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RULES OF DIFFERENTIATION
PART 2
GOOD
AFTERNOON
MS. JESSEL 0RENCIO
2
GOALS FOR THIS WEEK
I AM ABLE TO:
● derive the differentiation rules;
● apply the differentiation rules in computing the derivatives
1. algebraic functions,
2. exponential functions,
3. logarithmic functions, and
4. trigonometric functions;
● display perseverance to solve for the derivatives of functions.
3
CHAIN RULE
𝑑
𝑑π‘₯
𝑒𝑛
= π‘›π‘’π‘›βˆ’1
𝑑𝑒
𝑑π‘₯
EXAMPLE 1. Find the derivative of 𝑦 = π‘₯2 + 5
𝑦 = π‘₯2 + 5 1/2
CHAIN RULE
EXAMPLE 1. Find the derivative of 𝑦 = π‘₯2 + 5
𝑦 = π‘₯2
+ 5 1/2
Let 𝑒 = π‘₯2
+ 5
𝑛 = 1/2
𝑑𝑦
𝑑π‘₯
=
1
2
π‘₯2 + 5 βˆ’
1
2
𝑑
𝑑π‘₯
(π‘₯2 + 5)
𝑑𝑦
𝑑π‘₯
=
1
2
π‘₯2 + 5 βˆ’1/2 2π‘₯
𝑑𝑦
𝑑π‘₯
=
π‘₯
π‘₯2+5 1/2
𝑑𝑦
𝑑π‘₯
=
π‘₯
π‘₯2+5
CHAIN RULE
EXAMPLE 2. Find the derivative of 𝑦 = π‘₯ + 5 2
𝑦 = π‘₯ + 5 2
Let 𝑒 = π‘₯ + 5
𝑛 = 2
𝑑𝑦
𝑑π‘₯
= 2 π‘₯ + 5 2βˆ’1
𝑑
𝑑π‘₯
π‘₯ + 5
𝑑𝑦
𝑑π‘₯
= 2(π‘₯ + 5)(1)
𝑑𝑦
𝑑π‘₯
= 2π‘₯ + 10
Differentiation of
Exponential and
Logarithmic Functions
LESSON 7.2
7
The next set of functions that we like to focus on are
exponential and logarithmic functions. The most commonly
used exponential form in a calculus course is the natural
exponential function 𝒆𝒙
.
8
Summary of Derivative of
Exponential Functions
Solution:
𝑑
𝑑π‘₯
= π‘Žπ‘₯
= π‘Žπ‘₯
ln π‘Ž
𝑑
𝑑π‘₯
= (π‘₯πŸ‘
+ πŸ‘π‘₯
) = πŸ‘π‘₯𝟐
+ πŸ‘π‘₯
(ln πŸ‘)
EXAMPLE 1.
Find the derivative of 𝑦 = π‘₯3 + 3π‘₯ using
the differentiation rule.
Formula
Solved the derivative of π‘₯πŸ‘
and πŸ‘π‘₯
.
Solution:
𝑑
𝑑π‘₯
𝑒𝑒 = 𝑒𝑒 𝑑𝑒
𝑑π‘₯
𝑑𝑦
𝑑π‘₯
= 𝑒𝑒π‘₯
= 𝑒𝑒π‘₯ 𝑑
𝑑π‘₯
𝑒π‘₯
= 𝑒𝑒π‘₯
βˆ™ 𝑒 βˆ™
𝑑
𝑑π‘₯
(π‘₯)
= 𝑒𝑒π‘₯ βˆ™ 𝑒 βˆ™ (1)
= 𝑒𝑒π‘₯+1
EXAMPLE 2.
Find the derivative of 𝑦 = 𝑒𝑒π‘₯.
10
Let 𝒖 = 𝒆𝒙 𝒅𝒖 = 𝒆
Formula
Differentiation is linear. Differentiated them
separately and pulled out constant factors
Derivative of x is 1
EXAMPLE 3.
Differentiate 𝑦 = π‘₯ βˆ™ ln π‘₯ βˆ’ π‘₯
11
Solution:
𝑑𝑦
𝑑π‘₯
= π‘₯ βˆ™ ln π‘₯ βˆ’ π‘₯
=
𝑑
𝑑π‘₯
π‘₯ βˆ™ ln π‘₯ βˆ’
𝑑
𝑑π‘₯
(π‘₯)
=
𝑑
𝑑π‘₯
π‘₯ βˆ™ ln π‘₯ + π‘₯ βˆ™
𝑑
𝑑π‘₯
ln π‘₯ βˆ’ 1
= 1 βˆ™ ln π‘₯ + π‘₯ βˆ™
1
π‘₯
βˆ’ 1
= ln π‘₯
Let 𝒖 = 𝒙 𝒅𝒖 = 𝟏
𝒗 = π₯𝐧 𝒙 𝒅𝒗 =
𝟏
𝒙
(to be discussed in logarithm)
Differentiation is linear. Differentiated
them separately and pulled out constant
factors
Apply the product rule
Simplified (derivative of 𝒍𝒏𝒙 is
𝟏
𝒙
)
Final answer
EXAMPLE 4. Find the derivative of 𝑦 = 𝑒4π‘₯+7.
