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Relationships Between
Binomial Coefficients
Relationships Between
Binomial Coefficients
Binomial Theorem
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)   

n
k
k
k
nn
xCx
0
1
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
let x = 1;
  

n
k
k
k
nn
xCx
0
1
  

n
k
k
k
nn
C
0
111
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
let x = 1;
  

n
k
k
k
nn
xCx
0
1
  

n
k
k
k
nn
C
0
111


n
k
k
nn
C
0
2
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
let x = 1;
  

n
k
k
k
nn
xCx
0
1
  

n
k
k
k
nn
C
0
111


n
k
k
nn
C
0
2


n
k
k
nnn
CC
1
02
Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
let x = 1;
  

n
k
k
k
nn
xCx
0
1
  

n
k
k
k
nn
C
0
111


n
k
k
nn
C
0
2


n
k
k
nnn
CC
1
02
0
1
2 CC nn
n
k
k
n

Relationships Between
Binomial Coefficients
Binomial Theorem   

n
k
k
k
nn
xCx
0
1
n
n
nk
k
nnnn
xCxCxCxCC  2
210
e.g. (i) Find the values of;

n
k
k
n
C
1
a)
let x = 1;
  

n
k
k
k
nn
xCx
0
1
  

n
k
k
k
nn
C
0
111


n
k
k
nn
C
0
2


n
k
k
nnn
CC
1
02
0
1
2 CC nn
n
k
k
n

12
1

n
n
k
k
n
C
 7531b) CCCC nnnn
 7531b) CCCC nnnn
  

n
k
k
k
nn
xCx
0
1
 7531b) CCCC nnnn
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
let x = -1;    54321011 CCCCCC nnnnnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
let x = -1;    54321011 CCCCCC nnnnnnn
 20 543210  CCCCCC nnnnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
let x = -1;    54321011 CCCCCC nnnnnnn
 20 543210  CCCCCC nnnnnn
subtract (2) from (1)
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
let x = -1;    54321011 CCCCCC nnnnnnn
 20 543210  CCCCCC nnnnnn
subtract (2) from (1)
 531 2222 CCC nnnn
 7531b) CCCC nnnn
let x = 1;
  

n
k
k
k
nn
xCx
0
1
 5
5
4
4
3
3
2
210 xCxCxCxCxCC nnnnnn
   54321011 CCCCCC nnnnnnn
 12 543210  CCCCCC nnnnnnn
let x = -1;    54321011 CCCCCC nnnnnnn
 20 543210  CCCCCC nnnnnn
subtract (2) from (1)
 531 2222 CCC nnnn

531
1
2 CCC nnnn

n
k
k
n
Ck
1
c)

n
k
k
n
Ck
1
c)
  

n
k
k
k
nn
xCx
0
1

n
k
k
n
Ck
1
c)
Differentiate both sides
  

n
k
k
k
nn
xCx
0
1

n
k
k
n
Ck
1
c)
Differentiate both sides
  

n
k
k
k
nn
xCx
0
1
  1
0
1
1 


 k
n
k
k
nn
xCkxn

n
k
k
n
Ck
1
c)
Differentiate both sides
  

n
k
k
k
nn
xCx
0
1
  1
0
1
1 


 k
n
k
k
nn
xCkxn
let x = 1;   


n
k
k
nn
Ckn
0
1
11

n
k
k
n
Ck
1
c)
Differentiate both sides
  

n
k
k
k
nn
xCx
0
1
  1
0
1
1 


 k
n
k
k
nn
xCkxn
let x = 1;   


n
k
k
nn
Ckn
0
1
11
    


n
k
k
nnn
CkCn
1
0
1
02

n
k
k
n
Ck
1
c)
Differentiate both sides
  

n
k
k
k
nn
xCx
0
1
  1
0
1
1 


 k
n
k
k
nn
xCkxn
let x = 1;   


n
k
k
nn
Ckn
0
1
11
    


n
k
k
nnn
CkCn
1
0
1
02
  1
1
2



n
n
k
k
n
nCk
 
 
n
k
k
nk
k
C
0 1
1
d)
 
 
n
k
k
nk
k
C
0 1
1
d)
  

n
k
k
k
nn
xCx
0
1
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
let x = 0;
 
1
0
1
01 1
0
1



 


 k
CK
n
kn
k
k
n
n
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
let x = 0;
 
1
0
1
01 1
0
1



 


 k
CK
n
kn
k
k
n
n
1
1



n
K
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
let x = 0;
 
