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Fourier Series 
主講者:虞台文 
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Content 
Periodic Functions 
Fourier Series 
Complex Form of the Fourier Series 
Impulse Train 
Analysis of Periodic Waveforms 
Half-Range Expansion 
Least Mean-Square Error Approximation 
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Fourier Series 
Periodic Functions 
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The Mathematic Formulation 
 Any function that satisfies 
f (t) = f (t +T) 
where T is a constant and is called the period 
of the function. 
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Example: 
f (t) = cos t + t Find its period. 
4 
cos 
3 
cos t + t = t +T + t +T 
( ) cos 1 
3 
f (t) = f (t +T) ( ) 
4 
cos 1 
4 
cos 
3 
Fact: cosq = cos(q + 2mp) 
T = 2mp 
3 
T = 2np 
4 
T = 6mp 
T = 8np 
T = 24p smallest T 
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Example: 
f t t t 1 2 ( ) = cosw + cosw Find its period. 
f (t) = f (t +T) cos cos cos ( ) cos ( ) 1 2 1 2 w t + w t = w t +T + w t +T 
w T = 2mp 1 
w T = 2np 2 
= m 
n 
w 
1 
w 
2 
w must be a 
1 
w 
2 
rational number 
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Example: 
f (t) = cos10t + cos(10 + p)t 
Is this function a periodic one? 
10 
1 not a rational 
+ p 
= 
w 
w 
10 
2 
number 
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Fourier Series 
Fourier Series 
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Introduction 
 Decompose a periodic input signal into 
primitive periodic components. 
AA p peerriiooddiicc s seeqquueennccee 
t 
T 2T 3T 
f(t) 
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Synthesis 
b nt 
= +å p +å p ¥ 
T 
f t a a nt 
T 
n 
n 
n 
n 
= 
¥ 
= 
cos 2 sin 2 
2 
( ) 
1 1 
0 
DC Part Even Part Odd Part 
T is a period of all the above signals 
f t a0 a n t b n t 
n = +å w +å w ¥ 
( ) 0 
cos( ) sin( ) 
2 
1 
0 
1 
n 
n 
n 
= 
¥ 
= 
Let w0=2p/T. 
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Orthogonal Functions 
Call a set of functions {fk 
} orthogonal 
on an interval a < t < b if it satisfies 
î í ì 
m ¹ 
n 
ò f t f t dt 
= r m = 
n 
n 
b 
a m n 
0 
( ) ( ) 
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Orthogonal set of Sinusoidal 
Functions 
Define w0=2p/T. 
m t dt m T 
T 
cos( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
m t dt m T 
T 
sin( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
cos( m t ) cos( n t ) dt T / 2 0 0 
/ 2 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
sin( m t )sin( n t ) dt T / 2 0 0 
/ 2 
We now prove this one 
m t n t dt m n T 
T 
sin( ) cos( ) 0, for all and / 2 
/ 2 0 0 ò w w = - 
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Proof 
cosacosb = 1 a +b + a -b 
òT 
/ 2 
cos( m w t ) cos( n w t ) 
dt - 
T / 2 0 0 cos[( ) ] 1 
T 
T ò ò- - 
1 
= + w + - w / 2 
/ 2 
/ 2 0 cos[( ) ] 
1 T 
sin[( ) ] 1 
2sin[( ) ] 1 
= m n 
0 
[cos( ) cos( )] 
2 
m n t dt m n t dt T 
T 
/ 2 0 
2 
2 
/ 2 
0 / 2 
0 
/ 2 
0 / 2 
0 
sin[( ) ] 
1 
( ) 
2 
1 
( ) 
2 
T 
T 
T m n t 
m n 
m n t 
+ w + 
- w 
m + n w 
- - w 
- = 
m ¹ n 
2sin[( ) ] 
1 
( ) 
2 
1 
( ) 
1 
2 
0 0 
- p 
+ w 
+ p + 
+ w 
m n 
m n 
m n 
0 0 =admission.edhole.com
Proof 
cosacosb = 1 a +b + a -b 
cos2 a = 1 + a 
òT 
/ 2 
cos( m w t ) cos( n w t ) 
dt - 
T / 2 0 0 1 
1 T 
t 
- - 
0 
[cos( ) cos( )] 
2 
m t dt T 
T ò- 
= w / 2 
cos2 ( ) 
/ 2 0 
/ 2 
/ 2 
0 
0 
/ 2 
/ 2 
sin 2 ] 
4 
1 
2 
T 
T 
T 
m t 
m 
w 
w 
= + 
m = n 
= T 
2 
[1 cos 2 ] 
2 
m t dt T 
T ò- 
= + w / 2 
/ 2 0 [1 cos 2 ] 
2 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
cos( m t ) cos( n t ) dt T / 2 
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Orthogonal set of Sinusoidal 
Functions 
Define w0=2p/T. 
1, 
ì 
m t dt m T 
T 
cos( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
ü 
m t dt m T 
T 
sin( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
t t t 
w w w 
cos ,cos 2 ,cos3 , 
î í ì 
m ¹ 
n 
0 
ò w w = - T m n 
0 0 0 
t t = 
t 
T 
/ 2 
cos( m t ) cos( n t ) dt T / 2 0 0 
/ 2 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
sin( m t )sin( n t ) dt T / 2 0 0 
/ 2 
m t n t dt m n T 
T 
sin( ) cos( ) 0, for all and / 2 
/ 2 0 0 ò w w = - 
ïþ 
ïý 
ïî 
ïí 
w w w 
 
 
sin ,sin 2 ,sin 3 , 
0 0 0 
aann oorrtthhooggoonnaall sseett.. 
