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Chem Ch 9 Notes
• 9.1 Stoichiometry- calculation of quantities
  in chemical reactions
• From the coefficients in a BALANCED
  equation you can get:
   • N2+3H2 2NH3
• 1. # particles (molecules, formula units,
  atoms)
   • 1 molecule N2: 3 molecules H2 : 2
     molecules NH3
• 2. # moles
   • 1 mole N2: 3 mole H2 : 2 mole NH3
• 3. Mass- Obeys Law of Conservation of
    Mass
    • 1 mol N2 = 28.0 g
    • +3 mol H2 = 6.0 g
    • 2 mol NH3 = 34.0 g

•   4. Volume- GASES at STP 1 mol= 22.4L
•   3 mol H2 = 3(22.4)=67.2L
•   1 mol N2 = 1(22.4) = 22.4 L
•   2 mol NH3 = 2(22.4) = 44.8 L
•   Notice that the number of atoms & mass
    are always conserved, but the volume &
    molecules may not be!!
• Mole-Mole calculations
  • N2+3H2  2NH3
  • 1mol N2     1moleN2    2 mol NH3
    3 mol H2    2mol NH3 3 mol H2
  These are your mole conversion factors

  How many moles of NH3 are in 0.60 mol
   N2?
• Mass:Mass
• 1. Convert mass to moles (1mol/ g)
• 2. Convert moles of what you have to moles
  of what you want
• 3. Convert mol to mass ( g/1mol)

• How many g NH3 are produced when 5.40 g
  of H2 react w/ excess N2?



• For all problems
• Convert to mol, use mol:mol, convert to
  wanted units
• How many moles O2 are produced when 29.2
 g H2O decomposed into O2 & H2?




• Assuming STP, how many L O2 are needed
 to produce 19.8 L SO3?
  • 2SO2(g) + O2(g)  2 SO3(g)
• Use ratios from coefficients b/c the
  volumes relate from 22.4L=1mol
   • 2NO(g) + O2 (g)  2 NO2(g)
  • How many mL NO2 are produced when
    3.4mL O2 react with excess NO at STP?
  • 1mL O2=2 mL NO2=2 mL NO
• Limiting reactant & % Yield

• Limiting Reagent- determines amt. Of
  product formed, runs out 1st
• Steps: (if given 2 reactants)
   • 1. Solve for same product
   • 2. One w/least amount of product is
     limiting
   • 3. Other is excess (left over)
   • 4. Limiting determines the amount of
     product
• 2 Na(s) + Cl2 (g)  2NaCl (s)
• Suppose 8.70 mol Na react w/3.20 mol Cl2.
   • What is limiting reactant?
   • How many moles of NaCl are produced?
   • How many g NaCl are produced?
   • How much of the excess reactant is
    left?
• 2Cu (s) + S (s)  Cu2S(s)
   • What is the limiting reactant when 80.0
    g Cu reacts with 25.0 g S?
  • How many g Cu2S can be formed?
  • How much of the excess reactant is
    left?
• % yield- measures the efficiency of
 reaction
  • Normally can’t be larger than 100%
  • Most are less than 100 % b/c:
     • Reactions don’t go to completion
     • Impure reactants
     • Competing side reaction
     • Loss of product during transfer
       or filtration
     • Human error (bad measurement,
       miscalculation)
• Actual yield- amt. of product formed in lab
• Theoretical yield- amt. product that could
  be formed from calculations

• % Yield:     actual yield    X 100
             theoretical yield


• CaCO3 (s)  CaO (s) + CO2 (g)
   • What is the theoretical yield of CaO if
    24.8 g CaCO3 is heated?
  • What is the % yield if 13.1 g CaO is
    produced?

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Ch 9 power point notes

  • 1. Chem Ch 9 Notes • 9.1 Stoichiometry- calculation of quantities in chemical reactions • From the coefficients in a BALANCED equation you can get: • N2+3H2 2NH3 • 1. # particles (molecules, formula units, atoms) • 1 molecule N2: 3 molecules H2 : 2 molecules NH3 • 2. # moles • 1 mole N2: 3 mole H2 : 2 mole NH3
  • 2. • 3. Mass- Obeys Law of Conservation of Mass • 1 mol N2 = 28.0 g • +3 mol H2 = 6.0 g • 2 mol NH3 = 34.0 g • 4. Volume- GASES at STP 1 mol= 22.4L • 3 mol H2 = 3(22.4)=67.2L • 1 mol N2 = 1(22.4) = 22.4 L • 2 mol NH3 = 2(22.4) = 44.8 L • Notice that the number of atoms & mass are always conserved, but the volume & molecules may not be!!
  • 3. • Mole-Mole calculations • N2+3H2  2NH3 • 1mol N2 1moleN2 2 mol NH3 3 mol H2 2mol NH3 3 mol H2 These are your mole conversion factors How many moles of NH3 are in 0.60 mol N2?
  • 4. • Mass:Mass • 1. Convert mass to moles (1mol/ g) • 2. Convert moles of what you have to moles of what you want • 3. Convert mol to mass ( g/1mol) • How many g NH3 are produced when 5.40 g of H2 react w/ excess N2? • For all problems • Convert to mol, use mol:mol, convert to wanted units
  • 5. • How many moles O2 are produced when 29.2 g H2O decomposed into O2 & H2? • Assuming STP, how many L O2 are needed to produce 19.8 L SO3? • 2SO2(g) + O2(g)  2 SO3(g)
  • 6. • Use ratios from coefficients b/c the volumes relate from 22.4L=1mol • 2NO(g) + O2 (g)  2 NO2(g) • How many mL NO2 are produced when 3.4mL O2 react with excess NO at STP? • 1mL O2=2 mL NO2=2 mL NO
  • 7. • Limiting reactant & % Yield • Limiting Reagent- determines amt. Of product formed, runs out 1st • Steps: (if given 2 reactants) • 1. Solve for same product • 2. One w/least amount of product is limiting • 3. Other is excess (left over) • 4. Limiting determines the amount of product
  • 8. • 2 Na(s) + Cl2 (g)  2NaCl (s) • Suppose 8.70 mol Na react w/3.20 mol Cl2. • What is limiting reactant? • How many moles of NaCl are produced? • How many g NaCl are produced? • How much of the excess reactant is left?
  • 9. • 2Cu (s) + S (s)  Cu2S(s) • What is the limiting reactant when 80.0 g Cu reacts with 25.0 g S? • How many g Cu2S can be formed? • How much of the excess reactant is left?
  • 10. • % yield- measures the efficiency of reaction • Normally can’t be larger than 100% • Most are less than 100 % b/c: • Reactions don’t go to completion • Impure reactants • Competing side reaction • Loss of product during transfer or filtration • Human error (bad measurement, miscalculation)
  • 11. • Actual yield- amt. of product formed in lab • Theoretical yield- amt. product that could be formed from calculations • % Yield: actual yield X 100 theoretical yield • CaCO3 (s)  CaO (s) + CO2 (g) • What is the theoretical yield of CaO if 24.8 g CaCO3 is heated? • What is the % yield if 13.1 g CaO is produced?