linear inequalities

1. Inequalities

2. Ruler
Besides marking positions, a ruler also defines a direction.
Inequalities

3. Ruler
Besides marking positions, a ruler also defines a direction.
Starting from 0, we define the direction the ruler is extending
to be the positive (+) direction
Inequalities

4. Ruler
Besides marking positions, a ruler also defines a direction.
Starting from 0, we define the direction the ruler is extending
to be the positive (+) direction.
By convention, when a ruler is used horizontally,
the positive (+) direction is to the right.
Inequalities
+
0

5. Ruler
Besides marking positions, a ruler also defines a direction.
Starting from 0, we define the direction the ruler is extending
to be the positive (+) direction.
By convention, when a ruler is used horizontally,
the positive (+) direction is to the right.
So the distance between two horizontal locations L and R,
we subtract: R – L (i.e. Right Point – Left Point).
L R
R – L
Inequalities
+
0

6. Ruler
Besides marking positions, a ruler also defines a direction.
Starting from 0, we define the direction the ruler is extending
to be the positive (+) direction.
By convention, when a ruler is used horizontally,
the positive (+) direction is to the right.
So the distance between two horizontal locations L and R,
we subtract: R – L (i.e. Right Point – Left Point).
L R
R – L
When used vertically, the positive (+) direction is to
the top and the distance between two vertical
locations T and B on a ruler is T – B:
(Top Point – Bottom Point).
0
T
B
T – B
Inequalities
+
+0

7. Ruler
Besides marking positions, a ruler also defines a direction.
Starting from 0, we define the direction the ruler is extending
to be the positive (+) direction.
By convention, when a ruler is used horizontally,
the positive (+) direction is to the right.
So the distance between two horizontal locations L and R,
we subtract: R – L (i.e. Right Point – Left Point).
L R
R – L
When used vertically, the positive (+) direction is to
the top and the distance between two vertical
locations T and B on a ruler is T – B:
(Top Point – Bottom Point).
0
T
B
T – B
Next, we extend the ruler to both directions utilizing
negative numbers to mark the negative (–) direction.
Inequalities
+
+0

8. Inequalities

9. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
Inequalities

10. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
Inequalities

11. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3
Inequalities

12. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½
Inequalities

13. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
Inequalities
–π  –3.14..

14. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
This line with each position addressed by a real number is
called the real (number) line.
Inequalities
–π  –3.14..

15. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
This line with each position addressed by a real number is
called the real (number) line.
Inequalities
–π  –3.14..
Given two numbers corresponding to two points on the real
line, we define the number to the right to be greater than the
number to the left.

16. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
This line with each position addressed by a real number is
called the real (number) line.
Inequalities
+–
RL
–π  –3.14..
Given two numbers corresponding to two points on the real
line, we define the number to the right to be greater than the
number to the left.

17. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
This line with each position addressed by a real number is
called the real (number) line.
Inequalities
+–
R
We write this as L < R and called this the natural form because
it corresponds to their respective positions on the real line.
L
<
–π  –3.14..
Given two numbers corresponding to two points on the real
line, we define the number to the right to be greater than the
number to the left.

18. We associate each real number with a position on a line,
positive numbers to the right and negative numbers to the left.
-2 20 1 3
+
-1-3
–
2/3 2½ π  3.14..
This line with each position addressed by a real number is
called the real (number) line.
Inequalities
+–
R
We write this as L < R and called this the natural form because
it corresponds to their respective positions on the real line.
This relation may also be written as R > L (less preferable).
L
<
–π  –3.14..
Given two numbers corresponding to two points on the real
line, we define the number to the right to be greater than the
number to the left.

19. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
Inequalities

20. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities

21. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x".

22. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a).

23. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
a < x

24. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
If we want all the numbers x greater than or equal to a
(including a), we write it as a < x.
a < x

25. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
If we want all the numbers x greater than or equal to a
(including a), we write it as a < x. In picture
+–
a
solid dot
a < x
a < x

26. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
If we want all the numbers x greater than or equal to a
(including a), we write it as a < x. In picture
+–
a
solid dot
a < x
a < x
The numbers x fit the description a < x < b where a < b are all
the numbers x between a and b.

27. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
If we want all the numbers x greater than or equal to a
(including a), we write it as a < x. In picture
+–
a
solid dot
a < x
a < x
The numbers x fit the description a < x < b where a < b are all
the numbers x between a and b.
+–
a a < x < b b

28. Example A. 2 < 4, –3< –2, 0 > –1 are true statements
and –2 < –5 , 5 < 3 are false statements.
Inequalities
If we want all the numbers greater than 5, we may denote them
as "all number x where 5 < x". In general, we write "a < x" for all
the numbers x greater than a (excluding a). In picture,
+–
a
open dot
If we want all the numbers x greater than or equal to a
(including a), we write it as a < x. In picture
+–
a
solid dot
a < x
a < x
The numbers x fit the description a < x < b where a < b are all
the numbers x between a and b. A line segment as such is
called an interval.
+–
a a < x < b b

29. Example B.
a. Draw –1 < x < 3.
Inequalities

30. Example B.
a. Draw –1 < x < 3.
Inequalities
It’s in the natural form.

31. Example B.
a. Draw –1 < x < 3.
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.

32. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.

33. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.

34. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.

35. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

36. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

37. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Expressions such as 2 < x > 3 or 2 < x < –3 do not have
any solution.
Inequalities
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

38. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Expressions such as 2 < x > 3 or 2 < x < –3 do not have
any solution.
Inequalities
Adding or subtracting the same quantity to both retains the
inequality sign,
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

39. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Expressions such as 2 < x > 3 or 2 < x < –3 do not have
any solution.
Inequalities
Adding or subtracting the same quantity to both retains the
inequality sign, i.e. if a < b, then a ± c < b ± c.
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

40. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Expressions such as 2 < x > 3 or 2 < x < –3 do not have
any solution.
Inequalities
For example 6 < 12, then 6 + 3 < 12 + 3.
Adding or subtracting the same quantity to both retains the
inequality sign, i.e. if a < b, then a ± c < b ± c.
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

41. Example B.
a. Draw –1 < x < 3.
0 3
+
-1
– x
b. Draw 0 > x > –3
0
+
-3
–
x
Expressions such as 2 < x > 3 or 2 < x < –3 do not have
any solution.
Inequalities
For example 6 < 12, then 6 + 3 < 12 + 3.
We use the this fact to solve inequalities.
Adding or subtracting the same quantity to both retains the
inequality sign, i.e. if a < b, then a ± c < b ± c.
It’s in the natural form. Mark the numbers and x on the line
in order accordingly.
Put it in the natural form –3 < x < 0.
Then mark the numbers and x in order accordingly.

42. Example C. Solve x – 3 < 12 and draw the solution.
Inequalities

43. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
Inequalities

44. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
Inequalities

45. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x

46. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c.

47. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign,

48. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b

49. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.

50. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
For example 6 < 12 is true,

51. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12

52. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.

53. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
Example D. Solve 3x > 12 and draw the solution.
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.

54. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
Example D. Solve 3x > 12 and draw the solution.
3x > 12
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.

55. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
Example D. Solve 3x > 12 and draw the solution.
3x > 12 divide by 3 and keep the inequality sign
3x/3 > 12/3
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.

56. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
Example D. Solve 3x > 12 and draw the solution.
3x > 12 divide by 3 and keep the inequality sign
3x/3 > 12/3
x > 4 or 4 < x
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.