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Decomposition 
f t a0 a n t b n t 
n = +å w +å w ¥ 
( ) 0 
2 ( ) 
f t dt 
a t T 
t ò + = 0 
T 
0 
0 
( ) cos 1,2, 2 
a t T 
n t 
= ò 0 
+ f t n w tdt n 
= T 
0 
0 
( )sin 1,2, 2 
b t T 
n t 
= ò 0 
+ f t n w tdt n 
= T 
0 
0 
cos( ) sin( ) 
2 
1 
0 
1 
n 
n 
n 
= 
¥ 
= 
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Proof 
Use the following facts: 
m t dt m T 
T 
cos( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
m t dt m T 
T 
sin( ) 0, 0 / 2 
/ 2 0 ò w = ¹ - 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
cos( m t ) cos( n t ) dt T / 2 0 0 
/ 2 
î í ì 
m ¹ 
n 
0 
ò w w = - T m = 
n 
T 
/ 2 
sin( m t )sin( n t ) dt T / 2 0 0 
/ 2 
m t n t dt m n T 
T 
sin( ) cos( ) 0, for all and / 2 
/ 2 0 0 ò w w = admi-ssion.edhole.com
Example (Square Wave) 
f(t) 
1 
-6p -5p -4p -3p -2p -p p 2p 3p 4p 5p 
= òp a dt 
0 0 = 
1 1 
2 
2 
p 
sin 0 1,2, cos 1 
2 
= p p ò nt n 
2 
0 0 
= = 
p 
= 
p 
n 
a ntdt n 
= 
n n 
2 / 1,3,5, 
p p 
= ò = - = - - =  
0 2,4,6, 
sin 1 cos 1 (cos 1) 
2 
2 
0 0 î í ì 
= 
 
n 
n 
n 
nt 
n 
b ntdt n 
p 
p 
p p p 
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sin 3 1 
3 
ö çè 
( ) 1 
Example (Square Wave) 
-6p -5p -4p -3p -2p -p p 2p 3p 4p 5p 
= òp a dt 
0 0 = 
1 1 
2 
2 
p 
sin 0 1,2, cos 1 
2 
= p p ò nt n 
2 
0 0 
= = 
p 
= 
p 
n 
a ntdt n 
n n 
p = 
2 / 1,3,5, 
= p p ò  
0 2,4,6, 
sin 1 cos 1 (cos 1) 
1 
2 
0 0 î í ì 
= 
p - = 
p 
= - 
p 
= - 
p 
 
n 
n 
n 
nt 
n 
b ntdt n 
f(t) 
1 
÷ø 
æ + + + 
p 
f t = + t t sin 5t  
5 
2 sin 1 
2 
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sin 3 1 
3 
ö çè 
( ) 1 
Example (Square Wave) 
-6p -5p -4p -3p -2p -p p 2p 3p 4p 5p 
= òp a dt 
0 0 = 
1 1 
2 
2 
p 
sin 0 1,2, cos 1 
2 
1.5 
1 
= p p ò nt n 
2 
0 0 
= = 
p 
= 
p 
n 
a ntdt n 
n n 
p = 
2 / 1,3,5, 
0.5 
0 
= p p ò  
0 2,4,6, 
sin 1 cos 1 (cos 1) 
1 
2 
0 0 î í ì 
= 
p - = 
p 
= - 
p 
= - 
p 
 
n 
n 
n 
nt 
n 
b ntdt n 
f(t) 
1 
-0.5 
÷ø 
æ + + + 
p 
f t = + t t sin 5t  
5 
2 sin 1 
2 
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Harmonics 
b nt 
= +å p +å p ¥ 
T 
f t a a nt 
T 
n 
n 
n 
n 
= 
¥ 
= 
cos 2 sin 2 
2 
( ) 
1 1 
0 
f t a0 a n t b n t 
n = +å w +å w ¥ 
( ) 0 
cos( ) sin( ) 
DC Part Even Part Odd Part 
T is a period of all the above signals 
2 
1 
0 
1 
n 
n 
n 
= 
¥ 
= 
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Harmonics 
w = 2pf = 2p Define 0 0 , called the fundamental angular frequency. 
f t a a n t b n t 
( ) = +å w +å w ¥ 
0 cos sin 
2 
n 
n 
n 
n 0 
1 
0 
1 
= 
¥ 
= 
T 
0 w = nw Define n , called the n-th harmonic of the periodic function. 
f t a a t b t n 
= +å w n n +å ¥ 
w n 
n 
n 
= 
¥ 
= 
cos sin 
2 
( ) 
1 1 
0 
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Harmonics 
f t a a t b t n 
= +å w n n +å ¥ 
w n 
n 
n 
= 
¥ 
= 
cos sin 
2 
( ) 
1 1 
0 
a0 a t b t 
n w + w + = å¥ 
( cos sin ) 
2 1 
n n n 
n 
= 
ö 
æ 
t b 
a a b a 
= ÷ ÷ 
å¥ 
ø 
ç ç 
0 2 2 cos sin 
2 n 
n n t 
è 
w 
n 
+ 
w + 
n 
+ 
= + + 
1 
2 2 2 2 
n 
n n 
n 
n n 
a b 
a b 
n n n n n na a b t t 
( ) å¥ 
= 
0 2 2 cos cos sin sin 
2 n 
= + + q w + q w 
1 
n nt C C q - w + = å¥ 
cos( ) 
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0 n 
1 
n
Amplitudes and Phase Angles 
n nt C C t f q - w + = å¥ = 
( ) cos( ) 
0 n 
1 
n 
harmonic amplitude phase angle 
0 
C = a 
2 
0 
2 2 
n n n C = a + b 
ö 
÷ ÷ø 
æ 
tan 1 b 
ç çè 
q = - 
n 
n 
n a 
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Fourier Series 
Complex Form of the 
Fourier Series 
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Complex Exponentials 
e jn t n t j n t 
0 0 w0 = cos w + sin w 
e jn t n t j n t 
0 0 - w0 = cos w - sin w 
n t (e jn 0t e jn 0t ) 
cos 1 0 
w = w + - w 
2 
(e jn t e jn t ) j (e jn t e jn t ) 
j 
sin 1 0 
w = w - - w = - w - - w 
n t 0 0 0 0 
2 2 
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Complex Form of the Fourier Series 
f t a a n t b n t 
( ) = +å w +å w ¥ 
0 cos sin 
2 
n 
n 
n 
n 0 
1 
0 
1 
= 
¥ 
= 
( ) ( jn t jn t ) 
n a a e e j b e e 0 0 0 0 
= + å + - å - 
n 
n 
jn t jn t 
n 
1 1 
0 
1 
2 2 
2 
w - w 
¥ 
= 
w - w 
¥ 
= 
n n a a jb e a jb e 
å¥ 
( ) 1 
2 
0 0 ( ) 0 
= 
w - w 
ù 
úû 
êëé + + - + = 
1 
2 
1 
2 n 
jn t 
n n 
jn t 
[ - w 
] - 
å¥ 
= 
= + w + 
1 
0 
0 0 
n 
jn t 
n 
jn t 
n c c e c e 
c a 
0 
2 
1 
= 
c = a - 
jb 
( ) 
2 
n n n 
c = 1 
a + 
jb 
( ) 
2 
0 
n n n 
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Complex Form of the Fourier Series 
[ - w 
å¥ 
] = 
( ) 0 0 
- 
= + w + 
1 
0 
n 
jn t 
n 
jn t 
n f t c c e c e 
å å- 
=-¥ 
w 
¥ 
= + w + 
= 
1 
1 
0 
0 0 
n 
jn t 
n 
n 
jn t 
n c c e c e 
å¥ 
= w 
=-¥ 
n 
jn t 
nc e 0 
c a 
0 
2 
1 
= 
c = a - 
jb 
( ) 
2 
n n n 
c = 1 
a + 
jb 
( ) 
2 
0 
n n n 
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Complex Form of the Fourier Series 
= = 1 / 2 
( ) 
0 ò- 
/ 2 
0 
2 
T 
T 
f t dt 
T 
c a 
1 
n n n c = a - jb 
( ) 
2 
úû ù 
/ 2 
/ 2 0 1 ( ) cos T ( )sin 
T 
êë é 
/ 2 
/ 2 0 
T 
T 
= ò w - ò w - - 
