WELCOME
TO
MATHEMATICS 7
CLASS
QUARTER 3
WEEK 2
At the end of the
lesson, you must
be able to:
Differentiate algebraic expression,
equation and inequalities
Finds the Solution of a Linear
inequality in one variable
LINEAR INEQUALITIES
AND LINEAR EQUATION
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
is an algebraic expression related by
< “is less than,”
≤ “is less than or equal to,”
> “is greater than,” or
≥ “is greater than or equal
to.”
LINEAR EQUATION
is an algebraic expression related by
= “ is equal to”
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
is a statement that shows two
numbers or expressions that are
not equal.
Example: 𝟓 > 𝟑
𝟐𝒙 ≤ −𝟔
LINEAR EQUATION
◦ is a statement that shows two
numbers or expressions that are
equal.
◦ Example: x – 2 = 8
2y + 3 = 5
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
Solution of an inequality
◦ is a value of the variable that makes the
inequality true.
◦ Example: 𝑥 ≤ −3is a solution to the
inequality 2𝑥 ≤ −6
LINEAR EQUATION
Solution of an equality
◦ Is a value of a variable that makes the
equation true.
◦ Example: x = 2 is a solution of
2x = 4, because if we substitute 2 in the
equation 2x = 4 then, 2(2) = 4 which is
◦ 4 = 4 (true)
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
Solution set
◦ is the set of all solutions
◦ Example: {−3, −4, −5, −6, −7, … } this set
is a solution set of
2𝑥 ≤ −6
x ≤ −3
◦ If all negative integers x ≤ −3
Is written inside the braces, then it is called
a solution set.
LINEAR EQUATION
Solution set
◦ is the set of all solutions. Finding the
solutions of an equation is also called
solving the equation.
◦ Example: {2} is a solution set of 2x = 4
◦ If x = 2 is written inside the braces, then it
is called a solution set.
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
Solution set
◦ is the set of all solutions
◦ Example: {−3, −4, −5, −6, −7, … } this set is a
solution set of 2𝑥 ≤ −6
x ≤ −3
◦ If all negative integers x ≤ −3
Is written inside the braces, then it is called a
solution set.
◦ written in set notation using braces, { }. Solutions
may be given in set notation, or they may be
given in the form x = a certain real number
◦ {𝑥: 𝑥 ≤ −3}
LINEAR EQUATION
Solution set
◦ is the set of all solutions. Finding the solutions of an
equation is also called solving the equation.
◦ Example: {2} is a solution set of 2x = 4
◦ If x = 2 is written inside the braces, then it is called
a solution set.
◦ are written in set notation using braces, { }.
Solutions may be given in set notation, or they may
be given in the form x = n, where n is a real
number.
◦ {xIx = 2}
LINEAR INEQUALITIES vs LINEAR
EQUATION
LINEAR INEQUALITIES
◦ ILLUSTRATING LINEAR INEQUALITY in a
Number Line
{ 𝑚: 𝑚 < 8 }
The graph of the solution set 𝑚 < 8
LINEAR EQUATION
◦ ILLUSTRATING LINEAR EQUALITY in a Number
Line
The graph of 2x-8=3(x+5)
x= -23
{x:x = -23}
SOLVING LINEAR
INEQUALITIES
Addition and Subtraction Properties of Inequality
Addition Property of Inequality: You can add the same
number to both sides of an inequality and the statement
will still be true.
In numbers:
3 < 8
3 + 2 < 8 + 2
5 < 10
In Algebra:
𝑎 < 𝑏
𝑎 + 𝑐 < 𝑏 + 𝑐
Addition and Subtraction Properties of Inequality
Subtraction Property of Inequality: You can subtract
same number to both sides of an inequality and
statement will still be true.
