Design of Reinforced Concrete Structure (IS 456:2000)MachenLink
This is the 1st Lecture Series on Design Reinforced Cement Concrete (IS 456 -2000).
In this video, you will learn about the objective of structural designing and then basic properties of concrete and steel.
Concrete properties like...
1. Grade of Concrete
2. Modulus of Elasticity
3. Characteristic Strength
4. Tensile Strength
5. Creep and Shrinkage
6. Durability
Reinforced Steel Properties....
1. Grade and types of steel
2. Yield Strength of Mild Steel and HYSD Bars
Design of Reinforced Concrete Structure (IS 456:2000)MachenLink
This is the 1st Lecture Series on Design Reinforced Cement Concrete (IS 456 -2000).
In this video, you will learn about the objective of structural designing and then basic properties of concrete and steel.
Concrete properties like...
1. Grade of Concrete
2. Modulus of Elasticity
3. Characteristic Strength
4. Tensile Strength
5. Creep and Shrinkage
6. Durability
Reinforced Steel Properties....
1. Grade and types of steel
2. Yield Strength of Mild Steel and HYSD Bars
brief explanation about methods and safety measures in demolition of buildings
i hope this will help you know the demolition safety factors.
thank you
suggestions to:-
vamsiila@gmail.com +91 9581202355
Introduction on aggregate impact testing machine pptAbhishek Sagar
Toughness is the property of a material to resist impact. Due to traffic loads, the road stones are subjected to the pounding action or impact and there is possibility of stones breaking into smaller pieces. The road stones should therefore be tough enough to resist fracture under impact. A test designed to evaluate the toughness of stones
brief explanation about methods and safety measures in demolition of buildings
i hope this will help you know the demolition safety factors.
thank you
suggestions to:-
vamsiila@gmail.com +91 9581202355
Introduction on aggregate impact testing machine pptAbhishek Sagar
Toughness is the property of a material to resist impact. Due to traffic loads, the road stones are subjected to the pounding action or impact and there is possibility of stones breaking into smaller pieces. The road stones should therefore be tough enough to resist fracture under impact. A test designed to evaluate the toughness of stones
Structural Analysis of a Bungalow Reportdouglasloon
Taylor's University Lakeside Campus
School of Architecture, Building & Design
Bachelor of Science (Hons) in Architecture
Building Structures (ARC 2523 / BLD 60103)
Project 2: Structural Analysis of a Bungalow
It is to transform the art into verbal or words. Selection of painting is highly depended to our personality and the way we look at those painting. This is an exercise that requires considerable reflection on deeper meaning leading to new insights and surprising discoveries.
The Personal Narrative Essay is an outline of my character and defines my personality. The essay is intended to raise the consciousness of my background, experiences and abilities to promote experience in a design that is
consistent with your personal values and worldview.
This project is to define the project that we have designed. It is to be familiar with the scope of works by the Project Manager and the Architect and Consultants
Does the Home Environment Affect Work from Home?DavidJPCChai
This is a research report done by Taylor's University students for the subject Community Service Initiative.
This report is about a research based on the home environment that might affect the people to work from home.
This is the slides done by the students who had done the research on challenges in conserving a tourism heritage site with the Chew Jetty, Penang as the case study
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Acetabularia Information For Class 9 .docxvaibhavrinwa19
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
A Strategic Approach: GenAI in EducationPeter Windle
Artificial Intelligence (AI) technologies such as Generative AI, Image Generators and Large Language Models have had a dramatic impact on teaching, learning and assessment over the past 18 months. The most immediate threat AI posed was to Academic Integrity with Higher Education Institutes (HEIs) focusing their efforts on combating the use of GenAI in assessment. Guidelines were developed for staff and students, policies put in place too. Innovative educators have forged paths in the use of Generative AI for teaching, learning and assessments leading to pockets of transformation springing up across HEIs, often with little or no top-down guidance, support or direction.
This Gasta posits a strategic approach to integrating AI into HEIs to prepare staff, students and the curriculum for an evolving world and workplace. We will highlight the advantages of working with these technologies beyond the realm of teaching, learning and assessment by considering prompt engineering skills, industry impact, curriculum changes, and the need for staff upskilling. In contrast, not engaging strategically with Generative AI poses risks, including falling behind peers, missed opportunities and failing to ensure our graduates remain employable. The rapid evolution of AI technologies necessitates a proactive and strategic approach if we are to remain relevant.