f t n tdt j f t n tdt 
T 
ò- 
/ 2 0 0 1 T ( )(cos sin ) 
T 
= w - w / 2 
f t n t j n t dt 
T 
ò- 
1 ( ) 0 T 
= - w / 2 
/ 2 
T 
f t e jn tdt 
T 
( ) 1 ( ) 0 
2 
c a 
0 
2 
1 
= 
c = a - 
jb 
( ) 
2 
n n n 
c = 1 
a + 
jb 
c a jb ( ) 
ò- 
w 
- = + = / 2 
/ 2 
1 T 
T 
jn t 
n n n f t e dt 
T 
2 
0 
n n n 
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Complex Form of the Fourier Series 
å¥ 
= w 
=-¥ 
n 
jn t 
nf (t) c e 0 
1 ( ) 0 
= - w / 2 
f t e dt 
c T 
T 
T 
jn t 
n ò- 
/ 2 
c a 
0 
2 
1 
= 
c = a - 
jb 
( ) 
2 
n n n 
c = 1 
a + 
jb 
( ) 
2 
0 
n n n 
- 
If f(t) is real, 
* 
n n c = c - 
n j n 
=| | f , = * =| | 
n n n 
j 
c c e c c c e- f 
n n - 
| | | | 1 n n n n c = c = a + b - 
2 2 
2 
ö 
c = 1 a admission.edhole.com 
÷ ÷ø 
æ 
tan 1 b 
ç çè 
f = - - 
n 
n 
n a 
n = ±1,±2,±3, 
0 0 2
Complex Frequency Spectra 
n j n 
=| | f , = * =| | 
n n n 
j 
c c e c c c e- f 
n n - 
| | | | 1 n n n n c = c = a + b - 
2 2 
2 
ö 
tan 1 b n = ±1,±2,±3, 
÷ ÷ø 
æ 
ç çè 
f = - - 
n 
n 
n a 
c = 1 a 
0 0 2 
|cn| 
amplitude 
spectrum 
w 
fn 
phase 
spectrum 
w 
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Example 
-T - T T 
T 
2 
2 
d 
2 
t 
f(t) 
A 
- d 
2 
= - w / 2 
e dt 
c A d 
T 
d 
jn t 
n ò- 
/ 2 
0 
/ 2 
0 1 d 
0 d 
/ 2 
e jn t 
A 
T jn 
- 
- w 
- w 
= 
ö 
÷ ÷ø 
æ 
ç çè 
0 0 1 jn d 1 e jn d 
A 
= - w w / 2 
- w 
- 
- w 
0 
/ 2 
0 
jn 
e 
T jn 
A - w 
- w 
1 ( 2 sin / 2) 
0 
0 
j n d 
T jn 
= 
A w 
1 sin / 2 
n d 
T 1 n 
w 
0 
2 0 
= 
n d 
ö çè 
n d 
ö çè 
÷ø 
æ p 
÷ø 
æ p 
= 
T 
T 
Ad 
T 
sin 
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n d 
ö çè 
n d 
ö çè 
÷ø 
æ p 
÷ø 
æ p 
c = 
Ad n 
T 
T 
T 
sin 
A/5 
d T d 
, 1 
20 
= = = 
2 8 
1 
5 
T 
, 
4 
1 
0 w = p = p 
T 
Example 
-120p -80p -40p 0 40p 80p 120p 
5w0 10w0 15w0 -5w0 -10w0 -15w0 
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n d 
ö çè 
n d 
ö çè 
÷ø 
æ p 
÷ø 
æ p 
c = 
Ad n 
T 
T 
T 
sin 
A/10 
d T d 
, 1 
20 
= = = 
2 4 
1 
5 
T 
, 
2 
1 
0 w = p = p 
T 
Example 
-120p -80p -40p 0 40p 80p 120p 
10w0 20w0 30w0 -10w0 -20w0 -30w0 
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Example 
c A d jn t 
n ò = - w 
-T d T 
e dt 
T 
0 
0 
d 
0 1 - w 
- w 
e jn t 
A 
T jn 
0 0 
= 
ö 
÷ ÷ø 
æ 
A jn d 
ç çè 
1 1 0 
jn 
- w 
- 
= - w 
- w 
e 
0 0 
T jn 
A - - w 
1 (1 ) 0 
0 
e jn d 
T jn 
w 
= 
A - w w - - w 
0 / 2 
sin 
ö çè 
Ad - w 
e jn d 
n d 
n d 
ö T 
çè 
T 
T 
÷ø 
æ p 
÷ø 
æ p 
= 
t 
f(t) 
A 
0 
1 / 2 ( / 2 / 2 ) 
0 
e jn 0d e jn 0d e jn 0d 
T jn 
w 
= 
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Fourier Series 
Impulse Train 
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Dirac Delta Function 
î í ì 
¹ 
t 
0 0 
t and ò d( ) =1 ¥ 
¥ = 
d = 
0 
( ) 
t 
-¥ 
t dt 
0 t 
Also called unit impulse function. 
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Property 
ò ¥ 
d( t )f( t ) dt 
= f(0) -¥ 
f(t): Test Function 
ò ¥ 
d( t )f( t ) dt = ò ¥ 
d( t )f(0) dt = f(0)ò ¥ 
d( t ) dt 
= f(0) -¥ 
-¥ 
-¥ 
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Impulse Train 
-3T -2T -T 0 T 2T 3T t 
å¥ 
T (t) (t nT) 
d = d - 
=-¥ 
n 
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Fourier Series of the Impulse Train 
å¥ 
T (t) (t nT) 
d = d - 
=-¥ 
n 
2 / 2 ( ) 2 
T 
= ò d t dt 
= 0 - 
/ 2 a T 
T 
T T 
2 / 2 ( ) cos( ) 2 
/ 2 0 = ò d w = - 
2 / 2 ( )sin( ) 0 
T 
t n t dt 
a T 
n T T 
T 
b T 
n T T 
= ò d t n w t dt 
= - 
/ 2 0 T 
t 0 ( ) 1 2 cos 
å¥ 
T n t 
d = + w 
=-¥ 
n 
T T 
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Complex Form 
Fourier Series of the Impulse Train 
1 ( ) 1 
T 
= = ò d t dt 
= 0 - 
c a T 
T 
T T 
2 
/ 2 
/ 2 
0 
1 / 2 ( ) 1 
T 
= ò d t e 0 dt 
= - 
c T 
T 
T 
jn t 
n T 
/ 2 
- w 
å¥ 
T (t) (t nT) 
d = d - 
=-¥ 
n 
t 0 ( ) 1 
å¥ 
d = w 
=-¥ 
n 
jn t 
T e 
T 
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Fourier Series 
Analysis of 
Periodic Waveforms 
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Waveform Symmetry 
Even Functions 
f (t) = f (-t) 
Odd Functions 
f (t) = - f (-t) 
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Decomposition 
Any function f(t) can be expressed as the 
sum of an even function fe(t) and an odd 
function fo(t). 
f (t) f (t) f (t) e o = + 
( ) [ ( ) ( )] 2 
f t 1 f t f t e = + - 
( ) [ ( ) ( )] 2 
f t 1 f t f t o = - - 
Even Part 
Odd Part 
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Example 
î í ì 
> 
< 
= 
- 
0 0 
0 
( ) 
e t 
t 
f t 
t 
Even Part 
Odd Part 
î í ì < 
> 
= 
- 
0 
0 
( ) 
1 
2 
1 
e t 
2 
e t 
f t t 
t 
e 
î í ì 
> 
t 
1 
e t 
- < 
= 
- 
0 
0 
( ) 
1 
2 
2 
e t 
f t o 
t 
adamdmisissisoino.ne.dehdohloel.ec.ocmom
Half-Wave Symmetry 
f (t) = f (t +T) and f (t) = - f (t +T / 2) 
-T/2 T/2 T 
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Quarter-Wave Symmetry 
Even Quarter-Wave Symmetry 
-T/2 T/2 T 
Odd Quarter-Wave Symmetry 
T 
-T/2 T/2 
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Hidden Symmetry 
 The following is a asymmetry periodic function: 
A 
-T T 
 Adding a constant to get symmetry property. 