57. Example C. Solve x – 3 < 12 and draw the solution.
x – 3 < 12 add 3 to both sides
x – 3 + 3 < 12 + 3
x < 15
0 15
+–
Inequalities
x
A number c is positive means that 0 < c. We may multiply or
divide a positive number to the inequality and keep the same
inequality sign, i.e. if 0 < c and a < b, then ac < bc.
Example D. Solve 3x > 12 and draw the solution.
3x > 12 divide by 3 and keep the inequality sign
3x/3 > 12/3
x > 4 or 4 < x
40
+–
For example 6 < 12 is true, then multiplying by 3
3*6 < 3*12 or 18 < 36 is also true.
x

58. A number c is negative means c < 0.
Inequalities

59. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
Inequalities

60. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
Inequalities

61. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities

62. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
For example 6 < 12 is true.

63. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.

64. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

65. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
60
+–
12<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

66. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
60
+–
12–6 <
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

67. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

68. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

69. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
–x + 2 < 5
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

70. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
–x + 2 < 5 subtract 2 from both sides
–x < 3
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

71. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
–x + 2 < 5 subtract 2 from both sides
–x < 3 multiply by –1 to get x, reverse the inequality
–(–x) > –3
x > –3
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

72. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
–x + 2 < 5 subtract 2 from both sides
–x < 3 multiply by –1 to get x, reverse the inequality
–(–x) > –3
x > –3 or –3 < x
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

73. A number c is negative means c < 0. Multiplying or dividing by
an negative number reverses the inequality sign,
i.e. if c < 0 and a < b then
ca > cb .
Example E. Solve –x + 2 < 5 and draw the solution.
–x + 2 < 5 subtract 2 from both sides
–x < 3 multiply by –1 to get x, reverse the inequality
–(–x) > –3
x > –3 or –3 < x
0
+
-3
–
Inequalities
60
+–
12–6–12 <<
For example 6 < 12 is true. If we multiply –1 to both sides then
(–1)6 > (–1)12
– 6 > –12 which is true.
Multiplying by –1 switches the left-right positions of the originals.

74. To solve inequalities:
1. Simplify both sides of the inequalities
Inequalities

75. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides
Inequalities

76. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
Inequalities

77. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x.
Inequalities

78. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around.
Inequalities

79. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities

80. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9

81. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign

82. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign
3x – x > 9 – 5

83. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign
3x – x > 9 – 5
2x > 4

84. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign
3x – x > 9 – 5
2x > 4 div. 2
2x
2
4
2>

85. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign
3x – x > 9 – 5
2x > 4 div. 2
2x
2
4
2>
x > 2 or 2 < x

86. To solve inequalities:
1. Simplify both sides of the inequalities
2. Gather the x-terms to one side and the number-terms to the
other sides (use the “change side-change sign” rule).
3. Multiply or divide to get x. If we multiply or divide by
negative numbers to both sides, the inequality sign must be
turned around. This rule can be avoided by keeping the
x-term positive.
Inequalities
Example F. Solve 3x + 5 > x + 9
3x + 5 > x + 9 move the x and 5, change side-change sign
3x – x > 9 – 5
2x > 4 div. 2
20
+–
2x
2
4
2>
x > 2 or 2 < x

87. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
Inequalities

88. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
Inequalities

89. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
Inequalities

90. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18
Inequalities

91. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
Inequalities

92. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
Inequalities

93. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
–12
3
3x
3
>
div. by 3 (no need to switch >)
Inequalities

94. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
–12
3
3x
3
>
–4 > x or x < –4
div. by 3 (no need to switch >)
Inequalities

95. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
–4 > x or x < –4

96. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
We also have inequalities in the form of intervals.
–4 > x or x < –4

97. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
We also have inequalities in the form of intervals. We solve
them by +, –, * , / to all three parts of the inequalities.
–4 > x or x < –4

98. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
We also have inequalities in the form of intervals. We solve
them by +, –, * , / to all three parts of the inequalities.
Again, we + or – remove the number term in the middle first,
–4 > x or x < –4

99. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
We also have inequalities in the form of intervals. We solve
them by +, –, * , / to all three parts of the inequalities.
Again, we + or – remove the number term in the middle first,
then divide or multiply to get x.
–4 > x or x < –4

