1 of 39

## What's hot

1.4 complex numbers t
1.4 complex numbers tmath260

Weekly Dose 1 - Maths Olympiad Practice
Weekly Dose 1 - Maths Olympiad PracticeKathleen Ong

Η έννοια του κλάσματος
Η έννοια του κλάσματοςteaghet

3c. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.3)
3c. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.3)Dr. I. Uma Maheswari Maheswari

Solving Equations Transformable to Quadratic Equation Including Rational Alge...
Solving Equations Transformable to Quadratic Equation Including Rational Alge...Cipriano De Leon

Mathematics Form 1-Chapter 3 Squares, Square Roots, Cubes and Cube Roots KBSM...
Mathematics Form 1-Chapter 3 Squares, Square Roots, Cubes and Cube Roots KBSM...KelvinSmart2

Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...KelvinSmart2

Section 3.5 inequalities involving quadratic functions
Section 3.5 inequalities involving quadratic functions Wong Hsiung

Maths lesson1
Maths lesson1deepap25

Nature of the roots and sum and product of the roots of a quadratic equation
Nature of the roots and sum and product of the roots of a quadratic equationCipriano De Leon

Weekly Dose 3 - Maths Olympiad Practice
Weekly Dose 3 - Maths Olympiad PracticeKathleen Ong

Algebra Project Period 4
Algebra Project Period 4ingroy

3b. Pedagogy of Mathematics (Part II) - (Algebra Ex 3.2)
3b. Pedagogy of Mathematics (Part II) - (Algebra Ex 3.2)Dr. I. Uma Maheswari Maheswari

Class 10 arithmetic_progression_cbse_test_paper-2
Class 10 arithmetic_progression_cbse_test_paper-2dinesh reddy

Pythagorean theorem and distance formula
Pythagorean theorem and distance formula41878010

Section 1.4 circles
Section 1.4 circles Wong Hsiung

### What's hot(19)

1.4 complex numbers t
1.4 complex numbers t

Chapter 03 matrices
Chapter 03 matrices

Weekly Dose 1 - Maths Olympiad Practice
Weekly Dose 1 - Maths Olympiad Practice

Η έννοια του κλάσματος
Η έννοια του κλάσματος

3c. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.3)
3c. Pedagogy of Mathematics (Part II) - Algebra (Ex 3.3)

Solving Equations Transformable to Quadratic Equation Including Rational Alge...
Solving Equations Transformable to Quadratic Equation Including Rational Alge...

Mathematics Form 1-Chapter 3 Squares, Square Roots, Cubes and Cube Roots KBSM...
Mathematics Form 1-Chapter 3 Squares, Square Roots, Cubes and Cube Roots KBSM...

Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...
Mathematics Form 1-Chapter 5-6 Algebraic Expression Linear Equations KBSM of ...

Algebra
Algebra

Elements of a sequence
Elements of a sequence

Section 3.5 inequalities involving quadratic functions
Section 3.5 inequalities involving quadratic functions

Maths lesson1
Maths lesson1

Nature of the roots and sum and product of the roots of a quadratic equation
Nature of the roots and sum and product of the roots of a quadratic equation

Weekly Dose 3 - Maths Olympiad Practice
Weekly Dose 3 - Maths Olympiad Practice

Algebra Project Period 4
Algebra Project Period 4

3b. Pedagogy of Mathematics (Part II) - (Algebra Ex 3.2)
3b. Pedagogy of Mathematics (Part II) - (Algebra Ex 3.2)

Class 10 arithmetic_progression_cbse_test_paper-2
Class 10 arithmetic_progression_cbse_test_paper-2

Pythagorean theorem and distance formula
Pythagorean theorem and distance formula

Section 1.4 circles
Section 1.4 circles

## Similar to 2f. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.6)

Arithmetic progressions
Arithmetic progressionsDr. Nirav Vyas

ArithmeticProgression
ArithmeticProgression Prashant Jain

Question and Solutions Exponential.pdf
Question and Solutions Exponential.pdferbisyaputra

Arithmetic progression ex no. 4
Arithmetic progression ex no. 4AMIN BUHARI

Task compilation - Differential Equation II
Task compilation - Differential Equation IIJazz Michele Pasaribu

2018 mtap for g10 with answers
2018 mtap for g10 with answersJashey Dee

Pembahasan ujian nasional matematika ipa sma 2013
Pembahasan ujian nasional matematika ipa sma 2013mardiyanto83

2014 st josephs geelong spec maths
2014 st josephs geelong spec mathsAndrew Smith