A/2 
-T T 
-A/2 
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Fourier Coefficients of 
Symmetrical Waveforms 
 The use of symmetry properties simplifies the 
calculation of Fourier coefficients. 
– Even Functions 
– Odd Functions 
– Half-Wave 
– Even Quarter-Wave 
– Odd Quarter-Wave 
– Hidden 
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Fourier Coefficients of Even Functions 
f (t) = f (-t) 
f ( t a å¥ 
) = + a n w t 
0 cos 
2 
n 
n 0 
= 
1 
0 0 4 T ( ) cos( ) 
= ò w / 2 
n f t n t dt 
T 
a 
admission.edhole.com
Fourier Coefficients of Even Functions 
f (t) = - f (-t) 
sin ) ( w =å¥ 
f t b n t 
n 
n 0 
= 
1 
= ò / 2 
w 0 0 4 T ( )sin( ) 
n f t n t dt 
T 
b 
admission.edhole.com
Fourier Coefficients for Half-Wave Symmetry 
f (t) = f (t +T) and f (t) = - f (t +T / 2) 
-T/2 T/2 T 
TThhee FFoouurriieerr sseerriieess ccoonnttaaiinnss oonnllyy oodddd hhaarrmmoonniiccss.. admission.edhole.com
Fourier Coefficients for Half-Wave Symmetry 
f (t) = f (t +T) and f (t) = - f (t +T / 2) 
0 0 å¥ 
= 
f t = a n w t + b n w 
t 
n n ( ) ( cos sin ) 
1 
n 
n 
0 for even 
ïî 
ïí ì 
= w 4 ò ( ) cos( ) for odd 
a T 
n 
/ 2 
0 0 f t n t dt n 
T 
n 
0 for even 
ïî 
ïí ì 
= w 4 ò ( )sin( ) for odd 
b T 
n admission.edhole.com 
/ 2 
0 0 f t n t dt n 
T
Fourier Coefficients for 
Even Quarter-Wave Symmetry 
-T/2 T/2 T 
n w - =å¥ 
2 1 f t a n t 
( ) cos[(2 1) ] 0 
1 
n 
= 
- 
8 T / 4 
( ) cos[(2 1) ] 
2 1 0 0 = ò - w - 
n f t n t dt 
T 
a 
admission.edhole.com
Fourier Coefficients for 
Odd Quarter-Wave Symmetry 
n w - =å¥ 
2 1 f t b n t 
( ) sin[(2 1) ] 0 
1 
n 
= 
- 
8 T / 4 
( )sin[(2 1) ] 
2 1 0 0 = ò - w - 
n f t n t dt 
T 
b 
T 
-T/2 T/2 
admission.edhole.com
Example 
Even Quarter-Wave Symmetry 
1 
-T -T/4 T/4 
2 1 0 0 8 T ( ) cos[(2 1) ] 
a = n - 
ò / 4 
f t n - w t dt 
= ò / 4 
- w T 
0 0 8 T cos[(2 1) ]n t dt 
T 
/ 4 
8 T 
0 
0 
0 
sin[(2 1) ] 
(2 1) 
n t 
n T 
- w 
- w 
= 
( 1) 1 4 
- p 
= - - 
n 
(2 1) 
n 
T 
-T/2 T/2 
-1 
admission.edhole.com
cos3 1 
3 
ö çè 
Example 
Even Quarter-Wave Symmetry 
1 
-T -T/4 T/4 
2 1 0 0 8 T ( ) cos[(2 1) ] 
a = n - 
ò / 4 
f t n - w t dt 
= ò / 4 
- w T 
0 0 8 T cos[(2 1) ]n t dt 
T 
/ 4 
8 T 
0 
0 
0 
sin[(2 1) ] 
(2 1) 
n t 
n T 
- w 
- w 
= 
( 1) 1 4 
- p 
= - - 
n 
(2 1) 
n 
T 
-T/2 T/2 
-1 
÷ø 
æ w - w + w + 
p 
f t = t t t  0 0 0 cos5 
5 
( ) 4 cos 1 
admission.edhole.com
Example 
T 
1 
Odd Quarter-Wave Symmetry 
-T/2 T/2 
-T -T/4 T/4 
-1 
2 1 0 0 8 T ( )sin[(2 1) ] 
b = n - 
ò / 4 
f t n - w t dt 
= ò / 4 
- w T 
0 0 8 T sin[(2 1) ]n t dt 
T 
/ 4 
8 T 
0 
0 
0 
cos[(2 1) ] 
= - 
(2 1) 
n t 
n T 
- w 
- w 
4 
n 
= 
(2 1) 
- p 
admission.edhole.com
sin 3 1 
3 
ö çè 
Example 
T 
1 
Odd Quarter-Wave Symmetry 
-T/2 T/2 
-T -T/4 T/4 
-1 
2 1 0 0 8 T ( )sin[(2 1) ] 
b = n - 
ò / 4 
f t n - w t dt 
= ò / 4 
- w T 
0 0 8 T sin[(2 1) ]n t dt 
T 
/ 4 
8 T 
0 
0 
0 
cos[(2 1) ] 
= - 
(2 1) 
n t 
n T 
- w 
- w 
4 
n 
= 
(2 1) 
- p 
÷ø 
æ w + w + w + 
p 
f t = t t t  0 0 0 sin 5 
5 
( ) 4 sin 1 
admission.edhole.com
Fourier Series 
Half-Range 
Expansions 
admission.edhole.com
Non-Periodic Function Representation 
t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Without Considering Symmetry 
t T 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Expansion Into Even Symmetry 
t T=2t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Expansion Into Odd Symmetry 
t 
T=2t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Expansion Into Half-Wave Symmetry 
t T=2t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Expansion Into 
Even Quarter-Wave Symmetry 
t 
T/2=2t 
T=4t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Expansion Into 
Odd Quarter-Wave Symmetry 
t 
T/2=2t T=4t 
 A non-periodic function f(t) defined over (0, t) 
can be expanded into a Fourier series which is 
defined only in the interval (0, t). 
admission.edhole.com
Fourier Series 
Least Mean-Square 
Error Approximation 
admission.edhole.com
Approximation a function 
k 
S t a a n t b n t 
k n n Use = 0 + ( cos w + sin 
w 
) å= 
2 
n 
1 
0 0 
( ) 
to represent f(t) on interval -T/2 < t < T/2. 
Define (t) f (t) S (t) k k e = - 
1 T [ ( )]2 
E = / 2 
e Mean-Square 
ò- 
t dt 
k T / 2 
k T 
Error 
admission.edhole.com
Approximation a function 
Show that using Sk(t) to represent f(t) has 
least mean-square property. 