1
0
1
01 1
0
1



 


 k
CK
n
kn
k
k
n
n
1
1



n
K
let x = -1;    
1
1
1
111
1
0
1








 k
C
n
kn
k
k
n
n
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
let x = 0;
 
1
0
1
01 1
0
1



 


 k
CK
n
kn
k
k
n
n
1
1



n
K
let x = -1;    
1
1
1
111
1
0
1








 k
C
n
kn
k
k
n
n
 
1
1
1
1
1
0 






 nk
C
kn
k
k
n
 
 
n
k
k
nk
k
C
0 1
1
d)
Integrate both sides
  

n
k
k
k
nn
xCx
0
1
 
11
1 1
0
1



 


 k
x
CK
n
x kn
k
k
n
n
let x = 0;
 
1
0
1
01 1
0
1



 


 k
CK
n
kn
k
k
n
n
1
1



n
K
let x = -1;    
1
1
1
111
1
0
1








 k
C
n
kn
k
k
n
n
 
1
1
1
1
1
0 






 nk
C
kn
k
k
n
 
1
1
1
1
0 



 nk
C
kn
k
k
n
 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
 
 n
n
nn
n
nn
n
nnnn
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC
xCxCxCxCxCC










1
1
2
2
2
210
1
1
2
2
2
210


 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
n
x
n
nn













0






































 
01122
122 n
x
n
n
x
n
x
n
n
x
n
x
n
n nnn

 
 n
n
nn
n
nn
n
nnnn
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC
xCxCxCxCxCC










1
1
2
2
2
210
1
1
2
2
2
210


 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
n
x
n
nn













0
1
11














 n
x
n
n
x
n
 
 n
n
nn
n
nn
n
nnnn
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC
xCxCxCxCxCC










1
1
2
2
2
210
1
1
2
2
2
210


 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
n
x
n
nn













0
1
11














 n
x
n
n
x
n 22
22














 n
x
n
n
x
n
 
 n
n
nn
n
nn
n
nnnn
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC
xCxCxCxCxCC










1
1
2
2
2
210
1
1
2
2
2
210


 
      nnn
n
xxx
xii
2
111
identity;theofsidesbothonoftscoefficientheequatingBy

 
 2
2
0 !
!2
that;show
n
n
k
nn
k







  

n
k
k
k
nn
xCx
0
1
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC  



1
1
2
2
2
210 
   nnn
xxx  11inoftcoefficien
n
x
n
nn













0
1
11














 n
x
n
n
x
n 22
22














 n
x
n
n
x
n




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


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


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 
01122
122 n
x
n
n
x
n
x
n
n
x
n
x
n
n nnn

 
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n
nn
n
nn
n
nnnn
n
n
nn
n
nn
n
nnnn
xCxCxCxCxCC
xCxCxCxCxCC



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

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1
1
2
2
2
210
1
1
2
2
2
210




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
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













022110
oftcoefficien
n
n
n
n
nn
n
nn
n
nn
xn














kn
n
k
n
But






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
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





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
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


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
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



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
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




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





022110
oftcoefficien
n
n
n
n
nn
n
nn
n
nn
xn














kn
n
k
n
But
2222
210

























n
nnnn













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



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
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

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


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

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
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




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







022110
oftcoefficien
n
n
n
n
nn
n
nn
n
nn
xn







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n
k
n
But
2222
210



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
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
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
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




n
nnnn







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
n
k k
n
0
2



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
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




022110
oftcoefficien
n
n
n
n
nn
n
nn
n
nn
xn






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kn
n
k
n
But
2222
210




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

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
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
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n
nnnn









n
k k
n
0
2
  nn
xx
2
1inoftcoefficien 




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
022110
oftcoefficien
n
n
n
n
nn
n
nn
n
nn
xn





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n
k
n
But
2222
210
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n
nnnn
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




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n
k k
n
0
2
  nn
xx
2
1inoftcoefficien 
  nnn
x
n
n
x
n
n
x
n
x
nn
x 222
2
22
2
2
1
2
0
2
1 

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Now
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111 
Now
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2
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n
k
nn
k
2
0
2
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!!
!2
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n

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2
111 
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k
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k
2
0
2
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!!
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n
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!
!2
n
n

Now
      nnn
xxx
2
111 
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n
k
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k
2
0
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!!
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n

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 2
!
!2
n
n

Exercise 5F;
4, 5, 6, 8, 10,15
+ worksheets

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12 x1 t08 05 binomial coefficients (2013)