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Introduction to AI for Nonprofits with Tapp NetworkTechSoup
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
2. TABLE OF CONTENTS
1.0 INTRODUCTION
2.0 ARCHITECTURAL PLANS
2.1 GROUND FLOOR PLAN
2.2 FIRST FLOOR PLAN
2.3 ROOF PLAN
3.0 STRUCTURAL BRIEF
4.0 STRUCTURAL PLANS
4.1 GROUND FLOOR STRUCTURAL PLAN
4.2 FIRST FLOOR STRUCTURAL PLAN
4.3 ROOF STRUCTURAL PLAN
5.0 LOAD DISTRIBUTION PLAN
5.1 GROUND FLOOR LOAD DISTRIBUTION PLAN
5.2 FIRST FLOOR LOAD DISTRIBUTION PLAN
6.0 COLUMN TRIBUTARY AREA DIAGRAMS
6.1 GROUND FLOOR COLUMNS TRIBUTARY AREA DIAGRAM
6.2 FIRST FLOOR COLUMNS TRIBUTARY AREA DIAGRAM
7.0 CHAI PHEY CHIAT - BEAM AND COLUMN ANALYSIS
7.1 SELECTED BEAMS AND COLUMNS
7.2 BEAM ANALYSIS
7.2.1 UNIFORM DISTRIBUTED LOAD
7.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
7.3 COLUMN ANALYSIS
7.3.1 PERIMETER COLUMN
7.3.2 INTERNAL COLUMN
8.0 LI CHUN RON - BEAM AND COLUMN ANALYSIS
8.1 SELECTED BEAMS AND COLUMNS
8.2 BEAM ANALYSIS
8.2.1 UNIFORM DISTRIBUTED LOAD
8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
8.3 COLUMN ANALYSIS
8.3.1 PERIMETER COLUMN
8.3.2 INTERNAL COLUMN
9.0 REFERENCES
3. 1.0 INTRODUCTION
The objectives of this project are to introduce us to the basic process of structural design of
a two-storey bungalow to gain a holistic structural design experience including the basic
concepts in structural design, engineering considerations in building structure,
quantification of loads and stresses, as well as the estimation of the sizes of structural
members. Through this assignment, we will be able to apply structural theory in designing
structural elements, analyse loading conditions using simple mathematical calculation and
illustrate the manipulation of loading forces graphically.
The chosen building is a two storey bungalow located on Lot 1404, block 16 at Lorong
Hua Joo Park 8A1, Kuching Sarawak.
The architectural plans were refined and modified leaving only grid lines, dimensions, and
room labels. Then a list of drawings were produced in order to suit the requirements of the
assignment:
1. Ground Floor Structural Plan
2. First Floor Structural Plan
3. Roof Structural Plan
4. Ground Floor Load Distribution Plan
5. First Floor Load Distribution Plan
6. Roof Load Distribution Plan
7. Ground Floor Tributary Area Plan
8. First Floor Tributary Area Plan
9. Roof Tributary Area Plan
Group members were to choose 2 beams and 2 columns in order to conduct the structural
analysis and calculations:
1. One (1) beam with only uniform distributed load
2. One (1) beam with point load and uniform distributed load
3. One (1) perimeter column (from roof to ground level)
4. One (1) internal column (from roof to ground floor)
It is to produce load diagrams, shear forces diagram and bending moment diagram to
clearly illustrates the loads and forces acting on the structure. Also, the column, and the
ultimate load for the column is analysed.