1 T [ ( )]2 
= e / 2 
ò- 
t dt 
k T / 2 
k T 
E 
n n f t a a n t b n t dt 
= é - - w + w / 2 
ò å( ) - 
0 cos sin 
2 
= 
ù 
úû 
êë 
/ 2 
2 
1 
0 0 
1 T ( ) 
T 
k 
n 
T 
Proven by setting ¶Ek/¶ai = 0 and ¶Ek/¶bi = 0. admission.edhole.com
Approximation a function 
1 T [ ( )]2 
= e / 2 
ò- 
t dt 
k T / 2 
k T 
E 
n n f t a a n t b n t dt 
ò å( ) - 
0 cos sin 
2 
= 
ù 
úû 
êë= é - - w + w / 2 
/ 2 
2 
1 
0 0 
1 T ( ) 
T 
k 
n 
T 
1 ( ) 0 
E 2 / 2 ( ) cos 0 
¶ ò- 
2 
/ 2 
/ 2 
0 
0 
= - = 
¶ 
T 
T 
k f t dt 
T 
a 
a 
E 
¶ ò- 
k f t n tdt 
/ 2 0 = - w = 
¶ 
T 
n T 
n 
T 
a 
a 
E 
¶ ò- 
2 / 2 ( )sin 0 
k f t n tdt 
/ 2 0 = - w = 
¶ 
T 
n T 
n 
T 
b 
b 
admission.edhole.com
Mean-Square Error 
1 T [ ( )]2 
= e / 2 
ò- 
t dt 
k T / 2 
k T 
E 
n n f t a a n t b n t dt 
ò å( ) - 
0 cos sin 
2 
T 
= 
ò å - 
ù 
úû 
êë= é - - w + w / 2 
/ 2 
2 
1 
0 0 
1 T ( ) 
T 
k 
n 
= / 2 
f t dt - a - 1 
a + b 
k n n = 
/ 2 
1 
2 2 
2 
2 0 ( ) 
2 
4 
1 T [ ( )] 
T 
k 
n 
T 
E 
admission.edhole.com
Mean-Square Error 
1 T [ ( )]2 
= e / 2 
ò- 
t dt 
k T / 2 
k T 
E 
n n f t a a n t b n t dt 
ò å( ) - 
0 cos sin 
2 
T 
= 
ò å - 
ù 
úû 
êë= é - - w + w / 2 
/ 2 
2 
1 
0 0 
1 T ( ) 
T 
k 
n 
f t dt a 1 
a b 
n n ³ + + / 2 
/ 2 
= 
1 
2 2 
2 
2 0 ( ) 
2 
4 
1 T [ ( )] 
T 
k 
n 
T 
admission.edhole.com
Mean-Square Error 
1 T [ ( )]2 
= e / 2 
ò- 
t dt 
k T / 2 
k T 
E 
n n f t a a n t b n t dt 
ò å( ) - 
0 cos sin 
2 
T 
= 
ò å - 
ù 
úû 
êë= é - - w + w / 2 
/ 2 
2 
1 
0 0 
1 T ( ) 
T 
k 
n 
f t dt a 1 
¥ 
a b 
n n = + + / 2 
/ 2 
= 
1 
2 2 
2 
2 0 ( ) 
2 
4 
1 T [ ( )] 
T 
n 
T

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Admission in India

  • 1. Admission in India 2015 By: admission.edhole.com
  • 3. Content Periodic Functions Fourier Series Complex Form of the Fourier Series Impulse Train Analysis of Periodic Waveforms Half-Range Expansion Least Mean-Square Error Approximation admission.edhole.com
  • 4. Fourier Series Periodic Functions admission.edhole.com
  • 5. The Mathematic Formulation  Any function that satisfies f (t) = f (t +T) where T is a constant and is called the period of the function. admission.edhole.com
  • 6. Example: f (t) = cos t + t Find its period. 4 cos 3 cos t + t = t +T + t +T ( ) cos 1 3 f (t) = f (t +T) ( ) 4 cos 1 4 cos 3 Fact: cosq = cos(q + 2mp) T = 2mp 3 T = 2np 4 T = 6mp T = 8np T = 24p smallest T admission.edhole.com
  • 7. Example: f t t t 1 2 ( ) = cosw + cosw Find its period. f (t) = f (t +T) cos cos cos ( ) cos ( ) 1 2 1 2 w t + w t = w t +T + w t +T w T = 2mp 1 w T = 2np 2 = m n w 1 w 2 w must be a 1 w 2 rational number admission.edhole.com
  • 8. Example: f (t) = cos10t + cos(10 + p)t Is this function a periodic one? 10 1 not a rational + p = w w 10 2 number admission.edhole.com
  • 9. Fourier Series Fourier Series admission.edhole.com
  • 10. Introduction  Decompose a periodic input signal into primitive periodic components. AA p peerriiooddiicc s seeqquueennccee t T 2T 3T f(t) admission.edhole.com
  • 11. Synthesis b nt = +å p +å p ¥ T f t a a nt T n n n n = ¥ = cos 2 sin 2 2 ( ) 1 1 0 DC Part Even Part Odd Part T is a period of all the above signals f t a0 a n t b n t n = +å w +å w ¥ ( ) 0 cos( ) sin( ) 2 1 0 1 n n n = ¥ = Let w0=2p/T. admission.edhole.com
  • 12. Orthogonal Functions Call a set of functions {fk } orthogonal on an interval a < t < b if it satisfies î í ì m ¹ n ò f t f t dt = r m = n n b a m n 0 ( ) ( ) admission.edhole.com
  • 13. Orthogonal set of Sinusoidal Functions Define w0=2p/T. m t dt m T T cos( ) 0, 0 / 2 / 2 0 ò w = ¹ - m t dt m T T sin( ) 0, 0 / 2 / 2 0 ò w = ¹ - î í ì m ¹ n 0 ò w w = - T m = n T / 2 cos( m t ) cos( n t ) dt T / 2 0 0 / 2 î í ì m ¹ n 0 ò w w = - T m = n T / 2 sin( m t )sin( n t ) dt T / 2 0 0 / 2 We now prove this one m t n t dt m n T T sin( ) cos( ) 0, for all and / 2 / 2 0 0 ò w w = - admission.edhole.com
  • 14. Proof cosacosb = 1 a +b + a -b òT / 2 cos( m w t ) cos( n w t ) dt - T / 2 0 0 cos[( ) ] 1 T T ò ò- - 1 = + w + - w / 2 / 2 / 2 0 cos[( ) ] 1 T sin[( ) ] 1 2sin[( ) ] 1 = m n 0 [cos( ) cos( )] 2 m n t dt m n t dt T T / 2 0 2 2 / 2 0 / 2 0 / 2 0 / 2 0 sin[( ) ] 1 ( ) 2 1 ( ) 2 T T T m n t m n m n t + w + - w m + n w - - w - = m ¹ n 2sin[( ) ] 1 ( ) 2 1 ( ) 1 2 0 0 - p + w + p + + w m n m n m n 0 0 =admission.edhole.com
  • 15. Proof cosacosb = 1 a +b + a -b cos2 a = 1 + a òT / 2 cos( m w t ) cos( n w t ) dt - T / 2 0 0 1 1 T t - - 0 [cos( ) cos( )] 2 m t dt T T ò- = w / 2 cos2 ( ) / 2 0 / 2 / 2 0 0 / 2 / 2 sin 2 ] 4 1 2 T T T m t m w w = + m = n = T 2 [1 cos 2 ] 2 m t dt T T ò- = + w / 2 / 2 0 [1 cos 2 ] 2 î í ì m ¹ n 0 ò w w = - T m = n T / 2 cos( m t ) cos( n t ) dt T / 2 admission.edhole.com / 2 0 0