100. Example G. Solve 3(2 – x) > 2(x + 9) – 2x
3(2 – x) > 2(x + 9) – 2x simplify each side
6 – 3x > 2x + 18 – 2x
6 – 3x > 18 move 18 and –3x (change sign)
6 – 18 > 3x
– 12 > 3x
0
+
–12
3
3x
3
>
-4
div. by 3 (no need to switch >)
Inequalities
We also have inequalities in the form of intervals. We solve
them by +, –, * , / to all three parts of the inequalities.
Again, we + or – remove the number term in the middle first,
then divide or multiply to get x. The answer is an interval of
numbers.
–4 > x or x < –4

101. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw
Inequalities

102. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw.
12 > –2x + 6 > –4 subtract 6
–6 –6 –6
Inequalities

103. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw.
12 > –2x + 6 > –4 subtract 6
–6 –6 –6
6 > –2x > –10
Inequalities

104. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw.
12 > –2x + 6 > –4 subtract 6
–6 –6 –6
6 > –2x > –10 div. by -2, switch inequality sign
6
-2
-2x
-2<
-10
-2
<
Inequalities

105. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw.
12 > –2x + 6 > –4 subtract 6
–6 –6 –6
6 > –2x > –10
-3 < x < 5
div. by -2, switch inequality sign
6
-2
-2x
-2<
-10
-2
<
Inequalities

106. Example H. (Interval Inequality)
Solve 12 > –2x + 6 > –4 and draw.
12 > –2x + 6 > –4 subtract 6
–6 –6 –6
6 > –2x > –10
0
+
-3 < x < 5
5
div. by -2, switch inequality sign
6
-2
-2x
-2<
-10
-2
<
-3
Inequalities

107. Inequalities
Exercise. A. Draw the following Inequalities. Indicate clearly
whether the end points are included or not.
1. x < 3 2. –5 ≤ x 3. x < –8 4. x ≤ 12
B. Write in the natural form then draw them.
5. x ≥ 3 6. –5 > x 7. x ≥ –8 8. x > 12
C. Draw the following intervals, state so if it is impossible.
9. 6 > x ≥ 3 10. –5 < x ≤ 2 11. 1 > x ≥ –8 12. 4 < x ≤ 2
13. 6 > x ≥ 8 14. –5 > x ≤ 2 15. –7 ≤ x ≤ –3 16. –7 ≤ x ≤ –9
D. Solve the following Inequalities and draw the solution.
17. x + 5 < 3 18. –5 ≤ 2x + 3 19. 3x + 1 < –8
20. 2x + 3 ≤ 12 – x 21. –3x + 5 ≥ 1 – 4x
22. 2(x + 2) ≥ 5 – (x – 1) 23. 3(x – 1) + 2 ≤ – 2x – 9
24. –2(x – 3) > 2(–x – 1) + 3x 25. –(x + 4) – 2 ≤ 4(x – 1)
26. x + 2(x – 3) < 2(x – 1) – 2
27. –2(x – 3) + 3 ≥ 2(x – 1) + 3x + 13

108. Inequalities
F. Solve the following interval inequalities.
28. –4 ≤
2
x 29. 7 >
3
–x 30. < –4–x
E. Clear the denominator first then solve and draw the solution.
5
x2 3
1 2
3
2
+ ≥ x31. x4
–3
3
–4
– 1> x32.
x
2 8
3 3
4
5– ≤33. x
8 12
–5 7
1+ >34.
x
2 3
–3 2
3
4
4
1–+ x35. x4 6
5 5
3
–1
– 2+ < x36.
x
12 2
7 3
6
1
4
3–– ≥ x37.
≤
40. – 2 < x + 2 < 5 41. –1 ≥ 2x – 3 ≥ –11
42. –5 ≤ 1 – 3x < 10 43. 11 > –1 – 3x > –7
38. –6 ≤ 3x < 12 39. 8 > –2x > –4