7. 3.0 STRUCTURAL BRIEF
Structure Dimension
Type 1 Column 0.3m X 0.3m X 0.3m (Length X Width X Height)
Type 2 Column 0.15m X 0.4m X 0.3m (Length X Width X Height)
Beam 0.15m X 0.3m (Width X Depth)
Slab 0.15m (Thickness)
Wall 0.15m X 3.0m (Thickness X Height)
Dimension of the Structure
Standard Weight of Material (Refer to UBBL Fourth Schedule)
Material Standard Weight (kN/m³)
Reinforced Concrete 24
Brickwork 19
Structure Self-Weight
Structure Calculation Self-Weight
Type 1 Column 0.3m X 0.3m X 3.0m X 24 kN/m³ 6.5 kN
Type 2 Column 0.15m X 0.4m X 3.0m X 24 kN/m³ 4.32 kN
Beam 0.15m X 0.3m X 24 kN/m³ 1.08 kN/m
Slab 0.15m X 24 kN/m³ 3.6 kN/m²
Brick Wall 0.15m X 3.0m X 19 kN/m³ 8.55 kN/m
Roof - 1.0 kN/m²
19. 7.2 BEAM ANALYSIS
7.2.1 UNIFORM DISTRIBUTED LOAD
Ground Floor Beam 1b/E-D
Ground Floor Beam 1b/E-D carries:
● Dead Load from Beam Self Weight: Gridline E-D
● Dead Load from Brick Wall Weight: Gridline E-D
● Dead Load from Slab:
i) Gridline E-D/1-2
ii) Gridline E-D/1b-2
● Live Load from Slab:
i) Gridline E-D/1-2
ii) Gridline E-D/1b-2
Ground Floor Structural Plan Ground Floor Load Distribution Plan
20. 7.2.1 UNIFORM DISTRIBUTED LOAD
Ground Floor Beam 1b/E-D
Beam Self-Weight
= 0.15m X 0.3m X 24kN/m³
= 1.08 kN/m
Dead Load
Brick Wall Weight
= 0.15m X 3m X 19kN/m³
= 8.55 kN/m
Slab E-D/1-1b
= (0.15m X 24kN/m³) X (1.625 / 2)
= 2.925 kN/m
Slab E-D/1b-2
= (0.15m X 24kN/m³) X (1.525m / 2)
= 2.745 kN/m
Total Dead Load
= (1.08 + 8.55 + 2.925 + 2.745) kN/m
= 15.25 kN/m
21. 7.2.1 UNIFORM DISTRIBUTED LOAD
Ground Floor Beam 1b/E-D
Slab E-D/1-1b
= 1.5kN/m² X (1.625m / 2)
= 1.2188 kN/m
Live Load
Slab E-D/1b-2
= 1.5kN/m² X (1.525 / 2)
= 1.1438 kN/m
Total Live Load
= (1.2188 + 1.1438) kN/m
= 2.3626 kN/m
Ultimate Dead Load
= 15.25 kN/m X 1.4
= 21.35 kN/m
Ultimate Load
Ultimate Live Load
= 2.3626 kN/m X 1.6
= 3.78 kN/m
Total Ultimate Load
= (21.35 + 3.78) kN/m
= 25.13 kN/m
22. 7.2.1 UNIFORM DISTRIBUTED LOAD
Ground Floor Beam 1b/E-D
25.13kN/m X 3m
= 75.39 kN
Resultant Force
∑M = 0
= (Ra X 3) + [ -75.39 X (3/2) ]
= 3Ra - 113.09
3Ra = 113.09
Ra = 37.7 kN
37.7kN - 75.39kN
= -37.7kN
Shear Force Diagram
Positive Area
37.7kN X 1.5m X ½
= 28.28 kNm
Reaction Force
∑Fy = 0
= Rb + 37.7 + 75.39
Rb = 37.7 kN
37.7kN + (-37.7kN)
= 0 kN
Bending Moment Diagram
Negative Area
37.7kN X 1.5m X ½
= 28.28 kNm
Positive Area = Negative Area
23. 7.2 BEAM ANALYSIS
7.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
Ground Floor Beam E/1-2
Ground Floor Beam E/1-2 carries:
● Dead Load from Beam Self Weight: Gridline 1-2