  • 16. Orthogonal set of Sinusoidal Functions Define w0=2p/T. 1, ì m t dt m T T cos( ) 0, 0 / 2 / 2 0 ò w = ¹ - ü m t dt m T T sin( ) 0, 0 / 2 / 2 0 ò w = ¹ - t t t w w w cos ,cos 2 ,cos3 , î í ì m ¹ n 0 ò w w = - T m n 0 0 0 t t = t T / 2 cos( m t ) cos( n t ) dt T / 2 0 0 / 2 î í ì m ¹ n 0 ò w w = - T m = n T / 2 sin( m t )sin( n t ) dt T / 2 0 0 / 2 m t n t dt m n T T sin( ) cos( ) 0, for all and / 2 / 2 0 0 ò w w = - ïþ ïý ïî ïí w w w   sin ,sin 2 ,sin 3 , 0 0 0 aann oorrtthhooggoonnaall sseett.. admission.edhole.com
  • 17. Decomposition f t a0 a n t b n t n = +å w +å w ¥ ( ) 0 2 ( ) f t dt a t T t ò + = 0 T 0 0 ( ) cos 1,2, 2 a t T n t = ò 0 + f t n w tdt n = T 0 0 ( )sin 1,2, 2 b t T n t = ò 0 + f t n w tdt n = T 0 0 cos( ) sin( ) 2 1 0 1 n n n = ¥ = admission.edhole.com
  • 18. Proof Use the following facts: m t dt m T T cos( ) 0, 0 / 2 / 2 0 ò w = ¹ - m t dt m T T sin( ) 0, 0 / 2 / 2 0 ò w = ¹ - î í ì m ¹ n 0 ò w w = - T m = n T / 2 cos( m t ) cos( n t ) dt T / 2 0 0 / 2 î í ì m ¹ n 0 ò w w = - T m = n T / 2 sin( m t )sin( n t ) dt T / 2 0 0 / 2 m t n t dt m n T T sin( ) cos( ) 0, for all and / 2 / 2 0 0 ò w w = admi-ssion.edhole.com
  • 19. Example (Square Wave) f(t) 1 -6p -5p -4p -3p -2p -p p 2p 3p 4p 5p = òp a dt 0 0 = 1 1 2 2 p sin 0 1,2, cos 1 2 = p p ò nt n 2 0 0 = = p = p n a ntdt n = n n 2 / 1,3,5, p p = ò = - = - - =  0 2,4,6, sin 1 cos 1 (cos 1) 2 2 0 0 î í ì =  n n n nt n b ntdt n p p p p p admission.edhole.com
  • 20. sin 3 1 3 ö çè ( ) 1 Example (Square Wave) -6p -5p -4p -3p -2p -p p 2p 3p 4p 5p = òp a dt 0 0 = 1 1 2 2 p sin 0 1,2, cos 1 2 = p p ò nt n 2 0 0 = = p = p n a ntdt n n n p = 2 / 1,3,5, = p p ò  0 2,4,6, sin 1 cos 1 (cos 1) 1 2 0 0 î í ì = p - = p = - p = - p  n n n nt n b ntdt n f(t) 1 ÷ø æ + + + p f t = + t t sin 5t  5 2 sin 1 2 admission.edhole.com
  • 21. sin 3 1 3 ö çè ( ) 1 Example (Square Wave) -6p -5p -4p -3p -2p -p p 2p 3p 4p 5p = òp a dt 0 0 = 1 1 2 2 p sin 0 1,2, cos 1 2 1.5 1 = p p ò nt n 2 0 0 = = p = p n a ntdt n n n p = 2 / 1,3,5, 0.5 0 = p p ò  0 2,4,6, sin 1 cos 1 (cos 1) 1 2 0 0 î í ì = p - = p = - p = - p  n n n nt n b ntdt n f(t) 1 -0.5 ÷ø æ + + + p f t = + t t sin 5t  5 2 sin 1 2 admission.edhole.com
  • 22. Harmonics b nt = +å p +å p ¥ T f t a a nt T n n n n = ¥ = cos 2 sin 2 2 ( ) 1 1 0 f t a0 a n t b n t n = +å w +å w ¥ ( ) 0 cos( ) sin( ) DC Part Even Part Odd Part T is a period of all the above signals 2 1 0 1 n n n = ¥ = admission.edhole.com
  • 23. Harmonics w = 2pf = 2p Define 0 0 , called the fundamental angular frequency. f t a a n t b n t ( ) = +å w +å w ¥ 0 cos sin 2 n n n n 0 1 0 1 = ¥ = T 0 w = nw Define n , called the n-th harmonic of the periodic function. f t a a t b t n = +å w n n +å ¥ w n n n = ¥ = cos sin 2 ( ) 1 1 0 admission.edhole.com
  • 24. Harmonics f t a a t b t n = +å w n n +å ¥ w n n n = ¥ = cos sin 2 ( ) 1 1 0 a0 a t b t n w + w + = å¥ ( cos sin ) 2 1 n n n n = ö æ t b a a b a = ÷ ÷ å¥ ø ç ç 0 2 2 cos sin 2 n n n t è w n + w + n + = + + 1 2 2 2 2 n n n n n n a b a b n n n n n na a b t t ( ) å¥ = 0 2 2 cos cos sin sin 2 n = + + q w + q w 1 n nt C C q - w + = å¥ cos( ) = admission.edhole.com 0 n 1 n
  • 25. Amplitudes and Phase Angles n nt C C t f q - w + = å¥ = ( ) cos( ) 0 n 1 n harmonic amplitude phase angle 0 C = a 2 0 2 2 n n n C = a + b ö ÷ ÷ø æ tan 1 b ç çè q = - n n n a admission.edhole.com
  • 26. Fourier Series Complex Form of the Fourier Series admission.edhole.com
  • 27. Complex Exponentials e jn t n t j n t 0 0 w0 = cos w + sin w e jn t n t j n t 0 0 - w0 = cos w - sin w n t (e jn 0t e jn 0t ) cos 1 0 w = w + - w 2 (e jn t e jn t ) j (e jn t e jn t ) j sin 1 0 w = w - - w = - w - - w n t 0 0 0 0 2 2 admission.edhole.com
  • 28. Complex Form of the Fourier Series f t a a n t b n t ( ) = +å w +å w ¥ 0 cos sin 2 n n n n 0 1 0 1 = ¥ = ( ) ( jn t jn t ) n a a e e j b e e 0 0 0 0 = + å + - å - n n jn t jn t n 1 1 0 1 2 2 2 w - w ¥ = w - w ¥ = n n a a jb e a jb e å¥ ( ) 1 2 0 0 ( ) 0 = w - w ù úû êëé + + - + = 1 2 1 2 n jn t n n jn t [ - w ] - å¥ = = + w + 1 0 0 0 n jn t n jn t n c c e c e c a 0 2 1 = c = a - jb ( ) 2 n n n c = 1 a + jb ( ) 2 0 n n n admission.edhole.com -
  • 29. Complex Form of the Fourier Series [ - w å¥ ] = ( ) 0 0 - = + w + 1 0 n jn t n jn t n f t c c e c e å å- =-¥ w ¥ = + w + = 1 1 0 0 0 n jn t n n jn t n c c e c e å¥ = w =-¥ n jn t nc e 0 c a 0 2 1 = c = a - jb ( ) 2 n n n c = 1 a + jb ( ) 2 0 n n n admission.edhole.com -
  • 30. Complex Form of the Fourier Series = = 1 / 2 ( ) 0 ò- / 2 0 2 T T f t dt T c a 1 n n n c = a - jb ( ) 2 úû ù / 2 / 2 0 1 ( ) cos T ( )sin T êë é / 2 / 2 0 T T = ò w - ò w - - f t n tdt j f t n tdt T ò- / 2 0 0 1 T ( )(cos sin ) T = w - w / 2 f t n t j n t dt T ò- 1 ( ) 0 T = - w / 2 / 2 T f t e jn tdt T ( ) 1 ( ) 0 2 c a 0 2 1 = c = a - jb ( ) 2 n n n c = 1 a + jb c a jb ( ) ò- w - = + = / 2 / 2 1 T T jn t n n n f t e dt T 2 0 n n n admission.edhole.com -