In numbers:
3 < 8
3 − 2 < 8 − 2
1 < 6
In Algebra:
𝑎 < 𝑏
𝑎 − 𝑐 < 𝑏 – 𝑐
Solve the inequality 𝑚 + 12 < 20
𝒎 + 𝟏𝟐 < 𝟐𝟎
−𝟏𝟐 − 𝟏𝟐
Since 𝟏𝟐 is added to 𝒎,
subtract 12 both sides of the
inequality to undo the
𝒎 + 𝟎 < 𝟖 Simplify
𝒎 < 𝟖 Solution of the inequality
The solution set is { 𝒎: 𝒎 < 𝟖 }, read as, “𝒎 such that 𝒎 is less than 𝟖”.
𝒎 + 𝟏𝟐 < 𝟐𝟎 The given inequality
Solve the inequality 𝑏 – 5 > −7 and graph the solutions.
𝒃 – 𝟓 > −𝟕 The given inequality
𝒃 – 𝟓 > −𝟕
+𝟓 + 𝟓
Since 𝟓 is subtracted from 𝒃, add
𝟓 on both sides of the inequality
to undo the subtraction.
𝒃 + 𝟎 > −𝟐 Simplify
𝒃 > −𝟐 Solution of the inequality
𝒃 > −𝟐 is the solution of the inequality 𝒃 – 𝟓 > −𝟕
The solution set is {𝑏: 𝑏 > − 2}
◦ GRAPH
Solve the inequality 𝑡 + 1 ≤ 10
𝑡 + 1 ≤ 10 Write the inequality
𝑡 + 1 ≤ 10
−1 − 1
Since 1 is added to 𝑡, subtract 1
from both sides of the equation to
undo the addition.
𝑡 + 0 ≤ 9 Simplify
𝑡 ≤ 9 Solution of the inequality
𝑡 ≤ 9 is the solution of the inequality 𝑡 + 1 ≤ 10.
The solution set is {𝑡: 𝑡 ≤ 9}
◦ GRAPH
Multiplication and Division Property of Inequality
Multiplication Property of Inequality:
You can multiply both sides of an inequality by the same
number, and the statement will still be true.
In numbers:
7 < 12
7 3 < 12 3
21 < 36
In Algebra:
𝐼𝑓 𝑎 < 𝑏 𝑎𝑛𝑑 𝑐 > 0
𝑡ℎ𝑒𝑛 𝑎𝑐 < 𝑏𝑐
Multiplication and Division Property of Inequality
Division Property of Inequality:
You can multiply both sides of an inequality by the same
positive
number, and the statement will still be true.
In numbers:
15 < 35
15
5
<
35
5
3 < 7
In Algebra:
If 𝑎 < 𝑏 𝑎𝑛𝑑 𝑐 > 0
Then,
𝑎
𝑐
<
𝑏
𝑐
Solve the inequality 7𝑎 > −42
𝟕𝒂 > −𝟒𝟐 The given inequality
𝟕𝒂
𝟕
>
−𝟒𝟐
𝟕
Since 𝒂 is multiplied by 𝟕, divide
both sides by 𝟕 to undo the
multiplication operation.
𝟕𝒂
𝟕
>
−𝟒𝟐
𝟕
𝟏𝒂 > −𝟔
7 divided by 7 is 1; −𝟒𝟐 divided by
is −𝟔.
Note: The coefficient 1 does not necessarily be
written. Hence, the final solution shown below.
𝒂 > −𝟔 Solution of the inequality
𝒂 > −𝟔 is the solution of the inequality 𝟕𝒂 > −𝟒𝟐.
The solution set is {𝑎: 𝑎 > −6}
◦ GRAPH
Solve the inequality
3
4
𝑠 < 12
𝟑
𝟒
𝒔 < 𝟏𝟐
The given inequality
𝟒
𝟑
𝟑
𝟒
𝒔 < 𝟏𝟐
𝟒
𝟑
Since 𝒔 is multiplied by
𝟑
𝟒
, multiply
both sides by the reciprocal of
𝟑
𝟒
, which is
𝟒
𝟑
.
𝟏𝟐
𝟏𝟐
𝒔 <
𝟒𝟖
𝟑
𝟏𝒔 < 𝟏𝟔
Perform the operation on the left and the right of the
inequality symbol and simplify.