● Dead Load from Brick Wall Weight: Gridline 1-2
● Dead Load from Slab:
i) Gridline F-E/1-2
ii) Gridline E-D/1-1b
iii) Gridline E-D/1b-2
● Live Load from Slab:
i) Gridline F-E/1-2
ii) Gridline E-D/1-1b
iii) Gridline E-D/1b-2
● Point Load at Point E/1b from Beam 1b/E-D
Ground Floor Structural Plan Ground Floor Load Distribution Plan
24. 7.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
Ground Floor Beam E/1-2
Beam Self-Weight
= 0.15m X 0.3m X 24kN/m³
= 1.08 kN/m
Dead Load
Brick Wall Weight
= 0.15m X 3m X 19kN/m³
= 8.55 kN/m
Slab F-E/1-2
= (0.15m X 24kN/m³) X (3.15m / 2) X 2/3
= 3.78 kN/m
Slab E-D/1-1b
= (0.15m X 24kN/m³) X (1.625m / 2) X 2/3
= 1.95 kN/m
Total Dead Load for 1-1b
= (1.08 + 8.55 + 3.78 + 1.95) kN/m
= 15.36 kN/m
Slab E-D/1b-2
= (0.15m X 24kN/m³) X (1.525m / 2) X 2/3
= 1.83 kN/m
Total Dead Load for 1b-2
= (1.08 + 8.55 + 3.78 + 1.83) kN/m
= 15.24 kN/m
25. 7.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
Ground Floor Beam E/1-2
Slab E-D/1-1b
= 1.5kN/m² X (1.625m / 2) X 2/3
= 0.8125 kN/m
Live Load
Slab E-D/1b-2
= 1.5kN/m² X (1.525 / 2) X 2/3
= 0.7625 kN/m
Ultimate Load for 1-1b
= (15.36kN/m X 1.4) + (2.3875kN/m X 1.6)
= 25.32 kN/m
Ultimate Load
Ultimate Load for 1b-2
= (15.24kN/m X 1.4) + (2.3375kN/m X 1.6)
= 25.08 kN/m
Slab F-E/1-2
= 1.5kN/m² X (3.15m / 2) X 2/3
= 1.575 kN/m
Total Live Load for 1-1b
= (1.575 + 0.8125) kN/m
= 2.3875 kN/m
Total Live Load for 1b-2
= (1.575 + 0.7625) kN/m
= 2.3375 kN/m
Point Load from Beam 1b/E-D
= 37.7 kN
26. 7.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
Ground Floor Beam E/1-2
Point Load at Point 1b
= 37.7 kN
Resultant Force
∑M = 0
= (Ra X 3.15) + (-41.145 X 2.34)
+ (-37.7 X 1.525)
+ (-38.247 X 0.7625)
= 3.15Ra - 96.28 - 57.49 - 29.16
= 3.15Ra - 182.93
Ra = 58.07 kN
58.07kN - 41.145kN
= 16.925 kN
Shear Force Diagram
Positive Area
(58.07 + 16.925) kN X 1.625m X ½
= 74.98kN X 1.625m X ½
= 60.9 kNm
Reaction Force
∑Fy = 0
= 58.07 + Rb + (-41.15)
+ (-37.7) + (-38.25)
= Rb - 59.03
Rb = 59.03 kN
16.925kN - 37.7kN
= -20.775 kN
Bending Moment Diagram
Negative Area
(20.775 + 59.03)kN X 1.525m X ½
= 79.81kN X 1.525m X ½
= 60.9 kNm
Positive Area - Negative Area
= 60.9 kNm - 60.9 kNm
= 0 kNm
-20.775kN - 38.247 kN
= -59.03 kN
-59.03kN + 59.03 kN
= 0 kN
Positive Area = Negative Area
27. 7.3 COLUMN ANALYSIS
7.3.1 PERIMETER COLUMN
Column E/1
No Column at position E/1
Roof Level
Dead Load
First Floor Level
Roof Weight
= (3.95m X 1.575m) X 1.0kN/m²
= 6.22 kN
Roof Beam
= (3.95m + 1.575m) X 1.08kN/m
= 5.967kN
Total Dead Load