  • 31. Complex Form of the Fourier Series å¥ = w =-¥ n jn t nf (t) c e 0 1 ( ) 0 = - w / 2 f t e dt c T T T jn t n ò- / 2 c a 0 2 1 = c = a - jb ( ) 2 n n n c = 1 a + jb ( ) 2 0 n n n - If f(t) is real, * n n c = c - n j n =| | f , = * =| | n n n j c c e c c c e- f n n - | | | | 1 n n n n c = c = a + b - 2 2 2 ö c = 1 a admission.edhole.com ÷ ÷ø æ tan 1 b ç çè f = - - n n n a n = ±1,±2,±3, 0 0 2
  • 32. Complex Frequency Spectra n j n =| | f , = * =| | n n n j c c e c c c e- f n n - | | | | 1 n n n n c = c = a + b - 2 2 2 ö tan 1 b n = ±1,±2,±3, ÷ ÷ø æ ç çè f = - - n n n a c = 1 a 0 0 2 |cn| amplitude spectrum w fn phase spectrum w admission.edhole.com
  • 33. Example -T - T T T 2 2 d 2 t f(t) A - d 2 = - w / 2 e dt c A d T d jn t n ò- / 2 0 / 2 0 1 d 0 d / 2 e jn t A T jn - - w - w = ö ÷ ÷ø æ ç çè 0 0 1 jn d 1 e jn d A = - w w / 2 - w - - w 0 / 2 0 jn e T jn A - w - w 1 ( 2 sin / 2) 0 0 j n d T jn = A w 1 sin / 2 n d T 1 n w 0 2 0 = n d ö çè n d ö çè ÷ø æ p ÷ø æ p = T T Ad T sin admission.edhole.com
  • 34. n d ö çè n d ö çè ÷ø æ p ÷ø æ p c = Ad n T T T sin A/5 d T d , 1 20 = = = 2 8 1 5 T , 4 1 0 w = p = p T Example -120p -80p -40p 0 40p 80p 120p 5w0 10w0 15w0 -5w0 -10w0 -15w0 admission.edhole.com
  • 35. n d ö çè n d ö çè ÷ø æ p ÷ø æ p c = Ad n T T T sin A/10 d T d , 1 20 = = = 2 4 1 5 T , 2 1 0 w = p = p T Example -120p -80p -40p 0 40p 80p 120p 10w0 20w0 30w0 -10w0 -20w0 -30w0 admission.edhole.com
  • 36. Example c A d jn t n ò = - w -T d T e dt T 0 0 d 0 1 - w - w e jn t A T jn 0 0 = ö ÷ ÷ø æ A jn d ç çè 1 1 0 jn - w - = - w - w e 0 0 T jn A - - w 1 (1 ) 0 0 e jn d T jn w = A - w w - - w 0 / 2 sin ö çè Ad - w e jn d n d n d ö T çè T T ÷ø æ p ÷ø æ p = t f(t) A 0 1 / 2 ( / 2 / 2 ) 0 e jn 0d e jn 0d e jn 0d T jn w = admission.edhole.com
  • 37. Fourier Series Impulse Train admission.edhole.com
  • 38. Dirac Delta Function î í ì ¹ t 0 0 t and ò d( ) =1 ¥ ¥ = d = 0 ( ) t -¥ t dt 0 t Also called unit impulse function. admission.edhole.com
  • 39. Property ò ¥ d( t )f( t ) dt = f(0) -¥ f(t): Test Function ò ¥ d( t )f( t ) dt = ò ¥ d( t )f(0) dt = f(0)ò ¥ d( t ) dt = f(0) -¥ -¥ -¥ admission.edhole.com
  • 40. Impulse Train -3T -2T -T 0 T 2T 3T t å¥ T (t) (t nT) d = d - =-¥ n admission.edhole.com
  • 41. Fourier Series of the Impulse Train å¥ T (t) (t nT) d = d - =-¥ n 2 / 2 ( ) 2 T = ò d t dt = 0 - / 2 a T T T T 2 / 2 ( ) cos( ) 2 / 2 0 = ò d w = - 2 / 2 ( )sin( ) 0 T t n t dt a T n T T T b T n T T = ò d t n w t dt = - / 2 0 T t 0 ( ) 1 2 cos å¥ T n t d = + w =-¥ n T T admission.edhole.com
  • 42. Complex Form Fourier Series of the Impulse Train 1 ( ) 1 T = = ò d t dt = 0 - c a T T T T 2 / 2 / 2 0 1 / 2 ( ) 1 T = ò d t e 0 dt = - c T T T jn t n T / 2 - w å¥ T (t) (t nT) d = d - =-¥ n t 0 ( ) 1 å¥ d = w =-¥ n jn t T e T admission.edhole.com
  • 43. Fourier Series Analysis of Periodic Waveforms admission.edhole.com
  • 44. Waveform Symmetry Even Functions f (t) = f (-t) Odd Functions f (t) = - f (-t) admission.edhole.com
  • 45. Decomposition Any function f(t) can be expressed as the sum of an even function fe(t) and an odd function fo(t). f (t) f (t) f (t) e o = + ( ) [ ( ) ( )] 2 f t 1 f t f t e = + - ( ) [ ( ) ( )] 2 f t 1 f t f t o = - - Even Part Odd Part admission.edhole.com
  • 46. Example î í ì > < = - 0 0 0 ( ) e t t f t t Even Part Odd Part î í ì < > = - 0 0 ( ) 1 2 1 e t 2 e t f t t t e î í ì > t 1 e t - < = - 0 0 ( ) 1 2 2 e t f t o t adamdmisissisoino.ne.dehdohloel.ec.ocmom
  • 47. Half-Wave Symmetry f (t) = f (t +T) and f (t) = - f (t +T / 2) -T/2 T/2 T admission.edhole.com
  • 48. Quarter-Wave Symmetry Even Quarter-Wave Symmetry -T/2 T/2 T Odd Quarter-Wave Symmetry T -T/2 T/2 admission.edhole.com
  • 49. Hidden Symmetry  The following is a asymmetry periodic function: A -T T  Adding a constant to get symmetry property. A/2 -T T -A/2 admission.edhole.com
  • 50. Fourier Coefficients of Symmetrical Waveforms  The use of symmetry properties simplifies the calculation of Fourier coefficients. – Even Functions – Odd Functions – Half-Wave – Even Quarter-Wave – Odd Quarter-Wave – Hidden admission.edhole.com
  • 51. Fourier Coefficients of Even Functions f (t) = f (-t) f ( t a å¥ ) = + a n w t 0 cos 2 n n 0 = 1 0 0 4 T ( ) cos( ) = ò w / 2 n f t n t dt T a admission.edhole.com
  • 52. Fourier Coefficients of Even Functions f (t) = - f (-t) sin ) ( w =å¥ f t b n t n n 0 = 1 = ò / 2 w 0 0 4 T ( )sin( ) n f t n t dt T b admission.edhole.com
  • 53. Fourier Coefficients for Half-Wave Symmetry f (t) = f (t +T) and f (t) = - f (t +T / 2) -T/2 T/2 T TThhee FFoouurriieerr sseerriieess ccoonnttaaiinnss oonnllyy oodddd hhaarrmmoonniiccss.. admission.edhole.com
