This document provides a study guide for a chapter 17 thermochemistry exam, including practice problems on thermochemical equations, heat capacities, enthalpy changes, and Hess's law. The problems cover topics like: - Converting between calories and joules - Classifying processes as endothermic or exothermic - Calculating heat required to change temperatures of substances - Interpreting heating/cooling curves - Calculating enthalpy changes of phase changes and chemical reactions using standard enthalpy of formation values - Applying Hess's law to calculate enthalpy changes from multiple reaction steps

1. Chapter 17 Thermochemistry Study
Guide
17.1 – 17.2 Thermochemical Equations
Honors Chemistry
1. Make the following conversions:
a. 444 cal to joules = 1.86 x 103 J
b. 1.8 kJ to joules = 1.8 x 103 J
c. 0.45 kJ to calories = 1.1 x 102 cal
2. Classify each of these processes as endothermic or exothermic:
a. condensing steam – exo c. evaporating alcohol – endo
b. burning alcohol – exo d. baking a potato – endo
3. The specific heat capacity for silver is 0.24 J/goC. Calculate the energy required to
raise the temperature of 150.0 g Ag from 273 K to 298 K. Calculate the molar heat
capacity of silver.
Energy: q = (150.0)(.24)(298-273) = 9.0 x 102 J
Molar heat capacity: (0.24 J/goC)(107.87 g/mol Ag) = 26 J/mol
4. It takes 585 J of energy to raise the temperature of 125.6 g Hg from 20.0oC to
53.5oC. Calculate the specific heat capacity and the molar heat capacity of Hg.
Specific heat capacity: C = q/mΔt = 585/(125.6)(53.5-20) = 0.139 J/goC
Molar heat capacity: (0.139 J/goC)(200.59 g/mol Hg) = 27.9 J/mol
5. A 46.2-g sample of copper is heated to 95.4oC and then placed in a calorimeter
containing 75.0 g water at 19.6oC. The equilibrium temperature in the calorimeter
is 21.8oC. Calculate the specific heat capacity of copper; assuming that all the
heat lost by the copper is gained by the water.
C = 0.203 J/goC
6. A 15.0-g sample of nickel metal is heated to 100.0oC and dropped into 55.0 g of
water, initially at 23.0oC. Assuming that all the heat lost by the nickel is absorbed
by the water; calculate the final temperature of the nickel and the water. The
specific heat of nickel is 0.444 J/goC.
–15.0(.444)( Tf – 100.0) = 55.0(4.184)(Tf – 23.0)
– 6.66Tf + 666 = 230.12Tf – 5292.76
5958.76 = 236.78 Tf
25.2oC = Tf
7. Chloe was running bath water and realized it was too hot. If she has 20.0 L of
water in the tub at 95oC and then adds 15.8 L of water at 75oC, what will the final
temperature of the water be?
–20(Tf – 95) = 15.8(Tf – 75)
–20Tf + 1900 = 15.8 Tf – 1185
3085 = 35.8 Tf

2. 86.2 oC = Tf
8. For the combustion of methane, calculate the enthalpy change for the burning of
10.00 g of methane.
CH4(g)+ 2O2(g) CO2(g) + 2H2O(l) + 890 kJ
1molCH 4 890 kJ
H 10 .00 gCH 4
16 .05 gCH 4 1molCH 4
ΔH = - 555 kJ
17.3 Heat in Changes of State
9. Read heating curves (See Changes of State w/s) Label the phases, boiling point
and melting point here:
boiling point = 20oC , melting point = 10oC
a = solid
b = melting
c = liquid
d = boiling
e = gas
Indicate whether a heating curve would
be flat or rising in 10-14.
10. liquid is boiling - 13. PE is increasing – flat
flat
11. solid is warming – 14. KE is increasing –
rising rising
Heat of Fusion and Heat of 12. solid is melting –
Vaporization Problems flat
Values for Water: (SHOW YOUR WORK FOR FULL CREDIT!!)
Hfus = 6.02 kJ/mol Hvap = 40.7 kJ/mol
o
CH2O(s) = 2.03 J/g C CH2O(l) = 4.184 J/g C CH2O(g) = 2.02 J/goC
o
15. How much heat needs to be added to 10090 grams of ice at -10.0oC so that it
all becomes a vapor at 120.0oC?
A q = mCΔT = (10090g)(2.03 J/goC)(0-(-10.0)) = 204827 J
B ΔH =
10090 g H 2 O 1 mol H 2 O 6.02 kJ 1000 J
= 3370799.1 J
1 18.02 g H 2 O 1 mol H 2 O 1kJ
C q = mCΔT = (10090g)(4.184 J/goC)(100-0) = 4221656 J
D ΔH =
10090 g H 2 O 1 mol H 2 O 40 .7 kJ 1000 J
= 22789289.7 J
1 18.02 g H 2 O 1 mol H 2 O 1kJ
E q = mCΔT = (10090g)(2.02 J/goC)(120-100) = 407636 J