Note: The coefficient 1 does not necessarily be written. Hence, the final
shown below.
𝒔 < 𝟏𝟔 Solution of the inequality
𝒔 < 𝟏𝟔 is the solution of the inequality
𝟑
𝟒
𝒔 < 𝟏𝟐.
The solution set is {𝑠: 𝑠 < 16}
◦ GRAPH
Solve the inequality 4𝑐 > 24
4𝑐 > 24 The given inequality
4𝑐
4
>
24
4
Since 𝑐 is multiplied by 4, divide both sides
by 4 to undo multiplication.
4𝑐
4
>
24
4
1𝑐 > 6
4 divided by 4 is 1; 24 divided by 4 is 6.
Note: The coefficient 1 does not necessarily be written. Hence,
the final solution shown below.
𝑐 > 6 Solution of the inequality
𝑐 > 6 is the solution of the inequality 4𝑐 > 24.
The solution set is {c: c> 6}
Multiplication or Division of Negative Numbers on Inequalities
◦If you multiply or divide both sides of an
inequality by a negative number, flip or
reverse the direction of the inequality sign.
Solve the inequality −12𝑎 > 84
−12𝑎 > 84 The given Inequality
−12𝑎
−12
<
84
−12
Since 𝑎 is multiplied by −12, divide both sides by -
12 to undo multiplication. Then, change greater
than “>” to less than “<”.
−12𝑎
−12
<
84
−12
1𝑎 < −7
−12 divided by −12 is 1;
84 divided by −12 is −7.
Note: The coefficient 1 does not necessarily be written. Hence, the final
solution shown below.
𝑎 < −7 Solution of the inequality
𝑎 < −7 is the solution of the inequality −12𝑎 > 84.
The solution set is {𝑎: 𝑎 < −7}
Solve the inequality
𝑏
−3
≥ −8
𝑏
−3
≥ −8
The given inequality
−3
𝑏
−3
≤ −8 (−3)
Since 𝑏 is divided by −3, multiply both sides by −3
to undo division. Then, change greater than or equal
“≥” to less than or equal “≤”.
−3
𝑏
−3
≤ −8(−3)
1𝑏 ≤ 24
−3 divided by −3 is 1; −8 multiplied by −3 is 24.
𝑏 ≤ 24 Solution of the inequality
𝑏 ≤ 24 is the solution of the inequality
𝑏
−3
≥ −8.
The solution set is {𝑏: 𝑏 ≤ 24}
Solve the inequality − 𝑐 ≤ 10
− 𝑐 ≤ 10 The given inequality
(−1)(− 𝑐) ≥ 10(−1)
Multiply both sides by −1 to make 𝑐 positive.
Then, change less than or equal “≤” to greater
than or equal“≥”.
𝑐 ≥ −10 Solution of the inequality
𝑐 ≥ −10 is the solution of the inequality − 𝑐 ≤ 10
The solution set is {𝑐: 𝑐 ≥ −10}
ANSWER ACTIVITY
1. ANSWER ACTIVITY 3: EQUATION AND
INEQUALITY P. 96 (EDMODO)
2. ACTIVITY 5: FALL-ING FOR EQUALITIES
P.97(EDMODO)
3. OTHER ACTIVITY TO BE SENT AFTER THE
EDMODO ACTIVITY.(DROP IN THE DRIVE AND
ATTACH IN THE WEEKLY ACCOMPLISHMENT)
SEE NEXT SLIDES FOR ACTIVITY 3
ACTIVITY 3:
A. Solve the following Linear Inequalities. (show your complete steps)
B. Find the solution sets by set builder notation
C. Graph the solution set.
1.2(5x – 3) > 14
2.12x – 6 > 14x – 2
3.12 – ⅔ x > 6
4.3/5 x + 9 < 12
5.8(5x – 4) – 6(3x + 5) < -7
THANK YOU FOR
LISTENING!
SEE
YOU
AGAIN
NEXT
WEEK!

2.-Linear-Equation-and-Inequalities-Copy2.pptx

  • 1.
