2. Essential Questions
• How do you use Pascal’s Triangle to expand
powers of binomials?
• How do you use the Binomial Theorem to
expand powers of binomials?
5. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
6. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
1 1
7. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
1 1
1 12
8. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
1 1
1 12
3 31 1
9. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
1 1
1 12
3 31 1
1 4 4 16
10. Vocabulary
1. Pascal’s Triangle: A pattern of numbers that
can be used to determine the coefficients to
expand a binomial (a + b)n
1
1 1
1 12
3 31 1
1 4 4 16
10 105 51 1
18. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
19. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
20. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
This uses Pascal’s Triangle!
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
21. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
This uses Pascal’s Triangle!
The powers of the first part count down.
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
22. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
This uses Pascal’s Triangle!
The powers of the first part count down.
The powers of the second part count up.
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
23. Binomial Theorem
(a + b)n
= nC0an
b0
+ nC1an−1
b1
+ nC2an−2
b2
+...+ nCna0
bn
When expanding any binomial, we can use the pattern
This uses Pascal’s Triangle!
The powers of the first part count down.
The powers of the second part count up.
The powers within the term must add up to n.
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
56. Example 2
Expand (t −w)8
Pascal’s Triangle
Find the ninth row of the triangle for the coefficients of
each term, make count down the exponents from the
first part of your binomial and count up the exponents
from the second term.
57. Example 2
Expand (t −w)8
Pascal’s Triangle
(t −w)8
= t8
− 8t7
w + 28t6
w2
− 56t5
w 3
+ 70t 4
w 4
− 56t 3
w5
+ 28t2
w6
− 8tw7
+w8
Find the ninth row of the triangle for the coefficients of
each term, make count down the exponents from the
first part of your binomial and count up the exponents
from the second term.
63. Example 3
Find the third term of (3x − y )4
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
64. Example 3
Find the third term of (3x − y )4
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
3x − y( )4
=
4!
k!(4 − k )!
(3x )4−k
(−y )k
k =0
4
∑
65. Example 3
Find the third term of (3x − y )4
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
3x − y( )4
=
4!
k!(4 − k )!
(3x )4−k
(−y )k
k =0
4
∑
4!
2!(4 − 2)!
(3x )4−2
(−y )2
66. Example 3
Find the third term of (3x − y )4
a + b( )n
=
n!
k!(n − k )!
an−k
bk
k =0
n
∑
3x − y( )4
=
4!
k!(4 − k )!
(3x )4−k
(−y )k
k =0
4
∑
4!
2!(4 − 2)!
(3x )4−2
(−y )2
4!
2!2!
(3x )2
(−y )2