12
Solution:
𝑑
𝑑π‘₯
𝑒𝑒
= 𝑒𝑒 𝑑𝑒
𝑑π‘₯
= 𝑒4π‘₯+7 𝑑
𝑑π‘₯
(4π‘₯ + 7)
= 𝑒4π‘₯+7 4 βˆ™
𝑑
𝑑π‘₯
π‘₯ +
𝑑
𝑑π‘₯
(7)
= 𝑒4π‘₯+7
4 βˆ™ 1 + 0
= πŸ’π’†πŸ’π’™+πŸ•
Let 𝒖 = 4π‘₯ + 7 𝒅𝒖 = πŸ’
Formula
Differentiation is linear. Differentiated them
separately and pulled out constant factors
Differentiated each term
Final answer
Differentiating a
Logarithmic Function
Expressions written in exponential form can be converted
to logarithmic function and vice versa.
Exponential Form to Logarithmic Form
53
= 125 ⟹ log5 125 = 3
490.5
= 7 ⟹ log49 7 = 0.5
Logarithmic Form to Exponential Form
log2 8 = 3 ⟹ 23
= 8
log3 81 = 4 ⟹ 34
= 81
Hence π’š = π₯𝐨𝐠𝒃 𝒙 can be written as 𝑏𝑦 = π‘₯ and
π’š = π₯𝐨𝐠𝒆 𝒙 can be written as 𝑒𝑦 = π‘₯.
β€’ natural logarithms are to the base 𝒆
β€’ π₯𝐧 𝒙 is used for natural logarithms
The derivative of the Natural Logarithm Function
If 𝑦 = ln π‘₯, then
𝑑
𝑑π‘₯
ln π‘₯ =
1
π‘₯
.
15
If 𝑒 is a differentiable function of π‘₯, then according to the Chain Rule:
Derivative of Logarithmic Functions other than the
natural logarithms.
𝑑
𝑑π‘₯
(log𝑏 π‘₯) =
1
π‘₯ ln 𝑏
.
16
If 𝑒 is a differentiable function of π‘₯, then
EXAMPLE 1. Differentiate 𝑦 = ln 5π‘₯
17
Solution: Use
𝑑
𝑑π‘₯
ln 𝑒 =
1
𝑒
βˆ™
𝑑𝑒
𝑑π‘₯
𝑦 = ln(5π‘₯)
𝑑𝑦
𝑑π‘₯
=
1
5π‘₯
βˆ™
𝑑
𝑑π‘₯
(5π‘₯)
𝑑𝑦
𝑑π‘₯
=
1
5π‘₯
5
𝑑𝑦
𝑑π‘₯
=
5
5π‘₯
=
1
π‘₯
Let 𝒖 = πŸ“π’™ 𝒅𝒖 = πŸ“
EXAMPLE 1. Differentiate 𝑦 = ln 5π‘₯
18
𝑦 = ln 5π‘₯
𝑑𝑦
𝑑π‘₯
=
1
π‘₯
EXAMPLE 2.Find the derivative of 𝑦 = ln(π‘₯3 + 4).
19
Solution: Use
𝑑
𝑑π‘₯
ln 𝑒 =
1
𝑒
βˆ™
𝑑𝑒
𝑑π‘₯
𝑦 = ln(π‘₯3 + 4)
𝑑𝑦
𝑑π‘₯
=
1
π‘₯3+4
βˆ™
𝑑
𝑑π‘₯
(π‘₯3 + 4)
𝑑𝑦
𝑑π‘₯
=
1
π‘₯3+4
3π‘₯2
𝑑𝑦
𝑑π‘₯
=
3π‘₯2
π‘₯3+4
Let 𝒖 = π‘₯3 + 4 𝒅𝒖 = πŸ‘π’™πŸ
20
𝑑𝑦
𝑑π‘₯
=
3π‘₯2
π‘₯3 + 4
𝑦 = ln 5π‘₯
EXAMPLE 2.Find the derivative of 𝑦 = ln(π‘₯3 + 4).
Differentiation of
Trigonometric
Functions
LESSON 7.3
21
EXAMPLE.