3. A + B + C + D + E = 30994207.8 J = 3.10 x 107 J
16. If you are freezing special green ice cubes for St. Patrick’s Day, how much
energy do you need to remove from 2 ice trays of 12 cubes if each cube
holds 24.2 grams of water at 0oC?
194 kJ
17. Anand has a cold and wants to make steam in a vaporizer to help clear his
congestion. How much energy will be required to change one gallon of water
at 100oC to steam at 100oC? (The density of water is 1.00g/ml)
8547 kJ (no sig figs specified)
18. Chelsea’s prom dress is all wrinkled, but she doesn’t have the time or
patience to iron it. How much energy will be required to fire up the steamer to
remove wrinkles if she add 521 grams of water at 25.0oC and changes it all to
steam at 100.oC?
C q = mCΔT = (521g)(4.184 J/goC)(100-25) = 163489.8 J
D ΔH =
521 g H 2 O 1 mol H 2 O 40 .7 kJ 1000 J
= 1176731.41 J
1 18.02 g H 2 O 1 mol H 2 O 1kJ
C + D = 1340221.21 J = 1.34 x 106 J
19. The steamer Andrew is using to strip the NASCAR wallpaper off his bedroom
walls has used 32,967 kJ of energy. How many grams of water at 100 oC has
he changed to steam at 100oC?
14596 g
20. Using a coffee cup calorimeter, Abby finds a balance that works and adds
1.60 g of NH4NO3 to 75.0 g of water at an initial temperature of 25.00oC.
After the salt completely dissolves, the final temperature of the solution is
23.34oC. Assuming no heat is lost to the calorimeter; calculate the enthalpy
change for the dissolution of NH4NO3 in kJ/mol.
ΔH = 26.6 kJ/mol
17.4 Hess’s Law and Standard Enthalpies of Formation
21. Given the following data:
H2(g) + ½ O2(g) → H2O(l) ΔH = -285.8 kJ
N2O5(g) + H2O(l) → 2HNO3(l) ΔH = -76.6 kJ
½ N2(g) + 3/2 O2(g) + ½ H2(g) → HNO3(l) ΔH = -174.1 kJ
Calculate the ΔH for the reaction

4. 2N2(g) + 5O2(g) → 2N2O5(g)
ΔH = 28.4 kJ
22. Use the values of ΔHof from Appendix A handout to calculate the ΔHo for this
reaction:
SiCl4(l) + 2H2O(l) → SiO2(s) + 4HCl(aq)
o
ΔH = - 20 kJ
23. Use the values of ΔHof from Appendix A handout to calculate the ΔHo for this
reaction: (balance first!)
4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(l)
o
ΔH = - 1396 kJ
24. Write out the equation for the combustion of C3H6(g). Use the values of ΔHof from
the Appendix A handout to calculate the ΔHo for the reaction.
2 C3H6(g) + 9 O2(g) → 6 CO2(g) + 6 H2O(g)
ΔH = – 3854.8 kJ
25. Use the values of ΔHof from Appendix A and write each thermochemical equation
used to calculate the ΔHo for problem 24.
3 C(s) + 3 H2(g) → C3H6(g) ΔH = 20.9kJ
C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ
H2(g)+ ½ O2(g) → H2O(g) ΔH = -242 kJ