Ansys temperature distribution and heat flux furnace jan 10 2013 updated
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This document discusses performing a finite element analysis (FEA) thermal analysis of a furnace to determine temperature distribution and heat flux. It provides details on the furnace dimensions, material properties of the concrete and brick walls, convection heat transfer coefficients, and temperatures of the furnace interior and surrounding air. The steps outlined include defining element types, material thermal conductivities, modeling the furnace geometry, meshing, and assigning material numbers to the concrete and brick walls in the FEA software before running the thermal analysis.
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Temperature distribution and heat flux furnace jan 01 2014
This document describes modeling the temperature distribution and heat flux of a furnace using finite element analysis. It provides the dimensions and materials of the concrete and brick walls that make up the furnace, as well as the temperature conditions inside and outside. It outlines the steps to define element types, thermal conductivities, mesh size controls, assign material numbers, and mesh the model to simulate heat transfer via conduction, convection and radiation within the furnace.
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1. The document contains homework problems about heat transfer involving concepts like conduction, convection, and radiation. It includes problems calculating heat transfer rates through materials like glass and aluminum plates, as well as determining surface temperatures and heat transfer coefficients.
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The document discusses calculating the temperature at the boundary between a refractory brick layer and insulating material layer in a plane wall. Given information includes the thicknesses of each layer, thermal conductivities, and temperatures on both surfaces. The calculated temperature at the boundary is 867.75°C. Another example calculates the time to cool a glass sheet submerged in water from an initial to average final temperature. The calculated time is 130.21 hours.
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The document provides data from a test on a flat-walled furnace with inner and outer brick walls of unknown conductivity. It gives the temperatures measured at various points within the furnace walls. It then calculates the percentage of heat loss that would be saved by adding 5cm of magnesia insulation to the furnace outer wall. Without the insulation, the heat loss is calculated to be 1612.87W, and with it added the heat loss is reduced to 542W, saving 33.61% of the heat loss.
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The document contains multiple engineering problems involving heat transfer calculations. Problem 7 calculates the temperature at the boundary between a refractory brick layer and insulating material layer based on given temperatures, thicknesses, and thermal conductivities. Problem 15 calculates the time required for a glass sheet to cool from an initial to average temperature in a water stream. Problem Geankoplis 4.1-2 calculates thermal conductivity using given temperatures, heat flux, and material thickness. Problem Geankoplis 5.3-7 calculates the internal temperature of a steel rod after 1 hour of cooling in an oil bath using given properties and conditions.
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The document contains several engineering problems related to heat transfer and thermodynamics. Problem 16 asks the student to use a numerical finite difference method to construct a temperature profile table for a 1m thick slab initially at 150°C that is suddenly exposed to 250°C fluid on one face and insulated on the other, using 4 slices and time steps up to 4000s. Problem 4.1-1 asks the student to calculate the heat loss per square meter for a temporary insulating wall with given temperatures, thickness, and material properties. Problem 5.3-6 asks the student to determine the time for a furnace wall lining initially at 100°F to reach 500°F at a depth of 0.5ft, given properties
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The document describes a problem involving calculating the heat loss through a double pane window. It is given that the window dimensions are 0.914m x 1.83m and that each of the glass layers is 6.35mm thick, separated by a 6.35mm layer of stagnant air. The thermal conductivities of the glass and air are provided. The problem is to calculate the heat loss for the given temperature drop of 27.8K across the system.
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The document discusses calculating the temperature at the boundary between a refractory brick layer and insulating material layer in a plane wall. Given information includes the thicknesses of each layer, thermal conductivities, and temperatures on both surfaces. The calculated temperature at the boundary is 867.75°C. Another example calculates the time to cool a glass sheet submerged in water from an initial to average final temperature. The calculated time is 130.21 hours.
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The document describes a problem calculating the heat loss from a furnace with inner dimensions of 1m x 1.2m x 0.75m and 11cm thick refractory walls. It provides the inner and outer surface temperatures and conductivity and calculates the total heat loss as 881798399.8 J over 24 hours by conduction through the walls. A second problem calculates the heat loss from a duct with ceramic and insulation layers given temperatures, thicknesses, and conductivities. It uses an iterative process to calculate the interface temperature and heat loss.
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The document contains two problems related to heat transfer through walls and insulation. The first problem involves calculating the thickness of insulation required around a furnace wall to limit heat loss to 1830 W/m^2, given the wall and insulation material properties. The second problem involves calculating the time required for the center of a large aluminum slab to reach a temperature of 388.8 K, given its initial temperature and properties, when exposed to a cooler environment.
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- 1. FEA Thermal Analysis Temperature Distribution and Heat Flux of a Furnace Prof. Charlton S. Inao
- 2. CONDUCTION
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- 4. RADIATION
- 7. Given Data: • Outer Wall, 300 x 300 • Inner Wall , 120 x 120 • Furnace opening , 100x 100 • Kc= 0.01 W/mK, thermal conductivity of the concrete wall (Mat’l No. 1) • Kb=0.0057 W/mK, thermal conductivity of the brick wall (Material No.2) • T=673 K temp within the furnace • K1= 0.208 W/m2K, convection heat transfer coefficient in the furnace • Ta= 253 K temperature of the surrounding air, where the outside wall is exposed to. • K2=0.068 W/m2K, convection heat transfer coefficient of the outside wall and the surrounding air
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