The lesson plan is for a math class on factoring the difference of two squares. It outlines learning objectives, content, materials, and activities. The objectives are for students to factor differences of squares, find square roots, and understand real-world applications. Content includes the skill of factoring expressions and finding square roots. Students will do an activity investigating patterns in products of differences of squares and generalize the relationship. They will learn that to factor such expressions, the factors are the sum and difference of the square roots of the terms. An evaluation and assignment reinforce these skills.

1. Republic of the Philippines
Department of Education
Region VII Central Visayas
Division of Cebu City
Quiot National High School
Bogo, Quiot, Cebu City
A Semi-Detailed Lesson Plan
In Math 8
___________________
Date of Teaching
____________________
Time of Teaching
Quiot National High School- Afternoon Session
Venue of Teaching
Prepared by:
LORIE JANE L. LETADA
Teacher 1
Observed by:
ELEANOR D. GALLARDO
ASSISTANT PRINCIPAL

2. I. Intended Learning Outcomes
Through varied learning activities, the grade 8 students with at least80 % ofaccuracy shall able to:
1. Find the square rootof each term
2. Factor the difference oftwo squares
3. Relate the importance of factoring the difference oftwo squares in real life situation
II. Learning Content
A. Subject Matter
Factoring The Difference of Two Squares
B. Skill Focus
 factoring numerical expressions easily
 finding the square roots ofeach term
C. Reference
Diaz, Z., Mojica M. (2013) . Next Century Mathematics 8; Quezon City ; Phoenix Publishing House , Inc;
Mathematics 8 Learner’s Module K-12; DepEd K-12 Modified Curriculum Guide and Teacher’s Guide for
Mathematics 8
http://www.themathpage.com/Alg/difference-two-squares.htm
D. Materials
Learners’ Module; Google Classroom; powerpointpresentation; google forms
III. Learning Experiences
A. Activity
The students will do the activity that will help them understand the concepts ofdifference of
two squares and how this pattern is used to solve numerical expressions. Investigate the number
pattern by comparing the products, then write their generalizations afterwards.

3. B. Analysis
 How do you think the products are obtained?
 What are the different techniques used to solve for the products?
 What is the relationship of the products to its factor?
 Have you seen any pattern in this activity?
C. Abstraction
Factoring the difference of two squares is one of the common types of factoring a problem that
is very easy to identify.
The factors of the difference between two squares are the product of the sum and
difference of two numbers.
To factor the Difference of
Two Squares:
1. Get the principal square
root of each squares.
2. Using these square roots, form
two factors, one a sum and the
other a difference.
Factor each expression carefully.
1. 𝐱 𝟐
- 25
2. 𝐛 𝟐
- 4𝐜 𝟐
𝟑. 𝟑𝟔𝐟 𝟐
- 400𝐠 𝟖
Verify first
ifthe two
terms are
both
perfect
squares.
𝒂 𝟐
- 𝒃 𝟐
= ( a + b ) ( a – b )
A variable
is perfect
square if
its
exponent
is even
number.
You can apply
factoring difference of
two squares, if and
only if,
* The two terms are
both perfect squares
*The operation used is
subtraction.
Step 1
Get the square root of each
term.
First Term: √𝐱 𝟐 = x
Second Term: √ 𝟐𝟓 = 5
Step 2
Using x and 5 , form the sum
( x+ 5) and the difference (x – 5).
Thus, 𝐱 𝟐
- 25 = (x+ 5) (x+ 5)
Step 1
Get the square root of each
term.
First Term: √𝐛 𝟐 = b
Second Term: √𝟒𝐜 𝟐 = 2c
Step 2
Using b and 2c, form the sum
(b + 2c) & the difference (b - 2c).
Thus, 𝐛 𝟐
- 4𝐜 𝟐
= (b + 2c) (b – 2c).
Step 1
Get the square root of each
term.
First Term: √𝟑𝟔𝐟 𝟐 = 36f
Second Term: √ 𝟒𝟎𝟎𝐠 𝟖 = 20𝐠 𝟒
Step 2
Using 36f and 𝟐𝟎𝒈 𝟒
form the sum
(36f + 𝟐𝟎𝒈 𝟒
) and the difference (36f -
𝟐𝟎𝒈 𝟒
) .
Thus, 𝟑𝟔𝐟 𝟐
- 400𝐠 𝟖
= (36f + 𝟐𝟎𝒈 𝟒
) (36f - 𝟐𝟎𝒈 𝟒
)

4. D.Application
Factor each expression carefully.
𝟏. 𝐦 𝟐
- 81
𝟐. 𝐝 𝟐
- 16𝐞 𝟐
𝟑. 𝟏𝟎𝟎𝐫 𝟐
- 143𝐬 𝟒
IV. Evaluation
Factor each expression completely.
𝟏. 𝐚 𝟐
- 1 4. 𝐝 𝟏𝟐
- 4𝐜 𝟐
𝟐. 𝟗𝐩 𝟐
- 81 5. 𝐪 𝟐
- 225𝐫 𝟒
𝟑. 𝐰 𝟒
- 169 6. 𝟏𝟎𝟎𝐫 𝟐
- 289𝐬 𝟏𝟎
V. Assignment
Step 1 Step 2
Step 1 Step 2
Step 1 Step 2
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