1) The document provides instructions for students to work through a physics problem involving calculating the forces acting on Spiderman suspended from two webs. 2) The problem involves drawing force diagrams, using trigonometry to find components of the tension forces, and applying Newton's Second Law to calculate the tension in one of the webs. 3) Working through the steps provided, the tension in the second web (T2) is calculated to be approximately 636N or 637N.

1. SPIDERMAN’S WEB FORMULA

2. Rules of This Activity #1 All students must perform all of the work of the activity in their science journals, even the work that you also did on the large white board! #2 All 4th row students will begin the activity on a large whiteboard which will then be passed to the student seated in front of them when their assigned work is completed. #3 All previous work is to remain on the white board. #4 The board will continue to passed to the student in the next row as each student completes their assigned work. The column of students to correctly complete the work first will be declared the winners.

3. The Problem

4. Working the Problem Row #4 Draw a force diagram of this picture of Spiderman suspended from two webs on the whiteboard. Remember to use the four steps (C of M, long term forces, contact forces, labeled axes) in creating a force diagram! T2 T 1 = 400N 57*30* 75 kg.

5. Working the Problem Row #4 Draw a force diagram of this picture of Spiderman suspended from two webs. Row #3 Use SOH-CAH-TOA, to find the magnitude of the T1x , T1y, T2x , T2y and Fgcomponents. Show all of your work.

6. Working the Problem Row #3 Use SOH-CAH-TOA, to find the magnitude of the T1x , T1y, T2x , T2y and Fgcomponents. Show all of your work. Row #2 Draw a “clean” force diagram, breaking Fg, T1 and T2 into their x and y components. Again remember to use the four steps (C of M, long term forces, contact forces, labeled axes) in creating a force diagram!

7. Working the Problem Row #2 Draw a “clean” force diagram, breaking Fg, T1 and T2 into their x and y components. Row #1 Calculate the tension in T2 showing all of your work. When your work is completed, consult with all of the members of your column to decide if the final answer is thought to be correct before submitting it for approval.

8. The Force Diagram y T2 T1 400N 57*30* x Fg

9. SOH – CAH - TOA T1 = T1x +T1y COS 30* = T1x/400N (400N) (COS 30*) = T1x 346.4N = T1x SIN 30* = T1y/400N (400N) (SIN 30*) = T1y 200N = T1y

10. The “Clean” Force Diagram y T2y x T1y200N T2x T1x 346.4N Fg 735N

11. F = ma If you used the “x” direction εFx = ma T1x -T2x = (75 kg)(0m/s2) T1x -T2x = 0 T1x = T2x 346.4N = (T2)(cos 57*) 346.4N/(cos 57*) = T2 636N = T2 or

12. F = ma If you used the “y” directionεFy = ma T1y +T2y - Fg = (75 kg)(0m/s2) T1y +T2y - Fg = 0200N + (T2) (sin 57*) - (75 kg)(9.8m/s2) = 0200N + (T2) (sin 57*) – 735N = 0 (T2) (sin 57*) = 735N- 200N (T2) (sin 57*) = 535N T2 = 535N/(sin 57*) T2 = 637N

13. SPIDERMAN IS SAFE!