleton equations, balancing chemical equations by using coefficients, and the steps to take in writing a balanced chemical equation, including writing the skeleton equation first and then using coefficients to balance it so it obeys the law of conservation of mass. It also mentions that a catalyst speeds up a chemical reaction but is not used up in the reaction.
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPRAHUL
This Dissertation explores the particular circumstances of Mirzapur, a region located in the
core of India. Mirzapur, with its varied terrains and abundant biodiversity, offers an optimal
environment for investigating the changes in vegetation cover dynamics. Our study utilizes
advanced technologies such as GIS (Geographic Information Systems) and Remote sensing to
analyze the transformations that have taken place over the course of a decade.
The complex relationship between human activities and the environment has been the focus
of extensive research and worry. As the global community grapples with swift urbanization,
population expansion, and economic progress, the effects on natural ecosystems are becoming
more evident. A crucial element of this impact is the alteration of vegetation cover, which plays a
significant role in maintaining the ecological equilibrium of our planet.Land serves as the foundation for all human activities and provides the necessary materials for
these activities. As the most crucial natural resource, its utilization by humans results in different
'Land uses,' which are determined by both human activities and the physical characteristics of the
land.
The utilization of land is impacted by human needs and environmental factors. In countries
like India, rapid population growth and the emphasis on extensive resource exploitation can lead
to significant land degradation, adversely affecting the region's land cover.
Therefore, human intervention has significantly influenced land use patterns over many
centuries, evolving its structure over time and space. In the present era, these changes have
accelerated due to factors such as agriculture and urbanization. Information regarding land use and
cover is essential for various planning and management tasks related to the Earth's surface,
providing crucial environmental data for scientific, resource management, policy purposes, and
diverse human activities.
Accurate understanding of land use and cover is imperative for the development planning
of any area. Consequently, a wide range of professionals, including earth system scientists, land
and water managers, and urban planners, are interested in obtaining data on land use and cover
changes, conversion trends, and other related patterns. The spatial dimensions of land use and
cover support policymakers and scientists in making well-informed decisions, as alterations in
these patterns indicate shifts in economic and social conditions. Monitoring such changes with the
help of Advanced technologies like Remote Sensing and Geographic Information Systems is
crucial for coordinated efforts across different administrative levels. Advanced technologies like
Remote Sensing and Geographic Information Systems
9
Changes in vegetation cover refer to variations in the distribution, composition, and overall
structure of plant communities across different temporal and spatial scales. These changes can
occur natural.
Temple of Asclepius in Thrace. Excavation resultsKrassimira Luka
The temple and the sanctuary around were dedicated to Asklepios Zmidrenus. This name has been known since 1875 when an inscription dedicated to him was discovered in Rome. The inscription is dated in 227 AD and was left by soldiers originating from the city of Philippopolis (modern Plovdiv).
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.
it describes the bony anatomy including the femoral head , acetabulum, labrum . also discusses the capsule , ligaments . muscle that act on the hip joint and the range of motion are outlined. factors affecting hip joint stability and weight transmission through the joint are summarized.
How to Make a Field Mandatory in Odoo 17Celine George
In Odoo, making a field required can be done through both Python code and XML views. When you set the required attribute to True in Python code, it makes the field required across all views where it's used. Conversely, when you set the required attribute in XML views, it makes the field required only in the context of that particular view.
বাংলাদেশের অর্থনৈতিক সমীক্ষা ২০২৪ [Bangladesh Economic Review 2024 Bangla.pdf] কম্পিউটার , ট্যাব ও স্মার্ট ফোন ভার্সন সহ সম্পূর্ণ বাংলা ই-বুক বা pdf বই " সুচিপত্র ...বুকমার্ক মেনু 🔖 ও হাইপার লিংক মেনু 📝👆 যুক্ত ..
আমাদের সবার জন্য খুব খুব গুরুত্বপূর্ণ একটি বই ..বিসিএস, ব্যাংক, ইউনিভার্সিটি ভর্তি ও যে কোন প্রতিযোগিতা মূলক পরীক্ষার জন্য এর খুব ইম্পরট্যান্ট একটি বিষয় ...তাছাড়া বাংলাদেশের সাম্প্রতিক যে কোন ডাটা বা তথ্য এই বইতে পাবেন ...
তাই একজন নাগরিক হিসাবে এই তথ্য গুলো আপনার জানা প্রয়োজন ...।
বিসিএস ও ব্যাংক এর লিখিত পরীক্ষা ...+এছাড়া মাধ্যমিক ও উচ্চমাধ্যমিকের স্টুডেন্টদের জন্য অনেক কাজে আসবে ...
These aluminum satellite dishes at the National Radio Astronomy Observatory near Soccoro, New Mexico are naturally protected from corrosion by the formation of a thin film of aluminum oxide (Al2O3).
Rust weakens an iron chain.
In each container, the volume occupied by the gas molecules is small compared with the container’s volume, so the molecules are not tightly packed. a) The molecules in this container are small. b) This container can accommodate the same number of larger molecules.
This box, with a volume of 22.4 L, holds one mole of gas at STP.
The map shows the conversion factors needed to convert among volume, mass, and number of particles. Interpreting Diagrams How many conversion factors are needed to convert from the mass of a gas to the volume of a gas at STP?
The map shows the conversion factors needed to convert among volume, mass, and number of particles. Interpreting Diagrams How many conversion factors are needed to convert from the mass of a gas to the volume of a gas at STP?
The map shows the conversion factors needed to convert among volume, mass, and number of particles. Interpreting Diagrams How many conversion factors are needed to convert from the mass of a gas to the volume of a gas at STP?
The map shows the conversion factors needed to convert among volume, mass, and number of particles. Interpreting Diagrams How many conversion factors are needed to convert from the mass of a gas to the volume of a gas at STP?