  • 2.
    At the endof the lesson, you must be able to: Differentiate algebraic expression, equation and inequalities Finds the Solution of a Linear inequality in one variable
  • 3.
  • 4.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES is an algebraic expression related by < “is less than,” ≤ “is less than or equal to,” > “is greater than,” or ≥ “is greater than or equal to.” LINEAR EQUATION is an algebraic expression related by = “ is equal to”
  • 5.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES is a statement that shows two numbers or expressions that are not equal. Example: 𝟓 > 𝟑 𝟐𝒙 ≤ −𝟔 LINEAR EQUATION ◦ is a statement that shows two numbers or expressions that are equal. ◦ Example: x – 2 = 8 2y + 3 = 5
  • 6.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES Solution of an inequality ◦ is a value of the variable that makes the inequality true. ◦ Example: 𝑥 ≤ −3is a solution to the inequality 2𝑥 ≤ −6 LINEAR EQUATION Solution of an equality ◦ Is a value of a variable that makes the equation true. ◦ Example: x = 2 is a solution of 2x = 4, because if we substitute 2 in the equation 2x = 4 then, 2(2) = 4 which is ◦ 4 = 4 (true)
  • 7.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES Solution set ◦ is the set of all solutions ◦ Example: {−3, −4, −5, −6, −7, … } this set is a solution set of 2𝑥 ≤ −6 x ≤ −3 ◦ If all negative integers x ≤ −3 Is written inside the braces, then it is called a solution set. LINEAR EQUATION Solution set ◦ is the set of all solutions. Finding the solutions of an equation is also called solving the equation. ◦ Example: {2} is a solution set of 2x = 4 ◦ If x = 2 is written inside the braces, then it is called a solution set.
  • 8.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES Solution set ◦ is the set of all solutions ◦ Example: {−3, −4, −5, −6, −7, … } this set is a solution set of 2𝑥 ≤ −6 x ≤ −3 ◦ If all negative integers x ≤ −3 Is written inside the braces, then it is called a solution set. ◦ written in set notation using braces, { }. Solutions may be given in set notation, or they may be given in the form x = a certain real number ◦ {𝑥: 𝑥 ≤ −3} LINEAR EQUATION Solution set ◦ is the set of all solutions. Finding the solutions of an equation is also called solving the equation. ◦ Example: {2} is a solution set of 2x = 4 ◦ If x = 2 is written inside the braces, then it is called a solution set. ◦ are written in set notation using braces, { }. Solutions may be given in set notation, or they may be given in the form x = n, where n is a real number. ◦ {xIx = 2}
  • 9.
    LINEAR INEQUALITIES vsLINEAR EQUATION LINEAR INEQUALITIES ◦ ILLUSTRATING LINEAR INEQUALITY in a Number Line { 𝑚: 𝑚 < 8 } The graph of the solution set 𝑚 < 8 LINEAR EQUATION ◦ ILLUSTRATING LINEAR EQUALITY in a Number Line The graph of 2x-8=3(x+5) x= -23 {x:x = -23}
  • 10.
  • 11.
    Addition and SubtractionProperties of Inequality Addition Property of Inequality: You can add the same number to both sides of an inequality and the statement will still be true. In numbers: 3 < 8 3 + 2 < 8 + 2 5 < 10 In Algebra: 𝑎 < 𝑏 𝑎 + 𝑐 < 𝑏 + 𝑐
  • 12.
    Addition and SubtractionProperties of Inequality Subtraction Property of Inequality: You can subtract same number to both sides of an inequality and statement will still be true. In numbers: 3 < 8 3 − 2 < 8 − 2 1 < 6 In Algebra: 𝑎 < 𝑏 𝑎 − 𝑐 < 𝑏 – 𝑐
  • 13.