Differentiate 𝑦 = sin 4π‘₯
Chain rule has been applied here.
Differentiation is linear.
Differentiated them separately and pulled
out constant factor
Final answer
EXAMPLE.
Differentiate 𝑦 = cos(2π‘₯)
Chain rule has been applied here.
Differentiation is linear.
Differentiated them separately and pulled
out constant factor
Derivative of 𝒙 is 1.
Final answer
EXAMPLE.
Differentiate 𝑦 = tan(2π‘₯)
Chain rule has been applied here.
Differentiation is linear.
Differentiated them separately and pulled
out constant factor
Derivative of 𝒙 is 1.
Final answer
EXAMPLE.
Differentiate 𝑦 = 4π‘₯2 +cot π‘₯
Differentiation is linear.
Differentiated them separately
and pulled out constant factor.
Applied the differentiation rule
for π‘π‘œπ‘‘ π‘₯ and applied the power
rule for π‘₯𝟐.
Final answer
EXAMPLE.
Differentiate 𝑦 = sec(2π‘₯)
Differentiation is linear.
Differentiated them separately
and pulled out constant factor.
Differentiated them separately
and pulled out constant factor.
Derivative of x is 1.
Final answer
EXAMPLE.
Differentiate 𝑦 = csc 5π‘₯
Differentiation is linear.
Differentiated them separately
and pulled out constant factor.
Differentiated them separately
and pulled out constant factor.
Derivative of x is 1.
Final answer
SUMMARY
Derivative of Exponential and
Logarithmic Functions Exponential Functions
Logarithmic Functions
𝒅
𝒅𝒙
𝒍𝒏 𝒙 =
𝟏
𝒙
Rules of Derivatives of
Trigonometric Functions
RULE 1 RULE 2
RULE 3
Rules of Derivatives of
Trigonometric Functions
RULE 4
RULE 5
RULE 6
32
NICE job for
LISTENING
WELL!
Ask me question/s…
Message me @:
❑ messenger: Jessel-Ann Orencio Lpt
❑ email: jessel-ann.orencio@deped.gov.ph
REFERENCES
❑ Basic Calculus – Grade 11 Alternative Delivery Mode
Quarter 3 – Module 7: Rules of Differentiation, First
Edition, 2020 Department of Education
❑ Department of Education (2016). Teaching Guide for
Senior High School Basic Calculus
❑ Differential Calculus Technological University of the
Philippines
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Basic Cal_7.Rules of Differentiation (Part 2).pdf

  • 3. GOALS FOR THIS WEEK I AM ABLE TO: ● derive the differentiation rules; ● apply the differentiation rules in computing the derivatives 1. algebraic functions, 2. exponential functions, 3. logarithmic functions, and 4. trigonometric functions; ● display perseverance to solve for the derivatives of functions. 3
  • 5. CHAIN RULE EXAMPLE 1. Find the derivative of 𝑦 = π‘₯2 + 5 𝑦 = π‘₯2 + 5 1/2 Let 𝑒 = π‘₯2 + 5 𝑛 = 1/2 𝑑𝑦 𝑑π‘₯ = 1 2 π‘₯2 + 5 βˆ’ 1 2 𝑑 𝑑π‘₯ (π‘₯2 + 5) 𝑑𝑦 𝑑π‘₯ = 1 2 π‘₯2 + 5 βˆ’1/2 2π‘₯ 𝑑𝑦 𝑑π‘₯ = π‘₯ π‘₯2+5 1/2 𝑑𝑦 𝑑π‘₯ = π‘₯ π‘₯2+5
  • 6. CHAIN RULE EXAMPLE 2. Find the derivative of 𝑦 = π‘₯ + 5 2 𝑦 = π‘₯ + 5 2 Let 𝑒 = π‘₯ + 5 𝑛 = 2 𝑑𝑦 𝑑π‘₯ = 2 π‘₯ + 5 2βˆ’1 𝑑 𝑑π‘₯ π‘₯ + 5 𝑑𝑦 𝑑π‘₯ = 2(π‘₯ + 5)(1) 𝑑𝑦 𝑑π‘₯ = 2π‘₯ + 10
  • 8. The next set of functions that we like to focus on are exponential and logarithmic functions. The most commonly used exponential form in a calculus course is the natural exponential function 𝒆𝒙 . 8 Summary of Derivative of Exponential Functions
  • 9. Solution: 𝑑 𝑑π‘₯ = π‘Žπ‘₯ = π‘Žπ‘₯ ln π‘Ž 𝑑 𝑑π‘₯ = (π‘₯πŸ‘ + πŸ‘π‘₯ ) = πŸ‘π‘₯𝟐 + πŸ‘π‘₯ (ln πŸ‘) EXAMPLE 1. Find the derivative of 𝑦 = π‘₯3 + 3π‘₯ using the differentiation rule. Formula Solved the derivative of π‘₯πŸ‘ and πŸ‘π‘₯ .