= 6.22kN + 5.967kN
= 12.19 kN
Live Load
Roof Weight
= (3.95m X 1.575m) X 0.5kN/m²
= 3.11 kN
28. 7.3.1 PERIMETER COLUMN
Column E/1
Dead Load
Ground Floor Level
Concrete Slab
= (3.95m X 1.575m) X 3.6kN/m²
= 22.4 kN
Beam Self Weight
= (3.95m + 1.575m) X 1.08kN/m
= 5.967kN
Brick Wall
= (1.5m + 1.575m) X 8.55kN/m
= 26.29 kN
Live Load
Concrete Slab
= (3.95m X 1.575m) X 1.5kN/m²
= 9.33 kN
Column Self Weight
= (0.3m X 0.3m X 3m) X 24kN/m³
= 6.48 kN
Total Dead Load
= (22.4 + 5.967 + 26.29 + 6.48) kN
= 61.14 kN
Ultimate Load
Total Dead Load
= 12.19kN + 61.15kN
= 73.33 kN
Total Live Load
= 3.11kN + 9.33kN
= 12.44 kN
Ultimate Dead Load
= 73.33kN X 1.4
= 102.7 kN
Total Live Load
= 12.44kN X 1.6
= 19.9 kN
Total Ultimate Load
= 102.7kN + 19.9kN
= 122.6 kN
29. 7.3.2 INTERIOR COLUMN
Column E/2
Roof Level
First Floor Level
Dead Load
Roof Weight
= (1.95m X 1.5m) X 1.0kN/m²
= 2.925 kN
Roof Beam
= (1.95m + 1.5m) X 1.08kN/m
= 3.726 kN
Total Dead Load
= 2.925kN + 3.726kN
= 6.65 kN
Live Load
Roof Weight
= (1.95m X 1.5m) X 0.5kN/m²
= 1.4625 kN
Dead Load
Concrete Slab
= (1.95m X 1.5m) X 3.6kN/m²
= 10.53 kN
Beam Self Weight
= (3.95m + 3.525m) X 1.08kN/m
= 8.073 kN
Brick Wall
= (1.95m + 1.5m) X 8.55kN/m
= 29.5 kN
Column Self Weight
= (0.15m X 0.4m X 3m) X 24kN/m³
= 4.32 kN
Roof Weight
= (1.575m X 1.5m + 2.45m X 3.525) kN
X 1.0kN/m²
= 11.0 kN
Total Dead Load
= (10.53 + 11.0 + 8.073 + 29.5 + 4.32) kN
= 63.42 kN
30. 7.3.2 INTERIOR COLUMN
Column E/2
First Floor Level
Live Load
Concrete Slab
= (1.95m X 1.5m) X 1.5kN/m²
= 4.39 kN
Roof Weight
= (1.575m X 1.5m + 2.45m X 3.525m)
X 0.5kN/m
= 5.5 kN
Total Live Load
= 4.39kN + 5.5kN
= 9.89 kN
Ground Floor Level
Dead Load
Concrete Slab
= (3.95 X 1.575 + 1.5 X 1.95)m²
X 3.6kN/m²
= 32.93 kN
Beam Self Weight
= (3.95m + 3.525m) X 1.08kN/m
= 8.073 kN
Brick Wall
= (3.525m + 1.5m + 0.5m) X 8.55kN/m
= 47.24 kN
Column Self Weight
= (0.15m X 0.4m X 3m) X 24kN/m³
= 4.32 kN
Total Dead Load
= (32.93 + 8.073 + 47.24 + 4.32) kN
= 92.56 kN
31. 7.3.2 INTERIOR COLUMN
Column E/2
Ground Floor Level
Live Load
Concrete Slab
= (3.95 X 1.575 + 1.5 X 1.95)m²
X 1.5kN/m²
= 13.72 kN
Total Live Load
= 13.72 kN
Ultimate Load
Total Dead Load
= 6.65kN + 63.42kN + 92.56kN
= 162.63 kN
Total Live Load
= 1.4625kN + 9.89kN + 13.72kN
= 25.07 kN
Ultimate Dead Load
= 162.63kN X 1.4
= 227.68 kN
Total Live Load
= 25.07kN X 1.6
= 40.11 kN
Total Ultimate Load
= 227.68kN + 40.11kN
= 267.79 kN
32. 8.0 LI CHUN RON
BEAM AND COLUMN ANALYSIS
8.1 SELECTED BEAMS AND COLUMNS
8.2 BEAM ANALYSIS
8.2.1 UNIFORM DISTRIBUTED LOAD