    Solve the inequality𝑚 + 12 < 20 𝒎 + 𝟏𝟐 < 𝟐𝟎 −𝟏𝟐 − 𝟏𝟐 Since 𝟏𝟐 is added to 𝒎, subtract 12 both sides of the inequality to undo the 𝒎 + 𝟎 < 𝟖 Simplify 𝒎 < 𝟖 Solution of the inequality The solution set is { 𝒎: 𝒎 < 𝟖 }, read as, “𝒎 such that 𝒎 is less than 𝟖”. 𝒎 + 𝟏𝟐 < 𝟐𝟎 The given inequality
  • 14.
    Solve the inequality𝑏 – 5 > −7 and graph the solutions. 𝒃 – 𝟓 > −𝟕 The given inequality 𝒃 – 𝟓 > −𝟕 +𝟓 + 𝟓 Since 𝟓 is subtracted from 𝒃, add 𝟓 on both sides of the inequality to undo the subtraction. 𝒃 + 𝟎 > −𝟐 Simplify 𝒃 > −𝟐 Solution of the inequality 𝒃 > −𝟐 is the solution of the inequality 𝒃 – 𝟓 > −𝟕
  • 15.
    The solution setis {𝑏: 𝑏 > − 2} ◦ GRAPH
  • 16.
    Solve the inequality𝑡 + 1 ≤ 10 𝑡 + 1 ≤ 10 Write the inequality 𝑡 + 1 ≤ 10 −1 − 1 Since 1 is added to 𝑡, subtract 1 from both sides of the equation to undo the addition. 𝑡 + 0 ≤ 9 Simplify 𝑡 ≤ 9 Solution of the inequality 𝑡 ≤ 9 is the solution of the inequality 𝑡 + 1 ≤ 10.
  • 17.
    The solution setis {𝑡: 𝑡 ≤ 9} ◦ GRAPH
  • 18.
    Multiplication and DivisionProperty of Inequality Multiplication Property of Inequality: You can multiply both sides of an inequality by the same number, and the statement will still be true. In numbers: 7 < 12 7 3 < 12 3 21 < 36 In Algebra: 𝐼𝑓 𝑎 < 𝑏 𝑎𝑛𝑑 𝑐 > 0 𝑡ℎ𝑒𝑛 𝑎𝑐 < 𝑏𝑐
  • 19.
    Multiplication and DivisionProperty of Inequality Division Property of Inequality: You can multiply both sides of an inequality by the same positive number, and the statement will still be true. In numbers: 15 < 35 15 5 < 35 5 3 < 7 In Algebra: If 𝑎 < 𝑏 𝑎𝑛𝑑 𝑐 > 0 Then, 𝑎 𝑐 < 𝑏 𝑐
  • 20.
    Solve the inequality7𝑎 > −42 𝟕𝒂 > −𝟒𝟐 The given inequality 𝟕𝒂 𝟕 > −𝟒𝟐 𝟕 Since 𝒂 is multiplied by 𝟕, divide both sides by 𝟕 to undo the multiplication operation. 𝟕𝒂 𝟕 > −𝟒𝟐 𝟕 𝟏𝒂 > −𝟔 7 divided by 7 is 1; −𝟒𝟐 divided by is −𝟔. Note: The coefficient 1 does not necessarily be written. Hence, the final solution shown below. 𝒂 > −𝟔 Solution of the inequality 𝒂 > −𝟔 is the solution of the inequality 𝟕𝒂 > −𝟒𝟐.
  • 21.
    The solution setis {𝑎: 𝑎 > −6} ◦ GRAPH
  • 22.
    Solve the inequality 3 4 𝑠< 12 𝟑 𝟒 𝒔 < 𝟏𝟐 The given inequality 𝟒 𝟑 𝟑 𝟒 𝒔 < 𝟏𝟐 𝟒 𝟑 Since 𝒔 is multiplied by 𝟑 𝟒 , multiply both sides by the reciprocal of 𝟑 𝟒 , which is 𝟒 𝟑 . 𝟏𝟐 𝟏𝟐 𝒔 < 𝟒𝟖 𝟑 𝟏𝒔 < 𝟏𝟔 Perform the operation on the left and the right of the inequality symbol and simplify. Note: The coefficient 1 does not necessarily be written. Hence, the final shown below. 𝒔 < 𝟏𝟔 Solution of the inequality 𝒔 < 𝟏𝟔 is the solution of the inequality 𝟑 𝟒 𝒔 < 𝟏𝟐.
