技術動向の調査として、ICML Workshop Uncertainty & Robustness in Deep Learningの中で、面白そうなタイトルを中心に読んで各論文を4スライドでまとめました。
最新版:https://speakerdeck.com/masatoto/icml-2021-workshop-shen-ceng-xue-xi-falsebu-que-shi-xing-nituite-e0debbd2-62a7-4922-a809-cb07c5da2d08(文章を修正しました。)
技術動向の調査として、ICML Workshop Uncertainty & Robustness in Deep Learningの中で、面白そうなタイトルを中心に読んで各論文を4スライドでまとめました。
最新版:https://speakerdeck.com/masatoto/icml-2021-workshop-shen-ceng-xue-xi-falsebu-que-shi-xing-nituite-e0debbd2-62a7-4922-a809-cb07c5da2d08(文章を修正しました。)
[論文紹介] Understanding and improving transformer from a multi particle dynamic ...Makoto Takenaka
・本資料は下記イベントにおける第三者による論文紹介用資料です。
・間違い等のご指摘は @functionalaho までお願いします。
・イベント情報
https://lpixel.connpass.com/event/135045/
・紹介論文
Yiping Lu et al. "Understanding and Improving Transformer From a Multi-Particle Dynamic System Point of View"
https://arxiv.org/abs/1906.02762
[論文紹介] Understanding and improving transformer from a multi particle dynamic ...Makoto Takenaka
・本資料は下記イベントにおける第三者による論文紹介用資料です。
・間違い等のご指摘は @functionalaho までお願いします。
・イベント情報
https://lpixel.connpass.com/event/135045/
・紹介論文
Yiping Lu et al. "Understanding and Improving Transformer From a Multi-Particle Dynamic System Point of View"
https://arxiv.org/abs/1906.02762
JSSC holds certification exam of ability for statistics since 2011. Grade 2 is provided mainly for freshmen and sophomores. I introduced the level of this exam and solved acutual exam questions with R in Tokyo.R #49.
Peter Martin – How to Double Your Internet Closing Ratio in 90 DaysSean Bradley
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your sales in 90 days or less.
This slide was presented in Tokyo.R #22.It describes about design of experiment with R. DoE.base package is useful for software testing because it makes easier for us to make orthogonal array.
20. Rでやってみる
> 心理学テスト<-c(13,14,7,12,10,6,8,15,4,14,9,6,10,12,5,12,8,8,12,15)
> t.test(心理学テスト,mu=12)
One Sample t-test
data: 心理学テスト
t = -2.6166, df = 19, p-value = 0.01697
alternative hypothesis: true mean is not equal to 12
95 percent confidence interval:
8.400225 11.599775
sample estimates:
mean of x
10
31. 2 2分割表で期待度数が小さい場合には
χ二乗検定ではなく
フィッシャーの正確確率検定を用いるべし!
統計嫌い 統計好き 計
数学嫌い a b e e Ca ⇤ f Cc e!f !g!h!
P = =
n Cg n!a!b!c!d!
数学好き c d f
計 g h n
デメリット:階乗を含むので計算が大変
32. 周辺度数を固定したままセル内の人数を変え、
それぞれの確率を計算する
a b c d P
0.4
① 12 2 0 6 0.0007223942
② 11 3 1 5 0.01733746 0.3
③ 10 4 2 4 0.119195
④ 9 5 3 3 0.3178535 0.2
⑤ 8 6 4 2 0.3575851
0.1
⑥ 7 7 5 1 0.1634675
⑦ 6 8 6 0 0.02383901 0
① ② ③ ④ ⑤ ⑥ ⑦
計 1
パターン③と、それより確率の低い
パターン①,②,⑦のPを足し合わせる(両側検定)
p 0.16109
33. Rでやってみる
> A <- matrix(c(10,2,4,4),ncol=2,byrow=FALSE)
>
> fisher.test(A)
Fisher's Exact Test for Count Data
data: A
p-value = 0.1611
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
0.4459581 70.7319343
sample estimates:
odds ratio
4.565523