Quantitative techniques for MBA (QDM)
Quantitative techniques for MBA (QDM)npazare

Diagram Venn Beserta Contoh Soal
Diagram Venn Beserta Contoh SoalEman Mendrofa

Teoría y problemas de Sumatorias II PS25 ccesa007
Teoría y problemas de Sumatorias II PS25 ccesa007Demetrio Ccesa Rayme

### Similar to 2f. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.6)(20)

Arithmetic progressions
Arithmetic progressions

mathematics part-2.docx
mathematics part-2.docx

Smart sol
Smart sol

Smart sol
Smart sol

ArithmeticProgression
ArithmeticProgression

Question and Solutions Exponential.pdf
Question and Solutions Exponential.pdf

Arithmetic progression ex no. 4
Arithmetic progression ex no. 4

Task compilation - Differential Equation II
Task compilation - Differential Equation II

Arithmetic series
Arithmetic series

2018 mtap for g10 with answers
2018 mtap for g10 with answers

Pembahasan ujian nasional matematika ipa sma 2013
Pembahasan ujian nasional matematika ipa sma 2013

Fismat chapter 4
Fismat chapter 4

Chapter 2 sequencess and series
Chapter 2 sequencess and series

Tugas 5.3 kalkulus integral
Tugas 5.3 kalkulus integral

Ch9 SL3 ODE-BVP.pptx
Ch9 SL3 ODE-BVP.pptx

aapp.pdf
aapp.pdf

2014 st josephs geelong spec maths
2014 st josephs geelong spec maths

Quantitative techniques for MBA (QDM)
Quantitative techniques for MBA (QDM)

Diagram Venn Beserta Contoh Soal
Diagram Venn Beserta Contoh Soal

Teoría y problemas de Sumatorias II PS25 ccesa007
Teoría y problemas de Sumatorias II PS25 ccesa007

## More from Dr. I. Uma Maheswari Maheswari

2h. Pedagogy of mathematics part II (numbers and sequence - ex 2.8)
2h. Pedagogy of mathematics part II (numbers and sequence - ex 2.8)Dr. I. Uma Maheswari Maheswari

2c. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.3)
2c. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.3)Dr. I. Uma Maheswari Maheswari

2a. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.1)
2a. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.1)Dr. I. Uma Maheswari Maheswari

X std maths - Relations and functions (ex 1.5 &amp; 1.6)
X std maths - Relations and functions (ex 1.5 &amp; 1.6)Dr. I. Uma Maheswari Maheswari

Computers in Education - Information and communication technologies
Computers in Education - Information and communication technologiesDr. I. Uma Maheswari Maheswari

### More from Dr. I. Uma Maheswari Maheswari(20)

2h. Pedagogy of mathematics part II (numbers and sequence - ex 2.8)
2h. Pedagogy of mathematics part II (numbers and sequence - ex 2.8)

2c. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.3)
2c. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.3)

2a. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.1)
2a. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.1)

Computer language - Html forms
Computer language - Html forms

computer language - Html frames
computer language - Html frames

Computer language - Html tables
Computer language - Html tables

Pedagogy - teaching models
Pedagogy - teaching models

Computer language - html images and sounds
Computer language - html images and sounds

computer language - html lists
computer language - html lists

Computer language - HTML tags
Computer language - HTML tags

Computer language - HTML (Hyper Text Markup Language)
Computer language - HTML (Hyper Text Markup Language)

X std maths - Relations and functions (ex 1.5 &amp; 1.6)
X std maths - Relations and functions (ex 1.5 &amp; 1.6)

X std maths - Relations and functions (ex 1.4)
X std maths - Relations and functions (ex 1.4)

X std maths - Relations and functions (ex 1.3)
X std maths - Relations and functions (ex 1.3)

X std mathematics - Relations and functions (Ex 1.2)
X std mathematics - Relations and functions (Ex 1.2)

X std maths - Relations and functions (ex 1.1)
X std maths - Relations and functions (ex 1.1)

Computers in education - cyber resources
Computers in education - cyber resources

Computers in Education - Internet
Computers in Education - Internet

Computers in Education - Information and communication technologies
Computers in Education - Information and communication technologies

BỘ LUYỆN NGHE TIẾNG ANH 8 GLOBAL SUCCESS CẢ NĂM (GỒM 12 UNITS, MỖI UNIT GỒM 3...
BỘ LUYỆN NGHE TIẾNG ANH 8 GLOBAL SUCCESS CẢ NĂM (GỒM 12 UNITS, MỖI UNIT GỒM 3...Nguyen Thanh Tu Collection