  • 10. Solution: 𝑑 𝑑π‘₯ 𝑒𝑒 = 𝑒𝑒 𝑑𝑒 𝑑π‘₯ 𝑑𝑦 𝑑π‘₯ = 𝑒𝑒π‘₯ = 𝑒𝑒π‘₯ 𝑑 𝑑π‘₯ 𝑒π‘₯ = 𝑒𝑒π‘₯ βˆ™ 𝑒 βˆ™ 𝑑 𝑑π‘₯ (π‘₯) = 𝑒𝑒π‘₯ βˆ™ 𝑒 βˆ™ (1) = 𝑒𝑒π‘₯+1 EXAMPLE 2. Find the derivative of 𝑦 = 𝑒𝑒π‘₯. 10 Let 𝒖 = 𝒆𝒙 𝒅𝒖 = 𝒆 Formula Differentiation is linear. Differentiated them separately and pulled out constant factors Derivative of x is 1
  • 11. EXAMPLE 3. Differentiate 𝑦 = π‘₯ βˆ™ ln π‘₯ βˆ’ π‘₯ 11 Solution: 𝑑𝑦 𝑑π‘₯ = π‘₯ βˆ™ ln π‘₯ βˆ’ π‘₯ = 𝑑 𝑑π‘₯ π‘₯ βˆ™ ln π‘₯ βˆ’ 𝑑 𝑑π‘₯ (π‘₯) = 𝑑 𝑑π‘₯ π‘₯ βˆ™ ln π‘₯ + π‘₯ βˆ™ 𝑑 𝑑π‘₯ ln π‘₯ βˆ’ 1 = 1 βˆ™ ln π‘₯ + π‘₯ βˆ™ 1 π‘₯ βˆ’ 1 = ln π‘₯ Let 𝒖 = 𝒙 𝒅𝒖 = 𝟏 𝒗 = π₯𝐧 𝒙 𝒅𝒗 = 𝟏 𝒙 (to be discussed in logarithm) Differentiation is linear. Differentiated them separately and pulled out constant factors Apply the product rule Simplified (derivative of 𝒍𝒏𝒙 is 𝟏 𝒙 ) Final answer
  • 12. EXAMPLE 4. Find the derivative of 𝑦 = 𝑒4π‘₯+7. 12 Solution: 𝑑 𝑑π‘₯ 𝑒𝑒 = 𝑒𝑒 𝑑𝑒 𝑑π‘₯ = 𝑒4π‘₯+7 𝑑 𝑑π‘₯ (4π‘₯ + 7) = 𝑒4π‘₯+7 4 βˆ™ 𝑑 𝑑π‘₯ π‘₯ + 𝑑 𝑑π‘₯ (7) = 𝑒4π‘₯+7 4 βˆ™ 1 + 0 = πŸ’π’†πŸ’π’™+πŸ• Let 𝒖 = 4π‘₯ + 7 𝒅𝒖 = πŸ’ Formula Differentiation is linear. Differentiated them separately and pulled out constant factors Differentiated each term Final answer
  • 14. Expressions written in exponential form can be converted to logarithmic function and vice versa. Exponential Form to Logarithmic Form 53 = 125 ⟹ log5 125 = 3 490.5 = 7 ⟹ log49 7 = 0.5 Logarithmic Form to Exponential Form log2 8 = 3 ⟹ 23 = 8 log3 81 = 4 ⟹ 34 = 81 Hence π’š = π₯𝐨𝐠𝒃 𝒙 can be written as 𝑏𝑦 = π‘₯ and π’š = π₯𝐨𝐠𝒆 𝒙 can be written as 𝑒𝑦 = π‘₯. β€’ natural logarithms are to the base 𝒆 β€’ π₯𝐧 𝒙 is used for natural logarithms
  • 15. The derivative of the Natural Logarithm Function If 𝑦 = ln π‘₯, then 𝑑 𝑑π‘₯ ln π‘₯ = 1 π‘₯ . 15 If 𝑒 is a differentiable function of π‘₯, then according to the Chain Rule:
  • 16. Derivative of Logarithmic Functions other than the natural logarithms. 𝑑 𝑑π‘₯ (log𝑏 π‘₯) = 1 π‘₯ ln 𝑏 . 16 If 𝑒 is a differentiable function of π‘₯, then
  • 17. EXAMPLE 1. Differentiate 𝑦 = ln 5π‘₯ 17 Solution: Use 𝑑 𝑑π‘₯ ln 𝑒 = 1 𝑒 βˆ™ 𝑑𝑒 𝑑π‘₯ 𝑦 = ln(5π‘₯) 𝑑𝑦 𝑑π‘₯ = 1 5π‘₯ βˆ™ 𝑑 𝑑π‘₯ (5π‘₯) 𝑑𝑦 𝑑π‘₯ = 1 5π‘₯ 5 𝑑𝑦 𝑑π‘₯ = 5 5π‘₯ = 1 π‘₯ Let 𝒖 = πŸ“π’™ 𝒅𝒖 = πŸ“
  • 18. EXAMPLE 1. Differentiate 𝑦 = ln 5π‘₯ 18 𝑦 = ln 5π‘₯ 𝑑𝑦 𝑑π‘₯ = 1 π‘₯
  • 19. EXAMPLE 2.Find the derivative of 𝑦 = ln(π‘₯3 + 4). 19 Solution: Use 𝑑 𝑑π‘₯ ln 𝑒 = 1 𝑒 βˆ™ 𝑑𝑒 𝑑π‘₯ 𝑦 = ln(π‘₯3 + 4) 𝑑𝑦 𝑑π‘₯ = 1 π‘₯3+4 βˆ™ 𝑑 𝑑π‘₯ (π‘₯3 + 4) 𝑑𝑦 𝑑π‘₯ = 1 π‘₯3+4 3π‘₯2 𝑑𝑦 𝑑π‘₯ = 3π‘₯2 π‘₯3+4 Let 𝒖 = π‘₯3 + 4 𝒅𝒖 = πŸ‘π’™πŸ