8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
8.3 COLUMN ANALYSIS
8.3.1 PERIMETER COLUMN
8.3.2 INTERIOR COLUMN
33. 8.0 LI CHUN RON - BEAM AND COLUMN ANALYSIS
8.1 SELECTED BEAMS AND COLUMNS
Point Load & Uniform Distributed Load
Beam D/2-3
Uniform Distributed Load
Beam 2B/E-D
Perimeter Column
Column E3
Interior Column
Column D3
34. 8.2 BEAM ANALYSIS
8.2.1 UNIFORM DISTRIBUTED LOAD
First Floor Beam 2B/E-D
First Floor Beam 2B/E-D carries:
● Dead Load from Beam Self Weight: Gridline E-D
● Dead Load from Brick Wall Weight: Gridline E-D
● Dead Load from Slab:
i) Gridline E-D/2-2B
ii) Gridline E-D/2B-3
● Live Load from Slab:
i) Gridline E-D/2-2B
ii) Gridline E-D/2B-3
First Floor Structural Plan First Floor Load Distribution Plan
35. 8.2.1 UNIFORM DISTRIBUTED LOAD
First Floor Beam 2B/D-E
Beam Self-Weight
= 0.15m X 0.3m X 24kN/m³
= 1.08 kN/m
Dead Load
Brick Wall Weight
= 0.15m X 3m X 19kN/m³
= 8.55 kN/m
Slab E-D / 2-2B
= (0.15m X 24kN/m³) X (2.300m / 2)
= 4.14 kN/m
Slab E-D / 2B-3
= (0.15m X 24kN/m³) X (1.870m / 2)
= 3.366 kN/m
Total Dead Load
= (1.08 + 8.55 + 4.14 + 3.366) kN/m
= 17.136 kN/m
36. 8.2.1 UNIFORM DISTRIBUTED LOAD
First Floor Beam 2B/D-E
Slab D-E/2-2B
= 1.5kN/m² X (2.300m / 2)
= 1.725 kN/m
Live Load
Slab D-E/2B-3
= 1.5kN/m² X (1.870m / 2)
= 1.403 kN/m
Total Live Load
= (1.725 + 1.403kN/m)
= 3.128 kN/m
Ultimate Dead Load
= 17.136 kN/m X 1.4
= 23.9904 kN/m
Ultimate Load
Ultimate Live Load
= 3.128 kN/m X 1.6
= 5.0048 kN/m
Total Ultimate Load
= (23.9904kN/m + 5.0048kN/m)
= 28.9952 kN/m
37. 8.2.1 UNIFORM DISTRIBUTED LOAD
First FLoor Beam D-E / 2B
(Ra x 3.000) - (28.9952 x 3.000) x (3.000 ÷ 2)
3.000Ra = 130.478
Ra = 43.49 kN
43.49 kN - 86.9856 kN
= -43.49 kN
Shear Force Diagram
Positive Area
43.39 kN X 1.5m X ½
= 32.54 kNm
Reaction Force
43.49 kN + (-43.49 kN)
= 0 kN
Bending Moment Diagram
Negative Area
43.39 kN X 1.5m X ½
= 32.54 kNm
Positive Area = Negative Area
43.49 - (28.9952 x 3.00) Rb = 0
Rb = 43.49 kN
Resultant Force
28.9952 kN/m x3m
=86.9856 kN
0 kN
( + )
( - )
Ra = 43.49 kN
43.49 kN + (-43.49 kN)
= 0 kN
43.49 kN - 86.9856 kN
= -43.49 kN
0 kN 0 kN
32.52 kNm
38. First Floor Structural Plan First Floor Load Distribution Plan
8.2 BEAM ANALYSIS
8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
First Floor Beam D/2-3
First Floor Beam D/2-3 carries:
● Dead Load from Beam Self Weight: Gridline 2-3
● Dead Load from Brick Wall Weight: Gridline 2-3
● Dead Load from Slab:
i) Gridline E-D / 2-2B
ii) Gridline E-D / 2B-3
iii) Gridline D-C / 1C-3
● Live Load from Slab:
i) Gridline E-D / 2-2B
ii) Gridline E-D / 2B-3
iii) Gridline D-C / 1C-3
● Point Load at D / 2B from Beam 2B / E-D
39. 8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
First Floor Beam D / 2-3
Beam Self-Weight
= 0.15m X 0.3m X 24kN/m³
= 1.08 kN/m
Dead Load
Brick Wall Weight
= 0.15m X 3m X 19kN/m³
= 8.55 kN/m
Slab D-C / 1C-3
= (0.15m X 24kN/m³) X (5.1m / 2) X 2/3
= 6.12 kN/m
Slab E-D / 2-2B
= (0.15m X 24kN/m³) X (2.030m / 2) X 2/3
= 2.436 kN/m
Total Dead Load for 2-2B
= (1.08 + 8.55 + 6.12 + 2.436) kN/m
= 18.186 kN/m
Slab E-D / 2B-3
= (0.15m X 24kN/m³) X (1.870m / 2) X 2/3
= 2.244 kN/m
Total Dead Load for 2B-3
= (1.08 + 8.55 + 6.12 + 2.244) kN/m
= 17.994 kN/m
40. 8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
First Floor Beam D / 2-3
Slab E-D / 2-2B
= 1.5kN/m² X (1.625m / 2) X 2/3
= 0.8125 kN/m
Live Load
Slab E-D / 2B-3
= 1.5kN/m² X (1.525 / 2) X 2/3
= 0.7625 kN/m
Ultimate Load for 2-2B
= (18.186kN/m X 1.4) + (3.3625kN/m X 1.6)
= 30.8404kN/m
Ultimate Load
Ultimate Load for 2B-3
= (17.994kN/m X 1.4) + (3.3125kN/m X 1.6)
= 30.4916kN/m
Slab D-C / 1C-3
= 1.5kN/m² X (5.1m / 2) X 2/3
= 2.55 kN/m
Total Live Load for 2-2B
= (2.55 + 0.8125) kN/m
= 3.3625 kN/m
Total Live Load for 2B-3
= (2.55 + 0.7625) kN/m
=3.3125 kN/m
Point Load from Beam 2B / E-D
= 43.49 kN
41. 8.2.2 POINT LOAD & UNIFORM DISTRIBUTED LOAD
Ground Floor Beam D / 2-3
Point Load at Point 2B / E-D
= 43.39 kN
Resultant Force
∑M = 0
= (Ra X 3.9) + (-62.606 X 2.9)
+ (-43.49 X 1.95)
+ (-57.019 X 0.935)
= 3.9Ra - 181.6 - 84.8 - 53.3
= 3.9Ra - 318.7
Ra = 81.72 kN
81.72kN - 62.6kN
= 19.12 kN
Shear Force Diagram
Positive Area
(81.72 + 19.12) kN X 2.030m X ½
= 100.84kN X 2.030m X ½
= 102.4 kNm
Reaction Force
∑Fy = 0
= 81.72 + Rb + (-62.6)
+ (-43.49) + (-57.02)
= Rb - 81.39
Rb = 81.39kN
19.12kN - 43.49kN
= -24.37 kN
Bending Moment Diagram
Negative Area
(24.37 + 81.39)kN X 1.870m X ½
=105.8kN X 1.870m X ½
= 98.9 kNm
Positive Area - Negative Area
= 102.4 kNm - 98.9 kNm
= 3.5 kNm = 0
-24.37kN - 57.02kN
= -81.39 kN
-81.39kN + 81.39kN
= 0 kN
Positive Area = Negative Area
( + )
( - )
Ra = 81.72 kN
19.12kN - 43.49kN
= -24.37 kN
0 kN
0 kN
102.4 kNm
0 kN
0 kN
Rb = 81.39 kN
81.72kN - 62.6kN
= 19.12 kN
42. 8.3 COLUMN ANALYSIS
8.3.1 PERIMETER COLUMN
Column E / 3
Dead Load
Beam :
(3.0 + 1.95 + 1.95 + 2.55) x 0.15 x 0.45 x 24
= 15.3kN
Roof :
3.0 x (1.95 + 2.55) x 1.0kN/m2
=13.5kN
Total Dead load = 28.8kN
Live Load
Slab:
(1.95 + 2.55) x 3 x 0.5kN/m2
=6.75kN
Ultimate Load:
=(1.4 x 28.8) + (1.6 x 6.75)
= 40.32 + 10.8
= 51.12kN