  • 23.
    The solution setis {𝑠: 𝑠 < 16} ◦ GRAPH
  • 24.
    Solve the inequality4𝑐 > 24 4𝑐 > 24 The given inequality 4𝑐 4 > 24 4 Since 𝑐 is multiplied by 4, divide both sides by 4 to undo multiplication. 4𝑐 4 > 24 4 1𝑐 > 6 4 divided by 4 is 1; 24 divided by 4 is 6. Note: The coefficient 1 does not necessarily be written. Hence, the final solution shown below. 𝑐 > 6 Solution of the inequality 𝑐 > 6 is the solution of the inequality 4𝑐 > 24.
  • 25.
    The solution setis {c: c> 6}
  • 26.
    Multiplication or Divisionof Negative Numbers on Inequalities ◦If you multiply or divide both sides of an inequality by a negative number, flip or reverse the direction of the inequality sign.
  • 27.
    Solve the inequality−12𝑎 > 84 −12𝑎 > 84 The given Inequality −12𝑎 −12 < 84 −12 Since 𝑎 is multiplied by −12, divide both sides by - 12 to undo multiplication. Then, change greater than “>” to less than “<”. −12𝑎 −12 < 84 −12 1𝑎 < −7 −12 divided by −12 is 1; 84 divided by −12 is −7. Note: The coefficient 1 does not necessarily be written. Hence, the final solution shown below. 𝑎 < −7 Solution of the inequality 𝑎 < −7 is the solution of the inequality −12𝑎 > 84.
  • 28.
    The solution setis {𝑎: 𝑎 < −7}
  • 29.
    Solve the inequality 𝑏 −3 ≥−8 𝑏 −3 ≥ −8 The given inequality −3 𝑏 −3 ≤ −8 (−3) Since 𝑏 is divided by −3, multiply both sides by −3 to undo division. Then, change greater than or equal “≥” to less than or equal “≤”. −3 𝑏 −3 ≤ −8(−3) 1𝑏 ≤ 24 −3 divided by −3 is 1; −8 multiplied by −3 is 24. 𝑏 ≤ 24 Solution of the inequality 𝑏 ≤ 24 is the solution of the inequality 𝑏 −3 ≥ −8.
  • 30.
    The solution setis {𝑏: 𝑏 ≤ 24}
  • 31.
    Solve the inequality− 𝑐 ≤ 10 − 𝑐 ≤ 10 The given inequality (−1)(− 𝑐) ≥ 10(−1) Multiply both sides by −1 to make 𝑐 positive. Then, change less than or equal “≤” to greater than or equal“≥”. 𝑐 ≥ −10 Solution of the inequality 𝑐 ≥ −10 is the solution of the inequality − 𝑐 ≤ 10
  • 32.
    The solution setis {𝑐: 𝑐 ≥ −10}
  • 33.
    ANSWER ACTIVITY 1. ANSWERACTIVITY 3: EQUATION AND INEQUALITY P. 96 (EDMODO) 2. ACTIVITY 5: FALL-ING FOR EQUALITIES P.97(EDMODO) 3. OTHER ACTIVITY TO BE SENT AFTER THE EDMODO ACTIVITY.(DROP IN THE DRIVE AND ATTACH IN THE WEEKLY ACCOMPLISHMENT) SEE NEXT SLIDES FOR ACTIVITY 3
  • 34.
    ACTIVITY 3: A. Solvethe following Linear Inequalities. (show your complete steps) B. Find the solution sets by set builder notation C. Graph the solution set. 1.2(5x – 3) > 14 2.12x – 6 > 14x – 2 3.12 – ⅔ x > 6 4.3/5 x + 9 < 12 5.8(5x – 4) – 6(3x + 5) < -7
  • 35.