  • 54. Fourier Coefficients for Half-Wave Symmetry f (t) = f (t +T) and f (t) = - f (t +T / 2) 0 0 å¥ = f t = a n w t + b n w t n n ( ) ( cos sin ) 1 n n 0 for even ïî ïí ì = w 4 ò ( ) cos( ) for odd a T n / 2 0 0 f t n t dt n T n 0 for even ïî ïí ì = w 4 ò ( )sin( ) for odd b T n admission.edhole.com / 2 0 0 f t n t dt n T
  • 55. Fourier Coefficients for Even Quarter-Wave Symmetry -T/2 T/2 T n w - =å¥ 2 1 f t a n t ( ) cos[(2 1) ] 0 1 n = - 8 T / 4 ( ) cos[(2 1) ] 2 1 0 0 = ò - w - n f t n t dt T a admission.edhole.com
  • 56. Fourier Coefficients for Odd Quarter-Wave Symmetry n w - =å¥ 2 1 f t b n t ( ) sin[(2 1) ] 0 1 n = - 8 T / 4 ( )sin[(2 1) ] 2 1 0 0 = ò - w - n f t n t dt T b T -T/2 T/2 admission.edhole.com
  • 57. Example Even Quarter-Wave Symmetry 1 -T -T/4 T/4 2 1 0 0 8 T ( ) cos[(2 1) ] a = n - ò / 4 f t n - w t dt = ò / 4 - w T 0 0 8 T cos[(2 1) ]n t dt T / 4 8 T 0 0 0 sin[(2 1) ] (2 1) n t n T - w - w = ( 1) 1 4 - p = - - n (2 1) n T -T/2 T/2 -1 admission.edhole.com
  • 58. cos3 1 3 ö çè Example Even Quarter-Wave Symmetry 1 -T -T/4 T/4 2 1 0 0 8 T ( ) cos[(2 1) ] a = n - ò / 4 f t n - w t dt = ò / 4 - w T 0 0 8 T cos[(2 1) ]n t dt T / 4 8 T 0 0 0 sin[(2 1) ] (2 1) n t n T - w - w = ( 1) 1 4 - p = - - n (2 1) n T -T/2 T/2 -1 ÷ø æ w - w + w + p f t = t t t  0 0 0 cos5 5 ( ) 4 cos 1 admission.edhole.com
  • 59. Example T 1 Odd Quarter-Wave Symmetry -T/2 T/2 -T -T/4 T/4 -1 2 1 0 0 8 T ( )sin[(2 1) ] b = n - ò / 4 f t n - w t dt = ò / 4 - w T 0 0 8 T sin[(2 1) ]n t dt T / 4 8 T 0 0 0 cos[(2 1) ] = - (2 1) n t n T - w - w 4 n = (2 1) - p admission.edhole.com
  • 60. sin 3 1 3 ö çè Example T 1 Odd Quarter-Wave Symmetry -T/2 T/2 -T -T/4 T/4 -1 2 1 0 0 8 T ( )sin[(2 1) ] b = n - ò / 4 f t n - w t dt = ò / 4 - w T 0 0 8 T sin[(2 1) ]n t dt T / 4 8 T 0 0 0 cos[(2 1) ] = - (2 1) n t n T - w - w 4 n = (2 1) - p ÷ø æ w + w + w + p f t = t t t  0 0 0 sin 5 5 ( ) 4 sin 1 admission.edhole.com
  • 61. Fourier Series Half-Range Expansions admission.edhole.com
  • 62. Non-Periodic Function Representation t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 63. Without Considering Symmetry t T  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 64. Expansion Into Even Symmetry t T=2t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 65. Expansion Into Odd Symmetry t T=2t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 66. Expansion Into Half-Wave Symmetry t T=2t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 67. Expansion Into Even Quarter-Wave Symmetry t T/2=2t T=4t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 68. Expansion Into Odd Quarter-Wave Symmetry t T/2=2t T=4t  A non-periodic function f(t) defined over (0, t) can be expanded into a Fourier series which is defined only in the interval (0, t). admission.edhole.com
  • 69. Fourier Series Least Mean-Square Error Approximation admission.edhole.com
  • 70. Approximation a function k S t a a n t b n t k n n Use = 0 + ( cos w + sin w ) å= 2 n 1 0 0 ( ) to represent f(t) on interval -T/2 < t < T/2. Define (t) f (t) S (t) k k e = - 1 T [ ( )]2 E = / 2 e Mean-Square ò- t dt k T / 2 k T Error admission.edhole.com
  • 71. Approximation a function Show that using Sk(t) to represent f(t) has least mean-square property. 1 T [ ( )]2 = e / 2 ò- t dt k T / 2 k T E n n f t a a n t b n t dt = é - - w + w / 2 ò å( ) - 0 cos sin 2 = ù úû êë / 2 2 1 0 0 1 T ( ) T k n T Proven by setting ¶Ek/¶ai = 0 and ¶Ek/¶bi = 0. admission.edhole.com
  • 72. Approximation a function 1 T [ ( )]2 = e / 2 ò- t dt k T / 2 k T E n n f t a a n t b n t dt ò å( ) - 0 cos sin 2 = ù úû êë= é - - w + w / 2 / 2 2 1 0 0 1 T ( ) T k n T 1 ( ) 0 E 2 / 2 ( ) cos 0 ¶ ò- 2 / 2 / 2 0 0 = - = ¶ T T k f t dt T a a E ¶ ò- k f t n tdt / 2 0 = - w = ¶ T n T n T a a E ¶ ò- 2 / 2 ( )sin 0 k f t n tdt / 2 0 = - w = ¶ T n T n T b b admission.edhole.com
  • 73. Mean-Square Error 1 T [ ( )]2 = e / 2 ò- t dt k T / 2 k T E n n f t a a n t b n t dt ò å( ) - 0 cos sin 2 T = ò å - ù úû êë= é - - w + w / 2 / 2 2 1 0 0 1 T ( ) T k n = / 2 f t dt - a - 1 a + b k n n = / 2 1 2 2 2 2 0 ( ) 2 4 1 T [ ( )] T k n T E admission.edhole.com
  • 74. Mean-Square Error 1 T [ ( )]2 = e / 2 ò- t dt k T / 2 k T E n n f t a a n t b n t dt ò å( ) - 0 cos sin 2 T = ò å - ù úû êë= é - - w + w / 2 / 2 2 1 0 0 1 T ( ) T k n f t dt a 1 a b n n ³ + + / 2 / 2 = 1 2 2 2 2 0 ( ) 2 4 1 T [ ( )] T k n T admission.edhole.com
  • 75. Mean-Square Error 1 T [ ( )]2 = e / 2 ò- t dt k T / 2 k T E n n f t a a n t b n t dt ò å( ) - 0 cos sin 2 T = ò å - ù úû êë= é - - w + w / 2 / 2 2 1 0 0 1 T ( ) T k n f t dt a 1 ¥ a b n n = + + / 2 / 2 = 1 2 2 2 2 0 ( ) 2 4 1 T [ ( )] T n T