  • 20. 20 𝑑𝑦 𝑑π‘₯ = 3π‘₯2 π‘₯3 + 4 𝑦 = ln 5π‘₯ EXAMPLE 2.Find the derivative of 𝑦 = ln(π‘₯3 + 4).
  • 22. EXAMPLE. Differentiate 𝑦 = sin 4π‘₯ Chain rule has been applied here. Differentiation is linear. Differentiated them separately and pulled out constant factor Final answer
  • 23. EXAMPLE. Differentiate 𝑦 = cos(2π‘₯) Chain rule has been applied here. Differentiation is linear. Differentiated them separately and pulled out constant factor Derivative of 𝒙 is 1. Final answer
  • 24. EXAMPLE. Differentiate 𝑦 = tan(2π‘₯) Chain rule has been applied here. Differentiation is linear. Differentiated them separately and pulled out constant factor Derivative of 𝒙 is 1. Final answer
  • 25. EXAMPLE. Differentiate 𝑦 = 4π‘₯2 +cot π‘₯ Differentiation is linear. Differentiated them separately and pulled out constant factor. Applied the differentiation rule for π‘π‘œπ‘‘ π‘₯ and applied the power rule for π‘₯𝟐. Final answer
  • 26. EXAMPLE. Differentiate 𝑦 = sec(2π‘₯) Differentiation is linear. Differentiated them separately and pulled out constant factor. Differentiated them separately and pulled out constant factor. Derivative of x is 1. Final answer
  • 27. EXAMPLE. Differentiate 𝑦 = csc 5π‘₯ Differentiation is linear. Differentiated them separately and pulled out constant factor. Differentiated them separately and pulled out constant factor. Derivative of x is 1. Final answer
  • 29. Derivative of Exponential and Logarithmic Functions Exponential Functions Logarithmic Functions 𝒅 𝒅𝒙 𝒍𝒏 𝒙 = 𝟏 𝒙
  • 30. Rules of Derivatives of Trigonometric Functions RULE 1 RULE 2 RULE 3
  • 31. Rules of Derivatives of Trigonometric Functions RULE 4 RULE 5 RULE 6
  • 32. 32 NICE job for LISTENING WELL! Ask me question/s… Message me @: ❑ messenger: Jessel-Ann Orencio Lpt ❑ email: jessel-ann.orencio@deped.gov.ph
  • 33. REFERENCES ❑ Basic Calculus – Grade 11 Alternative Delivery Mode Quarter 3 – Module 7: Rules of Differentiation, First Edition, 2020 Department of Education ❑ Department of Education (2016). Teaching Guide for Senior High School Basic Calculus ❑ Differential Calculus Technological University of the Philippines
  • 34. CREDITS: This presentation template was created by Slidesgo, including icons by Flaticon, infographics & images by Freepik Does anyone have any questions? addyouremail@freepik.com +91 620 421 838 yourcompany.com THANKS!