ANTI PARKISON DRUGS.pptx
ANTI PARKISON DRUGS.pptxPoojaSen20

MOOD STABLIZERS DRUGS.pptx
MOOD STABLIZERS DRUGS.pptxPoojaSen20

The Ball Poem- John Berryman_20240518_001617_0000.pptx
The Ball Poem- John Berryman_20240518_001617_0000.pptxNehaChandwani11

diagnosting testing bsc 2nd sem.pptx....
diagnosting testing bsc 2nd sem.pptx....Ritu480198

TỔNG HỢP HƠN 100 ĐỀ THI THỬ T﻿ỐT NGHIỆP THPT VẬT LÝ 2024 - TỪ CÁC TRƯỜNG, TRƯ...
TỔNG HỢP HƠN 100 ĐỀ THI THỬ T﻿ỐT NGHIỆP THPT VẬT LÝ 2024 - TỪ CÁC TRƯỜNG, TRƯ...Nguyen Thanh Tu Collection

Envelope of Discrepancy in Orthodontics: Enhancing Precision in Treatment
Envelope of Discrepancy in Orthodontics: Enhancing Precision in Treatmentsaipooja36

II BIOSENSOR PRINCIPLE APPLICATIONS AND WORKING II
II BIOSENSOR PRINCIPLE APPLICATIONS AND WORKING IIagpharmacy11

Capitol Tech Univ Doctoral Presentation -May 2024
Capitol Tech Univ Doctoral Presentation -May 2024CapitolTechU

UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024Borja Sotomayor

An Overview of the Odoo 17 Knowledge App
An Overview of the Odoo 17 Knowledge AppCeline George

Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community Partnershipsexpandedwebsite

An overview of the various scriptures in Hinduism
An overview of the various scriptures in HinduismDabee Kamal

BỘ LUYỆN NGHE TIẾNG ANH 8 GLOBAL SUCCESS CẢ NĂM (GỒM 12 UNITS, MỖI UNIT GỒM 3...
BỘ LUYỆN NGHE TIẾNG ANH 8 GLOBAL SUCCESS CẢ NĂM (GỒM 12 UNITS, MỖI UNIT GỒM 3...

ANTI PARKISON DRUGS.pptx
ANTI PARKISON DRUGS.pptx

Including Mental Health Support in Project Delivery, 14 May.pdf
Including Mental Health Support in Project Delivery, 14 May.pdf

MOOD STABLIZERS DRUGS.pptx
MOOD STABLIZERS DRUGS.pptx

IPL Online Quiz by Pragya; Question Set.
IPL Online Quiz by Pragya; Question Set.

The Ball Poem- John Berryman_20240518_001617_0000.pptx
The Ball Poem- John Berryman_20240518_001617_0000.pptx

diagnosting testing bsc 2nd sem.pptx....
diagnosting testing bsc 2nd sem.pptx....

TỔNG HỢP HƠN 100 ĐỀ THI THỬ T﻿ỐT NGHIỆP THPT VẬT LÝ 2024 - TỪ CÁC TRƯỜNG, TRƯ...
TỔNG HỢP HƠN 100 ĐỀ THI THỬ T﻿ỐT NGHIỆP THPT VẬT LÝ 2024 - TỪ CÁC TRƯỜNG, TRƯ...

Word Stress rules esl .pptx
Word Stress rules esl .pptx

Envelope of Discrepancy in Orthodontics: Enhancing Precision in Treatment
Envelope of Discrepancy in Orthodontics: Enhancing Precision in Treatment

II BIOSENSOR PRINCIPLE APPLICATIONS AND WORKING II
II BIOSENSOR PRINCIPLE APPLICATIONS AND WORKING II

Capitol Tech Univ Doctoral Presentation -May 2024
Capitol Tech Univ Doctoral Presentation -May 2024

UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024

An Overview of the Odoo 17 Knowledge App
An Overview of the Odoo 17 Knowledge App

“O BEIJO” EM ARTE .
“O BEIJO” EM ARTE .