Roof Level
Dead Load
Beam :
24kN/m2 x 0.15 x 0.45 x (5.1 + 1.9 + 1.8)
=14.28kN
Slab :
24kN/m2 x 0.15 x 5.1 x 3.7
=67.9kN
Brick Wall:
19kN/m2 x 0.15 x 3m x (5.1 + 1.9 + 1.8)
=74.8
Total Dead load = 67.9 + 14.26 + 74.8
=156.96kN
Live Load
Slab:
1.5kN/m2 x 0.15 x 5.1 x 3.7
=4.24kN
Ultimate Load:
(1.4 x 156.96kN) + (1.6 x 4.24kN)
= 219.7 + 6.8
= 226.5kN
First Floor Level
43. 8.3.1 PERIMETER COLUMN
Column E / 3
Ground Floor Level
Ultimate Load
Total Dead Load
= 96.56kN + 28.8kN + 156.9kN
= 282.26 kN
Total Live Load
= 14.175kN + 4.24kN + 6.75kN
= 25.165kN
Ultimate Dead Load
= 282.26kN X 1.4
= 395.164 kN
Total Live Load
= 25.165kN X 1.6
= 40.264 kN
Total Ultimate Load
= 395.164kN + 40.264kN
= 435.428 kN
Dead Load
Beam :
(1.95 + 1.2 + 3.0) x 0.15 x 0.45 x 24
=9.96kN
Slab :
(1.95 + 1.2) x 3.0 x 0.15 x 24
=34.02kN
Brick Wall:
(1.95 + 1.2 + 3.0) x 0.15 x 19 x 3
=52.58kN
Total Dead load = 96.56kN
Live Load
Slab:
(1.95 + 1.2) x 3.0 x 1.5
=14.175kN
Ultimate Load:
(1.4 x 96.56kN) + (1.6 x 14.175kN)
=135.18 + 22.68
=157.86kN
44. 8.3.2 INTERIOR COLUMN
Column D / 3
Roof Level
Dead Load
Beam :
24kN2 x 0.15 x 0.45 x (3.0 + 4.5)
=12.15kN
Roof :
1.0kN/m2 x 3.0 x 4.5
=13.5kN
Total Dead load = 13.5kN + 12.15kN
=25.65kN
Live Load
Roof:
0.5kN/m2 x 4.5 x 3.0
=6.75kN
Ultimate Load:
=(1.4 x 25.65) + (1.6 x 6.75)
= 35.91 + 10.8
=46.71kN
Dead Load
Beam :
24kN2 x 0.15 x 0.45 x (3.0 + 3.9 + 1.2)
=9.72kN
Slab :
24kN/m2 x 0.15m x 3.9 x 1.2
=16.8kN
Brick Wall:
19kN/m2 x 0.15m x 3m x (1.95 + 1.2 +1.95
+3.0)
=16.65kN
Total Dead load = 16.8 + 9.72 + 16.65
=43.17
Live Load
Slab:
1.5kN/m2 x 0.15m x 5.1 x 3.0
=3.44kN
Ultimate Load:
=(1.4 x 43.17) + (1.6 x 3.44)
=60.4 + 5.5
=65.9kN
First Floor Level
45. 8.3.2 INTERIOR COLUMN
Column D / 3
Ground Floor Level
Ultimate Load
Total Dead Load
= 25.65kN + 43.17kN + 137.5kN
= 206.32 kN
Total Live Load
= 3.44kN + 3.44kN + 6.75kN
= 13.63 kN
Ultimate Dead Load
= 206.32kN X 1.4
= 288.85 kN
Total Live Load
= 13.63kN X 1.6
= 21.80 kN
Total Ultimate Load
= 288.85kN + 21.80kN
= 310.65 kN
Dead Load
Beam :
24kN2 x 0.15 x 0.45 x (3.0 + 3.9 + 1.2)
=9.72kN
Slab :
24kN/m2 x 0.15m x 5.1 x 3.0
=55.08kN
Brick Wall:
19kN/m2 x 0.15m x 3m x (3.0 + 3.9 + 1.2)
=69.3kN
Total Dead load = 55.08 + 13.12 + 69.3
=137.5kN
Live Load
Slab:
1.5kN/m2 x 0.15m x 5.1 x 3.0
=3.44kN
Ultimate Load:
=(1.4 x 137.5) + (1.6 x 3.44)
=192.5 + 5.5
=198kN
46. 9.0 REFERENCES
Malaysia.; International Law Book Services. Legal Research Board, Uniform Building By
Law 1984. Kuala Lumpur : International Law Book Services, 2013.