The document provides examples of solving real-life simultaneous equation problems using different methods. It gives two examples solved by elimination and substitution. The first example is about finding the cost of one pizza and chicken sandwich given the total costs and quantities of two orders. The second example asks how long one needs to stay in an apartment to make the cheaper option with a higher deposit a better deal. Links and videos are also provided to explain solving simultaneous equations by graphing, elimination, and substitution.

1. Real life simultaneous equations problems Alaa Sharfi 1/27/2012 Algebra 2 Ms. Rosanna

2. Links to websites that explain how to solve simultaneous equations by Graphing: http://www.bbc.co.uk/schools/gcsebitesize/maths/algebra/simultaneoushirev2.shtml Elimination: http://www.teacherschoice.com.au/maths_library/algebra/alg_10.htm Substitution: http://www.teacherschoice.com.au/Maths_Library/Algebra/Alg_9.htm

3. Videos to explain simultaneous equations Elimination: http://www.youtube.com/watch?v=XM7Q4Oj5OTc Substitution: http://www.youtube.com/watch?v=8ockWpx2KKI Graphing: http://www.youtube.com/watch?v=cqBwozd8nu8

4. Real life s imultaneous equations problem solved by Elimination 7 pizzas and 5 chicken sandwiches cost $155. 10 pizzas and 8 chicken sandwiches cost $230. Find the cost of one pizza and one chicken sandwich. P= Pizza & S= chicken sandwich. 7p+5s= 155 10p+ 8s= 230

5. Multiply to get similar variables: 8 X (7p+ 5s= 155) = 56p+ 40s = 1240 5 X(10p+8s= 230)= 50p + 40s = 1150 Since both s variables are positive we subtract the two equations. 56p + 40s = 1240 - 50p + 40s = 1150 6 = 90 = 15 6 6 P=15

7. Real life s imultaneous equations problem solved by substitution

8. Solve the following question You are looking to rent an apartment. One costs $800 a month and has a $1000 deposit and the other costs $850 but has an $850 deposit. How long do you need to stay there before the first one is a better deal?