Mattingly "AI and Prompt Design: LLMs with Text Classification and Open Source"
Mattingly "AI and Prompt Design: LLMs with Text Classification and Open Source"

Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships

An overview of the various scriptures in Hinduism
An overview of the various scriptures in Hinduism

### 2f. Pedagogy of Mathematics - Part II (Numbers and Sequence - Ex 2.6)

• 1. BY Dr. I. UMA MAHESWARI Principal Peniel Rural College of Education,Vemparali, Dindigul District iuma_maheswari@yahoo.co.in
• 3.
• 4.
• 5.
• 6.
• 7.
• 8.
• 9.
• 10.
• 11.
• 12.
• 13.
• 14.
• 15.
• 16. Solution: (i) 3, 7, 11,. . . upto 40 terms. a = 3, d = t2 – t1 = 7 – 3 = 4 n = 40 Sn = n/2 (2a + (n – 1)d) S40 = 20/2 (2× 3 + 39d) = 20(6 + 39 × 4) = 20(6 + 156) = 20 × 162 = 3240
• 17. (ii) 102, 97, 952,… up to 27 terms a = 102, d = t2 – t1 = 97 – 102 = -5 n = 27
• 18. (iii) 6 + 13 + 20 + … + 97 a = 6,d = 7, l = 97
• 19. Answer: 5,7,9, 11, 13,… Sn = 480 a = 5, d = 2, Sn = 480
• 20. 2n2 + 8n – 960 = 0 ⇒ n2 + 4n – 480 = 0 ⇒ n2 + 24n – 20n – 480 = 0 ⇒ n(n + 24) – 20(n + 24) = 0 ⇒ (n – 20)(n + 24) = 0 ⇒ n = 20,-24 No. of terms cannot be -ve. ∴ No. of consecutive odd integers beginning with 5 will sum to 480 is 20.
• 21. Answer: Number of terns (n) = 28 tn = 4n – 3 t1 = 4(1) – 3 = 4 – 3 = 1 t2 = 4(2) – 3 = 8 – 3 = 5 t3 = 4(3) – 3 = 12 – 3 = 9 Here a = 1, d = 5 – 1 = 4 S28 = n/2 [2a + (n – 1)d] = 28/2 [2 + (27) (4)] = 14 [2 + 108] = 14 × 110 = 1540 Sum of 28 terms = 1540
• 22. Solution: Given Sn = 2n2 – 3n S1 = 2(1)2 – 3(1) = 2 – 3 = – 1 ⇒ t1 = a = – 1 S2 = 2(22) – 3(2) = 8 – 6 = 2 t2 = S2 – S1 = 2 – (-1) = 3 ∴ d = t2 – t1 = 3 – (-1) = 4 Consider a, a + d, a + 2d, ….…. -1, -1 + 4, -1 + 2(4), …..… -1, 3, 7,…. Clearly this is an A.P with a = – 1, and d = 4.
• 23. Solution: t104 = 125 t4 = 0 a + (n – 1)d = tn
• 24.
• 25. Solution: Sum of all odd positive integers less than 450 is given by 1 + 3 + 5 + … + 449 a = 1 d = 2 l = 449
• 26. = 50625 Another method: Sum of all +ve odd integers = n2. We can use the formula n2 = 2252 = 50625
• 27. Answer: Natural numbers between 602 and 902 603,604, …, 901 a = 603, l = 901, d = 1,
• 28. Sum of all natural numbers between 602 and 902 which are not divisible by 4. = Sum of all natural numbers between 602 and 902 = Sum of all natural numbers between 602 and 902 which are divisible by 4. l = 902 – 2 = 900 To make 602 divisible by 4 we have to add 2 to 602. ∴ 602 + 2 = 604 which is divisible by 4. To make 902 divisible by 4, subtract 2 from 902. ∴ 900 is the last number divisible by 4.
• 29. Sum of all natural numbers between 602 and 902 which are not divisible 4. = 224848 – 56400 = 168448
• 30.
• 31.
• 32. Solution: LoanAmount = ₹ 65,000 Repayment through installments 400 + 700 + 1000 + 1300 + … a = 400 d = 300 Sn = 65000 Sn = n/2 (2a + (n – 1)d) = 65000 (n/2)(2 × 400 + (n – 1)300) = 65000 n(800 + 300n – 300) = 130000 n(500 + 300n) = 130000 500n + 300n2 = 130000
• 33. Number of terms should be (+ve) and cannot be (-ve) or fractional number. ∴ He will take 20 months to clear the loans.
• 34. Answer: Total number of steps = 30 ∴ n = 30 Number of bricks for the bottom = 100 a = 100 2 bricks is less for each step (i) Number of bricks required for the top most step tn = a + (n – 1)d t30 = 100 + 29 (-2) = 100 – 58 = 42
• 35. (ii) Number of bricks required Sn = n/2 [2a + (n-1) d] S30 = 30/2 [200 + 29 (-2)] = 15[200 – 58] = 2130 (i) Number of bricks required for the top most step = 42 bricks (ii) Number of bricks required = 2130
• 37.
Current LanguageEnglish
Español
Portugues
Français
Deutsche